CaCO 3 ( s) + CO 2 (aq) + H 2 O(l) = Ca 2 + (aq) + 2HCO 3 - (aq)

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CaCO 3 (s) CO 2 (aq) H 2 O(l) = Ca 2 (aq) 2HCO 3 (aq) HCO3 (aq) H (aq) s --- > CO 2 (g) H 2 O(l) Chapter 6 Chemical Equilibrium

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Chapter 6 Chemical Equilibrium. CaCO 3 ( s) + CO 2 (aq) + H 2 O(l) = Ca 2 + (aq) + 2HCO 3 - (aq) HCO3 - ( aq) + H + (aq) s --- > CO 2 ( g) + H 2 O(l). aA + bB = cC + dD in its standard state. HA = H + + A - K 1 = [H + ][A - ] / [HA] - PowerPoint PPT Presentation

Transcript of CaCO 3 ( s) + CO 2 (aq) + H 2 O(l) = Ca 2 + (aq) + 2HCO 3 - (aq)

Page 1: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

CaCO3(s) + CO2(aq) + H2O(l) = Ca2 + (aq) + 2HCO3 - (aq)

HCO3 - (aq) + H + (aq) s --- > CO2(g) + H2O(l)

Chapter 6 Chemical Equilibrium

Page 2: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

aA + bB = cC + dD in its standard state

HA = H + + A - K1 = [H + ][A - ] / [HA] 만약 반응의 방향을 바꾸면 새 K 값은 처음 K 값의 역수가 된다 .H + + A - = HA K1′ = [HA] / [H + ][A- ] = 1/K1 HA = H + + A - K1

H + + C = CH + K2

----------------------------------HA + C = A - + CH + K3

K3 = K1K2 = [H + ][A - ] / [HA] ·[CH + ] / [H + ][C] = [A - ] ·[CH + ] / [HA] [C]

Page 3: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 4: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Enthalpy change, ΔH 는 일정 압력하에서 반응이 일어날 때흡수되는 열이다 .

Standard enthalpy change, ΔH°는 모든 반응물과생성물이 표준 상태에 있을 때 흡수하는 열을 가리킨다 .

HCl(g) = H + (aq) + Cl - (aq) 25℃에서 ΔH° = - 74.85 kJ/mol (6-3)

ΔH: 양수인 반응을 흡열 반응 (endothermic), 음수인 반응을 발열 반응 (exothermic).

6-2 Equilibrium and Thermodynamics

Page 5: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Entropy, S 는 “무질서”의 척도

KCl(s) = K + (aq) + Cl - (aq) 25 , ℃ ΔS° = +76.41 J/(K·mol) (6-4)

ΔS°는 모든 화학종이 표준 상태에 있을 때 엔트로피 변화 .

ΔS°가 양수인 것은 K + (aq) 1몰과 Cl - (aq) 1몰을 합한 것이 용매 물에 KCl(s) 1몰을 더한 것보다 더 무질서하다는 뜻이다 .

25℃에서 반응 6-3의 ΔS° = - 130.4 J/(K·mol) 이다 . 수용액에 있는 이온들은 용매 물에 기체 HCl을 더한 것 보다 덜 무질서하다 .

Page 6: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

- Chemical Reaction:음수의 ΔH (발열 ) 및 / 또는 양수의 ΔS (엔트로피의 증가 ) 에 의해 생성물을만드는 쪽으로 진행된다 .

- ΔH 가 음수이고 ΔS가 양수이면 분명히 그 반응은 유리하지만 , ΔH 가 양수이고 ΔS가 음수이면 분명히 불리하다 .

Page 7: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Gibbs Free Energy, ΔG

- ΔG 가 음수이면 그 반응은 자발적이다 .

ΔG° = ΔH° - TΔS°= ( - 74.85 × 103 J/mol) - (298.15 K) (- 130.4 J/K·mol)= - 35.97 kJ/mol

- 어떤 반응의 평형 상수와 그 반응의 에너지 (ΔH°와 ΔS°) 를 관련 짓기 위함 .

R 는 기체 상수 [ = 8.314 472 J/(K·mol)] 이고 , T 는 절대 온도이다 . ΔG°가 더 음수이면 , 평형 상수는 더 커진다 .

R 는 기체 상수 [ = 8.314 472 J/(K·mol)] 이고 , T는 절대 온도이다 .

K = e - ΔG°/RT

K = e - ( - 35.97 × 103 J/mol)/[8.314 472 J/(K·mol)(298.15 K) = 2.00 ×106

Page 8: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 9: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Le Chˆatelier’s principle:

Reaction quotient:

Because Q > K, the reaction must go to the left

Page 10: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

When the temperature changes:

The term including e ᅀ S/R is independent of T. The term e- ᅀ H/RT increases with increasing temperature if ᅀ Ho is positive, and decreases if it is negative.

K of the endothermic reaction increases if T is raised.K of the exothermic reaction decreases if T is raised.

Page 11: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

6-3 Solubility product

Ion pair

Page 12: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Common ion effect

A salt will be less soluble if one of its constituent ions is already present in the solution.

Page 13: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Separation by Precipitation

Co-precipitation: foreign ions adsorbed on the precipitate.

Q < Ksp for PbI2, Pb ions will not precipitate.

Page 14: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Lewis Acid and Bases

6-4 Complex Formation

Page 15: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Effect of Complex Ion Formation on Solubility

Page 16: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 17: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

6-5 Protic Acids and Bases

- Hydronium ion: H3O+

Brønsted- Lowry Acids and Bases: Acid: proton donor, Base: proton acceptor

Salt: Any ionic solid

When [I-] = 1.0 M, [Pb]total = 3.2 x 10-4 M

Page 18: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Conjugate Acids and Bases

Page 19: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

The Nature of H+ and OH-

Page 20: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 21: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 22: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 23: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Autoprotolysis

- Protic solvents have a reactive H+

Page 24: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

6-6 pH

Page 25: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 26: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 27: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 28: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Is There Such a Thing as Pure Water?

6-7 Strength of Acids and Bases

Strong Acids and Bases

Page 29: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 30: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Weak Acids and Bases

Ka: Acid dissociation constant

Kb: Base hydrolysis constant

Page 31: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Common Classes of Weak Acids and Bases

Page 32: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 33: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 34: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 35: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 36: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Polyprotic Acids and Bases

Page 37: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 38: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 39: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 40: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Kal ( 또는 K1) 은 가장 많은 양성자를 가진 산성 화학종에 대한 것이고 , Kbl 은 가장 적은 양성자를 가진 염기성 화학종에 대한 것이다 .

Page 41: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Relationship between Ka and Kb

Page 42: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

Carbonic Acid

Page 43: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 44: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 45: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 46: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 47: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 48: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)
Page 49: CaCO 3 ( s)  +  CO 2 (aq)  +  H 2 O(l) = Ca 2 + (aq)  +  2HCO 3 - (aq)

6-8 Solving Equilibrium Problems