The Programs

S. No. To Find Given

1. nth term

When

first term, common difference,value of n

Is Given

2. Sum of n terms

3. Arithematic Mean

enter first term, common difference,value of n

4. n if nth term is given

enter first term, common difference, Enter nth term

5. n if sum of n term is given

enter first term, common difference, sum of n terms

Code#include<iostream.h>#include<conio.h>#include<math.h>int main(){clrscr();int ch;float a,nth,n,d,s,AM,i,j;cout<<"\n";cout <<"Choice Menu"<<"\n";cout<<"\n";cout<<"1. nth term"<<"\n";cout<<"2. Sum of n terms"<<"\n";cout<<"3. Arithematic Mean"<<"\n";cout<<"4. n if nth term is given"<<"\n";cout<<"5. n if sum of n term is given"<<"\n";cin>>ch;switch(ch){ case 1 : cout<<"enter first term, common difference,value of n";

cin>>a>>d>>n; nth = a + (n-1)*d; cout<<"the nth term is"<<nth<<"\n"; break;

case 2 : cout<<"enter first term, common difference,value of n"; cin>>a>>d>>n; s = n/2*((a+a) +(n -1))*d; cout<<"the sum is "<<s; break;

case 3 : cout<<"enter first term, common diff.,value of n";

cin>>a>>d>>n; nth = a + (n-1)*d; AM = (a + nth)/2; cout<<"the AM is"<<nth<<"\n"; break;

case 4 : cout<<"enter first term, common difference, Enter nth term"; cin>>a>>d>>nth; n = (nth - a + d)/d; cout<<"the value of n is " <<n; break;

case 5 : float b,c,e,f,g,h,i,m; cout<<"enter first term, common difference, Enter sum of n term"; cin>>a>>d>>s; h= (d -(2*a)); b =(-((2*a)- d)); c = pow(h,2.0); e = (8*d*s); g =(c+e); f =sqrt(g); n =(b + f)/2*d ; i =(b - f)/2*d ; if (i < 0) cout<<"the value of n is " <<n; else cout<<"the value of n is " <<n<<"or"<<m; break; }

getch ();return 0;}

The resultant value when a number is given with the power to which it has to be raised for any given numberFor Eg :- 5 raise to 3 is 125

Code

#include<iostream.h>#include<conio.h>#include<math.h>int main(){clrscr();float number, power, answer;cout<<"enter the number :- ";cin>>number;cout<<"enter the power of the number :- ";cin>>power;answer = pow (number,power);cout<< number<<" raised to "<< power<<" is "<< answer;getch();return 0;}

A quiz in C++

€ Code#include<iostream.h>#include<conio.h>int main(){clrscr();int IQ, ch1,ch2, ch3, ch4; int pnt = 0;cout<<"Qs.1)In how many ways cane we rename a file

"<<"\n";cout<<"1.1 way "<<"\n";cout<<"2.3 ways "<<"\n";cout<<"3.5 ways "<<"\n";cout<<"4.Can't say ";cin>>ch1; if (ch1==2) { pnt =(pnt + 3); cout<<"correct Answer............."; } else cout<<"wrong Answer..............."; cout<<"\n"; cout<<"Qs. 2) fullstop is a valid character for filename in

Win Xp. What about its validity in Win 7 "<<"\n";

cout<<"1.Valid "<<"\n"; cout<<"2.Unvalid "<<"\n"; cin>>ch2; if (ch2==2) { pnt =(pnt + 3); cout<<"correct Answer.............."; } else cout<<"wrong Answer................"; cout <<pnt; cout<<"\n";cout<<"Qs.3)The inventing country of supercomputer PACE

is "<<"\n"; cout<<"1.India "<<"\n"; cout<<"2.China "<<"\n"; cout<<"3.Japan "<<"\n"; cin>>ch3; if (ch3==1) { pnt =(pnt + 3); cout<<"correct Answer............."; } else cout<<"wrong Answer..............."; cout<<"\n";

cout<<"Qs.4)Uninitialized variable will give as output cout<<"Qs.4)Uninitialized variable will give as output "<<"\n";"<<"\n";

cout<<"1.Garbage Value "<<"\n";cout<<"1.Garbage Value "<<"\n"; cout<<"2.zero "<<"\n";cout<<"2.zero "<<"\n"; cout<<"3.No output "<<"\n";cout<<"3.No output "<<"\n"; cin>>ch4;cin>>ch4; if (ch4==1)if (ch4==1) {{ pnt =(pnt + 3);pnt =(pnt + 3); cout<<"correct Answer.............";cout<<"correct Answer............."; }} elseelse cout<<"wrong Answer...............";cout<<"wrong Answer..............."; cout<<"\n";cout<<"\n";

IQ = pnt/3;IQ = pnt/3;

cout<<"please Wait"<<"\n";cout<<"please Wait"<<"\n"; cout<<"Generating Result"<<"\n";cout<<"Generating Result"<<"\n"; cout<< "you Answered "<<IQ<<" question correctly";cout<< "you Answered "<<IQ<<" question correctly"; cout<<" your score is:- "<< pnt;cout<<" your score is:- "<< pnt;

getch();getch(); return 0;return 0; }}

€ Code continued

To determine whether the area of the given rectangle is greater then it’s perimeter or not

Code#include<iostream.h>#include<iostream.h>#include<conio.h>#include<conio.h>int main ()int main (){{clrscr();clrscr();float l,b, p, a;float l,b, p, a;cout<<"enter length, bredth of the rectangle";cout<<"enter length, bredth of the rectangle";cin>>l>>b;cin>>l>>b;p = 2* (l +b);p = 2* (l +b);a = l*b;a = l*b;if (a >p)if (a >p)cout <<"the area is greater then the permeter"<<"\n";cout <<"the area is greater then the permeter"<<"\n";elseelsecout<<"the area is smaller then the perimeter"<<"\n";cout<<"the area is smaller then the perimeter"<<"\n";cout<<"perimeter :-"<<p<<"\n";cout<<"perimeter :-"<<p<<"\n";cout<<"area :-"<<a;cout<<"area :-"<<a;getch();getch();return 0;return 0;}}

To determine the compound interest on given amount for a given period and rate

Code#include <iostream.h>#include <iostream.h>#include<conio.h>#include<conio.h>#include<math.h>#include<math.h>int main()int main(){{clrscr();clrscr();float P,R,N,A,H,B;float P,R,N,A,H,B;cout<<"Enter Principle Amount: ";cout<<"Enter Principle Amount: ";cin>> P;cin>> P;cout<<"Enter Rate of Interest: ";cout<<"Enter Rate of Interest: ";cin>> R;cin>> R;cout<<"Enter Time Period (in years): ";cout<<"Enter Time Period (in years): ";cin>>N;cin>>N;H = (1 + R/100);H = (1 + R/100);B = pow (H,N);B = pow (H,N);A = (P*B);A = (P*B);cout<<"Principle Amout Rs."<<P<<"\n";cout<<"Principle Amout Rs."<<P<<"\n";cout<<"Rate of Interest "<<R<<" %"<<"\n";cout<<"Rate of Interest "<<R<<" %"<<"\n";cout<<"Time Period "<<N<<" years"<<"\n";cout<<"Time Period "<<N<<" years"<<"\n";cout<<"the compoud interest for the given amount is Rs."<<A;cout<<"the compoud interest for the given amount is Rs."<<A;getch();getch();return 0;return 0;}}

To determine the Quotient and Remainder To determine the Quotient and Remainder when a given number is divided by another when a given number is divided by another given numbergiven number

σ CodeCode#include <iostream.h>#include <iostream.h>#include<conio.h>#include<conio.h>int main ()int main (){{clrscr();clrscr();int a,div,b,num;int a,div,b,num;cout<<"enter the number to be divided";cout<<"enter the number to be divided";cin>>num;cin>>num;cout<<"enter the number by which "<<num<<" has to be divided";cout<<"enter the number by which "<<num<<" has to be divided";cin>>div;cin>>div;a = num/div;a = num/div;b = num%div;b = num%div;cout<<num<<" divided by "<<div<<" gives "<<"\n";cout<<num<<" divided by "<<div<<" gives "<<"\n";cout <<"quotient as "<<a<<"\n";cout <<"quotient as "<<a<<"\n";cout <<"remainder as "<<b;cout <<"remainder as "<<b;getch();getch();return 0;return 0;}}

To determine the result when a given To determine the result when a given number is raised to all numbers from 1 to number is raised to all numbers from 1 to the given valuethe given value

∏ Code#include<iostream.h>#include<iostream.h>#include<conio.h>#include<conio.h>#include<math.h>#include<math.h>#include<process.h>#include<process.h>

int main ()int main (){{clrscr();clrscr();int num, por;int num, por;cout<<"Enter the number whose powers are to be listed";cout<<"Enter the number whose powers are to be listed";cin>>num;cin>>num;cout<<"enter the power till you want the powers to be listed";cout<<"enter the power till you want the powers to be listed";cin>>por;cin>>por;for ( int i = 1;i <= por; i++)for ( int i = 1;i <= por; i++)cout << pow(num,i)<<"\n";cout << pow(num,i)<<"\n";getch ();getch ();return 0;return 0;}}

To Know the money present in a customer’s account at the end of specific time. Given amount deposited and time period

Code#include<iostream.h>#include<conio.h>#include<math.h>#include<process.h>int main (){clrscr();float amt, rt, A, H, B;int yrs,ch;

cout<<"enter amount deposited";cin>>amt;cout<<"number of years";cin>>yrs;cout<<"\n";cout<<"choose most appropriate option about your amonut and time

period"<<"\n";cout<<"1. amout less than 2000, yrs more than 1"<<"\n";cout<<"2. amout between 2000 and 6000,yrs more than or equal to 1 "<<"\n";cout<<"3. amout more than 6000, yrs more than or equal to 1"<<"\n";cout<<"4. yrs more than or equal to 5"<<"\n";cout<<"5. none of the above ";

cin>>ch;switch(ch){case 1:rt =5;break;case 2:rt =7;break;case 3:rt =8;break;case 4:rt =10;break;case 5:rt = 3;break;}

H = (1 + rt/100);B = pow( H, yrs);A = (amt * B);cout <<" the C. I for the "<<A;getch();return 0;}

To find the entered amount’s value in another country’s currency

Serial no.Serial no. Amount entered in Amount entered in Resulting amount inResulting amount in

11 INR INR US $US $

22 US $US $ INRINR

33 INRINR EuroEuro

44 EuroEuro INRINR

55 INRINR YenYen

66 YenYen INR INR

δ Code#include<iostream.h>#include<conio.h>#include<process.h>int main(){clrscr();int ch;float inri, inra, usdi, usda,inrie, inrae,euri,

eura,inriy,inray,yeni,yena;cout<<"Choose from and to (currency)"<<"\n";cout<<"1.INR to US $"<<"\n";cout<<"2.US $ to INR"<<"\n";cout<<"3.INR to Euro"<<"\n";cout<<"4.Euro to INR"<<"\n";cout<<"5.INR to Yen "<<"\n";cout<<"6.Yen to INR "<<"\n";cin>>ch;switch(ch) { case 1:cout<<"Enter amount in INR(Indian National

Rupee) :-"; cin>>inri; inra = (inri/53); cout<<inri<<" rupees are equal to "<<inra<<" US $"<<"\n"; break;

case 2:cout<<"Enter amount in US $ (US dollars) :-"; cin>>usdi; usda = (usdi * 53); cout<<usdi<<" US $ are equal to "<<usda<<"Indian rupees

"<<"\n"; break;

case 3:cout<<"Enter amount in INR(Indian National Rupee) :-"; cin>>inrie; inrae = (inrie/70); cout<<inrie<<" rupees are equal to "<<inra<<" Euro's"<<"\n"; break; case 4:cout<<"Enter amount in Euro's :-"; cin>>euri; eura = (euri * 70); cout<<euri<<" Euor's are equal to "<<eura<<"Indian rupees "<<"\

n";break;

case 5:cout<<"Enter amount in INR(Indian National Rupee) :-"; cin>>inriy; inray = (inriy*1.4); cout<<inriy<<" rupees are equal to "<<inra<<" Yen"<<"\n"; break;

case 6:cout<<"Enter amount in Yen's :-"; cin>>yeni; yena = (yeni/1.4); cout<<inri<<" Yen are equal to "<<inra<<" Indian rupees"<<"\n";

break; }getch();return 0;}

To know the amount of solar energy received in the given area over a given period of time

Code #include<iostream.h>#include<conio.h>int main (){ clrscr();int t;float ar,s;float S = 1.4;cout<<"enter area(mt. sq.), time (sec)";cin>>ar>>t;s = ar*t*60*1.4;cout<<"solar energy recieved ="<<s<<"kJ";getch();return 0;}

THANK THANK YOUYOU