Buck-Boost and Flyback Converter

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    Basic Principle of Buck-Boost

    The buck-boost is a popular non-isolated inverting power stage topology, sometimes

    called a step-up/down power stage. Power supply designers choose the buck-boost

    power stage because the required output is inverted from the input voltage, and the

    output voltage can be either higher or lower than the input voltage. The input current

    for a buck-boost power stage is discontinuous, or pulsating, because the power switch

    (Q1) current that pulses from zero to IL every switching cycle. The output current for

    a buck-boost power stage is also discontinuous or pulsating because the output diode

    only conducts during a portion of the switching cycle.

    Figure 1 shows a simplified schematic of the buck-boost power stage. Inductor L and

    capacitor C make up the effective output filter. The capacitor equivalent series

    resistance (ESR), RC, and the inductor dc resistance, RL, are included in the analysis.

    Resistor R represents the load seen by the power supply output. The diode D1 is

    usually called the catch diode, or freewheeling diode.

    Figure 1. Buck Power Stage Schematic

    During normal operation of the buck-boost power stage, Q1 is repeatedly switched on

    and off with the on- and off-times governed by the control circuit. This switching

    action gives rise to a train of pulses at the junction of Q1, D1, and L. Although the

    inductor, L, is connected to the output capacitor, C, only when D1 conducts, an

    effective L/C output filter is formed. It filters the train of pulses to produce a DC

    output voltage.

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    Figure 2. Buck Power Stage States

    The inductor current increase during the on state is given by:

    The quantity IL(+) is the inductor ripple current.

    The inductor current decrease during the off state is given by:

    The quantity IL(-) is also the inductor ripple current.In steady conditions, the current increase, IL(+) and the current decrease IL(-) must

    be equal. Solving for VO:

    )1(...)(

    )( ONLLQi

    L TL

    RIVVI

    +=+

    )2(...)(

    )( OFFLLdO

    L TL

    RIVVI

    =

    )3(.....)1(1

    )(

    )()(

    =

    +=

    D

    RIV

    D

    DVV

    T

    TTRIV

    T

    TVVV

    LLdQi

    OFF

    OFFONLLd

    OFF

    ONQiO

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    A common simplification is to assume VQ, Vd, and RL are small enough to ignore.

    Setting VQ, Vd, and RL to zero, the above equation simplifies considerably to:

    Unlike the buck power stage, the average of the inductor current is not equal to the

    output current. To relate the inductor current to the output current, referring to Figures

    2 and 3, note that the inductor delivers current to the output only during the off state

    of the power stage. This current averaged over a complete switching cycle is equal to

    the output current because the average current in the output capacitor must be equal to

    zero.

    Figure 3. CCM Buck Power Stage Waveforms

    )4(.....1 D

    DVV iO

    =

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    Figure 4. Boundary Between Continuous and Discontinuous Mode

    Further reduction in output load current puts the power stage into discontinuous

    current conduction mode(DCM). The discontinuous mode power stage input-to-output

    relationship is quite different from the continuous mode.

    Figure 5. Discontinuous Current Mode

    The duration of the on state is TON=DTS, where D is the duty cycle set by the

    control circuit. The duration of the off state is TOFF=D2TS. The idle time is the

    remainder of the switching cycle and is given as TS-TON-TOFF= D3TS. These

    times are shown with the waveforms in Figure 5.

    The inductor current increase during the on state is given by:

    The ripple current magnitude, IL(+), is also the peak inductor current, Ipk, becausein discontinuous mode. The current starts at zero each cycle.

    )5()1()()( OAvgLS

    OFF

    AvgL IDIT

    TI ==

    )6()( PKSi

    ON

    i

    L ITDL

    VT

    L

    VI ===+

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    The inductor current decrease during the off state is given by:

    As in the continuous conduction mode case, the current increase, IL(+), during the

    on time and the current decrease during the off time, IL(-), are equal. So,

    Figure 6. Discontinuous Mode Buck Power Stage Waveforms

    )7(2)( SO

    OFFO

    L TDL

    VT

    L

    VI

    =

    =

    )8(2D

    DV

    T

    TVV i

    OFF

    ON

    iO ==

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    Now calculate the output current. It is the average over one switching cycle of the

    inductor current during the time when D1 conducts(D2*Ts).

    Now solve two equations, IO and VO (equation 8 and 10), the discontinuous

    conduction mode buck voltage conversion relationship is given by:

    Where K is defined as:

    )9(22

    1)(

    === SPK

    S

    O

    avgLO TDI

    TR

    VII

    )10(2

    2

    2)()1(2

    11

    L

    TDDV

    TDTDL

    V

    TR

    VI

    Si

    SSi

    S

    OO

    =

    ==

    K

    DVV iO =

    STRLK

    =2

    )11(KMD =

    )12(i

    O

    VVM =

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    Critical Inductance

    The previous analyses for the buck-boost power stage have been for continuous and

    discontinuous conduction modes of steady-state operation. The conduction mode of a

    power stage is a function of input voltage, output voltage, output current, and the

    value of the inductor. A buck-boost power stage can be designed to operate in

    continuous mode for load currents above a certain level usually5 to 10% of full load.

    Usually, the input voltage range, output voltage, and load current are defined by the

    power stage specification. This leaves the inductor value as the design parameter to

    maintain continuous conduction mode.

    The minimum value of inductor to maintain continuous conduction mode can be

    determined by the following procedure.

    First, define IOB as the minimum output current to maintain continuous conduction

    mode, normally referred to as the critical current. This value is shown in Figure 4. In

    boundary between CCM and DCM,

    On Boundary:

    CCM:

    )1(2 D

    III OBLLB

    =

    =

    )15(2

    )(

    2OFF

    LLdOON

    LLOiLB T

    L

    RIVVT

    L

    RIVVI

    =

    =

    )16()(22

    )(

    2

    (max)

    2

    (max)

    (min)

    (max)

    min

    io

    i

    OB

    SO

    ON

    LB

    LLQi

    VV

    V

    I

    TV

    TI

    RIVV

    L

    =

    )13(ONLLQi

    L TL

    RIVVI

    =

    )14(

    1 D

    DVVo i

    =

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    Output Capacitor

    In switching power supply power stages, the function of output capacitor is to store

    energy. The output capacitance for a boost power stage is generally selected to limit

    output voltage ripple to the level required by the specification. The series impedance

    of the capacitor and the power stage output current determine the output voltage ripple.

    The three elements of the capacitor that contribute to its impedance (and output

    voltage ripple) are equivalent series resistance (ESR), equivalent series inductance

    (ESL), and capacitance (C). The voltage variation due to the inductor current flow in

    the output capacitor is approximately:

    For CCM Mode:

    For DCM Mode

    )(2

    2

    INdO

    PKO

    VVVC

    LIV

    +

    =OS

    O

    Vf

    DIC

    maxmax

    os

    s

    O

    Vf

    TR

    LI

    C

    21(max)

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    The above equation is based on the assumption that all inductor ripple current flows

    through the capacitor and the ESR is zero. Now, assuming that the capacitor is very

    large, the ESR needed to Limit the ripple to VOmax is:

    For CCM Mode:

    For DCM Mode:

    *The output filter capacitor should be rated at least 10~20 times the calculated

    capacitance and 30 to 50 percent lower than the calculated ESR.

    The RMS value of the ripple current flowing in the output capacitance(CCM) is given

    by:

    PK

    O

    O

    Max

    O

    O

    I

    V

    I

    D

    I

    VESR max

    (max)

    max

    )21

    (

    =

    +

    PK

    O

    O

    O

    I

    V

    I

    VESR maxmax

    =

    D

    DII OCRMS

    =1

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    Buck-Boost DC/DC Converter Small Signal Model (Transfer Function):

    )1

    )(()()

    1

    )(()()

    1(

    1)()(

    T

    sZsi

    T

    sGVsV

    T

    T

    HsVsV OUTload

    g

    grefO +

    ++

    +=

    gainloopV

    sGVsGsHsT

    M

    dC ==)()()(

    )(

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    For CCM Mode:

    *Two Pole fLC , One Zero fESRfor GVd(s) and One Right-Half-Plane zero

    z From a practical view, at RHP zero frequency, the loop gain starts increasing at a20dB/decade rate but the loop phase decreases by 45 degrees (in a normal, LHPzero, the loop phase will increase by +45 degrees). This imposes the restriction

    that the gain be rolled off to 0dB before encountering the RHP zero.

    z The output inductor, capacitor and the capacitors ESR must be selected so thatthe double pole occurs first and then the output capacitor zero and then the RHP

    zero. This assures that the loop gain crosses 0dB at a slope that is first order

    (20dB/decade) and that the instability inherently associated with the RHP zero is

    circumvented by crossing 0dB before the RHP zero frequency occurs.

    ( )

    ++

    +

    =

    2

    00

    21

    2

    1

    11

    1)(

    w

    s

    Qw

    s

    w

    s

    w

    s

    D

    VsGV

    ZZg

    d

    C

    L

    RDQ

    )1(

    LC

    D

    R

    RDR

    LCw L

    )1()1(1 2

    0

    +=

    CRw

    C

    Z

    11 =

    ( )DL

    RD

    L

    RRDw LZ

    22

    2

    )1(1

    =

    Compensate rule:

    4.Decrease the double pole influence. LCrcompensatoZ ff4

    3)(

    5.Crossover frequency fC SCESRC ffff )6

    1~

    10

    1(> )(

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    Figure 11. Flyback converter CCM waveforms

    The simplified voltage conversion relationship for the flyback power stage operating

    in CCM is given by:

    D

    Dn

    V

    V

    i

    O

    =

    1

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    Figure 12. Flyback converter DCM waveforms

    The simplified voltage conversion relationship for the flyback power stage operating

    in DCM is given by:

    S

    SEC

    i

    O

    TR

    LK

    K

    Dn

    V

    V

    ==

    2

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    Flyback DC/DC Converter Small Signal Model (Transfer Function):

    )1

    )(()()

    1

    )(()()

    1(

    1)()(

    T

    sZsi

    T

    sGVsV

    T

    T

    HsVsV OUTload

    g

    grefO +

    ++

    +=

    gainloopV

    sGVsGsHsT

    M

    dC ==)()()(

    )(

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    For CCM Mode:

    *Two Pole fLC , One Zero fESRfor GVd(s) and One Right-Half-Plane zero

    z From a practical view, at RHP zero frequency, the loop gain starts increasing at a20dB/decade rate but the loop phase decreases by 45 degrees (in a normal, LHPzero, the loop phase will increase by +45 degrees). This imposes the restriction

    that the gain be rolled off to 0dB before encountering the RHP zero.

    z The output inductor, capacitor and the capacitors ESR must be selected so thatthe double pole occurs first and then the output capacitor zero and then the RHP

    zero. This assures that the loop gain crosses 0dB at a slope that is first order

    (20dB/decade) and that the instability inherently associated with the RHP zero is

    circumvented by crossing 0dB before the RHP zero frequency occurs.

    ( )

    ++

    +

    =

    2

    00

    21

    2

    1

    11

    1)(

    w

    s

    Qw

    s

    w

    s

    w

    s

    D

    VnsGV

    ZZg

    d

    C

    L

    RDQ

    SEC

    )1(

    CL

    D

    R

    RDR

    CLw

    SEC

    L

    SEC

    )1()1(12

    0

    +=

    CRw

    C

    Z

    11 =

    SEC

    ZLD

    RDw

    2

    2

    )1(

    Compensate rule:

    1.Decrease the double pole influence. LCrcompensatoZ ff4

    3)(

    2.Crossover frequency fC SCESRC ffff )6

    1~

    10

    1(