Boyles law

Gases

Boyle’s Law

have

Temperature

PressureAmount

Gases

Volume

Type

Amount

is

𝐹𝑜𝑟𝑐𝑒𝐴𝑟𝑒𝑎

Pressure

(P)

atm

is

𝐹𝑜𝑟𝑐𝑒𝐴𝑟𝑒𝑎𝑁

𝑚2=Pa

measured in

Pressure

(P)

𝑁𝑚2=Pa

atm

is


k

measured in

Pressure

(P)

𝑁𝑚2=Pa

atm

is

k

measured in


Pressure

(P)

is


Pressure

(P)

𝑁𝑚2=Pa

atm

k

measured in

is amount of

space

Volume

(V)

is amount of

space

measured in

Volume

(V)

measured in

Volume

(V)is amount of

spacecm3

measured in

Volume

(V)is amount of

spacecm3

dm3

measured in

cm3

dm3

Volume

(V)is amount of

space

VVV

V

VVV

V

P

P

P

P

PVVV

V

P

P

P

Inverse

relationship

x y

relationship

x y

Inverse

proportion

may be

relationship may be

x yyx

proportion

by same factor

Inverse

Inverse

relationshipproportion

may be

x yx y

by same factor

proportion

Inverse

PV

by same factor

by same factor

proportion

Inverse

PV

have

PressureAmount

Gases

Volume

Temperature

Type

Amount

have

PressureAmount

Gases

Temperature

Type

Amount

Volume

have

Amount

Gases

Temperature

Type

Amount

VolumePressur

e

have

Amount

Gases

Temperature

Type

Amount

Pressure

Volume

How does the volume

of a trapped gas affect the gas’s

How does the volume

of a trapped gas affect the gas’s

pressure

?the gas’s

volumechange

volume causeschange

volume

pressurecauses

change change

volume

pressurecauses

change change

volume

pressurecauses

change change

How does the

volume

exerted on a trapped gas affect

pressure

?the gas’s

How does the

volume

exerted by a trapped gas affect

pressure

?the gas’s

Volume(dm3)

Pressure(units)

Volume(dm3)

Pressure(units)

5 1

Volume(dm3)

Pressure(units)

5 1

2,5

Volume(dm3)

Pressure(units)

5 1

2,5 2

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

2

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

x22

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

3

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

3 x3

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

4

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

4 x4

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

5

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

5 x5

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

2

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

2 x2

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

x

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

X1,33

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

X1,33÷𝟏 ,𝟑𝟑

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

x

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

xx

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

x?

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

? 6

1

2

3

4

5

6

x6

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

0,833 6

1

2

3

4

5

6

x6

Volume(dm3)

Pressure(units)

k(proportionality constant: PV)

5 1 5

2,5 2 5

1,67 3 5

1,25 4 5

1 5 5

? 6 5

1

2

3

4

5

6

x =x =x =x =x =x =

x =x =x =x =x =

Volume(dm3)

Pressure(units)


5 1 5

2,5 2 5

1,67 3 5

1,25 4 5

1 5 5

V 6 5

1

2

3

4

5

6 x =

V x 6 = 5 =

V x 6 = 5 = V =

V x 6 = 5 = V = = 0,833

x =x =x =x =x =

Volume(dm3)

Pressure(units)


5 1 5

2,5 2 5

1,67 3 5

1,25 4 5

1 5 5

0,833 6 5

1

2

3

4

5

6 x =

V x 6 = 5 = V = = 0,833 dm3

Volume(dm3)

Pressure(units)


V1 = 5 P1 = 1 5

2,5 2 5

1,67 3 5

1,25 4 5

1 5 5

? 6 5

1

2

3

4

5

6

V1 x P1 = 5

Volume(dm3)

Pressure(units)


V1 = 5 P1 = 1 5

V2 = 2,5 P2 = 2 5

1,67 3 5

1,25 4 5

1 5 5

? 6 5

1

2

3

4

5

6

V1 x P1 = 5

V2 x P2 = 5

V1 x P1 = 5

V2 x P2 = 5

V1 x P1 = V2 x P2

V1 x P1 = 5

V2 x P2 = 5

V1 x P1 = V2 x P2

P1V1 = P2V2

Volume(dm3)

Pressure(units)


V1 = 5 P1 = 1 5

V2 = 2,5 P2 = 2 5

1,67 3 5

1,25 4 5

V5 = 1 P5 = 5 5

? 6 5

1

2

3

4

5

6

P1V1 = P5V5

15 = 51

Volume(dm3)

Pressure(units)


V1 = 5 P1 = 1 5

V2 = 2,5 P2 = 2 5

V3 = 1,67 P3 = 3 5

V4 = 1,25 P4 = 4 5

V5 = 1 P5 = 5 5

? 6 5

1

2

3

4

5

6

P3V3 = P4V4

31,67 = 41,25

P3V3 = P4V4

31,67 = 41,25 5 = 5

Volume(dm3)

Pressure(units)


1,25 4 5

? 6 5

1

2

3

4

5

6

Volume(dm3)

Pressure(units)


V1 = 1,25 P1 = 4 5

V2 = ? P2 = 6 5

1

2

3

4

5

6

P1V1 = P2V2

P1V1 = P2V2

41,25 = 6V2

P1V1 = P2V2

41,25 = 6V2

=

P1V1 = P2V2

41,25 = 6V2

=

V2 = 0,833 dm3

Question 1

P1V1 = P2V2

DOES apply

Question 1

10 dm3 of a fixed mass of hydrogen gas at 273 K and at a pressure of 100 kPa is subjected to a pressure of 200 kPa at the same temperature. What is the new volume of the gas, in dm3?

P1V1 = P2V2

P1V1 = P2V2

10010 = 200V2

P1V1 = P2V2

10010 = 200V2

=

V2 = 5 dm3

Question 2

P1V1 = P2V2

DOES NOT apply

Question 2

Calculate the volume of 132g of CO2 at a pressure of 9 x 105 Pa and at a temperature of 300K.

by same factor

proportion

Inverse

PV

VPis inversely

proportional to

PV

VPis inversely

proportional to

is inversely proportional

to

PV

VP ∝

∝ 1

1

VP ∝ 1 x

VxV

VP ∝ 1 x

VxV

P ∝ 1V

VP ∝ 1 x

VxV

P ∝ 1V

P = kV

Volume(dm3)

Pressure(units)


5 1 5

2,5 2 5

1,67 3 5

1,25 4 5

1 5 5

0,833 6 5

1

2

3

4

5

6

x =x =x =x =x =x =

Volume(dm3)

Pressure(units)

5 1

2,5 2

1,67 3

1,25 4

1 5

0,833 6

0 1 2 3 4 5 6 70

2

4

6

The effect of the pressure of a trapped gas on its volume

Pressure (units)

Volu

me

(dm

³)

Boyles law

Education

Transcript of Boyles law