Boundary Layer Finalppt

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    Boundary Layer Theory

    Presented by:

    Sadashiv Jha

    A-61

    B.Tech(Mechanical)

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    Contents

    Boundary Layers

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    Boundary LayersAs a fluid flows over a body, the no-slip condition ensures

    that the fluid next to the boundary is subject to large shear. A

    pipe is enclosed, so the fluid is fully bounded, but in an open

    flow at what distance away from the boundary can we begin

    to ignore this shear?

    There are three main definitions of boundary layer thickness:

    1. 99% thickness2. Displacement thickness

    3. Momentum thickness

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    99% ThicknessU

    U is the free-stream velocity

    (x)

    x

    y

    (x) is the boundary layer thickness when u(y) ==0.99U

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    Displacement thickness

    There is a reduction in the flow

    rate due to the presence of the

    boundary layer

    This is equivalent to having atheoretical boundary layer with

    zero flow

    y

    u

    y

    uU

    U

    d

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    Displacement thicknessThe areas under each curve are defined as being equal:

    0

    dyuUq and Uq d

    0

    d dyU

    u1

    Equating these gives the equation for the displacement

    thickness:

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    Momentum thicknessIn the boundary layer, the fluid loses momentum, so

    imagining an equivalent layer of lost momentum:

    0 dyuUum andm

    2

    Um

    0

    m dyU

    u1

    U

    u

    Equating these gives the equation for the momentum

    thickness:

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    8

    BOUNDARY LAYER ON A FLAT PLATE

    Consider the following scenario.

    1. Asteady potential flow has constant velocity U in the x direction.

    2. An infinitely thin flat plate is placed into this flow so that the plate is

    parallel to the potential flow (0 angle of incidence).

    Viscosity should retard the flow, thus creating a boundary layer on either side

    of the plate. Here only the boundary layer on one side of the plate is

    considered. The flow is assumed to be laminar.

    Boundary layer theory allows us to calculate the drag on the plate!

    xy

    U

    U

    u

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    9A STEADY RECTILINEAR POTENTIAL FLOW HAS ZERO

    PRESSURE GRADIENT EVERYWHERE

    xy

    U

    U

    u

    plate

    A steady, rectilinear potential flow in the x direction is described by the

    relations

    According to Bernoullis equation for potential flows, the dynamic pressure of

    the potential flow ppd is related to the velocity field as

    Between the above two equations, then, for this flow

    0y

    v,Ux

    u,Ux

    const)vu(21p 22pd

    0y

    p

    x

    p pdpd

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    11NOMINAL BOUNDARY LAYER THICKNESS

    xy

    U

    U

    u

    plate

    Until now we have not given a precise definition for boundary layer thickness.

    Here we use to denote nominal boundary thickness, which is defined to be

    the value of y at which u = 0.99 U, i.e.

    U99.0)y,x(uy

    x

    y

    u

    U

    u = 0.99 U

    The choice 0.99 is arbitrary; we could have chosen 0.98 or 0.995 or whatever

    we find reasonable.

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    12STREAMWISE VARIATION OF BOUNDARY LAYER

    THICKNESS

    Consider a plate of length L. Based on the estimate of Slide 11 of

    BoundaryLayerApprox.ppt, we can estimate as

    or thus

    where C is a constant. By the same arguments, the nominal boundary thickness

    up to any point x L on the plate should be given as

    UL,)(~L

    2/1ReRe

    2/12/1

    U

    L

    CorU

    L

    ~

    2/12/1

    UxCor

    Ux~

    xy

    U

    U

    u

    plateL

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    Laminar boundary layer growth

    + d

    dy

    x

    y

    Boundary layer => Inertia is of the same magnitude as Viscosity

    a) Inertia Force: a particle entering the b.l. will be slowed from a velocity

    U to near zero in time, t. giving force FIU/t. But u=x/t => t l/U

    where U is the characteristic velocity and lthe characteristic length in the

    x direction.

    Hence FIU2/l

    b) Viscous force: F/y 2u/y2U/2

    since U is the characteristic velocity and the characteristic length in the

    y direction

    (x)

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    Laminar boundary layer growth

    Comparing these gives:

    U

    l

    So the boundary layer grows according tol

    Alternatively, dividing through by l, the non-dimensionalised

    boundary layer growth is given by:

    lRl

    1

    Note the new Reynolds number

    characteristic velocity and

    characteristic length

    U

    U llRl

    )(U

    5 Blasius

    lU2/lU/2

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    Boundary layer growth

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    Length Reynolds Number

    UlRl

    l

    U

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    Flow at a pipe entry

    l

    U

    d

    If the b.l. meet while the flow is still laminar the flow in the pipe will be laminar

    If the b.l. goes turbulent before they meet, then the flow in the pipe will beturbulent

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    Boundary layer equations for laminarflowThese may be derived by solving the Navier-Stokes equations

    in 2d.

    0 yv

    xu

    dtdu

    yu

    xu

    xp

    1 2

    2

    2

    2

    Continuity MomentumU

    Assume:

    1. The b.l. is very thin compared to the length

    2. Steady state

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    Boundary layer equations for laminarflow

    y

    uv

    x

    uu

    y

    u

    x

    p

    12

    2

    This gives Prandtls b.l. equation:

    rate of change of u with

    x is small compared to y

    Blasius produced a perfect solution of these equations valid

    for 0

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    Blasius Solution

    0

    5

    0 1

    u/U

    y'

    y' f' (or u/U) f''

    0 0 0.332

    1 0.330 0.332

    2 0.630 0.3233 0.846 0.267

    4 0.956 0.161

    5 0.992 0.064

    6 0.999 0.002

    7 1.000 0.000

    l

    Uy'y

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    Laminar skin frictionThe shear stress at the surface can be found by evaluatingthe velocity gradient at the surface

    00 y

    u

    The friction drag force along the surface is then found by

    integrating over the length

    dxy

    ubF

    0y0

    f

    l

    where b is the breadth of the surface

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    Laminar skin frictionFrom the Balsius solution, the gradient of the velocityprofile at y=0 yields the result:

    0.5

    x0 Rx

    U

    0.332

    The shear force can be obtained by integration along the surface

    0.5

    0

    0f R0.664UbdxbF l

    l

    The frictional drag coefficient can then be calculated

    21

    R33.1AU

    FC

    2

    21

    ff

    l

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    Force and momentum in fluid

    mechanics - refresherNewtons laws still apply. Consider a stream

    tube:

    u1,A1

    q1=u1A1

    u2,A2

    q2=u2A2

    mass entering in time, t, is u1A1tmomentum entering in time, t, is m1 = (u1A1t)u1

    momentum leaving in time, t, is m2 = (u2A2t)u2

    Impulse = momentum change, F = (m2m1)/ t = (u22

    A2-u12

    A1)

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    The von Karman Integral Equation(VKI)

    A

    B

    C

    D

    Flow enters on AB and BC, and leaves on CD

    1 2

    2 -1

    x

    U

    u1(y)u2(y)

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    VKIThe momentum change between entering and leaving the control volume

    is equal to the shear force on the surface:

    122

    0

    2

    1

    0

    2

    20 Udyudyux12

    (CD) (AB) (BC)

    By conservation of fluid mass, any fluid entering the control volume must

    also leave, therefore

    12

    0

    1

    0

    212 )(

    dyudyuU

    12

    0

    1

    2

    1

    0

    2

    2

    20 dyUuudyUuux

    Force onfluid

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    VKI

    0

    2

    0 dyUuuddx

    As x 0, the two integrals on the right become closer and

    the equation may be written as a differential:

    0

    2

    0 dyU

    u1

    U

    u

    dx

    dU

    The integral is the definition of the momentum thickness, so

    dx

    dU m20

    dx

    dUUd if U(x)

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    Turbulent boundary layers

    The assumption is made that the flat plate approximates tothe behaviour in a pipe. The free stream velocity, U,

    corresponds to the velocity at the centre, and the boundary

    layer thickness, , corresponds to the radius, R.

    1/7 Power Law

    From experiments, one possibility for the shape of the

    boundary layer profile is71

    y

    U

    u

    and measurements of the shear profile give

    41

    U

    U0.0225 20

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    Turbulent boundary layers

    Putting the expression for the 1/7 power law into the

    equations for displacement and momentum thickness

    72

    7

    ,8

    md =99%

    d

    m

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    Turbulent boundary layersdx

    dU m20 becomes

    dx

    dU

    72

    7 20

    Equating this to the experimental value of shear stress:

    41

    U

    0.0225

    d

    d

    72

    7

    x

    Integrating gives:

    5

    1

    Ux0.37x

    The turbulent boundary grows as x4/5, faster than the

    laminar boundary layer.

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    Turbulent boundary layersMomentum thickness

    51

    Ux0.036x

    72

    7m

    To find the total force, first find the shear stress

    dx

    dU m20

    then integrate over the plate length

    m

    2

    0

    m2

    0

    0 Udx

    dx

    dUdxF

    ll

    f

    For a plate of length, l, and width b,

    51

    UbU0.036F 2

    l

    lf51

    0.074RC lf )10R10*5(

    75 l

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    Logarithmic boundary layerFrom the mixing length hypothesis it can be shown that

    the profile is logarithmic, but the experimental values

    are different from those in a pipe

    yVln85.556.5

    V

    u *

    *

    and the friction coefficient llf R

    A

    Rlog

    455.0

    C 58.2

    (A is a correction constant if part of the b.l. is laminar)

    )10R0( 9 l ritrit

    58.2

    rit

    RR

    1.328

    Rlog

    455.0c

    cc

    A

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    Quadratic approximation to the

    laminar boundary layer

    2

    y

    y2U

    u

    Remember - boundary layer theory is only applicable inside

    the boundary layer.

    This is sometimes written with =y/ and F()=u/U as

    2

    2F It provides a good approximation to the shape of the

    laminar boundary layer and to the shear stress at the surface

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    Turbulent Boundary Layer

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    Laminar Sub-Layer

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