Board Revision Maths Paper II.
Transcript of Board Revision Maths Paper II.
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8/14/2019 Board Revision Maths Paper II.
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By Nitin Oke for SAFE HANDS
Board Pattern Mathematics
Paper II
By
Nitin OkeFor Safe Hands
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Out line of paper
Qu.1
(A) Two out of three (3+3+3) (B) One out of two (2 + 2)
Qu.2
(A) Two out of three (3+3+3) (B) One out of two (2 + 2)
Qu.3, Qu.4, Qu.5 (A) (a) One out of two (3+3) (b) One out of two (3 + 3) (B) One out of two (2 + 2)
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By Nitin Oke for SAFE HANDS
Out line of paper
Limit and continuity(3+3+3) 06/09
Differentiation (3+3+3) 09/18 Application of differentiation (2+2) 04/08
Indefinite & definite integrals (3+3+2) 08/16
Application of integration (3) 03/06 Differential equation (2) 02/04
Application of differential equation(3) 03/06
Numerical methods (3+3) 03/06 Boolean Algebra (2+2) 02/04
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Theory questions are
Prove that
Use the fact
A(OAB) Area of sector OAC A(OAC) 1 > (sinx)/x > cosx taking limit of both sides
We get
Limit (3+3) and Continuity (3)
1
0
= x
xsinxLim
A
B
C
O
1
0=
xxsin
xLim
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8/14/2019 Board Revision Maths Paper II.
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By Nitin Oke for SAFE HANDS
You need to remember
L Hospitals rule is not allowed in board examination
Write standard result before using at end Trigonometric functions must have angle in radian
Be careful about problem of continuity whether it
is at point or on interval. Please note that following results are not standard
result you need to divide and multiply by properterm
b
a
bx
axsin
xLim =0
)ba(
e)
bx()ax(
xLim =+
1
1
0
i i i
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8/14/2019 Board Revision Maths Paper II.
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i erentiation + + +Derivative & application of derivatives
One proof (out of two) & two problems of 3 marks
( out of three) one problem of 2 marks (out of two) Proof will be of
Chain rule y= f(u) & u = g(x) then dy/dx = (dy/du).(du/dx)
If y = u+v then prove that y = u + v If y = u.v then prove that y = uv + uv
If y = u/v then prove that y = (vu uv)/v2
If y = f(x) then y = 1/(dx/dy)
If y = f(u) and x = g(u) then dy/dx = (dy/du)/(dx/du) If f(x) is derivable at x = a then f(x) is continuous at x=a
Derivatives of inverse circular functions.
Derivative by first principle.
i i
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8/14/2019 Board Revision Maths Paper II.
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ome important resu ts o inversetrigonometric functions
T-1(T(x)) = x
T (T-1(x)) = x
(CoT -1(x)) = T-1(1/x)
Sin-1(-x) = -sin-1(x)
Tan-1(-x) = -tan-1(x)
Cos-1(-x) = - cos-1(x)
Sin-1
(x) + cos-1
(x) =
/2 Tan-1(x) + cot-1(x) = /2
Sec-1(x) + cosec-1(x) = /2
=
xy
yxtan)y(tan)x(tan
1
111
( )
)ab(tanwhere
xsin(sin)
ba
xcosbxsina(sin
1
1
22
1
=
=+
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8/14/2019 Board Revision Maths Paper II.
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8/14/2019 Board Revision Maths Paper II.
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Application of derivatives
Geometrical applications
Geometrical meaning of derivative Tangent at a point of y = f(x), As y y1 = f(x).(x-x1)
Normal at a point of y = f(x) As y y1 = (x x1)/f(x)
Rate of change measure
Meaning of growth and decay rate Physical meaning
Approximation F (a + h) = h. f (a) + f (a) You need to identify function, value of a & h
Maxima minima Identification of critical points Single derivative test
Double derivative test
I t ti (3 3 3 2)
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8/14/2019 Board Revision Maths Paper II.
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One proof of indefinite integral or one property of definite
integral (out of two) & two problems of 3 marks ( one out oftwo each on I and D) one problem of 2 marks (out of 2 on I )
Proof will be of Integration by parts
Integration (3+3+3+2)Indefinite(3+3), Definite (3 + 2) & application
c)x(fxedx))x('f)x(f(xe + =+
cxaxlog[a
xax
dxxa + ++++=+ 222
222
2
22
caxxlog[a
axx
dxax + += 222
222
2
22
ca
xsin
axa
xdxxa +
= 1
2
222
2
22
I t ti (3 3 3 2)
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8/14/2019 Board Revision Maths Paper II.
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By Nitin Oke for SAFE HANDS
One proof of indefinite integral or one property of definite
integral (out of two) & two problems of 3 marks ( one out oftwo each on I and D) one problem of 2 marks (out of 2 on I )
Proof will be of
Integration (3+3+3+2)Indefinite(3+3), Definite (3 + 2) & application
=
a
b
b
a)x(f)x(f
+=b
c
c
a
b
a
)x(f)x(f)x(f
odd.if
evenis)x(fif)x(f)x(f
aa
a
0
2
0
=
=
f(x)-x)-f(2aif0
f(x)x)-f(2aif)x(f)x(f
aa
==
== 0
2
0
2
I t ti (3 3 3 2)
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One proof of indefinite integral or one property of definite
integral (out of two) & two problems of 3 marks ( one out oftwo each on I and D) one problem of 2 marks (out of 2 on I ) Problem to find area or volume of solid of revolution.
Integration (3+3+3+2)Indefinite(3+3), Definite (3 + 2) & application
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8/14/2019 Board Revision Maths Paper II.
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Boolean Algebra (2+2)
Questions will be based on
only properties of Booleanalgebra or on duals. Onequestion will be on logicgates or switching circuits
If x, y, z are elements ofBoolean algebra then withusual notations
x + x = x
x.x = x
x . x = 0
x. 1 = x
x + 1 = x x + x = 1
(x + y) = x . Y
(x . Y) = x + y
x + (x . Y ) = x x . ( x + y ) = x
x + x . y = x + y
(x) = x
(x + y) . (x + z) = x + y. z
x.y + x.y = (x + y) . (x + y)
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Boolean Algebra (2+2)
Logic gates
ANDx
yx . y (1,1 is 1 all other zero)
x
yx + y (0,0 is 0 all other one
OR
NOTy
y
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