[email protected] ENGR-45_Lec24A_MTE2_Exam-Review.ppt 1 Bruce Mayer, PE Engineering-45:...
20
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt 1 Bruce Mayer, PE Engineering-45: Materials of Engineering Bruce Mayer, PE Registered Electrical & Mechanical Engineer [email protected] Engineering 45 MT2 Exam MT2 Exam Review Review
-
Upload
austin-cooks -
Category
Documents
-
view
222 -
download
2
Transcript of [email protected] ENGR-45_Lec24A_MTE2_Exam-Review.ppt 1 Bruce Mayer, PE Engineering-45:...
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt1
Bruce Mayer, PE Engineering-45: Materials of Engineering
Bruce Mayer, PERegistered Electrical & Mechanical Engineer
Engineering 45
MT2 MT2 ExamExam
ReviewReview
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt2
Bruce Mayer, PE Engineering-45: Materials of Engineering
Paper CreepPaper Creep
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt3
Bruce Mayer, PE Engineering-45: Materials of Engineering
Paper CreepPaper Creep
A. Dwan, “Paper Complexity And The Interpretation Of Conservation Research ”, Journal of the American Institute of Conservation, Vol. 26, No. 1, pp. 1-17), 1987
Find a LINEAR equation, ε(t), that approximates the creep of paper over 1-100 minutes
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt4
Bruce Mayer, PE Engineering-45: Materials of Engineering
Draw “Good” Line, Find 2-ptsDraw “Good” Line, Find 2-pts
2.47%
2.16%
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt5
Bruce Mayer, PE Engineering-45: Materials of Engineering
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt6
Bruce Mayer, PE Engineering-45: Materials of Engineering
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt7
Bruce Mayer, PE Engineering-45: Materials of Engineering
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt8
Bruce Mayer, PE Engineering-45: Materials of Engineering
Lever-Law vs. T ProblemLever-Law vs. T Problem
Pb-Mg Alloy → 45 wt% Pb Quenched from Hi-Temp at Which The
Alloy is a solid with Phase Fractions:• Wα = 65% and WMg2Pb = 35%
Find the Approximate Temperature from Which the Alloy was Quenched
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt9
Bruce Mayer, PE Engineering-45: Materials of Engineering
Freeze-In
Pro
blem
Freeze-In
Pro
blem
45
For Troom Equil
%4.44081
4581
W%6.55081
0452
PbMgW
“Freeze In%35%65
2 PbMgWW
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt10
Bruce Mayer, PE Engineering-45: Materials of Engineering
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt11
Bruce Mayer, PE Engineering-45: Materials of Engineering
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt12
Bruce Mayer, PE Engineering-45: Materials of Engineering
T fo
r Pu
re T
for P
ure αα
= 26.5%
Pb
= 26.5%
Pb
25.6
“Freeze in from 360C%35%65
2 PbMgWW
360
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt13
Bruce Mayer, PE Engineering-45: Materials of Engineering
Lever-Law vs. T Problem AnsLever-Law vs. T Problem Ans
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt14
Bruce Mayer, PE Engineering-45: Materials of Engineering
Prob 10.9 → Avrami EqnProb 10.9 → Avrami Eqn Given that A→P Transformation
obeys the Avrami Eqn:nktey 1
% Xformed, yTime, t (S)
20 420
60 425
Given Xform Data Then find the time Required for 95% Transformation
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt15
Bruce Mayer, PE Engineering-45: Materials of Engineering
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt16
Bruce Mayer, PE Engineering-45: Materials of Engineering
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt17
Bruce Mayer, PE Engineering-45: Materials of Engineering
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt18
Bruce Mayer, PE Engineering-45: Materials of Engineering
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt19
Bruce Mayer, PE Engineering-45: Materials of Engineering
P10.9 MATLAB SolutionP10.9 MATLAB Solution>> Y1 = log(log(1/0.8))Y1 = -1.4999>> Y2 = log(log(1/0.4))Y2 = -0.0874>> X1 = log(280)X1 = 5.6348>> X2 = log(425)X2 = 6.0521>> P = [X1, 1; X2, 1] 5.6348 1.0000 6.0521 1.0000>> Q =[Y1; Y2]Q = -1.4999 -0.0874
>> z = P\Qz = 3.3849-20.5732>> n =z(1)n = 3.3849>> k = exp(z(2))k = 1.1620e-009
>> t = ((log(1/.05))/k)^(1/n)t = 603.0849
[email protected] • ENGR-45_Lec24A_MTE2_Exam-Review.ppt20
Bruce Mayer, PE Engineering-45: Materials of Engineering
Pb-Sn SoldersPb-Sn Solders
