BJT, Bipolar Junction Transisor
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Transcript of BJT, Bipolar Junction Transisor
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BJT, Bipolar Junction Transisor
Bollen
Base CurrentBase Current
ControlsControls
Output currentOutput current
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AGENDA
Bollen
BJT transistormanTransistor typesBipolar Junction TransistorBJT modelsparameterswater modelNPN and PNPoperation modesswitch openswitch closed
BJTlinear, controlled current sourceactive operationcharacteristicsDC input characteristicsac input characteristicsBJT DC biasing circuitsbase biasbase bias + collector feedbackbase bias + emitter feedbackvoltage divider
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BJT, transistor man
Bollen
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TransistorTypes
Bollen
Output currentOutput current controlled controlled
by by input currentinput current
Output currentOutput current controlledcontrolled
by by input voltageinput voltage
BJT ==
Bipolar Junction Bipolar Junction TransistorTransistor
FET ==
Field Effect TransistorField Effect Transistor
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BJT, Bipolar Junction Transisor
Bollen
BE ForwardBE Forward bias, bias, BC ReverseBC Reverse bias bias
So So lowlow ohmic ohmic highhigh ohmic ohmic
TransistorTransistor == TranTransfersfer ReResistorsistor
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BJT, Bipolar Junction Transisor
Bollen
Emitter Emitter = Sent = Sent electronselectrons
BaseBase = Base = Base
CollectorCollector = Get = Get electrons electrons
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BJT, Models
Bollen
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BJT, parameters
Bollen
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BJT, Water model
Bollen
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BJT, Water model
Bollen
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BJT, NPN and PNP
Bollen
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BJT, Operation modes
Bollen
Cut-off and Cut-off and saturation;saturation;
BJT is used as a BJT is used as a switchswitch
Active operationActive operation
Quiecent Point;Quiecent Point;
BJT is used as a BJT is used as a
controlled controlled
current source,current source,
or or analog amplifieranalog amplifier
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BJT, Switch open
Bollen
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BJT, Switch closed
Bollen
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BJT, Lineair, controlled current source
Bollen
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BJT, active operation
Bollen
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BJT, characteristics
Bollen
DCDC model model acac model model
DCDC model; Vbe = 0V7 Ube, Uce, Ic, Ib, Ie model; Vbe = 0V7 Ube, Uce, Ic, Ib, Ie CapitalsCapitals
acac model; re = 26mV/Ie ube, uce, ic, ib, ie model; re = 26mV/Ie ube, uce, ic, ib, ie Low Low casescases
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BJT, DC input characteristics
Bollen
Vbe = 0V7
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BJT, AC input characteristics
Bollen
re = 26mV/Ic
The dynamic resistor can be calculated by the DC current
Ic
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BJT, characteristics
Bollen
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BJT, DC biasing circuits
Bollen
A base biasA base bias
B base bias + emitter feedbackB base bias + emitter feedback
C base bias + collector feedbackC base bias + collector feedback
D voltage dividerD voltage divider
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BJT, base bias, introduction
Bollen
Base current determined by Vcc, Rb and Vbe
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BJT, base bias
Bollen
cc Rb beV U U
cc b b beV I R U
c bI I Calculate Ib and then Ic
Ic directly dependent on ß variation
So, for stability a “bad” circuit
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BJT, base bias load line
Bollen
Load line is the loading of the transistor seen from Uce (>0V7)
Vcc and Rc determines the; “open voltage” and the “short circuit current”
Q-point = Quiecient
point= Working point
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BJT, base bias load line
Bollen
Load line is the loading of the transistor seen from Uce (>0V7)
Vcc and Rc determines the; “open voltage” and the “short circuit current”
Reliable circuit= Q-point
stability
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BJT, base bias load line
Bollen
Vce always > 0V7BC junction
REVERSE
If Rc too big, transistor in saturation; then;
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BJT, base bias load line
Bollen
Vce always > 0V7BC junction
REVERSE
If Vcc too small, transistor in saturation; then;
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BJT, base bias example
Bollen
Calculate;
Ib, IcURc, Uc, Uce
Draw output caracteristic
Calculate now;
Uce if ß = 40How many % did Uce
ChangeIb = 47 uA, Ic = 2,35 mA, URc = 5,17 V, Uc = 6,83 V, Uce = 6,83 VUce (for ß = 40) = 7,86 Ξ 15 %
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BJT, base bias example
Bollen
Ib = 33 uA, Ic = 2,9 mA URc = 7,9 V, Uc = 8,1 V
Rb = 282,5 kΩ, Ic = 3,2 mA,
Rc = 1,855 kΩ
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BJT, base bias example
Bollen
ß = 200, VRc = 8,8 VVcc = 16 VRb = 765 kΩ
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BJT, base bias + emitter feedback
Bollen
Base current determined by Vcc, Rb, Vbe and Ve
More stable for ß variations, than base bias.
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BJT, base bias + emitter feedback
Bollen
Always calculate in the smallest current Ib !!
Recc Rb beV U U U
Re1cc b b be bV I R U I U
Rc c cV I R
c cc c cV V I R
e e eV I R
ce c eV V V
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BJT, base bias + emitter feedback
Bollen
Load line is the loading of the transistor seen from Uce (>0V7)
Vcc, Rc and Re determines the; “open voltage” and the “short circuit current”
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BJT, base bias + emitter feedback example
Bollen
Calculate;
Ib, IcURc, Uc, Ue, Uce
Draw output caracteristic
Ib = 6,2 uA, Ic = 0,74 mA, URc = 8,9 V, Uc = 7,1 V, Ue =-0,9 V, Uce = 8,0 V
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BJT, base bias + emitter feedback example
Bollen
Calculate;
Ib, IeURe, Ue, Uce
Draw output caracteristic
Ib = 24 uA, Ie = 2,9 mA, URc = 3,5 V, Ue = -2,5 V, Uce = 2,5 V
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BJT, base bias + collector/emitter feedback
Bollen
If Ic > then Uc < then Ib <
If Ic > then Uc <and Ue > then Ib <
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BJT, base bias + collector feedback
Bollen
cc Rc Rb beV U U U
1cc b c b b beV I R I R U
Always calculate in the smallest current Ib !!
The current through Rc is not Ic but Ic + Ib,
so (β+1)Ib !!!
If Ic rises for any reason, then Uc falls and
also Ib decreases, so then Ic decreases
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BJT, base bias collector feedback example
Bollen
Calculate;
Ib, ß, Ic
Draw output caracteristic
Ib = 13 uA, ß = 196, Ic = 2,5 mA
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BJT, base bias collector/emitter feedback
Bollen
Recc Rc Rb beV U U U U
1
1
cc b c
b b
be
b e
V I R
I R
U
I R
Always calculate in the smallest current Ib !!
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BJT, base bias collector/emitter feedback ex
Bollen
Calculate;
Ib, IeURc, Uc, Ue, Uce
Draw output caracteristic
Ib = 11,8 uA, Ie = 1,1 mA
URc = 5,2 V, Uc = 4,8 V
Ue = 1,3 V, Uce = 3,5 V
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BJT, voltage divider
Bollen
Vb is a stable voltage - 0,7 V =
so Ve is a stable voltageIe is determined by Ve/ Re
Ic = Ie . ß/(ß+1)
Ic is very stable and nearly independent to ß
variation, as long as ß is BIG in value
2 methods of calculating Ic - neglegting Ib, use voltage divider - not neglecting Ib and use thevenin
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BJT, voltage divider, neglect Ib
Bollen
2
1 2b cc
RV V
R R
0 7e bV V V
ee
e
VI
R
1c eI I
So neglegt Ib to R2, or in general Ri >> R2In practice 10 times bigger
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BJT, voltage divider, exact, thevenin
Bollen
Thevenin resistance
R1 // R2 62k // 9k1= 7k9
Thevenin voltage 2
1 2th cc
RV V
R R
9 116 2 0
62 9 1th
kV V
k k
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BJT, voltage divider, exact, thevenin
Bollen
2V0
7k9
1th b th be b eV I R V I R
2,0 7 9 0,7 80 1 0,68b bI k I k Ib = 20 uA
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BJT, voltage divider, example
Bollen
Thevenin resistance = 6k8
Thevenin voltage = 3V1
Ib = 18,8 uAIc = 2,25 mAre = 11,5 ΩURc = 7V4Uc = 10V6Ue = 2V3Uce = 5V1
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BJT, voltage divider, example
Bollen
Thevenin resistance = 255k
Thevenin voltage = 0V0
Ib = 14,3 uAIc = 1,9 mAre = 14 ΩURc = 17V3Uc = 0V7Ue = -3V7Uce = 4V4
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BJT
Bollen
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BJT
Bollen