BJT and JFET

Frequency Response

Contents

Logarithm and dB Low frequency analysis-Bode plot Low frequency response-BJT and FET

amplifiers Miller effect capacitance High frequency response-BJT and FET

amplifiers Multistage frequency effects Square wave testing

Low Frequency Response – BJT Amplifier

At low frequencies Coupling capacitors (Cs, CC) and Bypass capacitors (CE) will have capacitive reactance (XC) that affect the circuit impedances.

Coupling Capacitor - CSThe cutoff frequency due

to CS can be calculated:

using

sLs

Ri)C(Rs2

1f

βre||R2||R1Ri

Coupling Capacitor - CC

The cutoff frequency due

to CC can be calculated:

using

)CcRRo(2

1f

LLC

π

oC r||RRo

Bypass Capacitor - CEThe cutoff frequency due to CEcan be calculated:

using

where

EeLE

CR2

1f

π

)rβ

sR(||RR eEe

R2||R1||RssR

Examplea. Determine the lower cutoff freq. for the

network of Fig. 1 using the following parameters:

Cs = 10μF, CE = 20μF, Cc = 1μF

Rs = 1KΩ, R1= 40KΩ, R2 = 10KΩ,

RE = 2kΩ, RL = 2.2KΩ,

β = 100, r0 = ∞Ω, Vcc = 20V

b. Sketch the frequency response using a Bode plot

Bode Plot of Low Frequency Response – BJT Amplifier

The Bode plot indicates that each capacitor may have a different cutoff frequency.

It is the device that has the highest of the low cutoff frequency (fL) that dominates the overall frequency response of the amplifier (fLE).

Roll-off of Gain in the Bode Plot

The Bode plot not only indicates the cutoff frequencies of the various capacitors it also indicates the amount of attenuation (loss in gain) at these frequencies.

The amount of attenuation is sometimes referred to as roll-off.

The roll-off is described as dB loss-per-octave or dB loss-per-decade.

-dB/Decade

-dB/Decade refers to the attenuation for every 10-fold change in frequency.For Low Frequency Response attenuations it refers to the loss in gain from the lower cutoff frequency to a frequency 1/10th the lower cutoff frequency.In the above drawn example:fLS = 9kHz gain is 0dBfLS/10 = .9kHz gain is –20dBTherefore the roll-off is 20dB/decade. The gain decreases by –20dB/Decade.

-dB/Octave

-dB/Octave refers to the attenuation for every 2-fold change in frequency.For Low Frequency Response attenuations it refers to the loss in gain from the lower cutoff frequency to a frequency 1/2 the lower cutoff frequency.In the above drawn example:fLS = 9kHz gain is 0dBfLS/2 = 4.5kHz gain is –6dBTherefore the roll-off is 6dB/octave. This is a little difficult to see on this graph because the horizontal scale is a logarithmic scale.

Low Frequency Response – FET AmplifierAt low frequencies Coupling capacitors (CG, CC) and Bypass capacitors (CS) will have capacitive reactances (XC) that affect the circuit impedances.

Coupling Capacitor - CGThe cutoff frequency due

to CG can be calculated:

using

GLG

Ri)C(Rsig2

1f

π

GRRi

Coupling Capacitor - CC

The cutoff frequency due

to CC can be calculated:

using

CLLC

)CR(Ro2

1f

π

dD r||RRo

Bypass Capacitor - CSThe cutoff frequency due to CS canbe calculated:

where

using

Seq

LSCR2

1f

π

)///()1(1 LDddmS

Seq RRrrgR

RR

Ωr g

1||RR

dmSeq

Example

a. Determine the lower cutoff freq. for the network of Fig. 2 using the following parameters:

CG = 0.01μF, Cc = 0.5μF, Cs = 2μF

Rsig = 10KΩ, RG= 1MΩ, RD = 4.7KΩ,

RS = 1kΩ, RL = 2.2KΩ, IDSS = 8mA,

Vp = -4V, rd = ∞Ω, VDD = 20V

b. Sketch the frequency response using a Bode plot

Bode Plot of Low Frequency Response – FET Amplifier

The Bode plot indicates that each capacitor may have a different cutoff frequency.

The capacitor that has the highest lower cutoff frequency (fL) is closest to the actual cutoff frequency of the amplifier.

Miller Effect Capacitance

Any P-N junction can develop capacitance. This was mentioned in the chapter on diodes.

In a BJT amplifier this capacitance becomes noticeable between: the Base-Collector junction at high frequencies in CE BJT amplifier configurations and the Gate-Drain junction at high frequencies in CS FET amplifier configurations.

It is called the Miller Capacitance. It effects the input and output circuits.

Miller Input Capacitance (CMi)

It can be calculated: [Formula 11.42]

Note that the amount of Miller Capacitance is dependent on interelectrode capacitance from input to output (Cf) and the gain (Av).

fMi Av)C(1C

Miller Output Capacitance (CMo)

It can be calculated: [Formula 11.43]

If the gain (Av) is considerably greater than 1: [Formula 11.44]

fMo )CAv

1(1C

fMo CC

High-Frequency Response – BJT Amplifiers

Capacitances that will affect the high-frequency response:

• Cbe, Cbc, Cce – internal capacitances• Cwi, Cwo – wiring capacitances• CS, CC – coupling capacitors• CE – bypass capacitor

High-Frequency Cutoff – Input Network (fHi)

using and

iThiHi

CR2

1f

π

re||R||R||RsR 21Thi

Av)Cbc(1CbeCCCbeCCi WiMiWi

High-Frequency Cutoff – Output Network (fHo)

using and MoWo CCceCCo

oLCTho r||R||RR

CoR2

1f

ThoHo

π

High-Frequency Response – FET Amplifier

Capacitances that will affect the high-frequency response:• Cgs, Cgd, Cds – junction capacitances• Cwi, Cwo – wiring capacitances• CG, CC – coupling capacitors• CS – bypass capacitor

High-Frequency Cutoff – Input Network (fHi)

using and

iThiHi

CR2

1f

π

GsigThi R||RR

MigsWii CCCC

gdMi Av)C(1C

High-Frequency Cutoff – Output Network (fHo)

using and

oThoHo

CR2

1f

π

dLDTho r||R||RR

ModsWoo CCCC

gdMo )CAv

1(1C

Multistage Frequency Effects

Each stage will have its own frequency response. But the output of one stage will be affected by capacitances in the subsequent stage. This is especially so when determining the high frequency response. For example, the output capacitance (Co) will be affected by the input Miller Capacitance (CMi) of the next stage.

Total Frequency Response of a Multistage Amplifier

Once the cutoff frequencies have been determined for each stage (taking into account the shared capacitances), they can be plotted.

Again note the highest Lower Cutoff Frequency (fL) and the lowest Upper Cutoff Frequency (fH)

are closest to the actual response of the amplifier.

Square Wave Testing

In order to determine the frequency response of an amplifier by experimentation, you must apply a wide range of frequencies to the amplifier.

One way to accomplish this is to apply a square wave. A square wave consists of multiple frequencies (by Fourier Analysis: it consists of odd harmonics).

Square Wave Response Waveforms

If the output of the amplifier is not a perfect square wave then the amplifier is ‘cutting’ off certain frequency components of the square wave.