BBMP 1103Mathematic Management

Exam Preparation Workshop Sept 2011Part 5 - Application of Integration

Presented By: Dr Richard Ng

26 Nov 20112ptg – 4ptg

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Question: 12 (May 2010)

5. Focus on Application of Integration

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Suggested Answers:

i) Given xC 30'

cx

2

302

Hence, dxxC .30

cx 215

When x = 0, c = 15000

Hence, 1500015 2 xC

ii) When x = 100:

15000)100(15 2 C

15000150000

165000

When x = 150:

15000)150(15 2 C

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15000)22500(15

Hence, increase in cost = 352500 - 165000 = RM187,500

352500

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Question: 13 (Jan 2010)

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Suggested Answers:

i) Given2

80000'

xC

Hence, dxx

C .80000

2

dxx .80000 2

cx

1

80000 1

cx

80000

When x = 0, c = 27000

Hence, 2700080000

x

C

ii) When x = 200

27000)200(

80000C

27000400

26600

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When x = 400

27000)400(

80000C

27000200

26800

Hence, increase in cost = 26800 - 26600 = RM200

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End ofPart 5