Bao cao TN_ Dang

8/7/2019 Bao cao TN_ Dang

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Thc tp cng nhnGVHD: L Hng Nam

LI GII THIU

Ngy nay vi s pht trin ca cng nghip vi in t,k thut s th cc h thng

iu khin dn dn c t ng ha. Vi nhng k thut tin tin nh vi x l,vi mch

s th cc h thng iu khin bng c kh th s vi tc x l chm chp t chnh xc

s c thay th bng cc h thng iu khin t ng vi cc chng trnh c thit

lp trc

Trong nhiu lnh vc sn xut cng nghip hin nay,nht l ngnh cng nghip

luyn kim,ch bin thc phm. vn o v khng ch nhit c bit c ch trng

n v n l mt t quyt nh cht lng sn phm. p ng c yu cu o v khng

ch nhit th c nhiu phng php thc hin. Vi nhng g c hc,nghin cu

v kho st v vi iu khin th nhm ng dng n vo vic o v khng ch nhit l

phng php ti u nht. c s hng dn ca thy,nhm thc hin ti Thit k

mch iu khin nhit ng dng trong l nhit

Vi nhng kin thc c hc cng vi s hng dn ca thy gio v s gip

ca bn b,nhm c gng hon thnh ti ng thi hn. Do vy khng trnh khithiu st,nhm em mong nhn c kin t thy c ti ca nhm c pht trin

tt hn.

Nng,ngy ,thng ,nm2010


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THIT K MCH IU KHIN NHIT

NG DNG TRONG L NHIT

1.Nhim v thit k:

Nhim v cn thc hin l thit k mt b iu khin nhit vi di nhit t 30 0C n

1200C. Vy yu cu t ra l:

+Thit k b cm bin nhit .+Thit k b chuyn i tng t sang s ( khi ADC)

+Thit k khi x l trung tm

+Thit k khi bn phm

+Thit k khi cng sut

+Thit k khi hin th

+Thit k khi giao tip

+Vit thut ton.+Vit chng trnh iu khin

2.S khi:

CMU 8051

Khi hin th

L nhit

Khi cm bin

Khi ADC

Khi giao tip

Khi cng sut

Khi bn phm


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3. Chc nng tng khi:

+ Khi cm bin nhit :dng o nhit trong l nhit

+ Khi x l trung tm: dng x l cc tn hiu vo v xut tn hiu ra,iu khin mi

hot ng ca h thng.

+ Khi ADC: c nhim v s ha tn hiu ra ca cm bin nhit a vo VDK.

+ Khi cng sut: c nhim v iu khin,cp ngun cho l nhit,qua lm thay i nhit

trong l nhit.

+ Khi hin th: hin th nhit l nhit.

+ Khi giao tip: trao i vi my tnh v cc thng s ca qu trnh iu khin.

+ Khi bn phm: nhp d liu.

GII THIEU VE VI IEU KHIEN 8951

1. Tong quan ve ky thuat vi ieu khien

1.1. Khai quat chung ve vi ieu khien

Bo vi ieu khien viet tat la Micro-controller, la mach tch

hp tren mot chip co the lap trnh c, dung e ieu khien

hoat ong cua mot he thong. Theo chng trnh ieu khien a

nap san ben trong chip, bo vi ieu khien tien hanh oc, lutr thong tin, x ly thong tin, sau o da vao ket qua cua

qua trnh x ly e a ra cac thong bao, tn hieu ieu khien

tien hanh ieu khien qua trnh hoat ong cua cac thiet b


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ben ngoai. Vi ieu khien c ng dung trong rat nhieu san

pham cong nghiep va tieu dung.

Trong cac thiet b ien va ien t dan dung, cac bo viieu khien ieu khien hoat ong cua TV, may giat, au oc

laser, ien thoai, lo vi-ba ... Trong he thong san xuat t ong,

bo vi ieu khien c s dung trong Robot, day chuyen t

ong. Cac he thong cang thong minh th vai tro cua he vi

ieu khien cang quan trong.

1.2. Lch s phat trien cua vi ieu khien

Bo vi ieu khien thc ra la mot loai vi x l trong tap hp

cac bo vi x ly noi chung. Bo vi ieu khien c phat trien

t bo vi x l, t nhng nam 1970 do s phat trien va hoan

thien ve cong nghe vi ien t da tren ky thuat MOS (Metal-

Oxide-Semiconductor), mc o tch hp cua cac linh kien ban

dan trong mot chip ngay cang cao.

Nam 1971 xuat hien bo vi x l 4 bit loai TMS1000 do cong

ty texas Instruments va la ni phat minh va la nha san xuat.

Nhn tong the th bo vi x ly ch co cha tren mot chip

nhng chc nang can thiet e x ly chng trnh theo mot

trnh t, con tat ca bo phan phu tr khac can thiet nh: bo

nh d lieu, bo nh chng trnh, bo chuyen oi AD, khoi

ieu khien, khoi hien th, ieu khien may in, noi ong ho

va lch la nhng linh kien nam ben ngoai c noi vaobo vi x ly.

Mai en nam 1976 cong ty INTEL (Intelligen-Elictronics) mi

cho ra i bo vi ieu khien n chip au tien tren the gii

vi ten goi 8048. Ben canh bo x ly trung tam, 8048 con


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cha bo nh d lieu, bo nh chng trnh, bo em va phat

thi gian, cac cong vao ra digital tren mot chip. Cac cong ty

khac cung lan lc cho ra i cac bo vi ieu khien 8 bit tngt nh 8048 va hnh thanh ho vi ieu khien MCS-48.

en nam 1980 cong ty INTEL cho ra i the he th hai

cua bo vi ieu khien n chip vi ten goi 8951. Va sau o

hang loat cac vi ieu khien cung loai vi 8951 ra i va

hnh thanh ho vi ieu khien MCS-51 .

en nay ho vi ieu khien 8 bit MCS51 a co en 250thanh vien va hau het cac cong ty hang dan au the

gii che tao. ng au la cong ty INTEL va rat nhieu

cong ty khac nh : AMD, SIEMENS, PHILIPS, DALLAS, OKI

1.3. S o khoi cua mot bo vi ieu khien

S o khoi chung cua hau het cac bo vi ieu khien bao gom

CPU, bo nh ROM hay EPROM va RAM, mach giao tiep, mach giao

tiep song song, bo nh thi gian, he thong ngat va cac BUS

c tch hp tren cung mot chip.

2. Kien truc cua vi ieu khien 8951

IC vi ieu khien 8951 thuoc ho MCS51 co cac ac iem sau

:

+ 4 kbyte ROM

+ 128 byte RAM

+ 4 port I/0 8 bit

+ Hai bo nh thi 16 bits

+ Giao tiep noi tiep

+ 64KB khong gian bo nh chng trnh ngoai


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+ 64 KB khong gian bo nh d lieu ngoai

+ 210 bit c a ch hoa

+Bo nhan / chia 4 s

2.1. Cau truc ben trong cua 8951

INT\1

INT\0

TIMER2

TIMER1PORT noitiep

TXD* RXD*

T1*

T2*

P0

P1

P2

P3EA\ RST PSEN ALE

Cacthanh

ghikhac

128byteRam

Rom

4K-8951

OK-8031

Timer1

Timer2

ieukhienngat

ieukhienbus

CPU

Portnoitiep

Cc port I/O

Todaong


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S o Khoi 8951

Phan chnh cua vi ieu khien 8951 la bo x l trung

tam (CPU: central processing unit) bao gom :

+ Thanh ghi tch luy A

+ Thanh ghi tch luy phu B, dung cho phep nhan va phep

chia

+ n v logic hoc (ALU : Arithmetic Logical Unit )

+ T trang thai chng trnh (PSW : Prorgam Status Word)+ Bon bang thanh ghi

+ Con tro ngan xep

+ Ngoai ra con co bo nh chng trnh, bo giai ma lenh,

bo ieu khien thi gian va logic.

n v x l trung tam nhan trc tiep xung t bo dao ong,

ngoai ra con co kha nang a mot tn hieu gi nhp t ben

ngoai.Chng trnh ang chay co the cho dng lai nh mot

khoi ieu khien ngat ben trong. Cac nguon ngat co

the la: cac bien co ben ngoai, s tran bo em nh

thi hoac cung co the la giao dien noi tiep.


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Hai bo nh thi 16 bit hoat ong nh mot bo em.

Cac cong (port0,1,2,3), s dung vao muc ch ieu khien.

cong 3 co them cac ng dan ieu khien dung e traooi vi mot bo nh ben ngoai, hoac e au noi giao dien

noi tiep, cung nh cac ng ngat dan ben ngoai. Giao dien

noi tiep co cha mot bo truyen va mot bo nhan khong

ong bo, lam viec oc lap vi nhau.Toc o truyen qua cong

noi tiep co the at trong dai rong va c an nh bang

mot bo nh thi.

Trong vi ieu khien 8951 co hai thanh phan quan trong

khac o la bo nh va cac thanh ghi :

+ Bo nh gom co bo nh RAM va bo nh ROM dung

e lu tr d lieu va ma lenh.

+ Cac thanh ghi s dung e lu tr thong tin trong qua

trnh x l. Khi CPU lam viec no lam thay oi noi dung cua cac

thanh ghi.

2.2.Chc nang cac chan cua vi ieu khien 8951

C 1 3 0 p

C 2 3 0 p

U 2

8 0 5 1

3 1

1 9

1 8

9

1 21 31 41 5

1234567

8

3 93 83 73 63 53 43 3

3 2

2 12 22 32 42 52 62 72 8

1 71 62 93 01 1

1 0

E A / V P

X 1

X 2

R E S E T

I N T 0I N T 1T 0T 1

P 1 . 0P 1 . 1P 1 . 2P 1 . 3P 1 . 4P 1 . 5P 1 . 6

P 1 . 7

P 0 . 0P 0 . 1P 0 . 2P 0 . 3P 0 . 4P 0 . 5P 0 . 6P 0 . 7

P 2 . 0P 2 . 1P 2 . 2P 2 . 3P 2 . 4P 2 . 5P 2 . 6P 2 . 7

R DW R

P S E NA L E / P

T X D

R X D

R S T

1 2 M H z


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Hnh 2.3 :S o chan 8951

Vi ieu khien 8951 co 32 trong 40 chan co chc nang

nh la cac cong I/O, trong o 24 chan c s dung vi

hai muc ch. Ngha la ngoai chc nang cong I/O, moi

chan co cong dung kep nay co the la mot ng ieu

khien cua Bus a ch hay Bus d lieu hoac la moi chan

hoat ong mot cach oc lap e giao tiep vi cac thiet

n bit nh la cong tac, LED, transistor

a.Port0: la port co 2 chc nang, tren chan t 32

en 39 cua MC 8951. Trong cac thiet ke c nho khong

dung bo nh ngoai, P0 c s dung nh la nhng cong

I/O. Con trong cac thiet ke ln co yeu cau mot so

lng ang ke bo nh ngoai th P0 tr thanh cac ng

truyen d lieu va 8 bit thap cua bus a ch.b. Port1: la mot port I/O chuyen dung, tren cac chan 1-

8 cua MC8951. Chung c s dung vi mot muc ch duy

nhat la giao tiep vi cac thiet b ngoai khi can thiet.


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c. Port2: la mot cong co cong dung kep tren cac

chan 21 28 cua MC 8951. Ngoai chc nang I/O, cac chan

nay dung lam 8 bit cao cua bus a ch cho nhng mo

hnh thiet ke co bo nh chng trnh ROM ngoai hoac bo

nh d lieu RAM co dung lng ln hn 256 byte.

d. Port3: la mot cong co cong dung kep tren cac chan 10

17 cua MC 8951. Ngoai chc nang la cong I/O, nhng chan

nay kiem luon nhieu chc nang khac na lien quan en

nhieu tnh nang ac biet cua MC 8951, c mo ta trong bangsau:

Bit Ten Chc nang chuyen oiP3.

0

P3.

1P3.

2

P3.

3

P3.

4P3.

5

P3.

6

RxD

TxD

0INT

1INT

T0

T1

WR

RD

Ngo vao d lieu noi tiep.

Ngo xuat d lieu noi

tiep.

Ngat ngoai 0.Ngat ngoai 1.

Ngo vao TIMER 0.

Ngo vao cua TIMER 1.

ieu khien ghi d lieu len

bo nh ngoai.

ieu khien oc bo nh dlieu ngoai.


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P3.

7

Chc nang cua cac chan tren port3e. PSEN (Program Store Enable): 8951 co 4 tn hieu ieu khien,

PSEN la tn hieu ra tren chan 29. No la tn hieu ieu

khien e cho phep truy xuat bo nh

chng trnh m rong va thng c noi en chan OE

(Output Enable) cua mot EPROM e cho phep oc cac byte

ma lenh cua chng trnh. Tn hieu PSEN mc thap trongsuot pham vi qua trnh cua mot lenh. Cac ma nh phan

cua chng trnh c oc t EPROM qua bus va c chot

vao thanh ghi lenh cua 8951 e giai ma lenh. Khi thi hanh

chng trnh trong ROM noi PSEN se mc cao.

f. ALE (Address Latch Enable ): Tn hieu ra ALE tren chan 30

tng hp vi cac thiet b lam viec vi cac x ly 8585,

8088. 8951 dung ALE e giai a hp bus a ch va d

lieu, khi port 0 c dung lam bus a ch/d lieu a hp:

va la bus d lieu va la byte thap cua a ch 16 bit .

ALE la tn hieu e chot a ch vao mot thanh ghi ben

ngoai trong na au cua chu ky bo nh. Sau o, cac

ng Port 0 dung e xuat hoac nhap d lieu trong na

sau chu ky cua chu ky bo nh.

Cac xung tn hieu ALE co toc o bang 1/6 lan tan so

dao ong tren chip va co the c dung la nguon xung

nhp cho cac he thong. Neu xung tren 8951 la 12MHz th


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ALE co tan so 2MHz. Chan nay cung c lam ngo vao

cho xung lap trnh cho EPROM trong 8951.

g. EA (External Access): Tn hieu vao EA tren chan 31

thng c noi len mc cao (+5V) hoac mc thap (GND).

Neu mc cao, 8951 thi hanh chng trnh t ROM noi

trong khoang a ch thap (4K). Neu mc thap, chng

trnh ch c thi hanh t bo nh m rong. Ngi ta

con dung chan EA lam chan cap ien ap 21V khi lap

trnh cho EPROM trong 8951.h. RST (Reset): Ngo vao RST tren chan 9 la ngo reset

cua 8951. Khi tn hieu nay c a len mc cao (trong t

nhat 2 chu ky may), cac thanh ghi trong 8951 c a vao

nhng gia tr thch hp e khi ong he thong.

i.OSC: 8951 co mot bo dao ong tren chip, no thng

c noi vi thach anh gia hai chan 18 va 19. Tan sothach anh thong thng la 12MHz.

j. POWER: 8951 van hanh vi nguon n +5V. Vcc c

noi vao chan 40 va Vss (GND) c noi vao chan 20.

THIT K MCH CM BIN V ADC

1. GII THIU :

1.1.CHUYN I A/D :


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1.1.1. NGUYN TC CHUYN I:Mch chuyn i tn hiu tng t sang s,chuyn mt tn hiu ng vo tng t

(dng in hay in p) thnh dng m s nh phn c gi tr tng ng.

Chuyn i ADC c rt nhiu phng php.Tuy nhin,mi phng php iu c nhngthng s c bn khc nhau:

+ chnh xc ca chuyn i AD.+ Tc chuyn i .+ Di bin i ca tn hiu tng t ng vo

Hnh S khi tng qut ca mch ADC Hot ng

-u tin kch xung start b ADC hot ng

--Ti mt tn s c xc nh bng xung clock b iu khin lm thay i thnh snh phn c lu tr trong thanh ghi(Register).-S nh phn trong thanh ghi c chuynthnh dng in p Va bng b chuyn i DA.

-B so snh,so snh Va vi in p ng vo Va .Nu Va < Va th ng ra ca b sosnh vn gi mc cao. Khi Va > Va ng ra ca b so snh xung mc thp v qu trnhthay i s ca thanh ghi ngng. Lc ny V a gn bng Va , nhng s trong thanh ghi lnhng s cn chuyn i .1.1.2.ADC0804 :-CS (Chip select)Chn s 1, l chn chn Chip, u vo tch cc mc thp c s dng kch hot ChipADC0804. truy cp ADC0804 th chn ny phi mc thp.- RD (Read)Chn s 2, l mt tn hiu vo, tch cc mc thp. Cc b chuyn i u vo tng t thnh snh phn v gi n mt thanh ghi trong. RD c s dng c d liu c chyn i tiu ra ca ADC0804.

+StartcommandV

A

VA

Control Unit

Register

D/Aconverter

Comparator

clock

Digital output


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Khi CS = 0 nu c mt xung cao xung thp p n chn RD th d liu ra dng s 8 bit c ati cc chn d liu (DB0 DB7).- WR (Write)Chn s 3, y l chn vo tch cc mc thp c dng bo cho ADC bit bt u qu trnhchuyn i. Nu CS = 0 khi WR to ra xung cao xung thp th b ADC0804 bt u qu trnhchuyn i gi tr u vo tng t Vin v s nh phn 8 bit. Khi vic chuyn i hon tt th chnINTR c ADC h xung thp.

- Ngt INTR (Interupt)Chn s 5, l chn ra tch cc mc thp. Bnh thng chn ny trng thi cao v khi vic chuyni hon tt th n xung thp bo cho CPU bit l d liu chuyn i sn sng ly i. Saukhi INTR xung thp, cn t CS = 0 v gi mt xung cao xung thp ti chn RD a d liura.

Vin (+) v Vin (-)


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Chn s 6 v chn s 7, y l 2 u vo tng t vi sai, trong Vin = Vin(+) Vin (-). Thngthng Vin (-) c ni ti t v Vin (+) c dng lm u vo tng t v s c chuyn iv dng s.

- VccChn s 20, l chn ngun nui +5V. Chn ny cn c dng lm in p tham chiu khi u voVref/2 h.

- Vref/2Chn s 9, l chn in p u vo c dng lm in p tham chiu. Nu chn ny h th inp u vo tng t cho ADC0804 nm trong di 0 - +5V. Tuy nhin, c nhiu ng dng m uvo tng t p n Vin khc vi di 0 - +5V. Chn Vref/2 c dng thc hin cc in pu ra khc 0 - +5V.Bng quan h in p Vref/2 vi Vin

D0 - D7D0 - D7, chn s 18 11, l cc chn ra d liu s (D7 l bit cao nht MSB v D0 l bit thp nhtLSB). Cc chn ny c m ba trng thi v d liu c chuyn i ch c truy cp khichn CS = 0 v chn RD a xung mc thp. tnh in p u ra ta tnh theo cng thc sau


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- Mch to xung clock cho ADC 0804 :

Tuy nhin ADC0804 cng c mt b to xung ng h ring. dng ng h ring th cc chnCLK IN (chn s 4) v CLK R (chn s 19) c ni vi mt t in v mt in tr (nh hnhv). Khi y tn s c xc nh bng biu thc:

Vi R=10 k , C=150pF v tn s f=606 kHz v thi gian chuyn i l 110 ms.


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Hnh Biu thi gian ca ADC 0804

1.2.O NHIT BNG IC:

1.2.1.Gii thiu:

K thut vi in t cho php ch to c nhng mch kt ni gm nhng transistorging nhau c s dng lm cm bin hon ho o nhit da vo vic o s khc

bit in p VBE di tc ng ca nhit .Cc cm bin ny to ra cc dng in hcin p t l vi nhit tuyt i,vi tuyn tnh cao; n c iu li l vn hnh ngin, tuy nhin phm vi hot ng gii hn ch trong khong 550C n 1500C.

1.2.2.Nguyn l chung ca IC o nhit :L mch tch hp nhn tn hiu nhit chuyn thnh tn hiu di dng in p

hoc tn hiu dng in. Da vo c tnh rt nhy ca cc bn dn vi nhit , to ra inp hoc dng in t l thun vi nhit tuyt i. o tn hiu in, ta bit c gi trca nhit cn o.


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S tch cc ca nhit to ra in tch t do v cc l trng trong cht bn dnbng s ph v cc phn t, bt cc electron thnh dng t do di chuyn qua cc vng cutrc mng tinh th, to s xut hin cc l trng nhit lm cho t l in t t do v cc ltrng tng ln theo quy lut hm m vi nhit . Kt qu ca hin tng ny l di mcin p thun, dng thun ca mi ni p-n (trong diode hay transistor) s tng theo hm mtheo nhit .

2.MCH CM BIN NHIT :

P 1 .P 1 .P 1 .P 1 .P 1 .P 1 .P 1 .P 1 .P 3 .P 3 .P 3 .

U 4

L M 3 5

V S +1

V O U T2

G

N

D

3

U 5

A D C 0 8 0 4

+ I N6

- I N7

A

G

N

D

8

V R E F / 29

G

N

D

1

0

D B 71 1D B 61 2D B 51 3D B 41 4D B 31 5D B 21 6D B 11 7D B 01 8

C L K R1 9

V

C

C

/V

R

E

F

2

0

C L K I N4

I N T R5

C

S

1

R D2

W R3

V C C

U 6L M 3 3 6

-

+

U 7 A

L M 3 5 8

3

21

8

4

V C CR 9

1 0 k

C 4

1 u F

R 78 k 2

V C C

C 5

1 5 0 p

C 6

1 u F

R 8

1 0 k

V C C

R 1 02 k 2

o nhit c chnh xc, tt nhin cn c mt u d thch hp. u d l mtcm bin nhit c nhim v vn chuyn t nhit qua tn hiu in. C rt nhiu loicm bin nh gii thiu chng I.Da vo l thuyt v thc t ca mch cn thit k tadng phng php o bng IC cm bin nhit . Cc IC cm bin nhit c chnh

xc cao, d tm v gi thnh r. Mt trong s l IC LM35, l loi thng dng trn thtrng hin nay, ng thi n c nhng c tnh lm vic ph hp vi thit k chi tit camch.

-Mt s tnh cht c bn ca LM35:

- LM35 c bin thin theo nhit : 10mV / 1oC.


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- chnh xc cao, tnh nng cm bin nhit rt nhy, nhit 25oC n c sai skhng qu 1%. Vi tm o t -55oC 150oC, tn hiu ng ra tuyn tnh lin tc vi nhngthay i ca tn hiu ng vo.

- Thng s k thut:Tiu tn cng sut thp.

Dng lm vic t 450 A 5mA.

Dng ngc 15mA.

Dng thun 10mA.

- c tnh in:Theo thng s ca nh sn xut LM35, quan h gia nhit v in p ng ra nh

sau:

Vout = 0,01 ToC

Vy ng vi tm hot ng t 0oC 150oC ta c s bin thin in p ng ra l:

0oC th in p ng ra Vout = 0 (V).

150oC th in p ng ra Vout = 1,5(V).


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KHI HIN TH V BN PHM

1Kh i hin th:

1 .1.S nguyn l:

U 2

7 4 4 7

D 07

D 11

D 22

D 36

B I / R B O4

R B I5

L T3

A1 3

B1 2

C1 1

D1 0

E9

F1 5

G1 4

V

C

C

1

6

G

N

D

8

v c c

R 1 71 K 2

R 1 8

1 K 2

R 1 9

1 K 2

D 8

L E D

D 9

L E D

D 1 0

L E D

J 2

H E A D E R 8

1

2

3

4

5

6

7

8

5 V5 V 5 V

R 33 3 0

R 53 3 0

R 63 3 0

R 73 3 0

R 83 3 0

R 93 3 0

R 1 03 3 0

A

B

D

C

G

F

E

0

O 6

O 5

O 4

0

0

8

U 7

L E D 7 . 1

B6

E1

D2

T

3

C4

D P5

A7

L

8

F9

G1 0

8

U 8

L E D 7 . 2

B6

E1

D2

T

3

C4

D P5

A7

L

8

F9

G1 0

8

U 9

L E D

B6

E1

D2

T

3

C4

D P5

A7

L

8

F9

G1 0

A

C

B

F

E

D

B

A

G

D

C

G

F

E

C

B

A

E

D

G

F

R 2 0

3 3 0

R 1 11 K 2 R 1 21 K 2 R 1 31 K 2

O 5 O 6O 4

D 1 1

L E D

J 4

H E A D E R 2

1

2

J 5

H E A D E R 2

1

2

0

5 V

V c c

V C C

0

Q 7A 1 0 1 5

Q 8A 1 0 1 5

Q 9A 1

0Q 1 0A 1 0 1 5

Q 1 1

A 1 0 1 5

Q 1 2

A 1 0 1 5

R 1 4

3 3 0

R 1 5

3 3 0

R 1 6

3 3 0

V c cV c cV c c


21/55


Nguyn l hot ng :

Trong h thng vi x l, b hin th ng vai tr rt quan trng: dng giao tip vi my

tnh v ngi s dng, cho php ngi s dng quan st, cm nhn qu trnh lm vic ca

h thng. y b hin th ch c chc nng l hin th nhit ngoi ra khng c chc

nng khc. .. n gin c phn cng th ch cho php nhit hin th t 00C 999C

t port 1 ca vi iu khin. B hin th hng Led 7 on l loi c s dng ph bin.

Hnh 7.4.d . a: B hin th Led 7 on, b: Loi anode chung, c: Loi Cathod chung.

BCD inputs Segment outputsDisplay

A B C D a b c d e f g0 0 0 0 0 0 0 0 0 0 1 00 0 0 1 1 0 0 1 1 1 1 10 0 1 0 0 0 1 0 0 1 0 20 0 1 1 0 0 0 0 1 1 0 30 1 0 0 1 0 0 1 1 1 1 40 1 0 1 0 0 1 0 0 1 0 5

ff

g g

ccVcc

e e

d d

aa

b b


22/55


Khi hin th gm 3 led 7 on v 2 led n.Khi led n vng sng th ta nhp gi tr nhit

cn khng ch vo.Gi tr nhit ny s hin th trn led 7 on.Khi led xanh sng th

led 7 on s hin th nhit hin ti ca l.Nhit ny s ly t cm bin nhit .

*Kim tra khi hin th:

-Kim tra in p cung cp cho IC cm bin LM35,IC 89C52 v IC chuyn i m c ng

v c khng,o in p ra trn mi IC xem c t yu cu khng.

-Kim tra cc in tr ni t b chuyn i n cc led 7 on c ng khng,kim tra cc

in tr ko t ngun xung c ng khng.

-Kim tra cc led 7 on c ng loi khng( y dng loi anod chung)

*Nu led 7 on khng sng th phi kim tra:

-Kim tra led c ng loi khng(anod chung)

-Kch cho ng cung cp ngun(kim tra con bjt c dn khng)

-Kim tra con gii m c hot ng khng.

*Nu hin th khng ng th phi kim tra:

0 1 1 0 1 1 0 0 0 0 0 60 1 1 1 0 0 0 1 1 1 1 71 0 0 0 0 0 0 0 0 0 0 81 0 0 1 0 0 0 1 1 0 0 9


23/55


-Cho qut chm,qut ht ct ny n ct kia(cho delay ln)

-Kim tra in p kch cho ct,hng c ng khng(xut gi tr ra ri phi tt led)

Cc linh kin s dng trong mch:

a.IC74LS47: dng chuyn tn hiu dng s nh phn ng vo sang m 7 on. IC ny

hot ng tch cc mc thp. Do ta c bng chn thc sau:

IC hot ng ta kt ni chn 16 (Vcc) vi ngun 5 V, chn s 8 vi t. Ng vo c 4

chn l 7,1,2,6 tng ng vi A,B,C,D trong mc ngha gim dn t A n D. Kt ni

cc ng ra A,B,C,D ca iC vi cc cng tc m mi cng tc n gin l nm gia 2 mc

cao hoc thp. Cc chn LT, BI/RBO, RBI khng cn kt ni. Nu ta dng Led 7 on kiu

cathod chung th mi ng ra ca IC 7447 cn kt ni vi cc cng o trc khi n cc

chn ca Led.

1.2.Tnh gi tr n tr hn dng Rhd ni vi 74LS47 :

Ngun cung cp Vcc = 5V. Cc thng s ng ra ca IC7447 l :

Vol = 0.4V

Iol = 40mA .

- Gi s , ta mun cc led sng vi mt dng nh mc Iledm =10mA vy:

Ihd =T

T0 .Iledm

Vi T0 l thi gian 1 led sngT l thi gian led khng sng

Chn thi gian sng cho 1 led l 100s

Thi gian khng c dng chy qua led l 600 s


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- Mi on ca led cn dng khong 10mA sng , n gin ta xem led 7 on

gm 7 led n.

Vy dng qua led l ihd = 10.7 = 70 (mA)

Ihd =600

100 .70 = 28,5(mA)

Chn BJT 2SA1015 c = 70

Dng IBmin = 28,5/70 =0,41(mA)

Chn IB=(23)IBmin =2.0.41 =0.82(mA)

Rhd= (Vcc V LED Vol)/ILED => Rhd = (5V-1.8V 0.4V )/0.82mA

=> Rhd = 3,4K

Rhd =3,9K.

Lc ILED = (5V - 1,8V - 0,4V)/3,9k = 0,7(mA)

1.3 .Tnh gi tr in tr Rb ni vi BJT:

- Xt iu kin transistor bo ho l :Ic Ib

Vi led 7 on, 1 led sng cn dng 10mA, sng ht 7 led cn dng Ic = 7.10 = 70

(mA)Chn BJT A1015 c min = 70 .Ti ng ra ca IC8051 c cc thng s sau :

Iol = 3.2mA

Vol =0.4 V

Vy dng Ib nm trong gii hn sau :

c

IIbIol hay

c

I

b

b

R

UIol

T ta suy ra R:

Rbol

b

I

U=

ol

olcc

I

VVV =

0032,0

4,08,05 VVV =

0032,0

8,31187,5

Chn RB =1.2K

Lc vi led 7 on ta c:


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Ib =b

b

R

U=1200

8,3= 3,16 (mA)

70

70=1(mA)

Vi led n ta c:

Ib = 3,16 (mA) 70

10=0,14(mA)

2.Bn phm

Nguyn l:

thc hin ma trn bn phm ta dng phng php qut phm. Qut ct v c dliu ti hng hoc ngc li. Theo hnh v th cc ct cch nhau 1 n v, cc hng cchnhau 4 n vi.

Vy gi tr ca bn phm c tnh theo cng thc sau

Bp= C+h.4

Trong : Bp: Gi tr ca phm c nhn.

C: Ct c qut.H: Hng c phm nhn.

Khi mch cn nhiu phm th ta mi t chc ma trn phm gim s lng cng s

dng cho bn phm.

Ban u cc nt bm c set mc cao,khi nhn nt th chuyn sang mc thp(mc 0)

1 4

2 3

1 4

2 3

1 4

2 3C 3

1 4

2 3

71 4

2 3

P 1 .3

1

H 2

2

C

3

F1 4

2 3

H 0

P 1 .1

1 4

2 3

5

P 1 .0

1 4

2 3

1 4

2 3

P 1 .5

E

P 1 .4

1 4

2 3

D

1 4

2 3

64

1 4

2 3

98

0

1 4

2 3

C 0

H 1

1 4

2 3

P 1 .6

J 1

C O N 8

12345678

C 1

P 1 .7

1 4

2 3

H 3

A

C 2

1 4

2 3

P 1 .2

B


26/55


*Kim tra bn phm :

-Trc ht phi kim tra gn cc chan ca nt bm ng cha:c 1 cp chn ca nt

bm mc cao,khi bm th xung mc thp,dng ng h kim tra khi nhn nt c thngmch khng.

-Kim tra v tr cc nt bm chnh xc cha(tng ng vi hng v ct nh hnh v trn)

*Nu nhn phm v hin th khng m khng hin th s bm th phi kim tranh sau:

-Kim tra phn cng xem c ng vi chng trnh vit khng.

-Kim tra xem cc nt c b dnh vi nhau khng.

KHI GIAO TIP

1.C u tr c c n g ni tip:

Cngnitipcsdngtruyndliuhaichiugiamytnhvngoivi,cccuimsau:

- Khongcchtruynxahntruynsongsong.- Sdyktnit.

- Cthtruynkhngdydnghngngoi.

- CthghpniviviiukhinhayPLC(ProgrammableLogicDevice).

- Chophpnimng.

- Cththolpthitbtronglcmytnhanglmvic.

- Cthcungcpngunchoccmchinngin

Cc thit b ghp ni chia thnh 2 loi: DTE (Data Terminal Equipment) v

DCE (DataCommunicationEquipment).DCE lcc thitb trunggiannhMODEMcnDTEl ccthitbtipnhnhaytruyndliunhmytnh,PLC,viiukhin,Victraoitnhiuthngthngqua2chnRxD(nhn)vTxD(truyn).Cctnhiucnlicchc nng h tr thit lp v iu khin qu trnh truyn, c gi l cc tnhiu bt tay (handshake). u im ca qu trnh truyn dng tn hiubt tay l c thkimsotng truyn.

Tn hiu truyn theo chun RS-232 ca EIA (Electronics IndustryAssociations). Chun RS-232 quy nh mc logic 1 ng vi in p t -3V n -25V


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(mark),mc logic0 ngviinpt3Vn25V(space)vckhnngcungcpdngt10mAn20mA. Ngoira,ttcccngraucctnhchngchpmch.

Chun RS-232 chophp truyn tn hiu vi tc n 20.000bps nhng nu cp

truynngncthlnn115.200bps.CcphngthcnigiaDTEvDCE:

-ncng(simplexconnection):dliuchctruyntheo1hng.

- Bn song cng ( half-duplex): d liu truyn theo 2 hng, nhng mi thi imchctruyntheo1hng.

-Songcng(full-duplex):sliuctruynngthitheo2hng.

nhdngcakhungtruyndliutheochunRS-232nhsau:

Start D0 D1 D2 D3 D4 D5 D6 D7 P Stop0 1

Khikhngtruyndliu,ngtruynstrngthimark(inp-10V).Khibtutruyn, DTE s a ra xung Start (space: 10V) v sau ln lt truyn t D0 n D7 vParity,cuicnglxungStop(mark:-10V)khiphctrngthingtruyn.

CcctnhkthutcachunRS-232nhsau:

Chiudicablecci 15mTcdliucci 20Kbpsinpngracci 25V

inpngracti 5Vn 15VTrkhngti 3K n7Kinpngvo 15Vnhyngvo 3VTrkhngngvo 3K n7K

Cc tc truyn d liu thng dng trong cng ni tip l: 1200bps, 4800bps,9600bpsv19200bps

Schncngnitip


28/55


M t S chn1 Da ta carrier detect

(DCD)Trnh tn hiu mng d liu

2 Received data (RxD) D liu c nhn3 Transmitted data (TxD) D liu c gi4 Data terminal ready

(DTR)u d liu sn sng

5 Signal ground (GND) t ca tn hiu6 Request to send (RTS) D li u sn sng7 Request to send (RTS) Yu cu d liu8 Clear to send (CTS) Xo gi9 Ring indicator (RL) Bo chung

2.Giao tip vi vi iu khin

Khithchingiaotipviviiukhin,taphidngthmmchchuynmclogict TTL 232 v ngc li. Cc vi mch thng s dng l MAX232 ca Maxim hayDS275caDallas.Mchchuynmclogicmtnhsau:

P 1

D B 9

594837261

U 1

M A X 2 3 2

C 1 +1

C 1 -3

C 2 +4

C 2 -5

V

C

C

1

6

G

N

D

1

5

V +2

V -6

R 1 O U T1 2

R 2 O U T9

T 1 I N1 1

T 2 I N1 0

R 1 I N1 3

R 2 I N8

T 1 O U T1 4

T 2 O U T7

C 1

1 0 u

J 1

C O

1234

V C C

C 2

1 0 u

V C CC 3

1 0 uC 4

1 0 uC 5

1 0 u

MchchuynmclogicTTLRS232.

Tuynhin,khisdngmchchuynmc logicdngccvimch thihiphidngchungGNDgiamytnhvvimchckhnnglmhngcngnitipkhixyrahin tngchpmchmchngoi.Do, tac thdng thmopto4N35cch lyv

in.

*Kim tra Max232:

-o ngun,o cc t xem c t yu cu khng


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-Kim tra cc chn ca t,ca Max232 ng cha,cc iu kin c khng

-u chn (2) v chn (3) gi d liu xung => nhn c l c.

-Chp ng ra ca Max232,ni vi chn ra ca IC89C52 xem c giao tip c khng(xem c thupht d liu c khng)

-u tin cng COM trc.

KHI CNG SUT V NG B

1.S nguyn l:


30/55


R 1 8

1 0 0 k

V C C

R 2 05 k 6

-

+

U 9 A

L M 3 9 3

3

21

8

4

R 1 7

1 0 0 kJ 5

X O A Y C H I E U

12

R 2 6

1 2 k

V C C

R 2 48 k 2

U 8M O C 3 0 2 1

1

2

6

4

C 7

1 u F

Q 1T R I A C

Q 2

A 1 0 1 5

R 1 13 3 0

R 1 2

3 , 3 k

R 1 3

1 8 0

R 2 5

2 k 4

C 8

1 u F

J 4

T A I + N G

12

D 2

D I O D E

P 3 . 4

R 1 4

2 . 2 M

V C C

R 1 94 7 k

P 3 . 2

Q 6C 1 8 1 5

2.Nguyn l hot ng:-Mch ng b to ra xung iu khin tn hiu kch v p xoay chiu t ln triac,tora s ng b v tn hiu kch v p xoay chiu t vo triac

+Triac kch ch I+,III+

+Tn hiu xoay chiu qua b opamp so snh va BJT C1815 lt tin hiu.Tn hiu ra aqua VK nhn c v kt hp vi tn hiu t cm bin s iu khin tn hiu chn P3.4 iu khin BJT A1015 v to ra dng kch cho triac.

Nu mc ra t cm bin l Tmin th P3.4=0,BJT A1015 dn bo ho v to ra dngkch vo cng G ca triac,lm triac hot ng ,t nung nhit nng ln. Tn hiu kch tnti t nht phi 2us th triac mi bt u dn. Gc kch c iu chnh qua VK bngcch delay mt khong thi gian so vi tn hiu nhn v chn P3.2 theo sn ln haysn xung,v tn hiu ny phi nhn c sau khi c tn hiu t ADC l Tmin


31/55


Nu mc ra t cm bin l Tmax th P3.4=1,BJT A1015 ngt v lm triac ngng hot ng,t nhit gim dn

- iu khin ti AC: Ta dng phng php iu khin gc pha l phng php thayi gc kch ca Triac lm bin i in p t ln ti, khi gc kch = 0 th coi nhton b in p li t ln ti nu nh ta b qua st p trn Triac. u im ca phng

php ny l iu khin lin tc v chnh xc hn.

*Kim tra khi iu khin cng sut:

-Trc tin kim tra con triac gn ng cha(dng ng h xc nh chnh xc cc chnca triac)

-Kim tra cc thnh phn iu khin

-Kim tra ngun cung cp c khng


32/55


-Kim tra kch c hot ng c khng

*Nu ng mch m ng c khng chy th kim tra:

-Kim tra cc thnh phn iu khin (kim tra con triac,kch c hot ng c khng)

*Nhit khng n nh c th kim tra g?

Nu nhit hin th khng n nh c th kim tra:

-iu khin theo phng php gc pha:

+o xung kch mt nhit no ,y ra 1 xung kch xem nhit thay i nh thno?

* Phng php thc hin mch i n

Sau khi v hon chnh s mch in trn giy, chng ta bc sang giai on

thc hin mch in. Trnh t thc hin tin hnh theo cc bc sau:

Bc 1: Dng giy nhm nhuyn nh sch lp oxit ha ang bm trn tm mch in (phac trng lp ng), trc khi v cc ng mch.

Bc 2: To ng mch in trn mt ng c cc phng php sau:

- In mch in v ra giy in la hoc p nhit to mch in trn mt ng.

- Dng vit lng c dung mi acetone v ni cc ng mch trn mt ng (datheo cc im pointou va nh v v s mch v trc trn giy).

Trong khi v ta ch , c hai phng php v im pad hn trn mch in. im pad hnc th v theo hnh trn hoc hnh vung. Thng thng im pad trn d thc hin nhngli km tnh m thut hn im pad vung.Mun thc hin im pad vung, ta c th dngvit t rng (quanh v tr cnto im pad vung), sau dng u mi dao nhn v thc

k ta bt mc duy tr mt vng mc bm hnh vung cho im pad cn thc hin. Cngvic ny i hi nhiu thi gian v s t m khi thc hin.

- Sau khi to cc ng mch trn mt ng ca mch in, ta quan st xem c vtr no b v khng lin nt, m ca cc ng phi u nhau, ng thi khng b stng mch no c. Trong trng hp cn thit, sinh vin phi ch cho mc kh hn ri li mt ln na.


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Bc 3: Sau khi v hon chnh, sinh vin ch kh mi mang mch in nhng vo thuc ty.Ha cht ty s n mn lp ng ti cc v tr khng bm mc v s nguyn lp ng ticc v tr c bao ph bng cc ng v mc. Khi nhng mch in trong thuc ty, mun

phn ng ha hc xy ra nhanh, cn thc hin cc thao tc sau tng tc phn ng:

- Lc tm mch trong chu thuc.

- Nn t chu thuc ty ni c nh sng mt tri tng cng tc phn

ng nh hiu ng quang.

- Nu thuc ty c nung nng khong 50oC th thi gian ty s nhanh hn

khi thuc ty c nhit thp (bng nhit mi trng).

Bc 4: Sau khi ty xong cc phn ng khng cn thit, nn ngm mch vo

trong nc l v dng giy nhm nhuyn ch sch cc ng mc v. Cng vic

s chm dt khi cc ng mch c nh bng v sng.

Trc khi dng nha thng lng ph bo v lp ng, ta dng khoan (ng

knh li khoan khong 0,8 -1mm) khoan cc l ghim linh kin. Trong mt vi

trng hp, ta c th dng my dp bm l thay v khoan. Tuy nhin, l dp khng

trn v khi dp d lm m lp bakelite nhng tc thi cng nhanh hn, v d

thao tc hn phng php khoan.

Bc 5: Sau khi khoan (hay dp) l xong, cn nh s li mt ln mch in (pha c ccng ng) bng giy nhm nhuyn, lm sch lp oxit ha ln cui ri mi nhng tmmch vo dung dch nha thng pha vi xng v du la. Khi nhng xong mch, ro v

phi kh lp sn ph ri mi hn linh kin ln mch.

3.Tnh ton mch:

3.1Tnh mch cng sut:

Dng in tr dy t : Rs4=50()


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Khi dng qua mch:

I= = =4,4(A)

Chn triac :BT138 c VDRM=600(V) IT=12(A)VGM=5(V)

dIT/dt =45A/s IGM=2(A) PG(tb)=0,5(w) ton=2us

Tra datasheet chn dng kch cho triac IG=10mA

Chn p t vo triac khi kch l 14(V)

Khi : VGT2=0,7(V) (80oC)

Vtriacopto=1,4(v)

VR25+13=14- 0,7 - 1,4=11,9(v)

RR25+13= =1,19(k )

Chn R25=1(k) R13=180(ohm)

Dng kch cho triac l 10mAPtriacopto=10.1,4=14(mW)

Chonj opto_triac MOC3021:Input: Vm=1,5(V) Im=50mA Pm=100mV

Output: Vm=400(V) Im=100mA Pm=300mV

Chn dng qua Input ca opto triac :I=10mA ; Vdiode=1,2(v)

Chn BJT Qs1 l A1015

Khi opto hot ng th BJT A1015 dn bo ho

VCEs=0,1(v) P=10.0,1=1(mW) tho mn iu kin ca BJT

p ri trn: R11= = =330()

Chn R11=330()

Tnh chn R12


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QS1 A1015 dn bo ho th:

VEB=VEBs=0,8(v)

IB =0,15(mA)

Mc khc dng VK I=3,2(mA) Vmax=0,8(v) mc 0

IB.R12+0,8+0,8=5(v)

Chn IB=1(mA)

R12= =3,3(k)

Chn R12=3,3(k)

3.2Tnh mch ng b:

Chn p vo so snh VI=4v

=VI=4(v)

=3

Chn R26=12(k ) R20=5,6(k )

Chn R17=R20=100k hn dng vo opamp v hn ch dng lch khng.

Opamp co VO=3,5(V) IO=1(uA)

Khi C1815 bo ha VBES=0,7(V)

R14= =2,8(M )

R14=2,2(M )

R19= =49(k )

R19=47(k )


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*CHNG TRNH DELPHI

I/Gim st

- Nhit cm bin- Cc ci t t bn phm nh nhit n nh v tt m ngun ca l nhit v cnh bobng m thanh cng nh mu sc

II/iu khin- Ci t nhit n nh- Tt /m ngun ti

unit Unit1;

interface

usesWindows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,Dialogs, StdCtrls, CPort, ExtCtrls, Menus;

typeTForm1 = class(TForm)

ComPort: TComPort;Memo1Tcambien: TMemo;Edit1Send: TEdit;ButtonOpen: TButton;ButtonSetting: TButton;ButtonSend: TButton;

ButtonClear: TButton;ButtonExit: TButton;Label1: TLabel;Label2: TLabel;Timer1: TTimer;NGAY: TLabel;GIO: TLabel;Button1: TButton;Button2: TButton;Label3: TLabel;Memo3TrangThai: TMemo;Label4: TLabel;

Edit2Tnhap: TEdit;Label5: TLabel;Label6: TLabel;Label7: TLabel;Label8: TLabel;Label9COM: TLabel;Edit3LedPower: TEdit;ButtonPower: TButton;Edit1PHIM4X4: TEdit;


37/55


Label9PHIM4X4: TLabel;Edit1COM: TEdit;procedure ButtonExitClick(Sender: TObject);procedure ButtonOpenClick(Sender: TObject);procedure ButtonSettingClick(Sender: TObject);procedure ButtonSendClick(Sender: TObject);procedure ButtonClearClick(Sender: TObject);procedure ComportRxChar(Sender: TObject; Count: Integer);procedure Timer1Timer(Sender: TObject);procedure Button1Click(Sender: TObject);procedure Button2Click(Sender: TObject);procedure ButtonPowerClick(Sender: TObject);

private{ Private declarations }

public{ Public declarations }end;

varForm1: TForm1;

implementation

{$R *.dfm}//-----------thoat COM v chuong trinh---------------------------------procedure TForm1.ButtonExitClick(Sender: TObject);begin

ComPort.Close;Close;

end;//-----------turn on ---turn off---cong COM------------procedure TForm1.ButtonOpenClick(Sender: TObject);beginif ComPort.Connected then // Kiem tra cong COM co mo khong

beginComport.Close; // neu mo thi dong laiButtonOpen.Caption:='Close';

Memo3TrangThai.Color:=clwhite;Edit1COM.Color:=clwhite;Edit1PHIM4X4.Color:=clwhite;Edit3LedPower.Color:=clwhite;

Memo3TrangThai.Text :='' ;Memo1Tcambien.Text :='' ;Edit2Tnhap.Text :='' ;


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Edit1PHIM4X4.Text :='' ;Edit3LedPower.Text :='' ;

Label9COM.Caption :='Cong COM da dong';endelsebeginComport.Open;ButtonOpen.Caption:='Open';Edit1COM.Color:=clRED;Label9COM.Caption :='Cong COM da ket noi...';end;

end;

// ---------cai dat con COM-----------------------------procedure TForm1.ButtonSettingClick(Sender: TObject);beginComport.ShowSetupDialog;

Comport.Open;

end;

// ---------cai dat nhiet do on dinh---------------------------procedure TForm1.ButtonSendClick(Sender: TObject);

var s1,s2,s3,nguon:string;

var a,b,c,tg,nhietdodat:integer;begintg:=strtoint(Edit3LedPower.Text);nguon:=chr(tg) ;

if Comport.Connected thenbeginif(Edit1Send.Text='') thenShowMessage('Can nhap nhiet do vao')else

if(strtoint(Edit1Send.Text)>120)or(strtoint(Edit1Send.Text)


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tg:=nhietdodat mod 100;b:=tg div 10;s2:=chr(b);

c:=tg mod 10;s3:=chr(c);

ComPort.WriteStr(s1); //tram-phimComPort.WriteStr(s2); //chuc-phimComPort.WriteStr(s3) ; //donvi-phimComPort.WriteStr(nguon) ; //gui data dieu khien nguon

ShowMessage('Nhiet do on dinh da duoc cai dat') ;Edit2Tnhap.Text:=Edit1Send.Text;Edit1Send.Text:='';

endendelse ShowMessage('Cong com dang dong')

end;

// -------------------xoa o nhap nhiet do on dinh-------procedure TForm1.ButtonClearClick(Sender: TObject);beginbeep;Edit1Send.Text:='';end;

//----------doan code nhan data tu vdk phat len----------procedure TForm1.ComportRxChar(Sender: TObject; Count: Integer);var str:string;

beginif comport.Connected thenbegin

comport.ReadStr(str,Count) ;

Memo1Tcambien.Text := inttostr(ord(str[1]));

Edit2Tnhap.Text := inttostr(ord(str[2]));Edit3LedPower.Text := inttostr(ord(str[3]));Edit1PHIM4X4.Text := inttostr(ord(str[4]));

// kiem tra NGUON duoc ON or OFF de bat LedPowerif(strtoint(Edit3LedPower.Text)=1) then

beginEdit3LedPower.Color:=clred;ButtonPower.Caption:='TURN OFF';


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endelse

beginEdit3LedPower.Color:=clwhite;ButtonPower.Caption:='TURN ON';end;

//kiem tra co suu dung ban phim hay khongif(strtoint(Edit1PHIM4X4.Text)=1) then

beginLabel9PHIM4X4.CAPTION:='Dang nhap ban phim....hihi' ;Edit1PHIM4X4.Color:=clred;beep;end

else

beginLabel9PHIM4X4.CAPTION:='4X4 no use.hic' ;Edit1PHIM4X4.Color:=clgreen;end ;

// xem nhiet do cam bien voi nhiet do datif (Edit2Tnhap.Text='') then Memo3TrangThai.Text :='chua cai dat nhiet do on

dinh'else

beginif(strtoint(Edit2Tnhap.Text)>=strtoint(Memo1Tcambien.Text)) then

begin

Memo3TrangThai.Text :='binh thuong..hihi' ;Memo3TrangThai.Color:=clgreen;end

else beginbeep; //qua nhiet thi canh bao bang am thanhMemo3TrangThai.Text :='Oi qua nhiet sep oi..hic hic' ;Memo3TrangThai.Color:=clred;end

end

endend;

// --------thoi gian-------------------------------------procedure TForm1.Timer1Timer(Sender: TObject);beginGIO.Caption:=timetostr(now());NGAY.Caption:=datetostr(now());end;

//-------------about-------------------------------


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procedure TForm1.Button1Click(Sender: TObject);beginshowmessage('chuong trinh GIAM SAT VA ON DINH NHIET DO '+#13#10+'giao vien huong dan:Le Hong Nam'+#13#10+'sinh vien thuc hien:'+#13#10+'NGUYEN MANH HO'+#13#10+'NGUYEN TUAN THANH'+#13#10+'LUONG DUY NINH'+#13#10+'TRAN LE NHAT BINH'+#13#10+'PHAM VAN DANG'+#13#10+'NGO THI VAN DAT'+#13#10+'LE DAO ANH THU');end;// ------------help----------------------------procedure TForm1.Button2Click(Sender: TObject);

beginshowmessage('hotline:01268558797');end;

//----------dieu khien ON--OFF --nguon--------------procedure TForm1.ButtonPowerClick(Sender: TObject);var s1,s2,s3,nguon:string;var a,b,c,tg,nhietdodat:integer;

beginif(strtoint(Edit3LedPower.Text)=1) then

begin //TAT NGUONButtonPower.Caption:='TURN ON';nguon:=chr($0);

nhietdodat:=strtoint( Edit2Tnhap.Text);a:=nhietdodat div 100;s1:=chr(a) ;



ComPort.WriteStr(s1); //tram-phimComPort.WriteStr(s2); //chuc-phimComPort.WriteStr(s3) ; //donvi-phimComPort.WriteStr(nguon) ; //gui data dieu khien nguon

Edit3LedPower.Text:=inttostr(0);


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ShowMessage('Da tat nguon') ;end //HET MO NGUON

elsebegin //MO NGUON

ButtonPower.Caption:='TURN OFF';nguon:=chr($1);

nhietdodat:=strtoint( Edit2Tnhap.Text);a:=nhietdodat div 100;s1:=chr(a) ;



ComPort.WriteStr(s1); //tram-phimComPort.WriteStr(s2); //chuc-phimComPort.WriteStr(s3) ; //donvi-phimComPort.WriteStr(nguon) ; //gui data dieu khien nguonEdit3LedPower.Text:=inttostr(1);ShowMessage('Da mo nguon') ;

end //HET MO NGUONend;end.

Chng trnh chnh


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DONVI EQU 30H

CHUC EQU 31H

TRAM EQU 32H

DONVI_PHIM EQU 33H

CHUC_PHIM EQU 34H

TRAM_PHIM EQU 35H

T_NHAP EQU 36H

T_CAMBIEN EQU 37H ;nhiet doc tu cam bien

NGUON EQU 38H ;REG de phoi hop voi phanmem ON or OFF nguon,khong phai de dk goc pha

;NGUON=1 mo lo,NGUON=0 tat

lo

BANPHIM EQU 39H ;gui tin hieu lenchuong trinh giam sat biet co dang nhap ban phim 4x4 hay khong

;BANPHIM=1 la co su dungban phim 4x4,BANPHIM=0 la khong dung

;-----Dinh nghia cac Bit-----

RDCB BIT P3.7

WRCB BIT P3.6

INTR BIT P3.5

CONGSUAT BIT P3.4 ;BIT DIEU KHIEN CONG SUAT

LED_CONGSUAT BIT P3.3 ;DEN LED BAO QUA NHIET HAY KHONG

LEDPOWER BIT P2.7 ;DEN BAO ON-OFF NGUON

;CAC THANH GHI DA DUNG: R1 LA REG DEM DE NHAP BAN PHIM

; R2 LA DE CHUA GIA TRI TAM THOI CUA T_NHAP

;----------Chuong trinh----------------

ORG 0H

LJMP MAINMAIN

ORG 03H

LJMP XULYCONGSUAT

ORG 23H

LJMP TRUYENDULIEU

ORG 100H

MAINMAIN:


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MOV DONVI,#0H

MOV CHUC,#0H

MOV TRAM,#0H

MOV CHUC_PHIM,#1

MOV TRAM_PHIM,#1

MOV DONVI_PHIM,#9

MOV NGUON,#1 ;ban dau khoi dong NGUON=1 tuc la nguondc TURN ON

MOV BANPHIM,#0 ;ban dau khoi dong BANPHIM=0 =chua sudung

MOV TMOD,#21H

SETB EA ;CHO PHEP NGAT TOAN CUC

SETB EX0 ;CHO PHEP NGAT INT_CAMBIEN DE CHO PHAN DIEUKHIEN CONG SUAT

SETB IT0 ;NGAT THEO SUON XUONG

SETB ES ;CHO PHEP NGAT NOI TIEP

MOV TH1,#-3 ;toc do buad la 9600

MOV SCON,#50H ; set SMO/SM1 =0/1,set bit REN =1

SETB TR1 ;bo dinh thoi 1 hoat dong

MOV P1,#0FFH MOV P2,#0FFH

MOV P3,#0FFH

;--------------------------------------

;--------Chuong trinh chinh------------

;--------------------------------------

MAIN: MOV BANPHIM,#0 ;de bao maytinh rang khong su dung banphim4x4

CALL CHUYENMANGUOC ;chuyen ma nguoc de co T_NHAP,mac dinh luckhoi dong la 119 C

CALL DOC_CAM_BIEN ; Gia tri 8 bit--> A co dc gia tri tram,chuc, don vi

MOV T_CAMBIEN,A ;luu nhiet do cam bien vao regT_CAMBIEN

MOV SBUF,A

CALL CHUYENMA

CALL DISPLAY


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MOV P0,#0FEH

JNB P0.7,PHIM_MODE ;kiem tra xem co chon phim cai dat banphim

JMP MAIN

PHIM_MODE:

JNB P0.7,$

CALL NHAP_BAN_PHIM

JMP MAIN

;--------Chuong trinh con doc cam bien--

DOC_CAM_BIEN:

CLR WRCB ;bat dau cho phep chuyen doi

SETB WRCB

HERE:

JB INTR,HERE ;ket thuc chuyen doi

CLR RDCB ; gui data ra port 1

MOV A,P1

SETB RDCB ;ngat gui data

RET

*LU THUT TON CHNG TRNH QUT BN PHM VHIN TH


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;------chuong trinh con nhap ban phim--------------

NHAP_BAN_PHIM: MOV BANPHIM,#1 ;de bao cho may tinh biet dang sudung ban phim 4x4

CALL CHUYENMANGUOC

CALL CHUYENMA2

CALL DISPLAY

MOV SBUF,T_CAMBIEN

MOV P0,#0FEH

NOP

JNB P0.4,SO1

JMP NEXTX

SO1:


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CALL DELAY_MS

JNB P0.4,$

MOV R1,#1

JMP SOLVE_HIENTHI

SO4:

CALL DELAY_MS

JNB P0.5,$

MOV R1,#4

JMP SOLVE_HIENTHI

SO7:

JNB P0.6,$

MOV R1,#7 JMP SOLVE_HIENTHI

CANCEL: JNB P0.7,$

MOV R1,#0

MOV DONVI_PHIM,#0

MOV CHUC_PHIM,#0

MOV TRAM_PHIM,#0

JMP NHAP_BAN_PHIM

MODE:

JNB P0.7,$

CALL DELAY_MS

MOV R1,TRAM_PHIM

CJNE R1,#0,NEXTMODE ;KIEM TRA XEMNHIET NHIET DO DAT CO QUA120 DO HAY KHONG

JMP MAIN

NEXTMODE: CJNE R1,#1,NHAPLAI

MOV R1,CHUC_PHIM

CJNE R1,#0,NEXTMODE1

JMP MAIN

NHAPLAI:

JMP CANCEL

NEXTMODE1:

CJNE R1,#1,NEXTMODE2

JMP MAIN

NEXTMODE2:

CJNE R1,#2,NHAPLAI

MOV R1,DONVI_PHIM


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CJNE R1,#0,NHAPLAI

JMP MAIN

NEXTX:

MOV P0,#0FEH

JNB P0.4,SO1

JNB P0.5,SO4

JNB P0.6,SO7

JNB P0.7,MODE

MOV P0,#0FDH

JNB P0.4,SO2

JNB P0.5,SO5

JNB P0.6,SO8

JNB P0.7,SO0

MOV P0,#0FBH

JNB P0.4,SO3

JNB P0.5,SO6

JNB P0.6,SO9

JNB P0.7,CANCEL

MOV P0,#0F7H

JNB P0.7,KEY_ENTER

JMP NHAP_BAN_PHIM

KEY_ENTER: MOV R1,NGUON

CJNE R1,#0,TURN_OFF

MOV NGUON,#1

CLR LEDPOWER

JMP NHAP_BAN_PHIM

TURN_OFF: MOV NGUON,#0

SETB LEDPOWER

JMP NHAP_BAN_PHIM

SO0:

JNB P0.7,$

MOV R1,#0

JMP SOLVE_HIENTHI

SO2:

JNB P0.4,$

MOV R1,#2

JMP SOLVE_HIENTHI

SO3:

JNB P0.4,$

MOV R1,#3


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JMP SOLVE_HIENTHI

SO5:

JNB P0.5,$

MOV R1,#5

JMP SOLVE_HIENTHI

SO6:

JNB P0.5,$

MOV R1,#6

JMP SOLVE_HIENTHI

SO8:

JNB P0.6,$

MOV R1,#8

JMP SOLVE_HIENTHI SO9:

JNB P0.6,$

MOV R1,#9

JMP SOLVE_HIENTHI

SOLVE_HIENTHI: MOV A,CHUC_PHIM

MOV TRAM_PHIM,A

MOV A,DONVI_PHIM MOV CHUC_PHIM,A

MOV DONVI_PHIM,R1

JMP NHAP_BAN_PHIM

RET

;-----chuong trinh con chuyen ma --dung cho doc cambien---------------------------

CHUYENMA:

MOV B,#100

DIV AB

ADD A,#0E0H

MOV TRAM,A

MOV A,B

MOV B,#10

DIV AB

ADD A,#0D0H


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MOV CHUC,A

MOV A,B

ADD A,#0B0H

MOV DONVI,A

RET

;------chuong trinh chuyen ma 2--dung cho ban phim----------------

CHUYENMA2:

MOV A,TRAM_PHIM

ADD A,#0E0H

MOV TRAM,A

MOV A,CHUC_PHIM

ADD A,#0D0H

MOV CHUC,A MOV A,DONVI_PHIM

ADD A,#0B0H

MOV DONVI,A

RET

;****************chuyen ma nguoc**dung cho dk cong suat****************

CHUYENMANGUOC: MOV A,TRAM_PHIM

MOV B,#100

MUL AB

MOV T_NHAP,A

MOV A,CHUC_PHIM

MOV B,#10

MUL AB

MOV R0,#36H

ADD A,@R0

MOV T_NHAP,A

MOV A,DONVI_PHIM

ADD A,@R0

MOV T_NHAP,A

RET

;*---------------HIEN THI-----------------

DISPLAY:

MOV R0,#250

LOOPO: MOV P2,DONVI

CALL DELAY_MS

MOV P2,CHUC


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CALL DELAY_MS

MOV P2,TRAM

CALL DELAY_MS

DJNZ R3,LOOPO

RET

;***********************XU LY CONG SUAT**********************

XULYCONGSUAT: PUSH ACC

PUSH PSW

CALL CHUYENMANGUOC

MOV A,T_NHAP

CJNE A,T_CAMBIEN,KHONG_BANG ;T_NHAP-T_CAMBIEN

JMP BINHTHUONG

KHONG_BANG: JNC BINHTHUONG ;NEU BIT C =1 THI T_CAMBIEN


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CLR RI

JNB RI,$

MOV CHUC_PHIM,SBUF

CLR RI

JNB RI,$

MOV DONVI_PHIM,SBUF

CLR RI

JNB RI,$ ;nhan tin hieu dieu khien lam viec cualo la ON or OFF tu may tinh

MOV NGUON,SBUF

CLR RI

SJMP EXIT_TRUYENDULIEU

PHAT: MOV SBUF,T_CAMBIEN ;gui nhiet do cam bien

JNB TI,$

CLR TI

MOV SBUF,T_NHAP ;gui nhiet do nhap tu ban phim

JNB TI,$

CLR TI

MOV SBUF,NGUON ;gui TIN HIEU DIEU KHIEN NGUON

JNB TI,$

CLR TI

MOV SBUF,BANPHIM ;gui tin hieu co su dung ban phim4x4 hay khong

JNB TI,$

CLR TI

EXIT_TRUYENDULIEU: POP PSW

POP ACC

RETI

;-----Chuong trinh con tao tre 1ms------------

DELAY_MS:


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MOV TH0,#HIGH(-1000)

MOV TL0,#LOW(-1000)

SETB TR0

JNB TF0,$

CLR TF0

CLR TR0

RET

;--------delay--dung cho dk cong suat------------

DELAYX:

MOV TH0,#HIGH(-1000)

MOV TL0,#LOW(-1000)

SETB TR0

JNB TF0,$

CLR TF0

CLR TR0

DJNZ R7,DELAYX

RET

END


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*Nhim v ca mi c nhn

-Thnh+ng :hin th nhit & thi cng mch

-H +Ninh + Bnh: delphi&giao tip my tnh&layout

Bao cao TN_ Dang

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