Bài giảng môn Tín hiệu và Mạch - Ths Ngô Hán Chiêu [Tuần 1]

8/8/2019 Bi ging mn Tn hiu v Mch - Ths Ng Hn Chiu [Tun 1]

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GV: ThS Ng Hn ChiuEmail: [email protected]

HP: 0908.978.988

TN HIU V MCH

I HC CNG NGH THNG TIN


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TNG QUAN

H thng my ch:

S tn ch: 03

S tit hc: 45 tit

Tiu chun nh gi:

Thi gia k: 20%

Thi cui k: 80%.

Thang im: 10


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GIO TRNH & TI LIU THAM KHO

H thng my ch:

1. Phng Xun Nhn, L thuyt mch v h thng, i hc BckKhoa H Ni, 2001.

2. Nguyn Vn Chuyt, C s l thuyt truyn tin, NXB KHKT, 2004.3. Phm Th C, Mch in (tp 1,2), NXB HQG TP. HCM, 2007.4. L Phi Yn, K thut in t, NXB HQG TP. HCM, 2007.5. Nguyn Kim nh, K thut in, NXB HQG TP. HCM, 2007.6. Nguyn Quc Dinh, L thuyt mch, Hc vin CNBCVT, 2006.7. William Stalling, Introduction to Electronics design, Prentice Hall,

1995.8. Charles Belove, Circuit design and Analyse, McGraw Hill

Company, 1996.


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TNG QUAN


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TNG QUAN (tt)


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TNG QUAN (TT)


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TNG QUAN (TT)


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KHI NIM

Mch in l m hnh vt l thc, baogm cc in tr, t in, transitor,...cghp ni vi nhau bng cc on dy dnhay board mch in.

S mch in l m hnh l tng, ccphn t thc ca mch in c thay thbng cc phn t l tng

PHN TCH MCH V TNG HP MCH U THC HINTRN M HNH L TNG


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CC PHN T C BN CA MCH IN

IN TR


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IN TR (TT)


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GI TR IN TR

vd1 vd2


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PHN LOI IN TR

in tr thng : in tr thng l cc in tr c cng sut nht0,125W n 0,5W

in trcng sut : L cc in tr c cng sut ln hn t1W,2W, 5W, 10W.

in tr s, in tr nhit : L cch gi khc ca cc in trcng sut , in tr ny c v bc s, khi hot ng chng tonhit.

Cc in tr : 2W 1W 0,5W 0,25Win tr s hay tr nhit


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CNG SUT IN TR

Khi mc in tr vo mt on mch, bn thn in tr tiu thmt cng sut P tnh c theo cng thc

P = U . I = U2 / R = I2.R

Cng sut tiu th ca in tr ph thuc vo dng in iqua in tr hoc ph thuc vo in p trn hai u intr.

Cng sut tiu th ca in tr l hon ton tnh c trckhi lp in tr vo mch.

Nu em mt in tr c cng sut danh nh nh hn cngsut n s tiu th th in tr s b chy. Thng thng ngi ta lp in tr vo mch c cng sut

danh nh > = 2 ln cng sut m n s tiu th


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VD: CNG SUT IN TR


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BIN TR

Bin trL in tr c th chnh thay i gitr, c k hiu l VR chng c hnh dng nh sau :

Bin tr thng rp trong my phc v cho qu trnh sa cha,cn chnh ca k thut vin, bin tr c cu to nh hnh bndi.


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T INT in : T in l linh kin in t th ng c s dng rt rngri trong cc mch in t, chng c s dng trong cc mch lcngun, lc nhiu, mch truyn tn hiu xoay chiu, mch to daong,...

Cu to ca t in

Cu to ca t in gm hai bncc t song song, gia c mtlp cch in gi l in mi.Ngi ta thng dng giy, gm ,mica, giy tm ho cht lm cht

in mi v t in cng cphn loi theo tn gi ca cc chtin mi ny nh T giy, T gm,T ho.


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CC DNG T IN

T gm T ho

T mng nha T xoay s dng trong Radio


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in dung, n v v k hiu ca t inin dung : L i lng ni ln kh nng tch in trn hai bn cc cat in, in dung ca t in ph thuc vo din tch bn cc, vt liulm cht in mi v khong cch gi hai bn cc theo cng thc

C = . S / dTrong C : l in dung t in , n v l Fara (F)

: L hng s in mi ca lp cch in.d : l chiu dy ca lp cch in.S : l din tch bn cc ca t in.* n v in dung ca t : n v l Fara (F) , 1Fara l rt ln do trong thc t thng dng cc n v nh hn nh MicroFara (F) ,NanoFara (nF), PicoFara (pF).1 Fara = 1.000.000 Fara = 1.000.000.000 n F = 1.000.000.000.000 p F1 Fara = 1.000 n Fara1 n Fara = 1.000 p Fara


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T IN (TT)


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T IN (TT)


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T IN (TT)


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CUN DY

Cun cm gm mt s vng dy qun li thnh nhiu vng, dy qunc sn emay cch in, li cun dy c th l khng kh, hoc l vtliu dn t nh Ferrite hay li thp k thut

Li khng kh Li Ferit

L1 l cun dy li khng kh, L2 l cun dy li ferit, L3 l cun dy c li chnh, L4 l cun dy li thp k thut


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CUN DY (tt)


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CUN DY (tt)


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CUN DY (tt)


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CC THNG S CUN DY (tt)

H s t cm (nh lut Faraday)

H s t cm l i lng c trng cho sc in ng cm ng

ca cun dy khi c dng in bin thin chy qua.L = 4.3,14.10-7 n2.S.l

L : l h s t cm ca cun dy, n v l Henrry (H)

n : l s vng dy ca cun dy.

l : l chiu di ca cun dy tnh bng mt (m)S : l tit din ca li, tnh bng m2


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CC THNG S CUN DY (tt)

Cm khng

Cm khng ca cun dy l i lng c trng cho s cn

tr dng in ca cun dy i vi dng in xoay chiu .

ZL = 2.3,14.f.L

Trong : ZL l cm khng, n v l

f : l tn s n v l Hz

L : l h s t cm , n v l Henry


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ng dng ca cun dy

R le

Bin p

U1 / U2 = n1 / n2

U1 / U2 = I2 / I1Loa

Micro


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NGUN P


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NGUN P (TT)


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NGUN DNG


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GV: ThS Ng Hn ChiuEmail: [email protected]

HP: 0908.978.988

MCH 1 CHIU

I HC CNG NGH THNG TIN


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MCH 1 CHIUTNG QUAN


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CC NH LUT C BN

NH LUT OHM


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NH (NT), NHNH V VNG

Nhnh l phn t hai cc bt k, hoc gmcc phn t hai cc ni tip vi nhau trn c cng dng in chy qua.


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NH (NT), NHNH V VNG (tt)


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NH (NT), NHNH V VNG (tt)


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V D

Nhnh 1: e1, R1 ni tip.

Nhnh 2: e2, R2 ni tipNhnh 3: R3.Nhnh 4: R4Nhnh 5: R5Nhnh 6: R6n= 6

4 nh A,B,C v D

d= 4

V = n d + 1 = 6-4+1 = 303 mt li


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V D

Vng 1: nhnh 1,6 v 4.

Vng 2: nhnh 2,5 v 6Vng 3: 4,5 v 3Vng 4: 1,2 v 3

Vng 5: 1,6,5,3

Vng 6: 1,2,5,4Vng 7: 2,3,4,6


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NH LUT KIRCHOFF 1 (K1)


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V D

Nt A: i1 - i2 i6 = 0Nt B: i2 - i3 - i5 = 0Nt C: - i1 + i3 - i4 = 0Nt D: i4 + i5 + i6 = 0


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NH LUT KIRCHOFF 2 (K2) (tt)

Du ca in p c xc nh da trn chiudng ca in p chn so vi chiu ca vng.

Chiu ca vng c chn tu (thng chncng nhnhau: cng chiu hoc ngc chiu kimng h).

Trong mi vng, nu chiu vng i t cc (+)

sang cc ( - ) ca mt in p, th in p mangdu (+), ngc li in p y mang du ( - ).


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V D


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BI TP 1


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BI TP 1


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BI TP 1


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BI TP 2

Tm dng in chytrong cc nhnh

Tm dng in chytrong cc nhnh

Tnh tng cng sutpht ca cc ngunv tng cng suttiu tn ca cc R


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BI TP 3


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BI TP 2

K hiu cc dng nhnh

Chn i1 = variable

C : i = -10 AKCL : i2 = i1 + 5i = i1 - 50KCL : i3 = i2 + 20 = i1 - 30KCL : i4 = i - i1 = - 10 - i1Th vo pt KVL duy nht vit cho vng kn bao 2 ml pha trn :10*i1 + 20*i2 - 200 + 40*i3 - 30*i4 = 100

10*i1 + 20*[i1 - 50] - 200 + 40*[i1 - 30] - 30*[- i1 - 10] = 100100*i1 - 2100 = 100Suy ra i1 = 22 A

Bi gii 1A


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HOMEWORK

Homework1:1.2; 1.8; 1.11; 1.16; 1.17; 1.20; 1.23; 1.24; 1.29; 1.32;Sch Bi tp mch in 1 - Phm Th C NXB HQG TP. HCM - 2002

Bài giảng môn Tín hiệu và Mạch - Ths Ngô Hán Chiêu [Tuần 1]

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