Atap Dynabolt
Transcript of Atap Dynabolt
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5/27/2018 Atap Dynabolt
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Perhitungan base plate
150
100
150
81.3 237.5 81.3
318.7
400
Mutakterduga= 34083 kgNu = 3789.6 kg
Hu = 1365.1 kg
f'c = 35 Mpa = 250 kg/cm
B = 400 mm = 40 cm
H = 400 mm = 40 cmd = 250 mm
b = 125 mm
0,95d = 237.5 mm
0,8b = 100 mm
x= 81.3 mm = 8.13 cm
y = 150 mm = 15 cm
n Baut = 3
BJ 37 => fy = 240 Mpa = 2400 kg/cm
fu = 370 Mpa = 3700 kg/cm
1. Ukuran B x H
2.3685 kg/cm
2. Tebal pelat
0.70245 cm 0.8 cm
BxH
Nucf'
bfyHB
yNut
...
..2 2
1
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3. Baut angker (dipakai DYNABOLT)
Momen tak terduga dari pemasangan = 34083 kg
tension
34083 143.51
318.7
geser = Hu / jumlah baut geser
= 227.52
dipakai dynabolt 3 M16 48 mm
ket. dyna bolt
9
25.4
Sambungan di A 22.8
Dicoba tebal pelat 0.7 mm & baut 0.5 inchi 250 22.822.8
Mu = 68256 kg baut = A3250 22.8
Vu = 1365.1 kg fub = 8250 25.4
Nu = 3789.6 kg 9
3d = 38.1
d = 12.7 59.5 59.5di pakai baut1/2" --> mutu AST 320 dgn jmlh baut 16 pasang
= 12.70
22.53d = 38.1 cm 59.5 cm
y2 = 79.8
y1= 11.4
6
=
T
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Fut =
=
= 2514.69 kg/cm2
FuQ = VU 1365.1
baut 16
= 85.31875 kg/cm2
Fuv = 85.31875
1/4 1.27
= 67.39 kg/cm2
FuQ f. r1. fub. n .ab. m85.31875 63870.8
>baut yang memikul gaya tarik dan geser
Fut = 2514.69 ft (f1 - r2 FuY) r2 = 1.9
Abaut =1/4 1.27 f1 = 8070 kg/cm2
= 1986.13 ft = 7942 f2 = 6210 kg/cm2
= okeee.!
> baut yang memikul gaya tarik murni
Fut f. d2
2514.69 7834.15772 kg/cm2
okeeh!
Perhitungan las bas plate
Nu = 1230 kg
Hu = 922.38 kg
f'c = 25 Mpa = 250 kg/cm
B = 400 mm = 40 cm
H = 400 mm = 40 cm
BJ 37 => fy = 240 Mpa = 2400 kg/cm
fu = 370 Mpa = 3700 kg/cm
d = 250 mm = 25 cm
bf = 125 mm = 12.5 cm
tw = 6 mm = 0.6 cm
tf = 9 mm = 0.9 cm
t pelat = 10 mm = 1 cm
t diambil yang paling kecil = 6 mm
4.242 mm = 0.4242 cm
41.91096 cm
Sy = statis momen terhadap sumbu y
Sy = 203.38269 cm
22.008 kg/cm
14.674 kg/cm
26.45148604 kg/cm
(tegangan max pada las)
Dipakai elektroda E60
Syarat
fr 790.86 kg/cm (elektroda)
0,75.t.0,6.fu = 999 kg/cm (baja)
Sambungan Okeh!!!
Perhitungan las di sambungan A
ttt .707,0
20.26,0.215.443,0.panjanglastA tlas
1,9.5,0.42,0.1,9.255,9.42,0.9,0.21.1,9.42,0.6,0150,10.42,0.15Sy
911,41
38,922'
lasA
Huxf
911,41
1230'
lasA
Nuyf
2222
348.29008,22'' yfxffr
uwt ft .6,0..75,0
2
)(4
max
Yi
sMUxY
22
)875.7()125.1(4
875.7)2.1(_68256
x
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Mu = 68256
Nu = 3789.6 kg
Vuy = 1365.1
BJ 37 => fy = 240 Mpa = 2400 kg/cm
fu = 370 Mpa = 3700 kg/cm
d = 250 mm = 25 cmbf = 125 mm = 12.5 cm
tw = 6 mm = 0.6 cm
tf = 9 mm = 0.9 cm
t pelat = 10 mm = 1 cm
t diambil yang paling kecil = 6 mm
4.242 mm = 0.4242 cm
41.911 cm
F'p = Pu = (1365.1 x 1.2) = 39.09
Alas
F'N = Nu = 3789.6 = 90.420
A 41.911
> Menghitung tebal las diambil satu-satuan tebal
y1 = 11.6
Sy = statis momen terhadap sumbu y y2 = 10.7
sx = b tt y1 + (b-tw).tt.y2 + 2 tt y2 1/2 y2
sx = 12.5 x 0.424 x 11.6 + (12.5-0.6)x(2x0.424x10.7x1/2x10.7) 250
Sx = 164.1 cm
249.5816 kg/cm 9
302.50 kg/cm
(tegangan max pada las)
Dipakai elektroda E60 = 4143 kg
Syarat
fr 790.86 kg/cm (elektroda)
0,75.t.0,6.fu = 999 kg/cm (baja)
Mu = 2870 kg
Sambungan Okeh!!! Vu = 110.1 kg
Nu = 785.5 kg
9
25.4
22.5Dicoba tebal pelat 0.7 mm & baut 0.5 inchi 250 22.5
22.5
Mu = 2869.9 kg baut = A3250 22.5
Vu = 110.1 kg fub = 8250 25.4
Nu = 785.53 kg 9
3d = 38.1
d = 12.7 59.5 59.5
di pakai baut1/2" --> mutu AST 320 dgn jmlh baut 16 pasang
= 12.70
22.53d = 38.1 cm 59.5 cm
y2 = 78.75
y1= 11.25
Fut =
=
41.911
125
Sambungan di B
6
ttt .707,0
25.26,0.25,12.443,0___.panjanglastA tlas
uwt ft .6,0..75,0
22222 42,9009.39669.249)'()''( Nfyfxffr
012,1642
2.168256
2'
sx
Muyf
2
)(4
max
Yi
sMUxY
22
)875.7()125.1(4
875.7)2.1(_9.2869
x
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= 107.14 kg/cm2
FuQ = VU 110.1
baut 16
= 6.88125 kg/cm2
Fuv = 6.88125
1/4 1.27
= 5.43 kg/cm2
FuQ f. r1. fub. n .ab. m6.88125 63870.8
>baut yang memikul gaya tarik dan geser
Fut = 107.14 ft (f1 - r2 FuY) r2 = 1.9
Abaut =1/4 1.27 f1 = 8070 kg/cm2
= 84.62 ft = 8059.7 f2 = 6210 kg/cm2
= okeee.!
> baut yang memikul gaya tarik murni
Fut f. d2
107.14 7834.15772 kg/cm2
okeeh!
Perhitungan las di sambungan B
Mu = 2869.9
Nu = 785.53 kg
Vuy = 110.1
BJ 37 => fy = 240 Mpa = 2400 kg/cm
fu = 370 Mpa = 3700 kg/cm
d = 250 mm = 25 cm
bf = 125 mm = 12.5 cm
tw = 6 mm = 0.6 cm
tf = 9 mm = 0.9 cm
t pelat = 10 mm = 1 cm
t diambil yang paling kecil = 6 mm
4.242 mm = 0.4242 cm
41.911 cm
F'p = Pu = (110.1 x 1.2) = 3.15
Alas
F'N = Nu = 785.53 = 18.743
A 41.911
> Menghitung tebal las diambil satu-satuan tebal
y1 = 11.6
Sy = statis momen terhadap sumbu y y2 = 10.7
sx = b tt y1 + (b-tw).tt.y2 + 2 tt y2 1/2 y2
sx = 12.5 x 0.424 x 11.6 + (12.5-0.6)x(2x0.424x10.7x1/2x10.7) 250
Sx = 164.1 cm
10.49 kg/cm 9
23.18 kg/cm
(tegangan max pada las)
Dipakai elektroda E60 = 4143 kg
Syarat
fr 790.86 kg/cm (elektroda)
0,75.t.0,6.fu = 999 kg/cm (baja)
Mu = 2870 kg
Sambungan Okeh!!! Vu = 110.1 kg
Nu = 785.5 kg
Dicoba tebal pelat 0.7 mm & baut 0.5 inchi 250 22.8
22.8
41.911
125
ttt .707,0
25.26,0.25,12.443,0___.panjanglastA tlas
uwt ft .6,0..75,0
22222 42,9049.1015.3)'()''( Nfyfxffr
012,1642
2.19.2869
2'
sx
Muyf
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Mu = 20.55 kg baut = A3250 22.8
Vu = 1365.1 kg fub = 8250 25.4
Nu = 3789.6 kg 9
3d = 38.1
d = 12.7 59.5 59.5
di pakai baut1/2" --> mutu AST 320 dgn jmlh baut 16 pasang = 12.70
22.53d = 38.1 cm 59.5 cm
y2 = 79.8
y1= 11.4
Fut =
=
= 0.76 kg/cm2
FuQ = VU 1365.1
baut 16
= 85.31875 kg/cm2
Fuv = 85.31875
1/4 1.27
= 67.39 kg/cm2
FuQ f. r1. fub. n .ab. m85.31875 63870.8
>baut yang memikul gaya tarik dan geser
Fut = 0.76 ft (f1 - r2 FuY) r2 = 1.9
Abaut =1/4 1.27 f1 = 8070 kg/cm2
= 0.60 ft = 7942 f2 = 6210 kg/cm2
= okeee.!
> baut yang memikul gaya tarik murni
Fut f. d2
0.76 7834.15772 kg/cm2
okeeh!
Perhitungan las di sambungan A'
Mu = 34128
Nu = 1894.8 kg
Vuy = 682.55
BJ 37 => fy = 240 Mpa = 2400 kg/cm
fu = 370 Mpa = 3700 kg/cm
d = 250 mm = 25 cm
bf = 125 mm = 12.5 cm
tw = 6 mm = 0.6 cm
tf = 9 mm = 0.9 cm
t pelat = 10 mm = 1 cm
t diambil yang paling kecil = 6 mm
4.242 mm = 0.4242 cm
41.911 cm
F'p = Pu = (1894.8 x 1.2) = 19.54
Alas 41.911
F'N = Nu = 1894.8 = 45.210
A 41.911
125
> Menghitung tebal las diambil satu-satuan tebal
y1 = 11.6
Sy = statis momen terhadap sumbu y y2 = 10.7
6
ttt .707,0
2
)(4
max
Yi
sMUxY
22
)875.7()125.1(4
875.7)2.1(_68256
x
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sx = b tt y1 + (b-tw).tt.y2 + 2 tt y2 1/2 y2
sx = 12.5 x 0.424 x 11.6 + (12.5-0.6)x(2x0.424x10.7x1/2x10.7) 250
Sx = 164.1 cm
124.7908 kg/cm 9
151.25 kg/cm
(tegangan max pada las)
Dipakai elektroda E60 = 4143 kg
Syarat
fr 790.86 kg/cm (elektroda)
0,75.t.0,6.fu = 999 kg/cm (baja)
Mu = 2870 kg
Sambungan Okeh!!! Vu = 110.1 kg
Nu = 785.5 kg
25.26,0.25,12.443,0___.panjanglastA tlas
uwt ft .6,0..75,0
012,1642
2.134128
2
'
sx
Muyf