ASTR377: A six week marathon through the firmament
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Transcript of ASTR377: A six week marathon through the firmament
ASTR377:A six week marathon
through the firmament
by
Orsola De [email protected]
Office: E7A 316Phone: 9850 4241
Week 5, May 17-20, 2009
Overview of the course
What death becomes her?
• Depending on the main sequence mass, a star will end in a different way.
• M<0.08Mo no H burning – BD [L or T dwarfs].• 0.08Mo < M < 0.5Mo no He burning. Stars become
He WDs.• 0.5Mo < M < 5Mo no C burning: stars become CO
WDs.• 5Mo < M < 7Mo yes C burning to Ne and Mg: stars
become ONeMg WDs.• M > 7Mo burn all the way to Fe: these stars go
through a type II SN and become NSs or BHs.
What happens after the AGB?• Spectra of planetary nebulae indicate that the
“shell” is expanding with speeds of 20-30 km/s. The central star is often visible inside the PN.
Jacoby, De Marco & Sawyer 1998
What happens after the AGB?
Angular size and distance
34
76
km ?
D
Base
Hypotenuse= sin
Moon diameter
D= sin
The PN clock
• The central stars of PN on the HRD: they sit in a locus and have increasing ages along the red arrow.
• Conclusion: the star evolves to the blue in a very short time.
AGBlogTeff=3.5
PN “ignition”: log Teff ~ 4.4
Oldest PNe
Youngest PNe
Bob O’Dell American (alive)
O’Dell 1968
At the end of the AGB
• Core mass growing because of the He shell burning. This generates an increase in L.
• Two shell sources, H (out) and He (in). Every time a star has multiple shell sources, all burning outwards through the fresh fuel supply, there is instability.
• The relative speed at which they burn out can create an instability where the helium shell L increases with no release of pressure, leading to even more L.
• Eventually the L pushes the envelope out, the H shell extinguished and the He burning rate decreases, L gets out, then the entire star returns to equilibrium.
• At the end of each thermal shell flash the envelope convection zone extends downwards and dredges up the results of He burning: C and O. This is the third and last dredge up chance a star has and makes of AGB star the C factories of the Universe.
http://outreach.atnf.csiro.au/education/senior/astrophysics/stellarevolution_postmain.html
Departing the AGB
• When the AGB H envelope mass drops below a few times 10-4 Mo the star loses its equilibrium and contracts.
• The contraction and the increased transparency of the envelope result in a fast increase of the effective temperature.
• All the while the H or the He shell source are still burning.
• Eventually the burning stops and the star cools on the WD cooling track.
Vassiliadis & Wood 1994
The PN phase• As the star heats a fast
but this time tenuous wind sweeps AGB wind material up and creates a shells.
• When the photosphere of the heating star passes the ~25,000-K mark the swept up shell is ionized and can be seen in forbidden lines.
Animation from the Space Telescope Science Institute
What do Planetary Nebulae What do Planetary Nebulae look like in the skylook like in the sky
3 arcmin
Planetary Nebula shapes: round….
Abell 39; WIYN image; G. Jacoby
Planetary Nebula shapes: “elliptical”….
The Helix nebula; Spitzer image; K. Su
Planetary Nebula shapes: “elliptical++”….
The Cat’s Eye nebula; HST image
OH321.8+4.2; Bujarrabal; HST
PN shapes and shaping
• Young PN and pre-PN (shining from shocks not from radiative ionization) are always non-round.
NGC6543 HST/NOT [OIII]/[NII]/Ha. (P. Harrington, R. Corradi)
2.5 pc
3.4
Empirically shown to happen, theoretically unexplained
AGB
WD
post-AGB
CSPN
Planetary nebulae as we teach themPlanetary nebulae as we teach themHow do PN form?How do PN form?
Envelope mass < 10-3 to -4 Mo: departure from the AGB.Fast thin post-AGB wind compresses the super-wind.
3.4
Kwok 1982; Balick 1987Kwok 1982; Balick 1987
AGB
WD
post-AGB
CSPN
Planetary nebulae as we teach themPlanetary nebulae as we teach themHow do PN form?How do PN form?
Post-AGB star heats up T>25,000K: ionized PNA39: a well behaved PN
AGB
WD
post-AGB
CSPN
Planetary nebulae as we teach themPlanetary nebulae as we teach themHow do PN form?How do PN form?
… … but how do PN acquire their shapes?but how do PN acquire their shapes?
Relatively-fast rotation during AGB super-wind …
Garcia-Segura et al. 2003Garcia-Segura et al. 2003
… … but how do PN acquire their shapes?but how do PN acquire their shapes?
Garcia-Segura et al. 2003Garcia-Segura et al. 2003
… … but how do PN acquire their shapes?but how do PN acquire their shapes?
… and/or magnetic fields
… … but how do PN acquire their shapes?but how do PN acquire their shapes?
… result in circumstellar material with an equatorial enhancement
… … but how do PN acquire their shapes?but how do PN acquire their shapes?
When the star heats up, on its way to becoming a white dwarf, a fast wind rums into the previously-ejected gas.
… … but how do PN acquire their shapes?but how do PN acquire their shapes?
Let’s zoom out …
… but how do PN acquire their shapes?
Let’s zoom out …
… the lobes perpendicular to the plane of the disk continue to expand.
… but how do PN acquire their shapes?
When the star heats up
the gas “shines” and we see the bipolar PN
… … but how do PN acquire their shapes?but how do PN acquire their shapes?
The problem: giant stars do not rotate fast enough.
How can a companion spin up a giant?How can a companion spin up a giant?
Animation from the Space Telescope Science Institute
White dwarfs: key properties
• Small – about Earth radius.
• Not (all) white: some are very cool (~4000K).
• Super dense.
Srius A and B; HST/FGS image
History of WDs• 1844 Friedrich Bessel
discovers that Sirius changes position and the change is not due to annual parallax…. There must be an unseen companion.
• In 1864 the companion was found by Alvan Graham Clark. It was 25,000K bit only 10,000th the luminosity of the Sun. What does this mean?
• A better solution of the orbit gave us Sirius B’s mass (0.9Mo) This meant that this star was much denser.
Friedrich Wilhelm Bessel German 1784-1846
History of WDs• A better solution of the orbit
gave us Sirius B’s mass (0.9Mo) This meant that this star was much denser.
• In 1917 Adriaan van den Maaren discovered another WD (a single one).
• It was not till quantum mechanics that Ralph Fowler determined that degeneracy pressure was supporting the WDs.
• Eventually Chandrasekhar determined the mass limit above which WDs cannot exist (among many many other things that got him the Nobel Prize)
Ralph H. Fowler, UK 1889-1944
WD density and pressure
• You can determine the WD density from a value of its mass and radius (which for Sirius B come from observations).
• You can then determine a value for the central pressure of the WD using the equation of hydrostatic equilibrium.
The mass-radius relation for WDsaka: the more you have the smaller it is!
€
R ≈ 0.01 R•
M
0.7M•
⎛
⎝ ⎜
⎞
⎠ ⎟
−1/ 3
(No demonstration)
The Chandrasekhar limit for WDs• As you increase the mass of a WD the radius decreases,
the density increases and eventually the electrons speeds approach the speed of light, i.e., they become relativistic.
• By equating the core pressure for a star in hydrostatic equilibrium, to the pressure for relativistic electrons we see that there is no radius for which the star will be in equilibrium: the star just collapses.
• From the same equation we can derive the mass of such star. For masses larger than the Chandrasekhar mass limit, the star collapses.
€
M ≤1.4 M•
for stability
(Board demonstration)
Neutron Stars: formation
• Si-burning adds Fe to the core which increases in mass. And contracts under its own weight.
• Electron degeneracy provides the pressure but when the electrons become relativistic at the Chandrasekhar limit the star collapses in a free-fall time (<1 second).
• Protons and electrons combine to form neutrons and neutrinos (the neutrinos take energy out).
• Collapse is halted by neutron degeneracy pressure. • We have a neutron star.• A neutron star is not technically a star because it is not
gaseous and it is not powered by thermonuclear fusion….
Neutron stars: radius
• The mass radius relations for WD is the same as that for neutron star except that the neutron mass is in place of the electron mass.
€
RNS
RWD
≈ me
mn
MWD
MNS
⎛
⎝ ⎜
⎞
⎠ ⎟
1/ 3
Neutron stars: escape velocity
• The escape velocity from a NS is about ½ of the speed of light.
€
vesc ≈ 2GM
R
⎛
⎝ ⎜ ⎜
⎞
⎠ ⎟ ⎟
1/ 2
≈ 2 ×108 m s-1 M
1.4M•
⎛
⎝ ⎜
⎞
⎠ ⎟
2 / 3
Neutron stars: luminosity
• When first formed a NS has T~106K. So, despite their small radius the luminosity is not terribly low.
• Using Wien’s law we see this spectrum peaks at ~30A or 400 eV in the X-ray range.
• But there is another type of radiation from NS.
€
LNS ≈ RNSR•
⎛
⎝ ⎜
⎞
⎠ ⎟
2TNST•
⎛
⎝ ⎜
⎞
⎠ ⎟
4
L• ≈ 0.2 L•
Neutron stars: pulsars
• As the star collapses conservation of angular momentum makes it spin at about 0.1c, implying a rotation period of the order of milliseconds.
• Magnetic flux is also conserved such that the surface B fields is intensified.
• The rotating B field creates an E field that rips charged particles from the surface of the star, which later get beamed by the B field and ejected at the poles.
• They were discovered during a radio survey of the Galaxy and the first one was named LGM-1.
• There are about 500 known pulsars and considering the selection effects, there must be a lot more.
Neutron stars: pulsars
• Why are pulsars not WDs?• If the periodicity was
due to pulsations, the material pulsating would have to be very dense indeed, much denser than a WD can be.
• If it were a rotating WD, the rotation speed at the periphery of the WD would have to be 100c.
• Pulsars are often seen in the middle of SN remnants.
BH History
• Postulated by John Mitchell 200 years ago as objects with such high g that not even light could escape (he called them black stars).
• Calculated by Schwarzschild in 1916, as soon as GR was invented.
• Died shortly after at the front of some disease– very sad.
• John Wheeler called them Black Holes
John Wheeler American 1911-2008
Karl Schwarzschild German 1873-1916
Black Holes: the Oppenheimer-Volkov limit
Black Holes: the Schwarzshild radius
• By equating the escape velocity to the speed of light you see the size of a BH’s event horizon.
• Nothing going inside can emerge, not particles, not light, not information.
€
RSch ≈ 2GM
c2
⎛
⎝ ⎜
⎞
⎠ ⎟= 3 km
M
M•
⎛
⎝ ⎜
⎞
⎠ ⎟
BH: tidal ripping
• At what distance can a BH rip a person approaching feet first? (assuming that a force that can rip a person is about 16 tonnes)
• For a 2000 Mo BH you will be ripped at exactly the Schwarzshild radius.
€
ΔF ≈ GMm
R3
⎛
⎝ ⎜
⎞
⎠ ⎟l
Rrip ≈ 435 M
M•
⎛
⎝ ⎜
⎞
⎠ ⎟
1
3
km
compare with
RSch = 3 km M
M•
⎛
⎝ ⎜
⎞
⎠ ⎟
RripRSch
≈ 160 M
M•
⎛
⎝ ⎜
⎞
⎠ ⎟
−2
3
Observations of BHs
• V404 Cyg – binary system where a K0 star donates mass to a dark object via an accretion disk.
• The BH is revealed by the orbital motion of the companion or the luminosity of the accretion disk.