Askiitians Physics Test209

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    AskIITiansIIT JEE Physics Test

    Code AP209

    Time - One hour

    Please read the instructions carefully. You are allotted 5 minutes specifically for this purpose.

    A. General :1. This booklet is your Question paper containing 69 questions.2. Blank papers, clipboard, log tables, slide rules, calculators, cellular phones, pagers and electronic gadgets in

    any form are not allowed to be carried inside the examination hall.3. The answer sheet, a machine-readable Objective Response Sheet (ORS), is provided separately.B. Filling the ORS :4. On the lower part of the ORS, write in ink, your name, your Registration No. Do not write these anywhere

    else.5. Make sure the CODE on the ORS is the same as that on this booklet and put your signature on the ORS

    affirming that you have verified.6. Write your Registration No. in ink, provided in the lower part of the ORS and darken the appropriate bubble

    UNDER each digit of your Registration No. with a good quality HB pencil.C. Question paper format.7. The question paper consists of 3 parts (Physics, Chemistry and Mathematics). Each part has 4 sections.8. Section I contains 6 multiple choice question. Each question has four choices (A), (B), (C) and (D), out of

    which only one is correct.9. Section II contains 4 questions. Each question has four choices (A), (B), (C) and (D), out of which one or

    more choices is correct.10. Section III contains 4 questions. Each question contains Statement -1 (Assertion) and Statement -2

    (Reason).Bubble (A) if both the statements are TRUE and STATEMENT-2 is the correct explanation ofSTATEMENT-1.

    Bubble (B) if both the statements are TRUE butSTATEMENT-2 is NOT the correct explanation ofSTATEMENT-2.Bubble (C) if STATEMENT-1 is TRUE and STATEMENT-2 is FALSE.Bubble (D) if STATEMENT-1 is FALSE and STATEMENT-2 is TRUE.

    11. Section IV contains 3 paragraphs. Based upon each paragraph, three multiple choice questions have to beanswered. Each question has four choices (A) (B) (C) (D) out of which only one is correct.

    D. Marking Scheme.12. For each question in Section I, you will be awarded 3 marks if you have darkened only the bubble

    corresponding to the correct answer and zero mark if no bubble is darkened. In all other cases, minus one (1) mark will be awarded.

    13. For each question in Section II, you will be awarded 4 marks, if you darken only the bubble corresponding tothe correct answer and zero mark if no bubble is darkened. In all other cases, (1) mark will be awarded.

    14. For each question in Section III, you will be awarded 3 marks, if you darken only the bubble correspondingto the correct answer and zero mark if no bubble is darkened. In all other cases, (1) mark will be awarded.

    15. For each question in Section IV, you will be awarded 3 marks, if you darken only the bubble corresponding

    to the correct answer and zero mark if no bubble is darkened. In all other cases, (

    1) will be awarded.

    Useful Data

    Gas Constant R = 8.314 J K1

    mol1

    1 Faraday = 96500 Coulomb= 0.0821 Lit atm K

    1mol

    1 1 calorie = 4.2 Joule

    = 1.987 2 Cal K1

    mol1

    1 Ev = 1.6 101

    JAvogadros Number Na = 6.023 1023Plancks constant h = 6.625 10

    34J . s

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    = 6.625 1027

    erg . s

    Atomic No: H = 1, D = 1, Li = 3, Na = 11, K = 19, Rb = 37, Cs = 55, F = 9, Ca = 20, He = 20, He = 2, O= 8, Au = 79, Ni = 28, Zn = 30, Cu = 29, CI = 17, Br = 35, Cr = 24,Mn = 25, Fe = 26, S = 16, P = 15, C = 6, N = 7, Ag = 47.

    Atomic Masses: He = 4, Mg = 24, C = 12, O = 16, N = 14, P = 31, Br = 80, Cu = 63.5, Fe = 56, Mn = 55, Pb

    = 207, Au = 197, Ag = 108, F = 19, H = 1, CI = 35.5, Sn = 118.6, Na = 23, D = 2, Cr = 52,K = 39, Ca = 40, Li = 7, Be = 4, AI = 27, S = 32.

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    SECTON I

    1. A charge passing through a resistor is varying with time as shown in

    figure. The amount of heat generated in time t is best described by

    (as a function of time):-5c

    2sec

    1 sec t

    -5c

    H H

    (a) (b)

    t 1 sec t 2 sec

    H H

    (c) (d)

    1 sec 2 sec t 1 sec 2 sec t

    2. The values of kinetic energy K and potential energy U are measuredas follows :-

    K = 100.0 + 2.0 JU = 200.0 + 1.0 J

    Then the percentage error in the measurement of mechanical energyis

    (a) 2.5%

    (b) 1%

    (c) 0.5%

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    (d) 1.5%

    3. A radioactive nucleus X decays to a stable nucleus Y. Then the graph

    of rate of formation of Y against the time t will be

    R R

    (a) (b)

    t t

    R R

    (c) (d)

    t t

    o

    4. Light of wavelength 4000A is incident at small angle on a prism ofapex angle 4o. The prism has nv = 1.5 and nr = 1.48. The angle of

    dispersion produced by the prism in this light is

    (a) 0.2o(b) 0.08o(c) 0.192o(d) none of these

    5. A particle of charge q and mass m moves in a circle of radius raround an infinitely long time charge of linear charge density + . Then

    time period will be:- +

    r q

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    (a) T = 2 r

    (b) T2 = r3

    (c) T =

    (d) T =

    Where k = .

    6. Maxwells velocity distribution curve is given for two different

    temperatures. For the given curves

    N

    T2

    T1

    V

    (a) T1 > T2

    (b) T1 < T2(c) T1 < T2(d) T1 = T2

    SECTION II

    1. The voltage applied to an X-ray tube is 18 KV. The maximum mass of

    photon emitted by the X-ray tube will be:-(a) 2 1013 kg

    (b) 3.2 1036 kg

    (c) 3.2 1032 kg

    (d) 9.1 1031 kg

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    2. AB is an L-shaped obstacle fixed on a horizontal smooth table. A ball

    strikes it at A, gets deflected and restrikes it at B. If the velocity vectorbefore collision is and coefficient of restitution of each collision is e,

    then the velocity of ball after its second collision at B is

    A

    O

    B

    (a) e2

    (b) e2

    (c) e

    (d) Data insufficient.

    3. In a Youngs Double slit Experiment; D = 1m, d = 1mm and = 5000

    nm. The distance of 100th maxima form the central maxima is:-(a) m

    (b) m

    (c) m

    (d) does not exists

    4. If the magnetic field at P can be written as K tan then K is:-

    i

    P|d|

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    (a)

    (b)

    (c)

    (d)

    SECTION III

    1. Statement 1: A uniform thin rod of length L is hinged about one of itsend and is free to rotate about the hinge without friction. Neglect the

    effect of gravity. A force F is applied at a distance x from the hinge on

    the rod such that force always is perpendicular to the rod. As the valueof x is increased from zero to L, the component of reaction by hinge onthe rod perpendicular to the length of rod increases.

    Statement 2: Under the conditions given in statement 1 as x is

    increased from zero to L, the angular acceleration of rod increases.

    2. Statement 1: Imagine holding two identical bricks under water. Brick

    A is completely submerged just below the surface of water, while BrickB is at a greater depth. The magnitude of force exerted by the person

    (on the brick) to hold brick B in place is the same as magnitude of

    force exerted by the person (on the brick) to hold brick A in place.

    Statement 2: The magnitude of buoyant force on a brick completely

    submerged in water is equal to magnitude of weight of water displaced

    and does not depend on depth of brick in water.

    3. Statement 1: The current density at any point in ohmic resistor is in

    direction of electric field at that point.

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    Statement 2: A point charge when released form rest in a region

    having only electrostatic field always moves along electric lines of

    force.

    4. Statement 1: In free space, a uniform spherical planet of mass M hasa smooth narrow tunnel along its diameter. This planet and another

    superdense small particle of mass M start approaching towards eachother from rest under action of their gravitational forces. When theparticle passes through the centre of the planet, sum of kinetic

    energies of both the bodies is maximum.

    M

    Statement 2: When the resultant of all forces acting on a particle like

    object (initially at rest) is constant in direction, the kinetic energy ofparticle keeps on increasing.

    SECTION IV

    Paragraph

    Two bodies A and B of masses 10 kg and 5 kg are placed very slightlyseparated as shown in figure. The coefficients of friction between the floor

    and the blocks are s = k = 0.4. Block A is pushed by an external force F.

    The value of F can be changed.

    When the welding between block A and ground breaks, block A will

    start pressing block B and when welding of B also breaks, block B will startpressing the vertical wall

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    A B5kg

    F

    1. If F = 20N, with how much force does block A presses the block B

    (a) 10 N

    (b) 20 N

    (c) 30 N

    (d) zero

    2. If F = 50 N, the friction force acting between block B and ground will

    be

    (a) 10 N

    (b) 20 N

    (c) 30 N

    (d) none

    3. The force of friction acting on B varies with the applied force F

    according to the curve :-

    FB FB

    (a) (b)

    F F

    10kg

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    FB FB

    (c) (d)

    F F

    Paragraph

    A body cools in a surrounding of constant temperature 30oC. Its heat

    capacity is 2J/oC. Initial temperature of the body is 40oC. Assume Newtons

    Law of cooling is valid. The body cools at 38

    o

    C in 10 minutes

    1. In further 10 minutes, it will cool from 38oC to ?(a) 36oC

    (b) 36.4oC

    (d) 37oC

    (d) 37.5oC

    2. The temperature of the body in oC denoted by , the variation ofversus time t is best denoted as

    40oC 40oC

    (a) (b) 30oC

    30oC

    t t

    40oC 40oC

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    (c) (d)30oC

    t t

    3. When the body temperature has reached 38oC, it is heated again so

    that it reaches to 40oC in 10 minutes. The total heat required from a

    heater by the body is(a) 3.6J

    (b) 0.364J

    (c) 8J

    (d) 4J

    Paragraph

    Figure shows a conducting rod of negligible resistance that can slide on

    smooth U-shaped rail made of wire of resistance 1 /m. Position of the

    conducting rod at t = 0 is shown. A time t dependent magnetic field B = 2t

    Tesla is switched on at t = 0.

    20cm

    |l = 40 cm|

    1. The current in the loop at t = 0 due to induced emf is

    (a) 0.16A, clockwise

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    (b) 0.08A, clockwise

    (c) 0.08A, anticlockwise

    (d) zero

    2. At t = 0, when the magnetic field is switched on, the conducting rod ismoved to the left at constant speed 5cm/s by some external means.

    The rod moves perpendicular to the rails. At t= 2s, induced emf hasmagnitude(a) 0.12V

    (b) 0.08V(c) 0.04V

    (d) 0.02V

    3. Following situation of the previous question, the magnitude of the

    force required to move the conducting rod at constant speed 5cm/s atthe same instant t = 2s is equal to

    (a) 0.16 N(b) 0.12 N

    (c) 0.08 N

    (d) 0.06 N