AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

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AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability

Transcript of AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

Page 1: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

AP CALCULUS AB

Chapter 3:DerivativesSection 3.2:

Differentiability

Page 2: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

What you’ll learn about How f’(a) Might Fail to Exist Differentiability Implies Local Linearity Derivatives on a Calculator Differentiability Implies Continuity Intermediate Value Theorem for

Derivatives

… and why

Graphs of differentiable functions can be approximated by their tangent lines at points where the derivative exists.

Page 3: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

How f’(a) Might Fail to Exist

A function will not have a derivative at a point ,

where the slopes of the secant lines,

fail to approach a limit as approaches .

The next figures illustrate four different instances w

P a f a

f x f a

x ax a

here this occurs.

For example, a function whose graph is otherwise smooth will fail to

have a derivative at a point where the graph has:

Page 4: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

How f’(a) Might Fail to Exist

1. a corner, where the one-sided derivatives differ;

f x x

Page 5: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

How f’(a) Might Fail to Exist

2

3

2. a cusp, where the slopes of the secant lines approach from one side and

approach - from the other (an extreme case of a corner);

f x x

Page 6: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

How f’(a) Might Fail to Exist

3

3. A vertical tangent, where the slopes of the secant lines approach

either or - from both sides;

f x x

Page 7: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

How f’(a) Might Fail to Exist

4. a discontinuity (which will cause one or both of the one-sided

derivatives to be nonexistent).

1, 0

1, 0

xU x

x

Page 8: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

Example How f’(a) Might Fail to Exist

3

Show that the function is not differentiable at 0.

, 0

4 , 0

x

x xf x

x x

The right-hand derivative is 4.

The left-hand derivative is 0.

The function is not differentiable at 0.x

Page 9: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

How f’(a) Might Fail to ExistMost of the functions we encounter in calculus are differentiable wherever they are defined, which means they will not have corners, cusps, vertical tangent lines or points of discontinuity within their domains. Their graphs will be unbroken and smooth, with a well-defined slope at each point.

Page 10: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

Differentiability Implies Local LinearityA good way to think of differentiable functions is that they are locally linear; that is, a function that is differentiable at a closely resembles its own tangent line very close to a.

In the jargon of graphing calculators, differentiable curves will “straighten out” when we zoom in on them at a point of differentiability.

Page 11: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

Differentiability Implies Local Linearity

Page 12: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

Section 3.2 - Differentiability You try: Find all points in the domain of

f(x) where f is not differentiable:1. f(x) = |x – 3| + 4

2. 2

, 22, 2

xx

f x

x x

Page 13: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

Derivatives on a Calculator

Many graphing utilities can approximate derivatives numerically with good

accuracy at most points of their domains. For small values of ,

the difference quotient

is often a good numerical app

h

f a h f a

h

roximation of .

However, the same value of will usually yield a better approximation if

we use the symmetric difference quotient

2which is what our graphing calculator uses to calculate N

f a

h

f a h f a h

h

DER , the

.

The as a function is denoted by NDER .

The numerical derivatives we compute in this book will use 0.001.

f a

f a

f f x

h

numerical derivative of at a point

numerical derivative of

Page 14: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

Section 3.2 - Differentiability Derivatives on a Calculator:1. On the TI-83, TI-83+ or TI-84

Use Nderiv (expression, x, x-value)Example:

2. On the TI-891. Use d (expression, x, order)| x= x-value

Example:

2. Use Nderiv (expression, x) | x = x-valueExample:

272,,32 Nderiv 3 xxx

27 2|32

2|),33^2(

3

xxxdx

d

xxxxd

27 2|,33^2 Nderiv xxxx

Page 15: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

Example Derivatives on a Calculator 2Find the numerical derivative of the function 3

at the point 2. Use a calculator with 0.001.

f x x

x h

Using a TI-83 Plus we get

Page 16: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

Derivatives on a CalculatorBecause of the method used internally by the calculator, you will sometimes get a derivative value at a nondifferentiable point.

This is a case of where you must be “smarter” than the calculator.

Page 17: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

Section 3.2 - Differentiability You try: Compute each numerical

derivative:1. NDERIV

2. NDERIV

33 , ,1x x

4 33 , , 5x x x

Page 18: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

Differentiability Implies Continuity If has a derivative at , then is continuous at .f x a f x a

The converse of Theorem 1 is false. A continuous functions might have a corner, a cusp or a vertical tangent line, and hence not be differentiable at a given point.

Page 19: AP CALCULUS AB Chapter 3: Derivatives Section 3.2: Differentiability.

Intermediate Value Theorem for DerivativesNot every function can be a derivative.

If and are any two points in an interval on which is

differentiable, then takes on every value between

and .

a b f

f

f a f b

If f is differentiable on the interval (a, b) and a < c < b, then f’(a) < f’(c) < f’(b).