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AP Biology Laws of Probability and Chi Square Probability & Genetics.
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Transcript of AP Biology Laws of Probability and Chi Square Probability & Genetics.
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AP Biology
Laws of Probability and Chi Square
Probability & Genetics
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AP Biology
Probability & Genetics Calculating probability of making a
specific gamete is just like calculating the probability in flipping a coin
probability of tossing heads? 50% probability making a P gamete…
Outcome of 1 toss has no impact on the outcome of the next toss
probability of tossing heads each time? 50% probability making a P gamete each time?
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AP Biology
Rule of Addition Chance that an event can occur
2 or more different ways SUM of the separate probabilities
Use for heterozygous possibilities Two ways to be heterozygous: Pp or pP Key word is “or”.
Ex: Probability of getting 2 or a 6 on the roll of a die. 1/6 + 1/6 = 2/6 = 1/3
Ex: Probability of having offspring with dominant phenotype? PP or Pp or pP ¼+ ¼ + ¼ = ¾
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AP Biology
Rule of multiplication Chance that 2 or more independent
events will occur together probability that 2 coins tossed at the
same time will land heads up probability of pp or PP offspring
Ex: Probability of getting a head and a tail with two different coins. ½ x ½ = 1/4 Key word is “and”
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AP Biology
Calculating
Probability of
Pp x Pp
½ x ½ = ¼ = PP
½ x ½ = ¼ = pp
What about Pp?
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AP Biology
Calculating Dihybrid Probability Rule of multiplication application with
Dihybrid crosses: heterozygous parents — YyRr probability of producing yyrr? probability of producing y gamete = 1/2 probability of producing r gamete = 1/2 probability of producing yr gamete
= 1/2 x 1/2 = 1/4 probability of producing a yyrr offspring
= 1/4 x 1/4 = 1/16
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AP Biology
What is Chi-Squared?
In genetics, you can predict genotypes based on probability (expected results)
Chi-squared is a form of statistical analysis used to compare the actual results (observed) with the expected results
NOTE: 2 is the name of the whole variable – you will never take the square root of it or solve for
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AP Biology
Chi-squared
If the expected and observed (actual) values are the same then the 2 = 0
If the 2 value is 0 or is small then the data fits your hypothesis (the expected values) well.
By calculating the 2 value you determine if there is a statistically significant difference between the expected and actual values.
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AP Biology
Step 1: Calculating 2
First, determine what your expected and observed values are.
Observed (Actual) values: That should be something you get from data– usually no calculations
Expected values: based on probability Suggestion: make a table with the
expected and actual values
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AP Biology
Step 1: Example
Observed (actual) values: Suppose you have 90 tongue rollers and 10 nonrollers
Expected: Suppose the parent genotypes were both Rr using a punnett square, you would expect 75% tongue rollers, 25% nonrollers
This translates to 75 tongue rollers, 25 nonrollers (since the population you are dealing with is 100 individuals)
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AP Biology
Step 1: Example
Table should look like this:
Expected Observed (Actual)
Tongue rollers 75 90
Nonrollers 25 10
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AP Biology
Step 2: Calculating 2
Use the formula to calculated 2 For each different category (genotype
or phenotype calculate
(observed – expected)2 / expected Add up all of these values to determine
2
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AP Biology
Step 2: Calculating 2
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AP Biology
Step 2: Example Using the data from before: Tongue rollers
(90 – 75)2 / 75 = 3 Nonrollers
(10 – 25)2 / 25 = 9 2 = 3 + 9 = 12
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AP Biology
Step 3: Determining Degrees of Freedom
Degrees of freedom = # of categories – 1
Ex. For the example problem, there were two categories (tongue rollers and nonrollers) degrees of freedom = 2 – 1
Degrees of freedom = 1
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AP Biology
Step 4: Critical Value
Using the degrees of freedom, determine the critical value using the provided table
Df = 1 Critical value = 3.84
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AP Biology
Step 5: Conclusion
If 2 > critical value…
there is a statistically significant difference between the actual and expected values.
If 2 < critical value…
there is a NOT statistically significant difference between the actual and expected values.
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AP Biology
Step 5: Example 2 = 12 > 3.84There is a statistically significant
difference between the observed and expected population
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AP Biology
Bozeman Chi-squared test video http://www.youtube.com/watch?v=WXP
BoFDqNVk&edufilter=vBrBKiVMlaMnBrdX3oXR-Q&safe=active
Fill in video questions
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AP Biology
Animal Behavior Chi SquareWet Dry
Observed value 8.9 1.1
Expected value 5 5
Chi Square = Σ (O – E)2 / E
(8.9 – 5)2 / 5 + (1.1-5)2 / 5
15.21 / 5 + 15.21 / 5
30.42/ 5 = 6.084
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AP Biology
2 variable – wet and dry so1 degree of freedom
6.084 is higher than 3.841 so must reject null hypothesis. Something influenced the Pill bugs.
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AP Biology
In 2002 The distribution for Skittles is: Green: 19.7%, Yellow: 19.5%, Orange: 20.2%, Red: 20%, Purple: 20.6%.
Color distribution for M&Ms
Brown15% Yellow12% Orange20% Red 13% Green 16% Blue 24%