Answer to questions1.Applications:MicrophoneThe impedance of each microphone will be listed as a specification. According to the Maximum Power Transfer Theorem, when the load impedance matches the microphone impedance, the power transferred will reach the maximum. However, in most cases, the two impedances dont match each other. Despite of this, the microphone still can be used. If the micros impedance is lower than 600, it is considered as low impedance; when its value is in a range from 600 to 10,000, it is considered as middle impedance; if the value is greater than 10,000, it will be regarded as high impedance.A model of pocket headphone

There are several situations, where the pocket amp could benefit from a higher voltage power supply - when driving high impedance headphones, when the amplifier is being fed from a high gain equalizer or when the listener just wants more volume. With very high impedance headphones (600 ohms or more), the amp may not be able to develop sufficient voltage across the load for maximum power transfer. If the amp is fed from an equalizer or tone control with a high boost, the output of the pocket amp could be driven into clipping.Power consumed in BluetoothThe Bluetooth has low power consumption longevity for battery-powered devices. During data transfer the maximum current drain is 30mA. However during pauses or at lower data rates will be lower.2.The Maximum Power Transfer Theorem: The maximum power will be absorbed by one network from another joined to it at two terminals, when the impedance of the receiving network is varied, if the impedance looking into the two networks at the junction is conjugates of each other. This analysis will use a simple system consisting of a prime-mover and DC Generator to illustrate an application of the Maximum Power Transfer Theorem (MPTT) and the Conjugate Match. Historically, the MPTT has been misunderstood first from the standpoint of understanding all of its implications and second from the standpoint of its effect on the maximum possible efficiency of a system. Consider the possibility that every system have its internal impedance equal to its load impedance. Such a system would be limited to 50% efficiency.

3.When the researcher want to obtain the maximum power output, for instance in an amplifier system we make RLine = RLoad. In this case, the efficiency of the system is sacrificed at the cost of delivering maximum power load.Efficiency = Poutput / Pinput = I2 RLoad / I2 (RLoad + RLine ) =

4.It is because under maximum power condition, the efficiency is reduced to 50% Moreover, electric companies would be half the power it generates under this condition.5.To obtain maximum external power from a source with a finite internal resistance, the resistance of the load must equal the resistance of the source as viewed from its output terminals.6.TRIAL LOAD RESISTNCE E1 (VOLTS) I1 (AMPS) E2 (VOLTS)W1(E1,I1)(WATTS)W2(E2,I1)(WATTS)EFFICIENCY (%)

12001200119.90.089100.110.999.18183.54%

600600120.9.14086.1418.3513.1571.66%

4006001200119.9.19275.3323.7714.9362.81%

300300119.1.22866.2327.9615.5655.65%

2401200300119.7.25559.6031.4215.6549.81%

200600600600118.9.2755433.7615.4045.62%

1716001200600118.9.29549.6536.3515.1641.71%

150300300118.7.31145.4638.0514.5638.27%

1331200300300118.9.32542.4640.2514.3535.65%

120600300300119.7.33839.7741.7513.9133.32%

1093003001200600119.6.34837.2242.6813.3431.26%

100300300300119.3.35634.9743.6912.7829.25%

923003006006001200118.8.36232.8544.4212.3830.63%

863003006006001200119.37031.1745.4511.9626.31%

7.

8.TRIALVOLTAGE DROP

120019.8

60034.76

40044.57

30052.77

24060.1

20064.9

17169.25

15073.24

13376.44

12079.93

10982.38

10084.33

9285.95

8687.83

9.