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ANSWER y + 4 = 2(x 6) Daily Homework Quiz Review 5.3 Write an equation in point-slope form of the line that passes through (6, –4) and has slope 2. 1. Write an equation in point-slope form of the line that passes through (–1, – 6) and (3, 10). 2. ANSWER y + 6 = 4(x + 1) or y –10 = 4(x–3) y y 1 = m(x x 1 ) m = 10− −6 3− −1 = 16 4 =4

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1. Write an equation in point-slope form of the line that passes through (6, – 4) and has slope 2. ANSWER. y + 4 = 2( x – 6). 2. Write an equation in point-slope form of the line that passes through ( –1, –6 ) and ( 3 , 10). y + 6 = 4( x + 1) or y –10 = 4( x –3). ANSWER. - PowerPoint PPT Presentation

Transcript of ANSWER

Page 1: ANSWER

ANSWER y + 4 = 2(x – 6)

Daily Homework Quiz

Review 5.3

Write an equation in point-slope form of the line that passes through (6, –4) and has slope 2.

1.

Write an equation in point-slope form of the line that passes through (–1, –6) and (3, 10).

2.

ANSWER y + 6 = 4(x + 1) or y –10 = 4(x–3)

y – y1 = m(x – x1)

m =10 − −63 − −1

=164

= 4

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Review 5.3

ANSWER

ANSWER

1. (1, 4), (6, –1)

y + 2 = 3(x + 1) or y – 7 = 3(x – 2)

y – 4 = –1(x – 1) or y + 1 = –1(x – 6)

2. (–1, –2), (2, 7)

Write an equation in point-slope form of the line that passes through the given points.

NOW PUT EACH ANSWER IN SLOPE-INTERCEPT FORM!!

y – 4 = – x + 1 or y + 1 = - x + 6

y = – x + 5 or y = - x + 5

+ 4 + 4 - 1 - 1

y + 2 = 3x + 3 or y – 7 = 3x – 6- 2 - 2 + 7 + 7

y = 3x + 1 or y = 3x + 1

m =−1− 46 −1

=−55

= −1

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5.4 Write Linear Equations in Standard Form

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Convert this equation into standard form:

1.)

y =25

x − 3 Multiply everything by 5

5y = 2x −15-2x -2x

Ax + By = C

−2x + 5y = −15

Move over the “x” term

I CAN’T LEAD WITH A NEGATIVE!!!So let’s change the sign of each term.

2x − 5y =15 It’s kind of like moving backwards!

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Convert this equation into standard form:

2.)

y = −x + 5

+ x + x

Ax + By = C

Move over the “x” term

x + y = 5

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Convert this equation into standard form:

3.)

y =−12

x + 7 Multiply everything by 2

2y = −1x +14+ 1x + 1x

Ax + By = C

Move over the “x” term

x + 2y =14

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Convert this equation into standard form:

4.)

y =23

x + 4 Multiply everything by 3

3y = 2x +12-2x -2x

Ax + By = C

−2x + 3y =12

Move over the “x” term

I CAN’T LEAD WITH A NEGATIVE!!!So let’s change the sign of each term.

2x − 3y = −12

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Write an equation of the line in STANDARD FORM using the information given.

5.) m = 2 and (3,-2)Start with Point-Slope Form

y − y1 = m(x − x1)

y + 2 = 2(x − 3)Now put into slope-intercept form

y + 2 = 2x − 6-2 -2

y = 2x − 8-2x -2x

−2x + 3y =12

Now put into Standard form

No LEADING NEGATIVES!Change all the signs of each term

2x − 3y = −12

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Write an equation of the line in STANDARD FORM using the information given.

5.) m = and (4,-5)Start with Point-Slope Form

y − y1 = m(x − x1)

y + 5 =32

(x − 4)Now put into slope-intercept form

y + 5 =32

x − 6- 5 - 5

y =32

x −11- 3x - 3x

−3x + 2y = −22

Now put into Standard form

No LEADING NEGATIVES!Change all the signs of each term

3x − 2y = 22

32

Multiply everything by 2

2y = 3x − 22

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Every one get communicators with a blank side!!!

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Write an equation of the line in STANDARD FORM using the information given.

5.) (-4,4) and (0,3)Start with Point-Slope Form

y − y1 = m(x − x1)

y − 4 =−14

(x + 4)Now put into slope-intercept form

y − 4 =−14

x −1+ 4 + 4

y =−14

x + 3+1x +1x

x + 4y =12

Now put into Standard form

No LEADING NEGATIVES!Change all the signs of each term

Multiply everything by 4

4y = −1x +12

m =3 − 4

0 − −4=

−14

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Write the point-slope form of the line that passes through (4,3) and (1,2)

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Write the slope-intercept form of the line that passes through (4,5) and (1,-1)

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Write an equation of the line in STANDARD FORM using the information given.

5.) m = -2 and (-4,3)Start with Point-Slope Form

y − y1 = m(x − x1)

y − 3 = −2(x + 4)Now put into slope-intercept form

y − 3 = −2x − 8+ 3 + 3

y = −2x − 5+ 2x + 2x

2x + y = −5

Now put into Standard form

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Write an equation of the line in STANDARD FORM using the information given.

5.) m = -3 and (3,-5)Start with Point-Slope Form

y − y1 = m(x − x1)

y + 5 =32

(x − 4)Now put into slope-intercept form

y + 5 =32

x − 6- 5 - 5

y =32

x −11- 3x - 3x

−3x + 2y = −22

Now put into Standard form

No LEADING NEGATIVES!Change all the signs of each term

3x − 2y = 22

Multiply everything by 2

2y = 3x − 22

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Write an equation of the line in STANDARD FORM using the information given.

5.) (4,0) and (0,3)Start with Point-Slope Form

y − y1 = m(x − x1)

y − 0 =−34

(x − 4)Now put into slope-intercept form

y =−34

x + 3

+ 3x + 3x

Now put into Standard form

3x + 4 y =12

Multiply everything by 4

4y = −3x +12

m =3 − 00 − 4

=3

−4=

−34

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Write an equation of the line in STANDARD FORM using the information given.

5.) (2,0) and (0,5)Start with Point-Slope Form

y − y1 = m(x − x1)

y − 0 =−52

(x − 2)Now put into slope-intercept form

y =−52

x + 5

+ 5x + 5x

Now put into Standard form

5x + 2y =10

Multiply everything by 2

2y = −5x +10

m =5 − 00 − 2

=5−2

=−52

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SOLUTION

y – y1 = m(x – x1)

Calculate the slope.STEP 1

EXAMPLE 2 Write an equation from a graph

–3m = 1 – (–2)1 – 2 =

3–1 =

Write an equation in point-slope form. Use (1, 1).

Write point-slope form.

y – 1 = –3(x – 1) Substitute 1 for y1, 3 for m and 1 for x1.

Write an equation in standard form of the line shown.

STEP 2

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Rewrite the equation in standard form.

EXAMPLE 2 Write an equation from a graph

3x + y = 4 Simplify. Collect variable terms on one side, constants on the other.

STEP 3

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EXAMPLE 2 Write an equation from a graphGUIDED PRACTICE for Examples 1 and 2

Write an equation in standard form of the line through (3, –1) and (2, –3).

2.

–2x + y = –7ANSWER

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Simplify.

Find the value of A. Substitute the coordinates of the given point for x and y in the equation. Solve for A.

STEP 1

SOLUTION

EXAMPLE 4

Find the missing coefficient in the equation of the line shown. Write the completed equation.

Ax + 3y = 2A(–1) + 3(0) = 2

–A = 2A = –2

Write equation.Substitute –1 for x and 0 for y.

Divide by –1.

EXAMPLE 3EXAMPLE 4Complete an equation in standard form

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EXAMPLE 4Complete an equation in standard form

Complete the equation.

–2x + 3y = 2 Substitute –2 for A.

STEP 2

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Write equations of the horizontal and vertical lines that pass through the given point.

GUIDED PRACTICE for Examples 3 and 4

3. (–8, –9)

y = –9, x = –8ANSWER

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GUIDED PRACTICE for Examples 3 and 4

4. (13, –5)

y = –5, x = 13ANSWER

Write equations of the horizontal and vertical lines that pass through the given point.

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EXAMPLE 4Complete an equation in standard form

Find the missing coefficient in the equation of the line that passes through the given point. Write the completed equation.

EXAMPLE 3 Write an equation of a lineGUIDED PRACTICE for Examples 3 and 4

5. –4x + By = 7, (–1, 1)

ANSWER 3; –4x + 3y = 7

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To write another equivalent equation, multiply each side by 0.5.

4x – 12y = 8

To write one equivalent equation, multiply each side by 2.

SOLUTION

Write two equations in standard form that are equivalent to 2x – 6y = 4.

EXAMPLE 1 Write equivalent equations in standard form

x – 3y = 2

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EXAMPLE 1GUIDED PRACTICE for Examples 1 and 2

Write two equations in standard form that are equivalent to x – y = 3.

1.

2x – 2y = 6, 3x – 3y = 9ANSWER

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Substitute 0 for s.8(0) + 12l = 144

l = 12

Substitute 0 for l.

s = 188s + 12(0) = 144

ANSWERThe equation 8s + 12l = 144 models the possible combinations.

b. Find the intercepts of the graph.

EXAMPLE 5 Solve a multi-step problem

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EXAMPLE 4Complete an equation in standard formEXAMPLE 3 Write an equation of a lineGUIDED PRACTICE for Examples 3 and 4

6. Ax + y = –3, (2, 11)

Find the missing coefficient in the equation of the line that passes through the given point. Write the completed equation.

ANSWER –7; –7x +y = –3