Techniques For Answering SPM FIZIK SECTION A,B &C

TECHNIQUES OF ANSWERING STRUCTURED QUESTION SECTION AAble to interprete diagram,graph,table and photograph to relate to scientific concepts or principles. Understand the keyword like name,state, compare,calculate,explain,sketch/draw the graph, what is meant by etc.Answer should be short and concise.For quantitative problem, calclulating step like correct substitution must be clearly shown and give the final answer with correct unit. Pay attention to the marks allocated. The marks indicate the number of points required in your answer.

SPM FIZIK 2006 Q11(a)(i) Name the instrument Q correctly.(1) Voltmeter

1(a)(ii) State the function of R correctly.(1) To control the flow of current in the circuit.

1(b)(i) State which ammeter is more sensitive correctly.(1) Ammeter Y

1(b)(ii) State the reason correctly.(1) The smallest division of the scale in Ammeter X is 0.1A whereas the smallest division of the scale in Ammeter Y is 0.25A

SPM FIZIK 2007 Q66(a)(i) Underline the correct answer.(1) Parallel

(a)(ii) Give the correct state of the bulb.(1) Still light up with normal brightness.

6(b)(i) State the meaning of 240V, 60W correctly.(1) The working voltage of the bulb is 240V. It is light up with normal power of 60W when connected to its working voltage. (b)(ii) Give correct substitution and correct answer with unit.(1) P = VI 60 = 240I I = 60/240 = 0.25 A

6(b)(iii)Calculate resistance of one bulb correctly.(1) R = V2/P = 2402/60 = 960 .

Correct substitute for finding the total resistance.(1) 1/RT= 1/960 +1/960 +1/960

State the total resistance correctly.(1) RT= 320

6(b)(iv)State the correct connection.(1)

The bulbs are connected in series.

SPM FIZIK 2008 Q33(a) State the correct diagram.(1) Diagram 3.2 (b) Draw the electrical circuit for Diagram 3.1 correctly.(2)

3(c)(i)Substitute correctly.(1)R = 1 + (1/10 + 1/10)-1

State the correct answer with unit.(1) R= 1 + 5 = 6

3(c)(ii)Calclulate the current correctly.(1)I = V/R = 12/6 = 2A

3(c)(iii) State what happen to the ammeter correctly.(1) The reading of the ammeter deceases.

SPM FIZIK 2011 Q66(a) Underline the correct answer.(1) parallel6(b)(i) Compare the number of bulb correctly.(1) Diagram 6.1 has more number of bulbs than in Diagram 6.2.

6(b)(ii) Compare the ammeter reading correctly.(1) Ammeter reading in Diagram 6.1 is higher than in Diagram 6.2

6(b)(iii) State the relationship correctly.(1) The bigger the number of bulbs, the higher the ammeter reading.

6(c) State the reason correctly.(1) The total current flows in the circuit Diagram 6.1 is higher.

6(d) Make the correct deduction.(1) The bigger the number of bulbs, the higher the current.

6(e)(i) State the bulb correctly.(1) Bulb P and Q

(e)(ii) State the correct reason.(1) The voltage/p.d across the bulb P and Q is higher than across R and S which are connected in series.

Technique For Answering Section B & CUnderstand keywords like state,why,relate,explain,calculate,draw, compare,modification etc.Underline important information.Identify information given directly or indirectly.Plan your answer by jotting down keywords and concepts in point form or via mapping.Need to give your answer in detail. Encourage to use diagram,equation,graph,table and other suitable methods to explain your answer.Use simple and short points. Advisable to use a new line for each new point.Pay attention to the marks allocated. The marks indicate the number of points required in your answer.

Type of Question For Section BTest your ability to conceptualise a physical concept from two particular situations given in the question.Candidates are asked to give a series of comparison between the two situations(normally in diagrams) before deduce the relationship between the physical quantities involved.Test ability to solve qualitative problems in a given situation by applying the appropriate physical concepts.

Type Of Question In Section C

Test abilily on applying physical concept to solve quantitative problems. Test ability to make logical decision based on the physical concepts.

SPM2009 SECTION C Q12

12(a) Define potential difference correctly. ( 1 )

Work done in carrrying a coulomb of charge between two point in a closed electrical circuit.

12(b)(i)State the correct relationship between V and I.(1) V increases exponentially with I.State the correct conclusion about the resistance of the lamp.(1) Resistance increases with the current.Give correct reason.(1) Gradient of the graph increases.//Temperature of the lamp increases.//Non-ohmic conductor.

Note: Give the number of points according to the marks allocated for the question.

12(b)(ii)State the dissipation of energy correctly when current increases. ( 1 )

Energy dissipated in the filament lamp increases when the current flowing is increased

12(c)Give the suitable design and characterisitcs of the filament lamp and correct reason.State the correct type of material and reason.(2) Tungsten wire.(1) Have high melting point, not easily broken under high temperature and more durable.(1)

12(c)State the correct thickness of the wire and reason.(2) Thin tungsen wire is preferred.(1) More resistance and thus more efficient in converting electrcal energy into heat and light energy.(1)

12(c)State the correct shape of the wire and reason.(2) Coiled wire.(1) Can place longer wire into small space inside the bulb. Thus the resistance of the wire increases and more heat and light energy can be produced.(1)

12(c)State the correct nitrogen gas pressure in the bulb and reason.(2) Nitrogen gas at low pressure.(1) Prevent bulb from bursting//explode.(1)

The answer can be in table form

SPM FIZIK 2010 Q12

Q.12(a)(i) ( i ) State the meaning of elelctric field correctly.(1)

A region of space where another electrical charged object experiences electrostatic force.

Q12(a)(ii)State the observation of the candle flame correctly.(1)-The candle flame spreads out in two opposite direction with the major part of the flame spreads towards the negative plate.(1)

Q12(a)(ii)Explain how the spread of the flame occurs correctly.(3)Heat energy of the candle flame causes ionization of the air molecules surrounding the it.(1)Positive charged ions which consist of heavier air molecules losing an electron are accelerated towards the negative plate.(1)Negative ions which consist of lighter electrons are accelerated towards the positive plate.(1) Note : Answer can be in point form

Q12(b)(i)State the type of connection of the cells and reason correctly.(2)

The cells are connected in series.(1) To produce enough electromotive force of 4.5 V across the circuit.(1)

Q12(b)(ii)State the connection of the terminals of the cells and reason correctly.(2) The negative terminal of the cell is connected to the positive terminal of the next cell.(1) To ensure correct connection of the cells in series so that current can flow through.(1)

129b)(iii)State the correct connection between the resistor and the bulb and the reason.(2) The resistor and the bulbs are in series.(1) The resistor and the bulbs share the potential difference provided by the cell. It ensures that the potential difference across the bulb is 2 V so that they can be lit up with normal brightness.(1)

Q.12(b)(iv)State the type of connection of the bulbs and the reason correctly.(2)

The bulbs are connected in parallel.(1) To ensure that the potential difference across each bulb is 2 V so that they can be lit up with normal brightness.(1)

Q12(b)Choose the correct circuit.(1) Circuit XState all the reasosns for your choice.(1) -Cells are connected in series. -Negative terminal of the cell is connected to the positive terminal of the next cell. -The resistor is connected in series with the bulbs. (Demonstrate the calculation to show the p.d across the bulb is 2 V ) - The bulbs are connected in parallel.

Q12(c)(i).Show the correct substitution.(1) E = I(R + r) 2 = I(5 + 1) Answer with correct unit.(1) I = 2/6 = 0.333A

12(c)(ii)Show the correct substitution to determint the effective resistance of the circuit.(1) 1/R = (1/5 + ) R = 3.5294Show the correct substitution to determine the current,I flows through the ammeter.(1) 2 =( 1 + 3.5294)IAnswer with correct unit.(1) I = 0.4416 A