Analysis of Phasor Diagram

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Gandhinagar Institute Of Technology opic : Analysis of Phasor Diagram Guided By : nch : Batch : MR. RAHISH SIR Active Learning Assignment Electrical F1 Elements Of Electrical Engineering (2110005)

Transcript of Analysis of Phasor Diagram

Page 1: Analysis of Phasor Diagram

Gandhinagar Institute Of Technology

Topic : Analysis of Phasor Diagram Guided By :

Branch : Batch :

MR. RAHISH SIR

Active Learning Assignment

Electrical F1

Elements Of Electrical Engineering (2110005)

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Name ENROLLMENT NO. Abhishek Chokshi 140120109005 Raj Shah Adnan Vohra

PREPARED BY:-

140120109054140120109063

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Series R-C circuit

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Circuit contain a pure resistance R ohms connected in series with pure capacitor C farads.

It is known as R-C circuit.

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Voltage across resistance V=IR.

Voltage across capacitor V=IC.

Vr remain in same phase.Vc lag behind current

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6

Kirchhoff’s voltage law:

Or;

0 CR VVEV

CR VVE

R-C

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in such circuits the voltage across each of the components is the same and it is the currents that are of interest

Phasor analysis of parallel circuits

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Phasor analysis of an RC circuit

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Series R-L circuit

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Circuit contains a pure resistance R ohms connected in series with a pure inductance L henry .

It known as R-L circuit

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Phasor analysis of an RL circuit

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Voltage across resistor :V=IR.

Voltage across inductor:V=IL.

Vr is in same phase.Vl leads by 90’.

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From the phasor diagram it is clear that that the magnitude of the voltage across the arrangement V is

where Z is the magnitude of the impedance, so Z =|Z|

IZXRI

IXIR

VVV

L

L

LR

22

22

22

)()(

22LXRZ

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In this case ,when only inductor current leads the voltage by 90’.

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But when we combine Resistance and inductance the phase angle is between 0’ to 90’.

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Phasor diagram:

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Series R-L-C circuit

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Circuit which contains a pure resistance of R ohms.

A pure inductor of L henry.A pure capacitor of capacitance C farads.

It is known as R-L-C series circuit.

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Voltage drop across resistance:Vr=IR in phase with current I.

Voltage drop across inductance:VL=IXL leadin by 90 ‘

Voltage drop across capacitance:Vc=Ixc lagging behind by 90’.

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Phasor analysis of an RLC circuit

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Three possible cases: (1)VL >VC that is XL>XC:

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According to case(1):

The phase angle is positive .

Behave as R-L circuit.Current lag behind voltage Power factor is lagging

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According to case(2):Phase angle is negative.Behave as a R-C circuit.Current leads the voltage.Power factor is leading.

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According to case(3):Phase angle is zero.Circuit is purely resistive circuit.

Current is in phase with applied voltage.

Power factor is unity.

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Thank You