Algebra Unit 2

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Algebra Unit 2

Transcript of Algebra Unit 2

Page 1: Algebra Unit 2

Algebra Unit 2

Page 2: Algebra Unit 2

Solve the following equations.

x + 0 = 5 1x = 6

x = 5 x = 6Are numbers allowed to disappear? Yes Only which two numbers can disappear? 0 and 1

is the same as is the same as

Tuesday Oct 13, 2020 Activator

Page #3 Lesson 2.1

Page 3: Algebra Unit 2

Today’s Objective Unit 2Lesson 1

Students will be able to solve one step equations.

Page 4: Algebra Unit 2

Solve the one step equation.

y + 7 = -4 What is happening to the variable?

What is the identity for subtraction? 0

Add 7

Subtract 7

Solve means to get the variable by itself.

-7 -7y + 0 = -11

y = -11

Today’s New Vocab (1 of 4)

Solve means do opposites

https://www.youtube.com/watch?v=NybHckSEQBI 3:30

Page 5: Algebra Unit 2

Today’s New Vocab (2 of 4)Solve the one step equation.

w - 5 = 8 What is happening to the variable?

Solve means do opposites

Add 5

Subtract 5

What is the identity for addition? 0

+5 +5w + 0 = 13

w = 13

Page 6: Algebra Unit 2

Today’s New Vocab (3 of 4)Solve the one step equation.

-80 = 4h What is happening to the variable?

What is the identity for division? 1

Multiply 4

Divide 4

÷ 4 ÷ 4-20 = 1h-20 = h

Solve means do opposites

Page 7: Algebra Unit 2

Today’s New Vocab (4 of 4)Solve the one step equation.

-15 = 𝑘

−5

What is happening to the variable?

Multiply -5

Divide -5

What is the identity for multiplication? 1

(-5) (-5)+75 = 1k+75 = k

Solve means do opposites

Page 8: Algebra Unit 2

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Solve for x.𝑥

2= 8

Same answer or different answers? Different Why?

(2) (2)

1x = 16 x = 16

What number disappears? 1

Why? We multiplied

or divided.

2x = 8÷ 2 ÷ 2

1x = 4x = 4

Tuesday Oct 13, 2020 WP Page #2 Lesson 2.1

Page 9: Algebra Unit 2

Solve 𝑥

−2= -4 Solve – 2 + x = -10

Same answer or different answers? Different

(-2) (-2) +2 +2

1x = 8

x = 8

0 + x = -8

x = -8

Tuesday Oct 13, 2020 Exit Ticket

Page 10: Algebra Unit 2
Page 11: Algebra Unit 2

.

y - 5 = -11 -5 + y = -11

Same answer or different answers? Same Why?

Solve for y.What number disappears? 0

Why? identity of

addition

+5 +5 y+0 = -6

Y = -6

+5 +5 0 + y = -6

y = -6

Thursday Oct 15, 2020 Activator Page #7 Lesson 2.2

Page 12: Algebra Unit 2

Today’s Objective

Students will be able to solve two step equations.

Lesson 2.2

Page 13: Algebra Unit 2

Solve 𝑥

2= -4 Solve 2x = -4

(2) (2) 1x = -8

x = -8

Today’s New Vocab (1 of 4)

÷ 2 ÷ 2

1x = −2x = −2

Equal sign in the question, always equal sign in the answer.

Solve means to do the opposite.

Page 14: Algebra Unit 2

Today’s New Vocab (2 of 4)Solve the two step equation.

-5x + 4 = -6 What is happening to x? Multiplied by -5Then, add 4

Do the opposite backwards

Subtract 4Divide by -5

-5x = -10

x = 2÷−5 ÷ −5

-4 -4

Page 15: Algebra Unit 2

Today’s New Vocab (3 of 4)Solve the two-step equation. 𝑥

−3- 5 = 7

What is happening to x? Divided by -3Then, subtract 5

Do the opposite backwards

Add 5multiply by -3

𝑥

−3= 12

x = -36

+5 +5

(-3) (-3)

Page 16: Algebra Unit 2

Today’s New Vocab (4 of 4)Solve the two step equation. -12 =

3𝐴

−4 What is happening to x? Multiplied by 3Then, Divided by -4

Do the opposite backwards

Multiply by -4Divide by 3

(-4) (-4)

+48 = 3A

16 = A

÷ 3 ÷ 3

Page 17: Algebra Unit 2

Thursday Oct 15, 2020

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2x - 6 + 1 = 19

Can anything be done to only one side of the equation? YES Why?

2x - 5 = 19

One side is called an expression.

Distribute

Combine Like Terms

Page #8 Lesson 2.2

Page 18: Algebra Unit 2

Thursday Oct 15, 2020 Exit Ticket

.2x - 5 = 19Solve for x.

2x - 5 = 19+5 +52x = 24

x = 12

÷ 2 ÷ 2

2(12) - 5 = 1924 - 5 = 19

19 = 19Yes, the last equation is TRUE.

SubstitutionCheck your work. How?

Doesx = 12?

Page 19: Algebra Unit 2
Page 20: Algebra Unit 2

Monday Oct 19, 2020 Activator Solve the left equation.

3x + 4x = 21 4x = 3x + 7

The x’s are on different sides of the equation =.

7x = 21

x = 3

1x = 0 + 7x = 7

-3x -3x

÷ 7 ÷ 7

Why can’t the x’s be added on the right equation?

Page #11 Lesson 2.3

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Today’s Objective

Students will be able to solve equations with variables on both sides.

Lesson 2.3

Page 22: Algebra Unit 2

Today’s New Vocab (1 of 4)Write an equation.

Two times a number added to twelve is the same as

Negative five times a number subtracted by nine

Let x = an unknown

number 2x + 12 = -5x - 9

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Today’s New Vocab (2 of 4)

How do you get variables to the same side? Add or Subtract

2x + 12 = -5x - 9 2x + 12 = -5x - 9 -2x -2x +5x +5x

12 = -7x - 9 7x + 12 = - 9 If you were to solve both equations, would you get the same answer?

Do the first step of the equation.

Yes Why?

Page 24: Algebra Unit 2

Today’s New Vocab (3 of 4)Finish solving.

What’s happening?(7) and + 12

Do the oppositebackwards.

-12 and ÷ 7

7x + 12 = - 9

7x = - 21

x = - 3

-12 -12

÷ 7 ÷ 7

Page 25: Algebra Unit 2

Today’s New Vocab (4 of 4)Is x = -3 a solution to this equation? Yes

Because, the last equation is true.

Substitute

Distribute

Combine Like Terms

2x + 12 = -5x - 9 2(-3) + 12 = -5(-3) - 9

-6 + 12 = 15 - 9 6 = 6

Page 26: Algebra Unit 2

Monday Oct 19, 2020 Work Period

.10x – 35 = 15x - 10-10x - 10x

– 35 = 5x - 10+10 + 10– 25 = 5x ÷ 5 ÷ 5−5 = 𝑥

Solve thisequation.

Page # 12Lesson 2.3

Page 27: Algebra Unit 2

Monday Oct 19, 2020 Exit Ticket

.

This candy store sells one pound bags of candy. If the one pound price is $8, what is the cost per ounce, x? Write and solve an equation.

Cost per ounce is $0.50

How many ounces are in a pound? 16$8 = 16x

$0.50 = x

÷ 16 ÷ 16

Total Cost ounces times cost

Let x = cost per ounce

Page 28: Algebra Unit 2
Page 29: Algebra Unit 2

Wednesday Oct 21, 2020 Activator Solve the equation and inequality.

2x – 7 > 1 2x – 7 = 1

What’s happening?(2) and - 7

Do the opposite.+7 and ÷ 2

Did you solve the problem in a similar way? Yes

+7 +7 +7 +72x = 8

x = 4

2x > 8 ÷ 2 ÷ 2 ÷ 2 ÷ 2

x > 4

Page #15 Lesson 2.4

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Today’s Objective

Students will be able to solve and graph inequalities in one variable.

Lesson 2.4

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Write an inequality for the graphs. 𝑥 ≥ −2

𝑥 > −2 𝑥 < −2

𝑥 ≤ −2

Today’s New Vocab (1 of 4)https://www.youtube.com/watch?v=W87ymSALLiM 0:30-2:30

Page 32: Algebra Unit 2

Today’s New Vocab (2 of 4)Solve and graph the inequality.

-9x ≥ 18 ÷ -9 ÷ -9

x ≤ −2

Flip the inequality

when you multiply or divide by a negative

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Today’s New Vocab (3 of 4)Solve and graph the inequality.

𝑥

−3< 2

(−3) (−3)x > −6

Flip the inequality when you multiply or divide by a negative

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Today’s New Vocab (4 of 4)

x + 2 < -3Graph the inequality.

Open circle Closed circle

Shade LeftShade Right

x < -5-2 -2

Did we flip the inequality? No

Graph the inequality.

Page 35: Algebra Unit 2

Wednesday Oct 21, 2020 WP

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Solve and Graphthe inequality.

3x – 5 < -2x + 15+2x +2x 5x – 5 < +15

+5 +5 5x < 20

x < 4÷5 ÷5

https://www.youtube.com/watch?v=SHD6sSBePZ4 0-2:30

Saving on fuel can help…(1) A person’s budget(2) The environment

Page #16Lesson 2.4

Page 36: Algebra Unit 2

.-5x - 4 = -14Solve the equation.

-5x - 4 > -14+4 +4

-5x = -10

x = 2

÷−5 ÷ −5

Wednesday Oct 21, 2020 Exit Ticket

+4 +4-5x > -10

x < 2÷−5 ÷ −5

Remember to FLIP the inequality when you multiply or divide by a negative

Solve the inequality.

Page 37: Algebra Unit 2
Page 38: Algebra Unit 2

Tuesday Oct 27, 2020 Activator

𝑥

−3+ 9 < -6

Solve the inequality.

Explain the answer in words.

𝑥

−3< -15

X > 45

-9 -9

(-3) (-3) Is 10 a solution? No, 10 is not > 45.

Page #19Lesson 2.5

Flip the inequality when you multiply or divide by a negative

Page 39: Algebra Unit 2

Today’s Objective

Students will be able to substitute and solve word problem equations.

Lesson 2.5

Page 40: Algebra Unit 2

Today’s New Vocab (1 of 4)Write the inequality. Then, Substitute.

Let x = an unknown number

Y ≥ 2x + 300 To use a variable

https://www.youtube.com/watch?v=3fYD_3V6MWUVideo: Y=MX+B Real-Life Equations 2:20

Sarah is paid $300 per week and $2 per eye liner that she sells. If she sells 350 eye liners, can she pay her $1000 in bills? YES

Y = 𝑚x + b

Y ≥ 2(350) + 300 Y ≥ 700 + 300

Page 41: Algebra Unit 2

Today’s New Vocab (2 of 4)

Tony is 2 more than triple Andrea’s age. Tony is 6 less than four times Andrea’s age. How old is Andrea?

Write the two equations.

Let T = Tony’s age Let A = Andrea’s age

Let StatementT = 2 + 3A

and T = 4A – 6

Page 42: Algebra Unit 2

Today’s New Vocab (3 of 4)T = 2 + 3A T = 4A – 6

Solve the two equations.

2 + 3A = 4A – 6

2 = 1A – 6

8 = 1A What’s happening?

(1) and -6 Do the opposite.

+6 and ÷ 1

-3A -3A

+6 + 6

÷ 1 ÷ 18 = A

If two things are equal to the same thing, then they are equal.

Page 43: Algebra Unit 2

Today’s New Vocab (4 of 4)

T = 2 + 3A T = 4A – 6 How old is Tony? If Andrea is 8.

T = 2 + 3(8) T = 4(8) - 6

T = 2 + 24T = 26

T = 32 - 6T = 26

Tony is 26 years old.

Page 44: Algebra Unit 2

Tuesday Oct 27, 2020 Work Period

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Songs can be purchased on iTunes for $0.99. Sandy

figured she would be charged $49.50 for 50 songs.

Is she correct? Let s = the number of songs downloaded.

Let p = the total price

p = $0.99s p = $0.99(50) p = $49.50

Yes, she is correct.

Page #20Lesson 2.5

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Tuesday Oct 27, 2020 Exit Ticket

.

A Sprint charges $40.00 a month for up to 1 gigabyte of data.

The cost of additional data is $0.02 per megabyte.

d = the number of additional megabytes used and

C = the total charges at the end of the month,

Write the linear equation for user's monthly bill.

What would be the cost of 1000 megabytes (1GB) extra?

C = $0.02d + $40C = $0.02(1000) + $40C = $20 + $40

C = $60

Page 46: Algebra Unit 2
Page 47: Algebra Unit 2

Thursday Oct 29, 2020 Activator Solve the both equations for x.

x – 8 = -24 x – y = -z

Do you solve the problems the same way? Yes

x = -24 + 8 x = -16

+8 +8x = -z + y x = -z + y

+y +y

Can –z+y be combined ? No Why? Not like terms

Page #23Lesson 2.6

Page 48: Algebra Unit 2

Today’s Objective

Students will be able to solve literal equations.

Lesson 2.6

Page 49: Algebra Unit 2

Today’s New Vocab (1 of 4)Solve for x in terms of C.

6x = 12C What’s happening to x? (6)

Do the opposite to x. ÷ 6

÷ 6 ÷ 6

x = 2c

Can other variables be in the answer? YES https://www.youtube.com/watch?v=-Y9y3T0GO7E

Video 2:45 seconds.

Page 50: Algebra Unit 2

Today’s New Vocab (2 of 4)Solve for x in terms of B and C.

6x – 18B = 12C+ 18B + 18B

6x = 12C + 18B

What’s happening to x?(6) and -18B

Do the opposite to x.+18B and ÷ 6÷ 6 ÷ 6

x = 2C + 3B

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Today’s New Vocab (3 of 4)

Solve for x interms of D and R.

𝐷 =𝑥 − 𝑅

2

What’s happening to x?−𝑅 and ÷ 2

Do the opposite to x.(2) and +𝑅

(2) (2)

2𝐷 = 𝑥 − 𝑅

+𝑅 +𝑅

2D+R = x

https://www.youtube.com/watch?v=ZQQ7wrEzUr8 14:53-16:20

Page 52: Algebra Unit 2

Today’s New Vocab (4 of 4)Rx – C = 6 Solve for x in

terms of R and C. What’s happening to x?(𝑅) and −𝐶

Do the opposite to x.+C and ÷ 𝑅

+ C + CRx = 6 + C

÷ 𝑅 ÷ 𝑅

x = 6+𝐶

𝑅

Page 53: Algebra Unit 2

Thursday Oct 29, 2020 Work Period

.

Evaluate (substitute)and solve for x in terms

of A = 2 and B = 6.

𝐴𝑋

𝐵= 5

2𝑋

6= 5

2x = 30

x = 15

(6) (6)

÷ 2 ÷ 2Page #24Lesson 2.6

Page 54: Algebra Unit 2

Thursday Oct 29, 2020 Exit Ticket

.

Solve for x interms of A and B.

𝐴𝑋

𝐵= 5

(B) (B) AX = 5𝐵

X = 5𝐵

𝐴

÷ 𝐴 ÷ 𝐴

What’s happening to x?(𝐴) and ÷ 𝐵

Do the opposite to x.(B) and ÷ 𝐴

Page 55: Algebra Unit 2
Page 56: Algebra Unit 2

Thursday Nov 5, 2020 Activator

#7

The last equation is TRUE (correct/yes).

Page 57: Algebra Unit 2

Today’s Objective

Students will be able to review all objectives from Unit #2.

Page 58: Algebra Unit 2

Today’s New Vocab (1 of 4)#10

Page 59: Algebra Unit 2

Today’s New Vocab (2 of 4)

#12

Page 60: Algebra Unit 2

Today’s New Vocab (3 of 4)

#13

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Today’s New Vocab (4 of 4)

Open circle Closed circle

Shade LeftShade Right

Did we flip the inequality? No

Graph the inequality.

x ≤ 4

#14

Page 62: Algebra Unit 2

Thursday Nov 5, 2020 Exit ticket Make the inequalities true when x = -2.

X < 0 X > -100

There are lots of correct answers on this question.

(-2) < 0 (-2) > -100

Yes, True Yes, True

Page 63: Algebra Unit 2
Page 64: Algebra Unit 2

Monday Nov 9, 2020 Test #2Test 2 requirements #1: Send Mr. V all of your Classwork 2.1-2.6#2: Did you do your Boom Cards for Unit 2?#3: Do Test 2: Submit answers with Google Forms.

Test #2 can be found here (after scrolling down). https://mrvanscoyk.weebly.com/algebra.html