Algebra II Unit 1 Lesson 2, 3 & 5 Lesson 2 : F 502. Find the next term in a sequence described...
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Transcript of Algebra II Unit 1 Lesson 2, 3 & 5 Lesson 2 : F 502. Find the next term in a sequence described...
![Page 1: Algebra II Unit 1 Lesson 2, 3 & 5 Lesson 2 : F 502. Find the next term in a sequence described recursively. Lesson 3 : F 603. Find a recursive expression.](https://reader035.fdocuments.net/reader035/viewer/2022062803/56649f155503460f94c2b04c/html5/thumbnails/1.jpg)
Algebra II Unit 1 Lesson 2, 3 & 5
Lesson 2: F 502. Find the next term in a sequence described recursively.
Lesson 3: F 603. Find a recursive expression for the general term in a sequence described recursively.
Lesson 5: Exhibit knowledge of geometric sequences.
Lesson 4: Solve complex arithmetic problems involving percent of increase /decrease or requiring integration of several concepts
(i.e. using several ratios, comparing percentages or averages).
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Do Now:
Identify each sequence as arithmetic, geometric or neither.
a.14, 7, 3.5, 1.75,…
b.47, 41, 35, 29,…
c.1, 1, 2, 3, 5, 8,…d.The non-horizontal cards
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According to the US EPA, each American produced an average of 978 lb of trash in 1960.This increased to 1336 lb in 1980. By 2000, trash production had risen to 1646 lb/yr per person. How would you find the total amount of trash a person produced in a lifetime?
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Arithmetic Series
Key Concepts:
We are learning about mathematical series and the summation notation used to represent them.
Write recursive and explicit formulas for the terms of the series and find partial sums of the series.
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Vocabulary
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Summation SymbolWhen we don’t want to write out a whole bunch of numbers in the series, the summation symbol is used when writing a series. The limits are the greatest and least values of n.
Summation symbol
Upper Limit (greatest value of n)
Lower Limit (least value of n)
Explicit function for the sequence
So, the way this works is plug in n=1 to the equation and continue through n=3.
(5*1 + 1) + (5*2 +1) + (5*3 + 1) = 33
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Understanding Sigma Notation
Evaluate the following expressions
4
1
3n
n
1
2
)14(p
p
5
1
2 )2(k
k
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What did Gauss do?
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ExamplesEx. 1.) Find the sum of the first 50 multiples of 6:
Ex.2.) Find the sum of the first 75 even numbers starting with 2.
50,...18,12,6 u
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Find the indicated values
1.
2. if
3. if
18
4
16k
k
9S 65 nun
18u 43 nun
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The concert hall in the picture below has 59 seats in Row 1, 63 seats in Row 2, 67 seats in Row 3, and so on.
How many seats are there in all 35 rows of the concert hall?
Suppose that Seat 1 is at the left end of Row 1 and that Seat 60 is at the left end of Row 2. Describe the location of Seat 970.
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Practice
Page: 633 #(1 – 5)
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Sum of a Finite Arithmetic Series
)(2
1 nn aan
S
119)295(2
7nS
Let’s try one: evaluate the series:
5, 9, 13,17,21,25,29
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Writing the given series in summation form.
Evaluate: Yes, you can add manually. But let’s try using the shortcut:
)(2
1 nn aan
S
642)112102(2
6nS
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Practice
Find the number of terms, the first term and the last term. Then evaluate the series:
Ex.1 Ex.2
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Notice we can use the shortcut here:
Why is the answer not 58?
Note: this is NOT an arithmetic series. You can NOT use the shortcut; you have to manually calculate all values.
25)5(5)72(2
10nS
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Arithmetic Sequence:Arithmetic Sequence:
The difference between consecutive The difference between consecutive terms is constant (or the same).terms is constant (or the same).
The constant difference is also known as The constant difference is also known as the the common difference common difference (d).(d).
(It’s also the number you are adding (It’s also the number you are adding every time!)every time!)
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The general form of an ARITHMETIC sequence.
1aFirst Term:
Second Term: 2 1a a d
Third Term:
Fourth Term:
Fifth Term:
3 1 2a a d
4 1 3a a d
5 1 4a a d
nth Term: 1 1na a n d
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Formula for the nth term of an ARITHMETIC sequence.
1 1na a n d
The nth termna
The term numbern
The common differenced
1 The 1st terma
If we know any
If we know any three of these we
three of these we ought to be able
ought to be able to find the fourth.
to find the fourth.
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Example: Decide whether each Example: Decide whether each sequence is arithmetic.sequence is arithmetic.
-10,-6,-2,0,2,6,10,…-10,-6,-2,0,2,6,10,…
-6-(-10)=4-6-(-10)=4
-2-(-6)=4-2-(-6)=4
0-(-2)=20-(-2)=2
2-0=22-0=2
6-2=46-2=4
10-6=410-6=4
Not arithmetic (because Not arithmetic (because the differences are not the differences are not the same)the same)
5,11,17,23,29,…5,11,17,23,29,…
11-5=611-5=6
17-11=617-11=6
23-17=623-17=6
29-23=629-23=6
Arithmetic (common Arithmetic (common difference is 6)difference is 6)
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Rule for an Arithmetic Rule for an Arithmetic SequenceSequence
n = number of termsn = number of terms
aann = last term = last term
aann= a= a11+(n-1)d+(n-1)d
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ExampleExample: Write a rule for the nth : Write a rule for the nth term of the sequence 32,47,62,77,… . term of the sequence 32,47,62,77,… . Then, find u Then, find u1212..
There is a common difference where d=15, There is a common difference where d=15, therefore the sequence is arithmetic.therefore the sequence is arithmetic.
Use uUse unn=u=u11+u(n-1)d+u(n-1)d
uunn=32+(n-1)(15) =32+(n-1)(15)
uunn=32+15n-15=32+15n-15
uunn=17+15n=17+15n
uu1212=17+15(12)=197=17+15(12)=197
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ExampleExample: One term of an arithmetic sequence : One term of an arithmetic sequence is ais a88=50. The common difference is 0.25. =50. The common difference is 0.25.
Write a rule for the nth term.Write a rule for the nth term.Use aUse ann=a=a11+(n-1)d to find the 1+(n-1)d to find the 1stst term! term!
aa88=a=a11+(8-1)(.25)+(8-1)(.25)
50=a50=a11+(7)(.25)+(7)(.25)
50=a50=a11+1.75+1.75
48.25=a48.25=a11
* Now, use a* Now, use ann=a=a11+(n-1)d to find the rule.+(n-1)d to find the rule.
aann=48.25+(n-1)(.25)=48.25+(n-1)(.25)
aann=48.25+.25n-.25=48.25+.25n-.25
aann=48+.25n=48+.25n
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Example: Two terms of an arithmetic sequence are Example: Two terms of an arithmetic sequence are aa55=10 and a=10 and a3030=110. Write a rule for the nth term.=110. Write a rule for the nth term.
Begin by writing 2 equations; one for each term given.Begin by writing 2 equations; one for each term given.
aa55=a=a11+(5-1)d OR 10=a+(5-1)d OR 10=a11+4d+4d
AndAnd
aa3030=a=a11+(30-1)d OR 110=a+(30-1)d OR 110=a11+29d+29d
Now use the 2 equations to solve for aNow use the 2 equations to solve for a11 & d. & d.
10=a10=a11+4d+4d
110=a110=a11+29d (subtract the equations to cancel a+29d (subtract the equations to cancel a11))
-100= -25d -100= -25d
So, d=4 and aSo, d=4 and a11=-6 (now find the rule)=-6 (now find the rule)
aann=a=a11+(n-1)d+(n-1)d
aann=-6+(n-1)(4) OR a=-6+(n-1)(4) OR ann=-10+4n=-10+4n
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Arithmetic SeriesArithmetic Series
The sum of the terms The sum of the terms in an arithmetic in an arithmetic sequencesequence
The formula to find the The formula to find the sum of a finite sum of a finite arithmetic series is:arithmetic series is:
2
1 nn
aanS
# of terms# of terms
11stst Term Term
Last Last TermTerm
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ExampleExample: Consider the arithmetic : Consider the arithmetic series 20+18+16+14+… .series 20+18+16+14+… .
Find n such that SFind n such that Snn=-760=-760
2
1 nn
aanS
2
28202525S 100)4(2525 S
2
1 nn
aanS
2
)222(20760
nn
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--1520=n(20+22-2n)1520=n(20+22-2n)
-1520=-2n-1520=-2n22+42n+42n
2n2n22-42n-1520=0-42n-1520=0
nn22-21n-760=0-21n-760=0
(n-40)(n+19)=0(n-40)(n+19)=0
n=40 or n=-19n=40 or n=-19
Always choose the positive solution!Always choose the positive solution!
2
)222(20760
nn
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An introduction…………Sequence Sum Sequence Sum
1, 4, 7,10,13
9,1, 7, 15
6.2, 6.6, 7, 7.4
, 3, 6
Arithmetic Sequences
ADDTo get next term
2, 4, 8,16, 32
9, 3,1, 1/ 3
1,1/ 4,1/16,1/ 64
, 2.5 , 6.25
Geometric Sequences
MULTIPLYTo get next term
35
12
27.2
3 9
62
20 / 3
85 / 64
9.75
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Vocabulary of Sequences (Universal)
1a First term
na nth term
nS sum of n terms
n number of terms
d common difference
n 1
n 1 n
nth term of arithmetic sequence
sum of n terms of arithmetic sequen
a a n 1 d
nS a a
2ce
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Example: The nth Partial Sum
The sum of the first n terms of an infinite sequence is called the nth partial sum.
1( )2n nnS a a
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Vocabulary of Sequences (Universal)
1a First term
na nth term
nS sum of n terms
n number of terms
r common ratio
n 1
n 1
n1
n
nth term of geometric sequence
sum of n terms of geometric sequ
a a r
a r 1S
r 1ence
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1, 4, 7, 10, 13, …. Infinite Arithmetic No Sum
3, 7, 11, …, 51 Finite Arithmetic n 1 n
nS a a
2
1, 2, 4, …, 64 Finite Geometric n
1
n
a r 1S
r 1
1, 2, 4, 8, … Infinite Geometricr > 1r < -1
No Sum
1 1 13,1, , , ...
3 9 27Infinite Geometric
-1 < r < 11a
S1 r
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Find the sum, if possible: 1 1 11 ...
2 4 8
1 112 4r
11 22
1 r 1 Yes
1a 1S 2
11 r 12
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Find the sum, if possible: 2 2 8 16 2 ...
8 16 2r 2 2
82 2 1 r 1 No
NO SUM
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Find the sum, if possible: 2 1 1 1...
3 3 6 12
1 113 6r
2 1 23 3
1 r 1 Yes
1
2a 43S
11 r 312
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Find the sum, if possible: 2 4 8
...7 7 7
4 87 7r 22 47 7
1 r 1 No
NO SUM
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Find the sum, if possible: 510 5 ...
2
55 12r
10 5 2 1 r 1 Yes
1a 10S 20
11 r 12
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The Bouncing Ball Problem – Version A
A ball is dropped from a height of 50 feet. It rebounds 4/5 of
it’s height, and continues this pattern until it stops. How far
does the ball travel?50
40
32
32/5
40
32
32/5
40S 45
504
10
1554
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The Bouncing Ball Problem – Version B
A ball is thrown 100 feet into the air. It rebounds 3/4 of
it’s height, and continues this pattern until it stops. How far
does the ball travel?
100
75
225/4
100
75
225/4
10S 80
100
4 43
1
0
10
3
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Sigma Notation
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B
nn A
a
UPPER BOUND(NUMBER)
LOWER BOUND(NUMBER)
SIGMA(SUM OF TERMS) NTH TERM
(SEQUENCE)
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j
4
1
j 2
21 2 2 3 2 24 18
7
4a
2a 42 2 5 2 6 72 44
n
n 0
4
0.5 2
00.5 2 10.5 2 20.5 2 30.5 2 40.5 2
33.5
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0
n
b
36
5
0
36
5
13
65
23
65
...
1aS
1 r
6
153
15
2
x
3
7
2x 1
2 1 2 8 1 2 9 1 ...7 2 123
n 1 n
2n 1S a a 15
2
3
2
747
527
![Page 46: Algebra II Unit 1 Lesson 2, 3 & 5 Lesson 2 : F 502. Find the next term in a sequence described recursively. Lesson 3 : F 603. Find a recursive expression.](https://reader035.fdocuments.net/reader035/viewer/2022062803/56649f155503460f94c2b04c/html5/thumbnails/46.jpg)
1
b
9
4
4b 3
4 3 4 5 3 4 6 3 ...4 4 319
n 1 n
1n 1S a a 19
2
9
2
479
784
![Page 47: Algebra II Unit 1 Lesson 2, 3 & 5 Lesson 2 : F 502. Find the next term in a sequence described recursively. Lesson 3 : F 603. Find a recursive expression.](https://reader035.fdocuments.net/reader035/viewer/2022062803/56649f155503460f94c2b04c/html5/thumbnails/47.jpg)
Rewrite using sigma notation: 3 + 6 + 9 + 12
Arithmetic, d= 3
n 1a a n 1 d
na 3 n 1 3
na 3n4
1n
3n
![Page 48: Algebra II Unit 1 Lesson 2, 3 & 5 Lesson 2 : F 502. Find the next term in a sequence described recursively. Lesson 3 : F 603. Find a recursive expression.](https://reader035.fdocuments.net/reader035/viewer/2022062803/56649f155503460f94c2b04c/html5/thumbnails/48.jpg)
Rewrite using sigma notation: 16 + 8 + 4 + 2 + 1
Geometric, r = ½
n 1n 1a a r
n 1
n
1a 16
2
n 1
n
5
1
116
2
![Page 49: Algebra II Unit 1 Lesson 2, 3 & 5 Lesson 2 : F 502. Find the next term in a sequence described recursively. Lesson 3 : F 603. Find a recursive expression.](https://reader035.fdocuments.net/reader035/viewer/2022062803/56649f155503460f94c2b04c/html5/thumbnails/49.jpg)
Rewrite using sigma notation: 19 + 18 + 16 + 12 + 4
Not Arithmetic, Not Geometric
n 1na 20 2
n 1
n
5
1
20 2
19 + 18 + 16 + 12 + 4 -1 -2 -4 -8
![Page 50: Algebra II Unit 1 Lesson 2, 3 & 5 Lesson 2 : F 502. Find the next term in a sequence described recursively. Lesson 3 : F 603. Find a recursive expression.](https://reader035.fdocuments.net/reader035/viewer/2022062803/56649f155503460f94c2b04c/html5/thumbnails/50.jpg)
Rewrite the following using sigma notation:3 9 27
...5 10 15
Numerator is geometric, r = 3Denominator is arithmetic d= 5
NUMERATOR: n 1
n3 9 27 ... a 3 3
DENOMINATOR: n n5 10 15 ... a 5 n 1 5 a 5n
SIGMA NOTATION: 1
1
n
n 5n
3 3