Algebra 5.3 Writing Linear Equations Given Two Points.
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Transcript of Algebra 5.3 Writing Linear Equations Given Two Points.
Algebra
5.3 Writing Linear Equations
Given Two Points
Point Slope Form (PS)
)( 11 xxmyy
Today we will use this formula to find the equation of a line when you are only given two points on the line.
Yesterday you learned to use this formula to find the equation of a line when you were given the slope and one point.
Writing an Equation of a Line from Two Points
STEPS
1. Use the slope formula to find the slope m from the two points
2. Plug one of the points and m into the point slope (PS) formula
3. Simplify to slope-intercept (SI) form
61
6
23
24
m
)3(6)4( xy
•
•
(2, 2)
(3, -4)
Step 1: Compute slope
Step 2: Use PS Form
Step 3: Simplify to SI Form
y + 4 = -6x + 18-4 -4
y = -6x + 14
Check with both points:
Using (3, -4)
2 = -6(2) + 14 -4 = -6(3) + 14
2 = 2 -4 = -4
y = -6x + 14
Now you try. Write the equation of the line through the two given points.
(2, -3) and (-3, 7)
m = -2
PS: y +3 = -2(x – 2) or y – 7 = -2(x + 3)
SI: y = -2x + 1
Write the equation of the line through the two given points.
3
8
)2(3
86)1(
3
82 xyorxy
(-1, -2) and (2, 6)
m =
SI:
PS:
3
2
3
8 xy
Perpendicular Lines
90 90
9090
Perpendicular lines have slopesthat are the opposite of the reciprocal of each other
m = -3
m = 1/3
Write the equation of the line perpendicular to the given line and passing through the given point.
Perpendicular to y = -4x + 6 and passing through (0, 2)
m = ¼
SI: y = ¼x + 2
PS: y – 2 = ¼(x – 0)
Homework
pg. 288 #18-32, 36-41, 45-47, 58-60Graph Paper