Algebra 2 Honors – Unit 1 – Review of Algebra 1

Day 1 – Combining Like Terms and Distributive Property

Objectives: SWBAT evaluate and simplify expressions involving real numbers.

SWBAT evaluate exponents SWBAT combine like terms

SWBAT plug values into expressions

SWBAT apply Distributive and Double Distributive Properties

Exponent Vocabulary

Base – The number that will be multiplied

Coefficient – the number in front of an exponent (assume it’s a 1 if there is none).

Exponent – the number of times the base will be multiplied Examples

Simplify the following expressions.

1. 34 2. (–2)4 3. (–5)3

4. –42 5. 2x3 6. (2y)3

Adding and Subtracting Expressions Vocabulary

Terms – Like Terms – A part or piece of an Terms with the exact variable makeup

expression or equation separated by a + or –

Constant – Simplified –

Number with no variable Combining all like terms or solving attached

3 3 3 3 81 ( 2) ( 2) ( 2) ( 2) 16 ( 5)( 5)( 5) 125

1 4 4 16 32x 3(2 )(2 )(2 ) 8y y y y

Distributive Property – Double Distributive Property (FOIL) –

( )b c ca a ab a ac cd dcb b bad

Examples

Simplify the following expressions.

7. (7z2 +2z) + (6z2 +3z) 8. (9v – 8w) – (10w – 5v)

9. 27 4x x 10. 3 22 3 3 2 5x x x x

2

3

(7 4)

7 x 4

x x

x

3 2

4 3 2

2 (3 3 2 5)

6 6 4 10

x x x x

x x x x

11. (2x – 9)(3x + 4) 12. (3x2 + 4)(x2 + 6)

2

2

6 8 27 36

6 19 36

x x x

x x

4 2 2

4 2

3 18 4 24

3 22 24

x x x

x x

2 2

2 2

2

7 2 6 3

7 6 2 3

13 5

z z z z

z z z z

z z

9 8 10 5

9 8 10 5

9 5 8 10

14 18

v w w v

v w w v

v v w w

v w

Imposters of Double Distributive

For the following examples, explain why they are not a double distributive, and then simplify.

13. (3x – 5y) – (4x + 3y) 14. 3 – 2(4m –2)

There is a +/- sign in-between the ( ) There is only one set of ( ) So it is not double distributive, it is so that means this is just Combining like terms distributive property

3 4 5 3

8

x x y y

x y

3 2(4 2)

3 8 4

8 7

m

m

m

15. (2x – 3)(5x2 – x + 3) 16. 3

2m

2

2

2

3 2 2

3 2

2 2 2

2 2 2

2 2 4 2

4 4 2

4 4 2

2 4 8 4 8

6 12 8

m m m

m m m

m m m m

m m m

m m m

m m m m m

m m m

2

3 2 2

3 2

(2 3)(5 3)

10 2 6 15 3 9

10 17 9 9

x x x

x x x x x

x x x

Day 2 – Solve Linear Equations and Inequalities

Objectives: SWBAT solve linear equations and inequalities. SWBAT use a formula.

SWBAT isolate any variable in a formula or literal equation.

GOLDEN RULE OF SOLVING LINEAR EQUATIONS

Six Steps to help solve equations.

1. PEMDAS

2. Combine like terms that are on the same side of the = sign

3. If there are variables on each side of the = sign, find the smallest variable and

move it to the other side.

4. Solve the two step equation by isolating the variable term

5. Multiply/Divide the coefficient of the variable so that there is a single positive

variable = a number

6. Check your work

Examples

Solve the following equations.

1. 8 37

x

2.

313 5

5w 3.

1 5

2 6m

8 37

8 8

57

7 5 77

35

x

x

x

x

313 5

5

5 5

318

5

5 18 3 5

3 1 5 3

30

w

w

w

w

1 5

2 6

3 5

6 6

3 3

6 6

2

6

1

3

11 1

3

1

3

m

m

m

m

m

m

4. 6 2 14n n 5. 14 3 17x x

6. 2 3 1 4 6 6x x 7. 2 6 4 17 2x x

Formulas and Rewriting Equations

Example: The equation 5

329

C F is used to change temperature from Fahrenheit to

Celsius. Find the equivalent Celsius temperature for each of the following Fahrenheit

temperatures.

8. 212 F 9. 70 C

Examples Solve each equation for the indicated variable

10. a2 + b2 = c2 , for a 11. 1 2

1

2A b b h , for 1b

2 2 2

2 2

2 2 2

2 2 2

2 2

a b c

b b

a c b

a c b

a c b

1 2

1 2

1 2

2 2

2 1

12 2

2

2

2

2

A b b h

A b b h

h

Ab b

h

b b

Ab b

h

5212 32

9

5180

9

100

C

C

C

570 32

9

9 5 970 32

5 9 5

126 32

32 32

158

F

F

F

F

2(3 1) 4 6 6

6 2 4 6 6

6 6 6 6

6 6

6 6

All Real Numbers

x x

x x

x x

x x

2( 6) 4 17 2

2 12 4 17 2

2 16 17 2

2 2

16 17

x x

x x

x x

x x

No Solution

6 2 14

6 14

14 14

8

n n

n n

n

n

14 3 17

14 14

0 17 17

17 17

17 17

17 17

17

1

x x

x x

x

x

x

x

Day 3 – Slope Intercept Form and Writing Equations of Lines

Objectives: SWBAT graph lines

SWBAT write the equation of lines from their graphs SWBAT write the equation of lines from a point and a slope

Slope –

Slope intercept form –

Examples State the slope and the y-intercept for each of the following equations.

1. y = x – 1 2. 2

xy 3. y = 5 4. x = –3

Rewrite each equation into slope-intercept form.

5. 3x + 2y = 15 6. 2x – y = 0

1

1

m

b

1

2

0

m

b

0

5

m or no slope

b

'

m undefined

b doesn t have one

3 2 15

3 3

2 3 15

2 2

3 15

2 2

x y

x x

y x

y x

2 0

2 2

2

2

x y

x x

y x

y x

intercept

b

b

m

m sl

y

ope

x

y

"

" "

"

b

begin with b

m

move wi

x

th

y

m

2 1

2 1

y yrisem

run x x

Graph each equation.

7. 2

( ) 13

f x x 8. 3x – 2y = 4

Put a dot on -3 on y axis, Put a dot on -2 on y axis, then move up 2 right 1 then move up 3 right 2 9. 2y 10. 5x

Horizontal Lines: Vertical Lines: y = any number x = any number

" "

32

2

3

2

2

Solve for y first

y x

m

b

22

1

3

m or

b

0

2

m or no slope

b

'

m undefined

b doesn t have one

Write the equation of each line graphed below.

Line a: 3 2y x Line d: 7y

Line b: 1

3y x Line e:

16

2y x

Line c: 9x

Point Slope form of a linear equation–

Traditional Formula (H, K)

Use point slope form to write an equation for each problem. Then change it to slope intercept form.

Pick either formula to use – they both will work

11. It passes through (4, 2) with a slope of –4

a

b

c

d

e

1 1, a pointx y

m s

x

y

o

y

l

x

pe

1 1my xy x

, a point

x x

y y

a slope

h k

y ha x k

2 4 16

2

2 4

2

4 18

4

y

x

x

y x

y

4 16 2

4

4 4

1

2

8

y x

y

y

x

x

12. Contains (4,1) and the slope is undefined

Since the slope is undefined means you will have a vertical line.

x = 1

13. Contains the origin and (–6, –3)

You must find the slope between those two points

2 1

2 1

3 0 3 1

6 0 6 2

y ym

x x

You can now use either point so use (0,0) because it is the easiest

14. Contains an x-intercept of 2 and y-intercept of 3

You must find the slope between those two points (2,0) and (0,3)

2 1

2 1

3 0 3 3

0 2 2 2

y ym

x x

You can now use either point so use (0,3) because it is the easiest

10 0

2

2

0 01

1

2

y

y

x

x

y x

10 0

2

2

2

0

1

01

y x

y

x

x

y

33

2

3

3

2

3

3 0

33

2

y x

x

y x

y

30 3

2

3

3

2

0

3

32

y

y x

x

y x

Day 4 – Solving Systems of Equations by Graphing and Substitution

Objectives: SWBAT solve systems of equations by graphing.

Objectives: SWBAT solve systems of equations by Substitution

What is a system of linear equations?

Two or more equations with the same variable make-up

What is a solution to a system of equations?

A Point

Finding Solutions to Systems of Equations by Graphing

1) Graph Both Lines

2) Find where they intersect

1) y = 2x + 3 and y = –3x – 2

2 3

2

3

y x

m

b

3 2

3

2

y x

m

b

Intersection point Check

1,1

2 3

1 2 1 3

1 2 3

1 1

y x

3 2

1 3 1 2

1 3 2

1 1

y x

Introduction to Substitution

Take the value of one variable and plug it into the second equation.

Find the solution to the system

1. 6

2 3

x

y x

2.

3 6 18

2

x y

y

x is already solved for, so plug it y is already solved for,

into the other equation. so plug it into the other equation.

2 3

2 6 3

12 3

9

y x

y

y

y

3 6 18

3 6 2 18

3 12 18

3 30

10

x y

x

x

x

x

6,9 10,2

Solving Systems of Equations by Substitution

1) Look at the system of equations. Decide which problem will be the easiest to isolate a variable. You have 4 ways to proceed WORKER SMARTER NOT HARDER

2) Decide which variable you want to solve for, and isolate that variable.

3) Plug or “Substitute” the equation into the variable into the other equation,

solve for the single variable.

4) Substitute the value of the first variable, and plug it back into the first equation. Solve for the Second equation. This will produce the part

of your answer.

5) Check it! Put both values into both equations to see if it checks out.

6) ***** If the two equations are the same, the answer is infinite solutions.

7)****** If the two equations are parallel, then there is no solution.

***** If your Math is good, it does not matter where you start substituting! The answer will be the same*******

Examples Solve the following systems of equations using substitution.

3. x = 3y – 4 and 8x – 3y = 136

1) Let’s look at the two equations, which equation would be easier to isolate a particular variable? (EQN 1 since it is already set equal to “x” 2) Take the “3y-4”, and plug into the equation 8x -3y =136. It should now read, “8(3y+4) -

3y =136” 3) Solve for y. Then take that “y” and plug the value of y into “x=3y-4”

4) Solve for x. 5) Check it.

24 32 3

8(

136

21 32 1

3 4) 3 136

36

21 168

8

y y

y

y

y

y y

24 4

2

3(8) 4

0

x

x

x

20 3(8) 4

20 24 4

20 20

8(20) 3(8) 136

160 24 136

136 136

4. 3x – y = 142 and x – 2y = 134

5. 3x + 6y = –39 and 2x – 5y = 55

2 134

2 134

x y

x y

6 402 142

5

3(

402 142

5 260

52

2 134) 142

y y

y

y y

y

y

104 134

2( 52) 134

30

x

x

x

3(30) ( 52) 142

90 52 142

142 142

30 2( 52) 134

30 104 134

134 134

3 6 39

3 6 39

2 13

x y

x y

x y

4 26 5 55

9 26 5

2( 2 13) 5 55

5

9 81

9

y y

y

y y

y

y

3 6( 9) 39

3 54 39

3 15

5

x

x

x

x

3(5) 6( 9) 39

15 54 39

39 39

2(5) 5( 9) 55

10 45 55

55 55

Day 5 – Solving Systems of Equations by Elimination

Objectives: SWBAT solve systems of equations by Elimination

Solving Systems of Equations by Elimination

1) Put both equations into the __Standard_ form. Usually this will be ___Ax + By = C____Form (X AND Y ON THE SAME SIDE).

2) Get __Matching___________________ coefficients in front of either the ‘x’ or ‘y’

variables.

3) Add the two equations together. Make sure this ___cancel out__________ one

of our variables. Solve the remaining __equation______________. You just

found _First part__ of your answer.

4) Substitute ___________ the value for the solved variable back into either equation. Then solve the remaining __Equation________________. This is the other __Part_______ of your answer.

5) Write your answer as a _______X=____________, and ________Y=____________. Or

as an ordered pair.

6) If both variables cancel out, then if it is a true statement then it is all real

numbers, and if it is a false statement then it is no solution.

7) Check your Work.

Examples

Solve the following systems of equations using elimination. 1. 3 2 17 5 2 7x y and x y 2. 7 2 22 7 2 20x y and x y

__ 3 2 1

8 2

7

( ) 7

4

3

5 2

x y

x

x

y

x

15 2

5(3) 2

7

2 8

4

7

y

y

y

y

__ 7 2 22

( ) 2

4

20

2

1

7

2

x

y

x y

y

y

7 1 21

7 2

17 2

1

3

202

x

x

x

x

3. 6y + 37 = 5x and 3x – 9 = 4y + 14 4. 3x – 4y = 18 and 9x – 12y = 54

9 12 54

3 3 4

9 12 5

18

9 12 5

0 0

4

0

4

x y

Infinately Many Solutions

x y

x

x y

x

y

y

5. 8x + 5 = –y and 11 + 2y = –16x

6 37 5

37 37

6 5 37

5 5

6 5 37

y x

y x

x x

y x

3 9 4 14

9 9

3 4 23

4 4

3 4 23

x y

x y

y y

x y

18 15 11

3

1

20 15 1

6 5 37

5 4 3 23

4

5

2

2 2

2

1

y x

y x

y x

y

y x

y

12 37 5

6 2 3

2

7

5

5

5 5

5 5

x

x

x

x

8 5

8 8

5 8

8 5

x y

x x

y x

x y

11 2 16

2 2

11 16 2

16 2 11

y x

y y

x y

x y

2 8 5

16 2 11

16 2 10

16 2 11

0 0 1

x y

x

No So

y

x y

x y

lu ion

y

t

x

Day 6 – Solving Systems of Equations with 3 Variables

Objectives: SWBAT to solve a system involving three equations and three unknowns.

Ordered Triple -

THE ELIMINATION METHOD FOR A THREE-VARIABLE SYSTEM

1) Write two Elimination Equations, (top two and bottom two – but you can pick

any two)

2) Eliminate a variable the first equation (you should be left with an equation

with two variables).

3) Eliminate the same variable in the second set of equations (you should be left with an equation with two variables).

4) Line up the equations with only two variables, and perform Elimination again. Then solve that equation (you will have one part of your ordered triple).

5) Back substitute that solution into one of the equations with two variables to

get the second answer (you will get the second part of your ordered triple).

6) Take those two answers, and back substitute into one of the original

equations for your third answer.

7) Write you answer as an ordered triple and Check your work.

Examples on the next page….

Examples: Solve the System.

1. 2.

Write two Elimination Equations, (top two and bottom two)

Eliminate a variable the first equation (you should be left with an equation with two variables).

Eliminate the same variable in the second set of equations (you should be left with an equation with two variables).

Line up the equations with only two variables, and perform Elimination again. Then solve that equation.

4 2 3 1

2 3 5 14

6 4 1

x y z

x y z

x y z

3 2 10

6 2 2

4 3 7

x y z

x y z

x y z

4 2 3 1

2 3 5 14

x y z

x y z

2 3 5 14

6 4 1

x y z

x y z

3 2 10

6 2 2

x y z

x y z

6 2 2

4 3 7

x y z

x y z

4 2 3 1

2 2 3 5 14

4 2 3 1

4 6 10 28

8 7 29

x y z

x y z

x y z

x y z

y z

3 2 3 5 14

6 4 1

6 9 15 42

6 4 1

8 11 41

x y z

x y z

x y z

x y z

y z

8 7 29

8 11 41

1 8 7 29

8 11 41

8 7 29

8 11 41

4 12

4 12

4

3

y z

y z

y z

y z

y z

y z

z

z

z

2 3 2 10

6 2 2

6 2 4 20

6 2 2

12 3 18

x y z

x y z

x y z

x y z

x z

2 6 2 2

4 3 7

12 4 2 4

4 3 7

13 5 3

x y z

x y z

x y z

x y z

x z

12 3 18

13 5 3

5 12 3 18

3 13 5 3

60 15 90

39 15 9

99 99

99 99

99

1

x z

x z

x z

x z

x z

x z

x

x

x

Back substitute that solution into one of the equations with two variables to get the second answer.

Take those two answers, and back substitute into one of the original equations for your third answer.

Write all three as an Ordered Triple – This is your answer

8 7 29

8 7 3 29

8 21 29

8 8

8 8

8

1

y z

y

y

y

y

y

4 2 3 1

4 2 1 3 3 1

4 2 9 1

4 7 1

4 8

4 8

2

4

x y z

x

x

x

x

x

x

3

1

2

2 1 3, ,

z

y

x

13 5 3

13 1 5 3

13 5 3

5 10

5 10

5

2

x z

z

z

z

y

y

6 2 2

6 1 2 2 2

6 2 2 2

2 4 2

2 6

2 6

2

3

x y z

y

y

y

y

y

y

1

2

3

1 3 2, ,

x

z

y

3.

Write two Elimination Equations, (top two and bottom two)

Eliminate a variable the first equation (you should be left with an equation with two

variables).

Eliminate the same variable in the second set of equations (you should be left with an

equation with two variables).

Line up the equations with only two variables, and perform Elimination again. Then solve that equation.

4 3 5 19

3 8 21

2 3 13

x y z

x y z

x y z

4 3 5 19

3 8 21

x y z

x y z

3 8 21

2 3 13

x y z

x y z

4 3 5 19

3 3 8 21

4 3 5 19

9 3 24 63

5 29 44

x y z

x y z

x y z

x y z

x z

3 8 21

2 3 13

3 8 21

2 3 13

5 8

x y z

x y z

x y z

x y z

x z

5 29 44

5 8

5 29 44

5 5 8

5 29 44

5 25 40

4 4

4 4

4

1

x z

x z

x z

x z

x z

x z

z

z

z

Back substitute that solution into one of the equations with two variables to get the second answer.

Take those two answers, and back substitute into one of the original equations for your third answer.

Write all three as an Ordered Triple – This is your answer

Special Cases

5. 6.

NO SOLUTION INFINATELY MANY SOLUTIONS

5 8

5 1 8

5 8

3

x z

x

x

x

2 3 13

2 3 3 1 13

6 3 13

9 13

4

x y z

y

y

y

y

1

3

4

3 4 1, ,

z

x

y

2 4 10 14

2 5 4

3 4 3 15

x y z

x y z

x y z

2 2 13

9

4 4 21

x y z

x y z

x y z

Day 7 – Domain and Range

Objectives: SWBAT state the domain and range from a set of points. SWBAT state the domain and range from a graph.

Vocabulary ~

Domain~

The set of all inputs or x-coordinates

of a function and/or graph

Range~ The set of all outputs or y-coordinates

of a function and/or graph

Find the domain of the following sets of points

1. (𝟑, −𝟓) , (𝟓, −𝟔) , (−𝟏𝟎, 𝟓) , (𝟐, 𝟎) 2. (−𝟓, 𝟕) , (𝟐, 𝟑) , (𝟑, 𝟑) , (𝟓, −𝟓)

Domain: −𝟏𝟎, 𝟐, 𝟑, 𝟓 Domain: −𝟓, 𝟐, 𝟑, 𝟓

Range: −𝟔, −𝟓, 𝟎, 𝟓 Range: −𝟓, 𝟑, 𝟕

Find the domain and range of each function

Domain: -9, -7, -5, -3, -1 Range: -10, -6, -2, 2, 6 domain: 9 9x Range: 1 9y

Domain

x coordinates

inputs

Domain: 4 5x Range: 5 8y Domain: 8 0x Range: 8 8y

Domain: 7 7x Range: 0 7y Domain: 4 5x Range: 6 6y

Find the domain and range of each function

Domain: 2x Range: 0y Domain: 8x Range: 1y

Domain: ARN Range: 3y Domain:

0x Range: ARN

Domain: ARN Range: ARN Domain: ARN Range: 9y

Day 8 – Notation

Objective: SWBAT write domain and ranges in set, interval, and inequality notation

Words Inequality Notation

Set Notation

Interval Notation

Graph

Open Interval

A set of numbers greater

than a and less than b

𝒂 < 𝒙 < 𝒃 {𝒙|𝒂 < 𝒙 < 𝒃} (𝒂, 𝒃)

Closed

Interval

A set of numbers greater than or

equal to a and less than or

equal to b

𝒂 ≤ 𝒙 ≤ 𝒃 {𝒙|𝒂 ≤ 𝒙 ≤ 𝒃} [𝒂, 𝒃]

Infinite Interval

(Positive)

A set of numbers

where x is greater than a

𝒙 > 𝒂

{𝒙|𝒙 > 𝒂}

{𝒙|𝒙 ≥ 𝒂}

(𝒂, +∞)

[𝒂, +∞)

Infinite Interval

(Negative)

A set of numbers

where x is less than or equal to b

𝒙 < 𝒃

{𝒙|𝒙 < 𝒃}

{𝒙|𝒙 ≤ 𝒃}

(−∞, 𝒃)

(−∞, 𝒃]

Given the following graph, write the domain and range in inequality, set, and interval notation. Also, describe using words.

1.

Words Inequality Set Interval

D

The domain is in-between -9 and 9 inclusive −𝟗 ≤ 𝒙 ≤ 𝟗 {𝒙| − 𝟗 ≤ 𝒙 ≤ 𝟗} [−𝟗, 𝟗]

R The range is in-between 1

and 9 inclusive 𝟏 ≤ 𝒚 ≤ 𝟗 {𝒚|𝟏 ≤ 𝒚 ≤ 𝟗} [𝟏, 𝟗]

2.

Words Inequality Set Interval

D

The domain is greater than

2 𝒙 > 𝟐 {𝒙|𝒙 > 𝟐} (𝟐, ∞)

R The range is less than -3 𝒚 < −𝟑 {𝒚|𝒚 < −𝟑} (−∞, 𝟐)

Words Inequality Set Interval

D

The domain is greater than

or equal to -3 𝒙 ≥ −𝟑 {𝒙|𝒙 ≥ −𝟑} [−𝟑, ∞)

R

The range is greater than or equal to 1 𝒚 ≥ 𝟏 {𝒚|𝒚 > 𝟏} [𝟏, ∞)

Words Inequality Set Interval

D The domain is all real numbers

−∞ < 𝒙 < ∞ {𝒙| − ∞ < 𝒙< ∞}

(−∞, ∞)

R The range is less than or equal to 1

𝒚 ≤ 𝟏 {𝒚|𝒚 ≤ 𝟏} (−∞, 𝟏]

Day 9 – Piecewise Functions – Day 1

Objectives: SWBAT graph functions with restrictive domains

SWBAT evaluate piecewise functions

Piecewise Function Functions or graphs that are formed

by piecing together two or more functions onto one coordinate plane.

Close Dot Indicates if an endpoint is included with

that particular piece of the graph

Open Dot Indicates if an endpoint is not included with that particular piece of the graph

Restricted Domains When the domain is restricted to include a set of specific numbers

Evaluating the piecewise functions given the following domains

2

31 2

2

1 2 1

3 1

x , if x

f ( x ) x , if x

x , if x

1. when x = 0 2. when x = –8 3. for f(–2) 4. for f(10)

2

3x 1, if x 2

2

f (x)

3x

x 1, if 2 x 1

f 0 0 1

f 0 0

, if

1

f

x

0

1

1

2

f (x) x 1, if 2 x 1

3x , if

3x 1, if x 2

2

3f 8 8 1

2

f 8 12 1

8 1

x

1

1

f

2

3x 1, if x 2

2

f (x)

3x , if

x 1, if 2 x 1

f 2 2 1

x 1

f 2 2 1

f 2 1

2

2

3x , i

3x 1, if x 2

2

f (x) x 1, if 2 x

f x 1

f 10 3 10

f 10 3 100

f 10 300

1

Graph the following functions:

You are not graphing the whole line, just the part that the restrictive domain tells you to.

1. = 2 1, 1f x x if x

1

2. = 5, 32

f x x if x

5. = 7, 3 2f x x if x

1

6. = 5 1 63

f x x if x

Day 10 – Piecewise Functions – Day 2

Objectives: SWBAT graph piecewise functions

Graph the following piecewise function.

5 3 if 3 1

2 2 if 2

x x. g( x )

x x

11 3

2 2

2 3

x , if x. f ( x )

x , if x

2 4, 1

3. = , 1

x xf x

x x

1, 4

4. = 2 1 , 3

8, 3 4

x x

f x x x

x

Step functions –

A piecewise functions that involve all horizontal lines.

2, 7 5

5. = 0, 3 3

4, 4 8

x

f x x

x

6. Write a piecewise function for the graph shown below.

1 0 1

2 1 2

3 2 3

if x

f x if x

if x

Given the following graphs, write a piecewise function.

7. 8.

3

2 4

0

1 2

1x if x

x ifx

xf

3 2

1

4

42

x

x if x

f xif x

9. In 2005, the cost C (in dollars) to send U.S. Postal Service Express Mail up to 5 pounds depended on the weight w (in ounces) according to the function below.

13.65, if 0 8

17.85, if 8 32

= 21.05, if 32 48

24.20, if 48 64

27.30, if 64 80

x

x

C w x

x

x

A) Graph the function.

B) What is the cost to send a parcel weighing 2 pounds and 9 ounces?

2 9 2 16 9

41

21.05

lbs ozs

ozs