Algebra 1: Graphing Linear Equations and … 1: Graphing Linear Equations and Inequalities in 2...
Transcript of Algebra 1: Graphing Linear Equations and … 1: Graphing Linear Equations and Inequalities in 2...
Algebra 1: Graphing Linear Equations and Inequalities in 2 Variables
Topic D5: Finding the Equation of a Line | VERSION A
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Name: _______________________________________
Give the equations of the lines with the given
slopes and y-‐intercepts.
1. 𝑚 = − 12 , 𝑏 = −5
𝑦 =
2. 𝑚 = 53 , 𝑏 = −4
𝑦 =
Find the slopes and y-‐intercepts for the following equations by writing them in the form 𝑦 = 𝑚𝑥 + 𝑏 then graph the equation.
3. −4𝑥 + 𝑦 = 2 𝑦 =
4. 3𝑥 + 6𝑦 = 18 𝑦 =
5. −6𝑥 − 2𝑦 = 12 𝑦 =
For the following problems, the slopes and one point on each line is given. Use the point-‐slope form to find the equations of the lines in slope-‐intercept form.
6. −2,−7 ,𝑚 = 2 𝑦 =
7. −3, 0 ,𝑚 = − 23 𝑦 =
8. −2, 5 ,𝑚 = −3 𝑦 =
9. 3,−4 ,𝑚 = 0 𝑦 =
x
y
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1 2 3 4 5
x
y
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1 2 3 4 5
x
y
54321
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Algebra 1: Graphing Linear Equations and Inequalities in 2 Variables
Topic D5: Finding the Equation of a Line | VERSION A
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Name: _______________________________________
Find the equations, in slope-‐intercept form, of the lines that pass through the following pairs of points.
10. 2,−8 , (1,−5) 𝑦 =
11. −1, 4 , (−2, 7) 𝑦 =
12. 6, 7 , (2, 1) 𝑦 =
13. 3,−2 , (6,−3) 𝑦 =
Find the slope and y-‐intercepts in the following graphs. Then write the equations of the lines in slope-‐intercept form.
14. Slope =
y-‐intercept =
Equations: 𝑦 =
15. Slope =
y-‐intercept =
Equations: 𝑦 =
16. Find the equation of the line with x-‐intercept
(2, 0) and y-‐intercept (0, 1).
𝑦 =
17. Find the slope of the line parallel to the line that
crosses (2,−2) and the y-‐intercept is (0,−3).
𝑚 =
18. Find the slope of the line parallel to the line that
passes through (3, 2) and (−2,−3).
𝑚 =
19. Find the slope of a line perpendicular to the line
that passes through (−1, 2) and (2,−3).
𝑚 =
20. Find the slope of a line perpendicular to the line
that passes through (2,−3) and (−4,−2).
𝑚 =
y
x
54321
1 2 3 4 5
y
x
54321
1 2 3 4 5
Algebra 1: Graphing Linear Equations and Inequalities in 2 Variables
Topic D5: Finding the Equation of a Line | VERSION A
www.varsitylearning.com 3
Name: _______________________________________
Give the equations of the lines with the given
slopes and y-‐intercepts.
1. 𝑚 = − 12 , 𝑏 = −5
𝑦 = − 12 𝑥 − 5
2. 𝑚 = 53 , 𝑏 = −4
𝑦 = 53 𝑥 − 4
Find the slopes and y-‐intercepts for the following equations by writing them in the form 𝑦 = 𝑚𝑥 + 𝑏 then graph the equation.
3. −4𝑥 + 𝑦 = 2 𝑦 = 4𝑥 + 2
4. 3𝑥 + 6𝑦 = 18 𝑦 = − 12 𝑥 + 3
5. −6𝑥 − 2𝑦 = 12 𝑦 = −3𝑥 − 6
For the following problems, the slopes and one point on each line is given. Use the point-‐slope form to find the equations of the lines in slope-‐intercept form.
6. −2,−7 ,𝑚 = 2 𝑦 = 2𝑥 − 3
7. −3, 0 ,𝑚 = − 23 𝑦 = − 2
3 𝑥 − 2
8. −2, 5 ,𝑚 = −3 𝑦 = −3𝑥 − 1
9. 3,−4 ,𝑚 = 0 𝑦 = −4
y
x
54321
1 2 3 4 5
y
x
54321
1 2 3 4 5
y
x
54321
1 2 3 4 5
Algebra 1: Graphing Linear Equations and Inequalities in 2 Variables
Topic D5: Finding the Equation of a Line | VERSION A
www.varsitylearning.com 4
Name: _______________________________________
Find the equations, in slope-‐intercept form, of the lines that pass through the following pairs of points.
10. 2,−8 , (1,−5) 𝑦 = −3𝑥 − 2
11. −1, 4 , (−2, 7) 𝑦 = −3𝑥 + 1
12. 6, 7 , (2, 1) 𝑦 = 32 𝑥 − 2
13. 3,−2 , (6,−3) 𝑦 = − 13 𝑥 − 1
Find the slope and y-‐intercepts in the following graphs. Then write the equations of the lines in slope-‐intercept form.
14. Slope = −2
y-‐intercept = 0, 4
Equations: 𝑦 = −2𝑥 + 4
15. Slope = − 12
y-‐intercept = 0,−5
Equations: 𝑦 = − 12 𝑥 − 5
16. Find the equation of the line with x-‐intercept (2, 0) and y-‐intercept (0, 1).
𝑦 = − 12 𝑥 + 1
17. Find the slope of the line parallel to the line that crosses (2,−2) and the y-‐intercept is (0,−3).
𝑚 = !!
18. Find the slope of the line parallel to the line that passes through (3, 2) and (−2,−3). 𝑚 = 1
19. Find the slope of a line perpendicular to the line that passes through (−1, 2) and (2,−3).
𝑚 = !!
20. Find the slope of a line perpendicular to the line that passes through (2,−3) and (−4,−2). 𝑚 = 6
y
x
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1 2 3 4 5
y
x
54321
1 2 3 4 5