Activated Sludge and SBR PDF

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    Activated Sludge Treatment andSBRs ATUs

    Pre-class questions Name 4 components necessary to have

    an activated sludge system forwastewater treatment.

    Aeration tank Sludge recycle Clarification tank Oxygen supply Sludge wasting

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    Aeration Tank

    Waste sludge

    EffluentFlow, Q

    BODTKNTSS

    Sludge recycle

    Oxygen suppliedclarifier

    Clarifiers for small system should be designed at hydraulic loadsof 200 gal/d-ft 2 compared to 600 gal/d-ft 2 for larger systems

    Why is that?

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    Mean cell residence time

    average time bacteria and solids are in the aeration tank

    Also more commonly called solids retention time (SRT)

    MCRT or SRT =lbs of solids in reactor or aeration tank divided by the lbs wasted per dayThe lbs wasted per day on average equals the lbs produced per day.

    If a system has shorter SRT, a larger fraction of its solids are removed per day

    Thus less solids in system, less bacteria to consume foodand lower efficiency

    But the removal efficiency is in general only a problemwhen the SRT gets below some critical level

    What is the definition of MCRT?

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    Why do you suppose nitrification system requires a

    longer MCRT, per Table 7-10.

    The ammonia oxidizing bacteria haveslower kinetics

    grow slower than heterotrophic bacteria need more time to achieve the same

    efficiency of substrate removal

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    Define SVI and what does it indicate aboutan activated sludge system?

    SVI is the volume in mL that 1.0 gr (dryweight) of sludge occupies after 30

    minutes of settling. Higher SVI means poorer settling Example 2 liter cylinder

    sludge conc. = 3000 mg/Lsettled volume at 30 min = 600 mLSVI = mL/g

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    High Growth of FilamentsSludge Volume Index > 300 mL/gPrefer SVI =

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    What does SBR stand for? Sequencing Batch Reactor One tank used for aeration and settling Steps

    Feed or fill React Settle Decant effluent withdrawal Idle

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    Batch-Fed Activated SludgeProcess:

    TIME

    React 30 -40%

    Cycle %

    Mix Aerate Settle

    15 - 20%

    IdleWithdraw

    15 - 20 %

    Fill

    20 - 30%

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    Rules to remember about activatedsludge treatment

    They all produce excess sludge that has to be

    removed and disposed Oxygen is required at sufficient rate

    2.0 to 2.5 lb O 2/lb BOD including nitrification

    Provided with proper aeration design Conservative designs needed for small systems High peak flows (3-4 times average daily Most of the flow can be in a few hours each day 18 to 24 hour aeration time good baed on avg flow Clarifies at 200 gpd/ft 2 based on average flow

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    Design Guidelines

    Temperature, 0C Min. SRT, days10 2015 1520 10

    Nitrification

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    Nitrification

    Temperature, 0C Min. SRT, days10 2015 1520 10

    SRT, days lb O2/lb BODr 5 1.03

    10 1.1715 1.26

    18 1.3020 1.3225 1.3630 1.39

    40 1.4360 1.48

    y = 0.183Ln(x) + 0.7559X=SRT

    Oxygen Required

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    Oxygen RequiredSRT, days lb O2/lb BODr

    5 1.03

    10 1.1715 1.2618 1.3020 1.32

    25 1.3630 1.3940 1.4360 1.48

    y = 0.183Ln(x) + 0.7559X=SRT

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    0.820.3360

    0.820.3840

    0.820.4230

    0.820.45250.820.4820

    0.870.5315

    0.910.5712

    0.940.6010

    1.000.667

    1.030.696

    1.090.754

    1.180.822

    1.230.871g TSS/g BODg TSS/g BODSRT, days

    Net YieldNet Yield,

    settlingsettling

    No

    primaryWith primary

    y

    =

    0.9967x-0.24

    53

    y

    =

    0.9967x-0.24

    53

    y = 0.9967x-0.2453 y = 1.2463x-0.1184

    Net sludgeYield Values

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    Simple activated sludge design

    Important to check vendor unit supplyIs the tank volume sufficient?Is the oxygen supply sufficient at peak loads?Is the clarification area sufficient?Did they estimate sludge production accurately?Is sludge handling design adequate?

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    Package Units for small flows Modules installed in ground for

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    Treats flow forabout 40 homes

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    Small FlowWWT

    Plant Owner

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    SBR System components Tank (depth can vary from 6 ft to 25 ft)

    Decant system and effluent pump Aeration and mixing equipment Feed pump

    Effluent collection chamber Level sensors Computer controller for cycle times and on/off

    controls Influent valves for multiple tanks

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    Effluent Quality from well-designedwell operated SBRs

    BOD < 8.0 mg/L TSS < 8.0 mg/L NH4-N < 1.0 mg/L NO3-N

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    Advantages Single tank design provides simple

    installation Quiescent settling provides low effluent

    TSS Can provide good nitrogen removal if

    properly designed and enough carbon and

    alkalinity Can be used to provide flow equalization

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    Disadvantages?

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    Key design elements SRT gets total volume

    Cycle Times Fill Volume/decant volume

    Effluent volume = fill volume

    Vs

    Vs = settled volume

    VF = fill volumeVF+VS= total tank liquidvolumeVF/VT= critical design parameter

    VF

    What is a good value for VF/V

    T?

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    Given the following for a 2 tank SBR system, what is the time per cycle of fill,

    aerate, settle, decant and idle and what is the aeration time per cycle?

    Average Flow = 10,000 gal/d = 416.6 gal/hr Based on SRTand load, volume/tank = 10,000 gallons

    Assume: VF/VT = 0.20

    Settle time = 1.0 hr Decant time = 0.5 hrsIdle time = 0.3 hrs

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    Typical Design (2 tanks) Average Flow = 10,000 gal/d = 416.6 gal/hr Based on SRTand load, volume/tank = 10,000 gallons

    Assume: V F/VT = 0.20, VF=0.2(10000) = 2000 gallons# of cycles per day/tank =10,000 gal/day divided by 2 tanks

    divided by 2000 gal/cycle= (10000)/(2*2000gal/fill) = 2.5 per day per tank

    Cycle time = 24/2.5 = 9.6 hrsTotal cycle time = Tfill+Taerate+Tsettle+Tdecant+Tidle = 9.6 hrs

    Fill time, = 2000 gal/416.6 gal/hr = 4.8 hrs

    Settle time = 1.0 hr Decant time = 0.5 hrsIdle time = 0.3 hrs

    Aeration/react time = 9.6-4.8-1.0-0.5-0.3 =3.0 hrs

    Fraction of aeration time =3/9.6 = 0.31