Activated complex theory

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Activated complex theory Using the concepts of statistical thermodynamics. Steric factor appears automatically in the expression of rate constants.

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Activated complex theory. Using the concepts of statistical thermodynamics. Steric factor appears automatically in the expression of rate constants. 27.4 The Eyring equation. - PowerPoint PPT Presentation

Transcript of Activated complex theory

Page 1: Activated complex theory

Activated complex theory

• Using the concepts of statistical thermodynamics.

• Steric factor appears automatically in the expression of rate constants.

Page 2: Activated complex theory

27.4 The Eyring equation • The transition state theory pictures a reaction between A and B as proceeding

through the formation of an activated complex in a pre-equilibrium: A + B -> C‡

K‡ = ( `‡` is represented by `±` in the math style)

• The partial pressure and the molar concentration has the following relationship:pJ = RT[J]

• thus[C‡] = K‡ [A][B]

• The activated complex falls apart by unimolecular decay into products, P,

C‡ → P v = k‡[C‡] • So v = k‡ K‡ [A][B]

Define k2 = k‡ K‡v = k2[A][B]

BA

C

pp

pp

p

RT

p

RT

p

RT

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(a) The rate of decay of the activated complex

k‡ = κv

where κ is the transmission coefficient. κ is assumed to be about 1 in the absence of information to the contrary. v is the frequency of the vibration-like motion along the reaction-coordinate.

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(b) The concentration of the activated complexBased on Equation 20.54, we have

with ∆E0 = E0(C‡) - E0(A) - E0(B)

are the standard molar partition functions.

provided hv/kT << 1, the above partition function can be simplified to

Therefore we can write qC‡ ≈

where denotes the partition function for all the other modes of the complex.

RTE

BA

CAe

qq

qNK /0

Jq

kThveq

/1

1

hv

kT

kThv

q

)( 11

1

cq

hv

kT

q

K

hv

kTRTE

BA

CA eqq

qNK /0

K‡ =

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(c) The rate constant

combine all the parts together, one gets

k2 = k‡ K‡ = κv

then we get

k2 = κ (Eyring equation)

p

RT

hv

kTp

RT

K

CK

h

kT

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(d) The collisions of structureless particles

A + B → AB

Because A and B are structureless atoms, the only contribution to their partition functions are the translational terms:

k2 = κ

k2 = κ NA

3J

mJ

Vq

212 /)( kTm

h

JJ

p

RTVm

C

mC

VIkTq

2

2

RTE

mC

BAA eIkT

V

N

p

RT

h

kT /023

33 2

RTEeru

kT //

0221

8

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Kinetics Salt EffectIonic reaction A + B → C‡ C‡ → P d[P]/dt = k‡[C‡]

the thermodynamic equilibrium constant

Then

d[P]/dt = k2[A][B]

Assuming is the rate constant when the activity coefficients are 1 ( )

Debye-Huckle limiting law with A = 0.509

log(k2) = log( ) + 2AZAZBI1/2 (Analyze this equation)

]][[

][

]][[

][

BA

CK

BA

C

aa

aK

BA

C

BA

C

K

Kkk

2

02k Kkk 02

K

kk

02

2

212 /)log( IAzJJ

02k

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Experimental tests of the kinetic salt effect

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• Example: The rate constant for the base hydrolysis of [CoBr(NH3)5]2+ varies with ionic strength as tabulated below. What cab be deduced about the charge of the activated complex in the rate-determining stage?

I 0.0050 0.0100 0.0150 0.0200 0.0250 0.0300

k/ko 0.718 0.631 0.562 0.515 0.475 0.447

Solution:

I1/2 0.071 0.100 0.122 0.141 0.158 0.173

Log(k/ko) -0.14 -0.20 -0.25 -0.29 -0.32 -0.35

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27.6 Reaction Collisions

• Properties of incoming molecules

can be controlled:

1. Translational energy.

2. Vibration energy.

3. Different orientations.

• The detection of product molecules:

1. Angular distribution of products.

2. Energy distribution in the product.

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27.7 Potential energy surface

• Can be constructed from experimental measurements or from Molecular Orbital calculations, semi-empirical methods,……

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Potential energy surfaces, pt. 2.

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Various trajectories through the potential energy surface

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27.8 Results from experiments and calculations

(a) The direction of the attack and separation

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Attractive and repulsive surfaces

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Classical trajectories