Acids & Bases Hydrolysis
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Acids & Bases
Hydrolysis
Lesson 7
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Hydrolysis
Hydrolysis of a salt is…• The reaction between water and the cation or
anion ( or both) that make up the salt in order to produce either an acidic or basic solution.
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Hydrolysis
Hydrolysis of a salt is…• All salts are considered 100% ionized in water.• We will only consider the reactions between
the ions and water.– Ignore any reactions between the ions
themselves.
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Hydrolysis
Not all ions will react with water.
The ones that do not are called “spectator ions”
Memorize these spectator ions!
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Spectator ions
• NaOH
• HCl
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Spectator Ions
Spectator Cations: alkali metals (group 1 on periodic table) + alkaline earth metals ( group 2 on periodic table)– Column I and column II
Spectator Anions: the first 5 anions found on the top right of the tableClO4, I, Br, Cl, NO3 memorize them!
HSO4 is not a spectator because it is a weak acid.
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So what to do with salts now?
• Determine ions that make them up• Discard any spectators• Remaining ions will act as acids if found on the
left side of table (acids), or they will act as bases if found on right side of the table.
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NaCl
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NH4Cl
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NaF
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Fe(H20)6Cl3
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Al(H2O)5(OH)(NO3)2
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AmphiproticIons
Acids or Bases?
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Amphiprotic Ions H3PO4 Acid
H2PO4- Amphiprotic
HPO42- Amphiprotic
PO43- Base
Amphiprotic ions have a Ka and a Kb.
If the Ka > Kb, then the ion is an acid.
If the Kb > Ka, then the ion is a base.
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Is H2PO4- acid or basic
acid
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1. Is H2PO4- an acid or base when in water? Write the predominate
hydrolysis equation for this ion.
Ka (H2PO4-) = 6.2 x 10-8
Kb (H2PO4-) = Kw
Ka(H3PO4)
= 1 x 10-14
7.5 x 10-3
= 1.3 x 10-12
Ka > Kb Acid
H2PO4- + H2O ⇄ HPO4
2- + H3O+
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Is HPO42- acid or basic
basic
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2. Is HPO42- an acid or base when in water? Write the hydrolysis
equation for this ion.
Ka (HPO42-) = 2.2 x 10-13
Kb (HPO4
2-) = Kw
Ka(H2PO4-)
= 1 x 10-14
6.2 x 10-8
= 1.6 x 10-7
Kb > Ka base
HPO42- + H2O ⇄ H2PO4
- + OH-
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3. Show by calculation if NH4F is an acid or base when in water.
NH4F → NH4+ + F-
acid baseNeither is a spectator; neither will cross off!What will the salt solution be?
Ka(NH4+) = 5.6 x 10-10
Kb (F-) = = KwKa(HF)
= 1 x 10-14
3.5 x 10-4
= 2.9 x 10-11
Ka > Kb acid
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TRY Show by calculation if NH4CH3COO is an acid or base when in water.
NH4CH3COO → NH4+ + CH3COO-
acid base
Ka(NH4+) = 5.6 x 10-10
Kb (CH3COO-) = = KwKa(CH3COOH)
= 1 x 10-14
1.8 x 10-5
= 5.6 x 10-10
Ka = Kb neutral pH = 7.00
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Homework
• Hebden 148– #69 (top row), #70 (top row)– # 71, 72, 73.