A Complete Maple and Maple TA Calculus Course · 2016. 9. 13. · A Complete Maple and Maple TA...
Transcript of A Complete Maple and Maple TA Calculus Course · 2016. 9. 13. · A Complete Maple and Maple TA...
A Complete Maple and Maple TA Calculus Course
Honours Calculus at the University of Guelph, Winter 2007 to the present
Memories of Math 1200 & 1210
Jack here is Our Thank You!
plotx2
5K 3, x2 K 5, 0.5 sin t K 1, 0.75 cos t C 1, t =Kp ..p , 0.5 sin t C 1,K0.75 cos t
C 1, t =Kp ..p , x =K1.58 ..1.58, color = blue, axes = none
Interactive ClassesConnect the algebra and the picture
Solve 7$x = xK 4.Method 1: Cases
Method 1: CasesCase 1: 7$xR 0 Case 2: 7$x! 0
Case 1: 7$xR 0 Case 2: 7$x! 0
rxR 0 and 7$x = 7$x rx! 0 and 7$x =K7$x
Solve 7$x = xK 4 Solve K7$x = xK. After
After work work work, we get x =K23
work work work, we get x = 12
No solution, since xR 0. No solution, since x! 0.
Let's see what is really going on!
P1 d plot 7 x , xK 4, , x =K4 ..6, color = black, red , thickness = 2 :P2 d plot K7 x, x = 0 ..2, color = black, thickness = 2, linestyle = dash :P3 d plot 7 x, x =K2 ..0, color = black, thickness = 2, linestyle = dash :P d plots display P1, P2, P3 , labels = "", "" :P
Method 2: Square both sides (and check!)
7$x = xK 4r 49$x
2= x
2K 8$xC 16
Solving eventually gives x =K23
, x = 12
. Checking in the original equation
shows in both cases, LS≠RS r No solution. Again, let's SEE.plot 49$x
2, xK 4
2, x =K2.1 ..4.1, y =K1 ..30, color = black, red ,
thickness = 2
Learning by intimidation
x4$sin x
5K 3 dx
x5$sin x
5K 3 dx
Effective use of animation and a bonus bit of funcycloid:n. the curve described by a point on (or rigidly connected to) the circumference of a circle as it rolls without slipping on a straight line.
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with plots :
animate s$tK sin s$t , 1Kcos s$t , t = 0 ..1 , sC cos l , 1C sin l , l
= 0 ..2$p , sK q$sin s , 1K q$cos s , q = 0 ..1 , sK sin s K 3C 6
$ w, 1K cos s K3$ sin s
1K cos sC w$ 6$ sin s
1K cos s, w = 0 ..1 , s
= 0 ..9$p, frames = 150, thickness = 2, scaling = constrained, tickmarks
= 2, 2 , view = K3 ..9$p,K3.5 ..3.5 , color = blue
Bringing Negative Radius in Polar Coords to Life With a Special Maplet!
#Title: PolarAnimate #Author: Gord Clement, August 2010 #Description: For a given function and interval, this animates the function in polar coordinates. # The radial arm is animated as the animation moves through the interval.
# When the radius is negative, the function is plotted with dots as if the radius were positive
#Usage: #Call : PolarAnimate function, interval #function: polar function to be used for the animation #interval: interval to be used in the animation, entered
in standard Maple notation, ie [a,b] would be entered q = a ..b # Note, the variable used in the interval will be interpretted as q in the animation PolarAnimate d proc expr, range
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#local declarations local signOfFunction, var, minX, maxX, function, maxR; #function that is -1 is the given value is negative, 0 otherwise signOfFunction d x/piecewise x ! 0,K1 ; #extract variable and endpoints var d op 1, range ; minX d evalf op 1, op 2, range ; maxX d evalf op 2, op 2, range ; #calculate maximum radius length for length of radial armmaxR d maximize abs expr , range ; function d var/expr; #create animationplots animate plot, expr$cos var , expr$sin var , var = minX ..s , expr
$signOfFunction expr $ cos var , expr$signOfFunction expr $sin var , var = minX ..s , maxR$ t$cos s , maxR$ t$sin s , t = 0 ..1 , color = red, black, black , thickness = 2,4, 1 , linestyle = solid, dot, dash , s = minX ..maxX, scaling = constrained, frames= 100
end proc:PolarAnimate 3$sin 2$q , q = 0 ..2$PiPolarAnimate 1K2$ cos q , q = 0 ..2$PiPolarAnimate 1C 2$ sin q , q = 0 ..2$PiPolarAnimate sin 0.4$q , q = 0 ..10$Pi
PolarAnimate cos e$q , q = 0 ..20$Pi
Maple TAGo to Maple TA Calc I NYC Maple TA Summit Sample TA Test
Resources for you!http://maplesoft.com/contact/webforms/CalculusKit.aspx
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Mobification!Go to Mobius