A Block is Held Stationary on a Friction Less Inclined Plane by Means of a String as Shown Below
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A block is held stationary on a frictionless inclined plane by means of a string as shown below. string force F mgSin θ mgCos θ θ (a) (i) On the diagram draw arrows to represent the three forces acting on the block. Ans:–done- (ii) The angle θ of inclination of the plane is 25. The block has mass 2.6 kg. Calculate the force in the string. You may assume that g 9.8 m s–2. Ans: F = mgSin θ=(2.6)(9.8)(Sin 25)=…newton. A resistor of resistance 1.0 is connected in series with a battery. The current in the circuit is 2.0 A. The resistor is now replaced by a resistor of resistance of 4.0 . The current in this circuit is 1.0 A. The best estimate for the internal resistance of the battery is
Transcript of A Block is Held Stationary on a Friction Less Inclined Plane by Means of a String as Shown Below
A block is held stationary on a frictionless inclined plane by means of a string as shown below.
string
force F
mgSin θ
mgCos θ
θ
(a) (i) On the diagram draw arrows to represent the three forces acting on the block. Ans:–done-(ii) The angle θ of inclination of the plane is 25. The block has mass 2.6 kg.Calculate the force in the string. You may assume that g 9.8 m s–2.Ans: F = mgSin θ=(2.6)(9.8)(Sin 25)=…newton.
A resistor of resistance 1.0 is connected in series with a battery. The current in the circuit is 2.0 A.The resistor is now replaced by a resistor of resistance of 4.0 . The current in this circuit is 1.0 A.The best estimate for the internal resistance of the battery is
