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Geometry Chapter 8 Area Review PA Anchors A3 B2 Cl

1 Find the missing value given BCDA is a rectangle Perimeter = 62 cm

Area =

B ---____---c

17 em

V dt- ~vJ A =- uJ

~ J

~) - - 0

rJ ~ -

lt+

A 0 (YCWLllL~)1 i+ )LI1)

0 ~3~ U1l)1t+~4 -~-J

- G)LT

Slshy

2 Find the missing value given BCDA is a rectangle Perimeter = 56 cm

p - LuArea = J2l -+-Jw ~ - lQ + J(3 ) A -- ( t CWgtk I 3 ~ )B C

5( ~ J J-4- U11 6 - Iqs- ~VYI9 _) U13 em J ~

J~ It~

VA IS Jshy

3 Calculate the area of the figure

mQ-_4=-=----7_c-r gtlt--R

6cm

~ lQ L

3 3clrJ rshy T

~

p u

3 cm

S

A=- A(~) ~ A w-l-~

A -- 4 t lJl Lgt Glgt ) -+ l L--- )[ ~ (An )

JU ~4- q ~L

(pound0


Q

12 km

lD

To)

u

A ACD~ A~

4km A- Lu - 1tJ

) (Y ~l-w-) - (Ytnll4~ )

A- Hib L-n-t - Ito yen-mtshy

CF7- J kll)

P 14 km W


Q R

-J 9 L 5m l - amp-luJ

15 m

I T~ S

i

U i

_A ~ l(~l(J fY) -U371 ~ rn )

V A =gtO m2_ 2Y rY)L L

h I ~1S-~0 p 16m w


c 7 mmQ lth R A J-p T~

4mm

p

~ L

d) ~

2mm A w -+ juJI jI X

I A lWI-n( 4 m ) 4- ~nw~-~mYV) I

-l 7tgt M I

T ~~1 S ~ ~- )I) )~ M 7 4 ~

02

u (0740

7 Find the area of parallelogram MNOP P 0

--____---

45 em

___ r M 16 em N

8 Find the area of parallelogram A1NOP

~___

P

-L ___ r

0

48 em

M 17 em N

9 Find the area of parallelogram QRST s

Ab~1 A =-- (l ~ C VYI )( i S-~ )o ~ Cftl)

A~bh A -=-( 1 (yenY X4 f6 (~ )

0~middot I(u0

A ~- bh A - (LPltt rrY 54 m)

cJ3ln- 0

10 Find the area of parallelogram QRST R____57_i_ll_---s A-b~

A -==-( 5 -=t I I) Y4 4 ~ Y) )

Cf- l -=11 raquoQ~_----L---_----

11 Find the area of MBC A- hbh B A ~ ~ (31 ~~iq ~J)

~~ 44 ~d~)~9 yd

A -E 32 yd gtC

12 Find the area of MBC

B

~A- ~(toP-X4f)16 ft 6 ft

A 4ft c CE~ fD R~ lt 20 ft gt

13 Find the area of trapezoid ABCD

C A~ k lb +bl-) h

A ~ ~ (24 + -X I ) p - r 5~ II~ A ~ 30)- ml-D

14 Find the area oftrapezoidABCD

B 16m C A ~(b-rb-)n

~D A~ J (ltO+30~11 )12 m 11 m ( -J A - ~ (H )li )

A 30 m 0 - 253 ())1)

15 Find the area of kite RSTU

A ~ kdcl2shyA - ~ (l)t)(~yen))

R~__==~__~=-__~T

lt2 ~ 40 u

s

16 Find the area of kite RSTU A ~ 5 dl t~2 s ~ - ~ (t3 I ltJltt ~)

T 0~q~n9

u

17 A rectangular piece of fabric measures 37 by 36 inches A triangular scarf with a height of 31 inches and a base of 28 inches is cut from the fabric How much fabric is left over

R

A -- k -A~ A ~ Lw - ~bh A - (1 [3(q ) - ~ (~~t3 I )

A- lJgt3~ I(~- +3f-

~7~ ii0 18 A rectangular piece of fabric measures 45 by 37 inches A triangular scarf with a height of

29 inches and a base of 32 inches is cut from the fabric How much fabric is left over

A Aa-AtI A - tltt) - -5bh A (45 37 0) lt~ (3l j-tt )

A ~ II (~~- )ll- - 4(~ In1shy

G IOLO9 19 Find the area of the regular polygon

Agt ~atgtn A-- i-( 5~ rf L i i k )

(poundQ3 ( I

gt-~ 6 in

- - -

20 Find the area of the regular polygon S A) ~asV)

T A gt ~(SIS- f))L~~is)

~~ lt~ n~ 8 in

21 If a regular octagon with 2-centimeter sides has an approximate area of 19 centimeters squared what is the approximate length of the apothem to the nearest

hundredth A - 1 ctS

lq ~ ~ o()~) )q YeL ltj lt2

a ~ 1 37~

3~W0

22 If a regular pentagon with 13-centimeter sides has an approximate area of 291 centimeters squared what is the approximate length of the apothem to the nearest

hundredth A ~tLS n

tl I ~ -3 0 (i 315)

~tj I 3) S 4shy

3 s 5 S

tl ~ ~r1S 3 ~ lj v ISLI

0~q~~

23 Find the area of a regular pentagon with an apothem 55 meters long and a side 8 meters long

A~ ~CLSV

b- ~ (5S Ygt( laquoy 5 J Q () f) -)

24 Find the area of a regular heptagon with an apothem 104 centimeters long and a side 10 centimeters long A - J-lt5 Y)

j - -z ()O4 LV Ie) Lny)

E3~~ ltYh0

25 In the figure each circle has a radius of 7 inches What is the area of the portion outside the

A-= A-o- qAQ A LtD - q1rrJ

A- (4)Y4) - q Tf()1-

A 1amp i - 19n-)[lJq)

0 -= (1 1-pound4- 4yen-11t) IJ~

26 In the figure each circle has a radius of 5 inches What is the area of the portion outside the circles but inside the square Express your answer in terms of Jr

A-=An-4Aco A -=- ~( - -J -r 1shy

A Cd(6)lJ)) - YIT l 5)shy

A ~ -1-00 - (4rryJ-0

( eLf 60 - )1)0 fT ) il)1)

circles but inside the square Express your answer in terms of Jr

ltElt---- 42 in ----gt~

lt 20 in --gt~

27 Find the area of a circle with radius 9 centimeters Use Jr = 314 (Round to the nearest two decimal places) A ~1t- 2- A ltt I 13 t 4

A 011 (-1)1- 1 II 1A ItJ tl6 3 CYIA - ~ Ii

28 Find the area of a circle with radius 13 centimeters Use Jr = 314 (Round to the nearest two decimal places) ) -rryL A~ I ~q 13 14

A - Ti ()~)l A r 30 Lgt 14 CIvIL

A ~11i7-

29 A circle has a circumference of 4Jrcentimeters What is the area of the circle

c -= ttr( A- it y_l )

Lt-1I ~ A ~ 1I~t)-___- middot

~ ~1

30 A circle has a circumference of30Jrcentimeters What is the area of the circle C - d 11Y A ~ frJ1

A - iTLI~)

f20lSlI ~0 31 A circle has an area of 64Jrcentimeters squared What is the diameter of the circle

A~ ~ cl-02 r l4 Tt 111- d JW)

1l 1r

L 1 =-- 1 ~ 32 A circle has an area of 484Jrcentimeters squared What is the circumference of the circle

po IY 2shy

lshyJ4-1T 1f( C-- ~lT Ll--)

o 4 Lf-1I (ftgt

33 The figure below represents the overhead view of a deck surrounding a hot tub What is the area of the deck Use 7r=314 (Round to the nearest two decimal places)

2 LA- lt1-R - nT

A c- til (amp5)7-_ 11(3)2

2m A ~~T - CJrt A - 10 fi

A ~ ~ l3 )ll)

cA ~ 50 ) m~

34 The figure below represents the overhead view of a deck surrounding a hot tub What is the area of the deck Use 7r =314 (Round to the nearest two decimal places)

A--- 1 r(- 11

2 2A ~ 1 i ) ) - 11(3 3) 24 m

A 3~ Lq rr - H)l iT

A ~ ~I ~ W

A t J iR (3 )4)

A ~ ~f ltil~

G -X-t7 ji 0 35 Find the exact area of the shaded portion of the figure

A~ A~ - Ao

A ~ ~bh- t1-t~

A =- ~llq )(1 tJ1 - If (J5i

l 511)0 A

19 in

B

16 in

~~sectsect=c 0 Q5 )

36 Find the exact area of the shaded portion of the figure

37 Find the area of the shaded region Use 7r = 314 (Round to the nearest two decimal places) tt 1shyA ---lTr

bull J llO

A ~ ~ 1 U)L3~c)

A -- ~ l)5Tt)

allA- ~

~ ~ pound3 14) A X l

A ~ J3 D~ 3

~o~vn9

38 Find the area of the shaded region Use 7r =314 (Round to the nearest two decimal places)

P (7shyA - 3IPo ~) )2shy

A - -3(0

Llo

A - ~ l3luli) A ~ -(Pushy

1( - S-

Al( ~~(3 ) Sshy

A t ll lo 0lt6

~ampL~

39 Find the surface area of this rectangular prism

5A ~ )ivJ+ dwh -+ )poundh SA 1 (10 )lIt)) + -l( I o ) llt 2( 1()0)

SA abo- -to -t- +0 10 em (sAC ~80 CYr1-)

40 SA - (iiL-o 4- Jv h 4- l-ih

SA ~ 1(JIXS- )-+ J(lS-(J) -+ L(I I(I)

lem SA -- 33o+- 30 r 22 llcm

41 Find the surface area of the right pyramid (Round to the nearest decimal place)

5A ~ AD +- LfA~

SA fLw -+ if (~bh)

9A -- ((pU) 4- -I ( ~ ~ lt0Y-) SA - 3ltP ~ 84

(fA ~ JO [-to-)

2em

Find the surface area of this rectangular prism

6ft


SA~ AD 4- LJ AIgt SA -= Pw -f- l7t bh) SA ~ (L(t-LO 4- L C-k)(4X()

SA J ~ ~ 4 $

(SA IA A0 4ft

43 Find the surface area of the cone (Round to the nearest decimal place)

5A -0 1Iy-t -T 1fr~

SA ~ (Xll)+ 1 ()2

S A - lq iT - ~q1r

(SA = 10~1i cW) SA LD~ C~ middot 14 )


SA -= 1Irt + ltif r l

4SA -= (~) bullbullf) + 11 ( lo)

S~A ~4- tT -+ 3ltamp IT

G A- ~ if (yAJ SA r 1)0 l3 l~)

(5~ I- 3--=r1 ~ (0

- --shy_ - shy

I

- I

45 Solve each problem The figures are not drawn to scale Area of shaded region = _

A ~ AD - Ao

1 A - ~ -Ifz

_ 1(10)2shy20 em

I dO n) ~Z-JIshy

46 Area of shaded region = __

A=- Ao - AoT A ~--nrZ 50 em A- 15u So) -rrCs-)2

l r--- 50 em ~


1 em A TI--R-- lTY2

A=- (~)~ IT(S)7

A-z- qcIT - 2S-i

(A Lrn)1 1

~

48 Area of shaded region = _ _

3cm

49 Solve each problem The figures are not drawn to scale Area of shaded region = _ tl 1J LA 3uo 1( - ~ b Y)

ct( 1shyA ~6 If() - ( 1 Y- )

50 Area of shaded region =_ _

- tl 2 1 lA ~ 3~o-n-r - )- () h

A ~ TrO5J-- ~(Ity- )

A ~ ~ ())5Tr) - yen


Q

12 km

lD

To)

u

A ACD~ A~

4km A- Lu - 1tJ

) (Y ~l-w-) - (Ytnll4~ )

A- Hib L-n-t - Ito yen-mtshy

CF7- J kll)

P 14 km W


Q R

-J 9 L 5m l - amp-luJ

15 m

I T~ S

i

U i

_A ~ l(~l(J fY) -U371 ~ rn )

V A =gtO m2_ 2Y rY)L L

h I ~1S-~0 p 16m w


c 7 mmQ lth R A J-p T~

4mm

p

~ L

d) ~

2mm A w -+ juJI jI X

I A lWI-n( 4 m ) 4- ~nw~-~mYV) I

-l 7tgt M I

T ~~1 S ~ ~- )I) )~ M 7 4 ~

02

u (0740


--____---

45 em

___ r M 16 em N


~___

P

-L ___ r

0

48 em

M 17 em N



A~bh A -=-( 1 (yenY X4 f6 (~ )

0~middot I(u0


cJ3ln- 0


A -==-( 5 -=t I I) Y4 4 ~ Y) )

Cf- l -=11 raquoQ~_----L---_----


~~ 44 ~d~)~9 yd

A -E 32 yd gtC


B




C A~ k lb +bl-) h

A ~ ~ (24 + -X I ) p - r 5~ II~ A ~ 30)- ml-D


B 16m C A ~(b-rb-)n

~D A~ J (ltO+30~11 )12 m 11 m ( -J A - ~ (H )li )

A 30 m 0 - 253 ())1)



R~__==~__~=-__~T

lt2 ~ 40 u

s


T 0~q~n9

u


R

A -- k -A~ A ~ Lw - ~bh A - (1 [3(q ) - ~ (~~t3 I )

A- lJgt3~ I(~- +3f-




A ~ II (~~- )ll- - 4(~ In1shy



(poundQ3 ( I

gt-~ 6 in

- - -



~~ lt~ n~ 8 in


hundredth A - 1 ctS


a ~ 1 37~

3~W0


hundredth A ~tLS n

tl I ~ -3 0 (i 315)

~tj I 3) S 4shy

3 s 5 S


0~q~~


A~ ~CLSV




E3~~ ltYh0



A- (4)Y4) - q Tf()1-


0 -= (1 1-pound4- 4yen-11t) IJ~


A-=An-4Aco A -=- ~( - -J -r 1shy


A ~ -1-00 - (4rryJ-0

( eLf 60 - )1)0 fT ) il)1)


ltElt---- 42 in ----gt~

lt 20 in --gt~





A ~11i7-




~ ~1


A - iTLI~)


A~ ~ cl-02 r l4 Tt 111- d JW)

1l 1r


po IY 2shy


o 4 Lf-1I (ftgt


2 LA- lt1-R - nT

A c- til (amp5)7-_ 11(3)2


A ~ ~ l3 )ll)

cA ~ 50 ) m~


A--- 1 r(- 11

2 2A ~ 1 i ) ) - 11(3 3) 24 m

A 3~ Lq rr - H)l iT

A ~ ~I ~ W

A t J iR (3 )4)

A ~ ~f ltil~


A~ A~ - Ao

A ~ ~bh- t1-t~

A =- ~llq )(1 tJ1 - If (J5i

l 511)0 A

19 in

B

16 in

~~sectsect=c 0 Q5 )



bull J llO

A ~ ~ 1 U)L3~c)

A -- ~ l)5Tt)

allA- ~


A ~ J3 D~ 3

~o~vn9



A - -3(0

Llo


1( - S-

Al( ~~(3 ) Sshy

A t ll lo 0lt6

~ampL~





SA ~ 1(JIXS- )-+ J(lS-(J) -+ L(I I(I)

lem SA -- 33o+- 30 r 22 llcm


5A ~ AD +- LfA~

SA fLw -+ if (~bh)

9A -- ((pU) 4- -I ( ~ ~ lt0Y-) SA - 3ltP ~ 84

(fA ~ JO [-to-)

2em


6ft



SA J ~ ~ 4 $

(SA IA A0 4ft


5A -0 1Iy-t -T 1fr~

SA ~ (Xll)+ 1 ()2

S A - lq iT - ~q1r







(5~ I- 3--=r1 ~ (0

- --shy_ - shy

I

- I


A ~ AD - Ao

1 A - ~ -Ifz

_ 1(10)2shy20 em

I dO n) ~Z-JIshy



l r--- 50 em ~


1 em A TI--R-- lTY2

A=- (~)~ IT(S)7

A-z- qcIT - 2S-i

(A Lrn)1 1

~


3cm


ct( 1shyA ~6 If() - ( 1 Y- )


- tl 2 1 lA ~ 3~o-n-r - )- () h


A ~ ~ ())5Tr) - yen


--____---

45 em

___ r M 16 em N


~___

P

-L ___ r

0

48 em

M 17 em N



A~bh A -=-( 1 (yenY X4 f6 (~ )

0~middot I(u0


cJ3ln- 0


A -==-( 5 -=t I I) Y4 4 ~ Y) )

Cf- l -=11 raquoQ~_----L---_----


~~ 44 ~d~)~9 yd

A -E 32 yd gtC


B




C A~ k lb +bl-) h

A ~ ~ (24 + -X I ) p - r 5~ II~ A ~ 30)- ml-D


B 16m C A ~(b-rb-)n

~D A~ J (ltO+30~11 )12 m 11 m ( -J A - ~ (H )li )

A 30 m 0 - 253 ())1)



R~__==~__~=-__~T

lt2 ~ 40 u

s


T 0~q~n9

u


R

A -- k -A~ A ~ Lw - ~bh A - (1 [3(q ) - ~ (~~t3 I )

A- lJgt3~ I(~- +3f-




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(poundQ3 ( I

gt-~ 6 in

- - -



~~ lt~ n~ 8 in


hundredth A - 1 ctS


a ~ 1 37~

3~W0


hundredth A ~tLS n

tl I ~ -3 0 (i 315)

~tj I 3) S 4shy

3 s 5 S


0~q~~


A~ ~CLSV




E3~~ ltYh0



A- (4)Y4) - q Tf()1-


0 -= (1 1-pound4- 4yen-11t) IJ~


A-=An-4Aco A -=- ~( - -J -r 1shy


A ~ -1-00 - (4rryJ-0

( eLf 60 - )1)0 fT ) il)1)


ltElt---- 42 in ----gt~

lt 20 in --gt~





A ~11i7-




~ ~1


A - iTLI~)


A~ ~ cl-02 r l4 Tt 111- d JW)

1l 1r


po IY 2shy


o 4 Lf-1I (ftgt


2 LA- lt1-R - nT

A c- til (amp5)7-_ 11(3)2


A ~ ~ l3 )ll)

cA ~ 50 ) m~


A--- 1 r(- 11

2 2A ~ 1 i ) ) - 11(3 3) 24 m

A 3~ Lq rr - H)l iT

A ~ ~I ~ W

A t J iR (3 )4)

A ~ ~f ltil~


A~ A~ - Ao

A ~ ~bh- t1-t~

A =- ~llq )(1 tJ1 - If (J5i

l 511)0 A

19 in

B

16 in

~~sectsect=c 0 Q5 )



bull J llO

A ~ ~ 1 U)L3~c)

A -- ~ l)5Tt)

allA- ~


A ~ J3 D~ 3

~o~vn9



A - -3(0

Llo


1( - S-

Al( ~~(3 ) Sshy

A t ll lo 0lt6

~ampL~





SA ~ 1(JIXS- )-+ J(lS-(J) -+ L(I I(I)

lem SA -- 33o+- 30 r 22 llcm


5A ~ AD +- LfA~

SA fLw -+ if (~bh)

9A -- ((pU) 4- -I ( ~ ~ lt0Y-) SA - 3ltP ~ 84

(fA ~ JO [-to-)

2em


6ft



SA J ~ ~ 4 $

(SA IA A0 4ft


5A -0 1Iy-t -T 1fr~

SA ~ (Xll)+ 1 ()2

S A - lq iT - ~q1r







(5~ I- 3--=r1 ~ (0

- --shy_ - shy

I

- I


A ~ AD - Ao

1 A - ~ -Ifz

_ 1(10)2shy20 em

I dO n) ~Z-JIshy



l r--- 50 em ~


1 em A TI--R-- lTY2

A=- (~)~ IT(S)7

A-z- qcIT - 2S-i

(A Lrn)1 1

~


3cm


ct( 1shyA ~6 If() - ( 1 Y- )


- tl 2 1 lA ~ 3~o-n-r - )- () h


A ~ ~ ())5Tr) - yen


~~ 44 ~d~)~9 yd

A -E 32 yd gtC


B




C A~ k lb +bl-) h

A ~ ~ (24 + -X I ) p - r 5~ II~ A ~ 30)- ml-D


B 16m C A ~(b-rb-)n

~D A~ J (ltO+30~11 )12 m 11 m ( -J A - ~ (H )li )

A 30 m 0 - 253 ())1)



R~__==~__~=-__~T

lt2 ~ 40 u

s


T 0~q~n9

u


R

A -- k -A~ A ~ Lw - ~bh A - (1 [3(q ) - ~ (~~t3 I )

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hundredth A - 1 ctS


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hundredth A ~tLS n

tl I ~ -3 0 (i 315)

~tj I 3) S 4shy

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A~ ~CLSV




E3~~ ltYh0



A- (4)Y4) - q Tf()1-


0 -= (1 1-pound4- 4yen-11t) IJ~


A-=An-4Aco A -=- ~( - -J -r 1shy


A ~ -1-00 - (4rryJ-0

( eLf 60 - )1)0 fT ) il)1)


ltElt---- 42 in ----gt~

lt 20 in --gt~





A ~11i7-




~ ~1


A - iTLI~)


A~ ~ cl-02 r l4 Tt 111- d JW)

1l 1r


po IY 2shy


o 4 Lf-1I (ftgt


2 LA- lt1-R - nT

A c- til (amp5)7-_ 11(3)2


A ~ ~ l3 )ll)

cA ~ 50 ) m~


A--- 1 r(- 11

2 2A ~ 1 i ) ) - 11(3 3) 24 m

A 3~ Lq rr - H)l iT

A ~ ~I ~ W

A t J iR (3 )4)

A ~ ~f ltil~


A~ A~ - Ao

A ~ ~bh- t1-t~

A =- ~llq )(1 tJ1 - If (J5i

l 511)0 A

19 in

B

16 in

~~sectsect=c 0 Q5 )



bull J llO

A ~ ~ 1 U)L3~c)

A -- ~ l)5Tt)

allA- ~


A ~ J3 D~ 3

~o~vn9



A - -3(0

Llo


1( - S-

Al( ~~(3 ) Sshy

A t ll lo 0lt6

~ampL~





SA ~ 1(JIXS- )-+ J(lS-(J) -+ L(I I(I)

lem SA -- 33o+- 30 r 22 llcm


5A ~ AD +- LfA~

SA fLw -+ if (~bh)

9A -- ((pU) 4- -I ( ~ ~ lt0Y-) SA - 3ltP ~ 84

(fA ~ JO [-to-)

2em


6ft



SA J ~ ~ 4 $

(SA IA A0 4ft


5A -0 1Iy-t -T 1fr~

SA ~ (Xll)+ 1 ()2

S A - lq iT - ~q1r







(5~ I- 3--=r1 ~ (0

- --shy_ - shy

I

- I


A ~ AD - Ao

1 A - ~ -Ifz

_ 1(10)2shy20 em

I dO n) ~Z-JIshy



l r--- 50 em ~


1 em A TI--R-- lTY2

A=- (~)~ IT(S)7

A-z- qcIT - 2S-i

(A Lrn)1 1

~


3cm


ct( 1shyA ~6 If() - ( 1 Y- )


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A ~ ~ ())5Tr) - yen


T 0~q~n9

u


R

A -- k -A~ A ~ Lw - ~bh A - (1 [3(q ) - ~ (~~t3 I )

A- lJgt3~ I(~- +3f-




A ~ II (~~- )ll- - 4(~ In1shy



(poundQ3 ( I

gt-~ 6 in

- - -



~~ lt~ n~ 8 in


hundredth A - 1 ctS


a ~ 1 37~

3~W0


hundredth A ~tLS n

tl I ~ -3 0 (i 315)

~tj I 3) S 4shy

3 s 5 S


0~q~~


A~ ~CLSV




E3~~ ltYh0



A- (4)Y4) - q Tf()1-


0 -= (1 1-pound4- 4yen-11t) IJ~


A-=An-4Aco A -=- ~( - -J -r 1shy


A ~ -1-00 - (4rryJ-0

( eLf 60 - )1)0 fT ) il)1)


ltElt---- 42 in ----gt~

lt 20 in --gt~





A ~11i7-




~ ~1


A - iTLI~)


A~ ~ cl-02 r l4 Tt 111- d JW)

1l 1r


po IY 2shy


o 4 Lf-1I (ftgt


2 LA- lt1-R - nT

A c- til (amp5)7-_ 11(3)2


A ~ ~ l3 )ll)

cA ~ 50 ) m~


A--- 1 r(- 11

2 2A ~ 1 i ) ) - 11(3 3) 24 m

A 3~ Lq rr - H)l iT

A ~ ~I ~ W

A t J iR (3 )4)

A ~ ~f ltil~


A~ A~ - Ao

A ~ ~bh- t1-t~

A =- ~llq )(1 tJ1 - If (J5i

l 511)0 A

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SA ~ 1(JIXS- )-+ J(lS-(J) -+ L(I I(I)

lem SA -- 33o+- 30 r 22 llcm


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SA ~ 1(JIXS- )-+ J(lS-(J) -+ L(I I(I)

lem SA -- 33o+- 30 r 22 llcm


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lem SA -- 33o+- 30 r 22 llcm


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SA fLw -+ if (~bh)

9A -- ((pU) 4- -I ( ~ ~ lt0Y-) SA - 3ltP ~ 84

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6ft



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A ',0 U1l)pa01000192.schoolwires.net/cms/lib7/PA01000192/Centricity/Domain/198/... · Geometry...

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Transcript of A ',0 U1l)pa01000192.schoolwires.net/cms/lib7/PA01000192/Centricity/Domain/198/... · Geometry...