9 precipitations - rainfall

191
Riccardo Rigon Some Atmospheric Physics Giorgione - La tempesta, 1507-1508 Saturday, September 11, 2010

Transcript of 9 precipitations - rainfall

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Riccardo Rigon

Some Atmospheric Physics

Gio

rgio

ne

- La

tem

pes

ta,

15

07

-15

08

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“The rain patters, the leaf quivers” Rabindranath Tagore

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Precipitations

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Objectives:

3

•To Give an introduction to general circulation phenomena and a description of the atmospheric phenomena that are correlated to precipitation

•To introduce a minimum of atmospheric thermodynamics and some clues regarding cloud formation

•To speak of precipitations, their formation in the atmosphere, and their characterisations on the ground

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Radiation

• The motor behind it all is solar radiation

Wik

iped

ia

- Su

n

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!"#$#"%"#& '%($()"*#$(+%,-./'/#(./#./$(#

('$",-%'(#0'%+#(./#/12$(%'#(%#(./#-%3/,#

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D = 2 ω V sin φ

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But the Earth rotates on its own axis

And this means that all bodies are subject to the Coriolis force

In the northern hemisphere, a body moving at non-null velocity is deviated to the right. In the southern hemisphere, to the left.

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D = 2 ω V sin φ

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But the Earth rotates on its own axis

And this means that all bodies are subject to the Coriolis force

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D = 2 ω V sin φ

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Coriolis Force

But the Earth rotates on its own axis

And this means that all bodies are subject to the Coriolis force

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D = 2 ω V sin φ

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Coriolis Force

Rotational velocity of the Earth

But the Earth rotates on its own axis

And this means that all bodies are subject to the Coriolis force

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D = 2 ω V sin φ

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Coriolis Force

Rotational velocity of the Earth

Relative velocity of the object considered

But the Earth rotates on its own axis

And this means that all bodies are subject to the Coriolis force

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D = 2 ω V sin φ

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Coriolis Force

Rotational velocity of the Earth

Relative velocity of the object considered

Latitude of the object considered

But the Earth rotates on its own axis

And this means that all bodies are subject to the Coriolis force

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Thus, the air masses rotate around the centres of low and high pressure

High pressurepolar, cold

Easterliescold

Westerlies, warm

High pressuresubtropical

warm

Polar

front

Low pressurezone

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And end up moving

parallel to the isobars

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Fou

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!"#$%#&#'()$*+'*,)(-+.&

+&$($'.-(-+&%$(-/.01"#'#

Forming a complex global circulation system

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!"#$%#&#'()$*+'*,)(-+.&

/&$($'.-(-+&%$(-0.12"#'#

3#(-$-'(&14#'$56

7+'#*-$-"#'0()$*#))

3#(-$-'(&14#'$56

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The forces of the pressure gradient...Pressure, mb

Isobaric surfaces

surface of the ground

surface of the ground

Pressure, mb

pressure gradienthigher pressure

lower pressure

map at 1,000m altitude

isob

ar

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...generate winds

The sea breeze

Sea Land

Day

Night

Sea Land

Plane

Valley

Plane

Valley

War

mW

arm

Col

dC

old

Pressure gradient

Pressure gradient

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14The up-valley and down-valley winds

...generate winds

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The hydrostatic equilibrium of the atmosphere

Column with section of unit area

Ground

Pressure = p + dp

Pressure = p

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dp = −g(z) ρ(z)dz

The hydrostatic equilibrium of the atmosphere

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dp = −g(z) ρ(z)dz

V a r i a t i o n i n pressure

The hydrostatic equilibrium of the atmosphere

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dp = −g(z) ρ(z)dz

V a r i a t i o n i n pressure

Acce l e ra t i on due to gravity

The hydrostatic equilibrium of the atmosphere

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dp = −g(z) ρ(z)dz

V a r i a t i o n i n pressure

Acce l e ra t i on due to gravity

Air density

The hydrostatic equilibrium of the atmosphere

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dp = −g(z) ρ(z)dz

V a r i a t i o n i n pressure

Acce l e ra t i on due to gravity

Air density

Thickness of the air layer

The hydrostatic equilibrium of the atmosphere

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dp = −g(z) ρ(z)dz

Ideal Gas Law

ρ(z) =p(z)

R T (z)

The hydrostatic equilibrium of the atmosphere

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dp = −g(z) ρ(z)dz

Temperature

Pressureρ(z) =

p(z)R T (z)

The hydrostatic equilibrium of the atmosphere

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dp = −g(z) ρ(z)dz

Air constant

Temperature

Pressureρ(z) =

p(z)R T (z)

The hydrostatic equilibrium of the atmosphere

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dp = −g(z) ρ(z)dz

Air constant

Temperature

Air density

Pressureρ(z) =

p(z)R T (z)

The hydrostatic equilibrium of the atmosphere

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dp(z) = −g(z)p(z)

R T (z)dz

dp

p= −g(z)

p(z)R T (z)

dz

� p(z)

p(0)

dp

p= −

� z

0g(z)

p(z)R T (z)

dz

The hydrostatic equilibrium of the atmosphere

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logp(z)p(0)

= −� z

0

g(z)R T (z)

dz

logp(z)p(0)

≈ g

R

� z

0

1T (z)

dz

The hydrostatic equilibrium of the atmosphere

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The first law of thermodynamicswith the help of the second

U = U(S, V )

Equilibrium thermodynamics states that the internal energy of a system is a

function of Entropy and Volume:

As a consequence, every variation in internal energy is given by:

∂U()∂S

:= T (S, V )

dU() = T ()dS − pU ()dV

∂U()∂V

:= −pU (S, V )

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The first law of thermodynamicswith the help of the second

U = U(S, V )

Equilibrium thermodynamics states that the internal energy of a system is a

function of Entropy and Volume:

As a consequence, every variation in internal energy is given by:

∂U()∂S

:= T (S, V )

Temperature

dU() = T ()dS − pU ()dV

∂U()∂V

:= −pU (S, V )

21

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The first law of thermodynamicswith the help of the second

U = U(S, V )

Equilibrium thermodynamics states that the internal energy of a system is a

function of Entropy and Volume:

As a consequence, every variation in internal energy is given by:

∂U()∂S

:= T (S, V )

Temperature pressure

dU() = T ()dS − pU ()dV

∂U()∂V

:= −pU (S, V )

21

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U = U(S, V )

Variation of internal energy

heat exchanged by the system

work done by the system

dU() = T ()dS − pU ()dV

The first law of thermodynamicswith the help of the second

As a consequence, every variation in internal energy is given by:

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Equilibrium thermodynamics states that the internal energy of a system is a

function of Entropy and Volume:

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UT := U(S(T, V ), V )

However, while temperature is directly measurable, entropy is not - a

consequence of the second law of thermodynamics. For this reason it is

preferred to express entropy as a function of temperature, by means of a

change of variables. In this case, it should be observed that entropy is not

solely a function of temperature, but also of volume:

pS() :=∂U()∂S

∂S()∂V

dUT = CV ()dT + (pS()− pU ())dV

The first law of thermodynamicswith the help of the second

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UT := U(S(T, V ), V )

However, while temperature is directly measurable, entropy is not - a

consequence of the second law of thermodynamics. For this reason it is

preferred to express entropy as a function of temperature, by means of a

change of variables. In this case, it should be observed that entropy is not

solely a function of temperature, but also of volume:

Entropic PressurepS() :=

∂U()∂S

∂S()∂V

dUT = CV ()dT + (pS()− pU ())dV

The first law of thermodynamicswith the help of the second

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The sum of the two pressures, entropic ed energetic, if so they can be defined,

is the normal pressure:

p() := pS()− pU ()

The first law of thermodynamicswith the help of the second

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By definition (!) the internal energy of an ideal gas does NOT explicitly

depend on the volume. Therefore:

Variation of internal energy

heat exchanged by the system

U = U(S)

dU() = T ()dS !!!!!!! =⇒ dQ() = dU()

The first law of thermodynamicswith the help of the second

As a consequence, every variation in internal energy is given by:

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Therefore, for an ideal gas:

CV () :=∂UT

∂T

or:

dividing the expression by the mass of air present in the volume:

dUT = dQ() = CV ()dT + ps()dV

dUT = CV ()dT + d(ps() V )− V dps()

The first law of thermodynamicswith the help of the second

26

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Therefore, for an ideal gas:

CV () :=∂UT

∂T

or:

dividing the expression by the mass of air present in the volume:

dUT = dQ() = CV ()dT + ps()dV

dUT = CV ()dT + d(ps() V )− V dps()

The first law of thermodynamicswith the help of the second

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specific heat at constant volume

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v :=1ρ

duT = cV ()dT + d(ps() v)− v dps()

dividing the expression by the mass of air present in the volume:

The first law of thermodynamicswith the help of the second

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v :=1ρ

specific volume

duT = cV ()dT + d(ps() v)− v dps()

dividing the expression by the mass of air present in the volume:

The first law of thermodynamicswith the help of the second

27

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And using the ideal gas law per unit of mass:

ps() v = R T

The following results:

duT = cV ()dT + d(R T )− v dps()

duT = cV ()dT − d(ps() v) + v dps()

The first law of thermodynamicswith the help of the second

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Which can be rewritten as (in this case being du = dq):

During isobaric transformations, by definition, dp() = 0, and

dq|p = (cV () + R) dT = cpdT

cp() := cv() + R

cp is known as specific heat at constant pressure

dq = (cV () + R) dT − v dp()

The first law of thermodynamicswith the help of the second

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Adiabatic lapse rate

The information given in the first law of thermodynamics can be

combined with that obtained from the law of hydrostatics. In fact,

assuming that a rising parcel of air is subject to an adiabatic

process, then:

v dps() = −g dz

dq() = cp() dT + v dps()

dq() = 0

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Resolving the previous system results in:

dT

dz= −Γd

Γd :=g

cp≈ 9.8◦K Km−1

Adiabatic lapse rate

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So what happens when a balloon rises?

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The conditions of atmospheric stability

Temperature

STABLE AIR

Temperature

Altitude Temperature

GROUND LEVEL

1. The wind pushes the parcels of air at 21°C up the hill

2. The moving air cools to 18.3°C

3. The air is cooler than the surrounding air and therefore it drops

Alti

tude

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The conditions of atmospheric stability

Temperature

STABLE AIR

Temperature

Altitude Temperature

GROUND LEVEL

1. The wind pushes the parcels of air at 21°C up the hill

2. The moving air cools to 18.3°C

3. The air is cooler than the surrounding air and therefore it drops

Alti

tude

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The conditions of atmospheric stability

Temperature

STABLE AIR

Temperature

Altitude Temperature

GROUND LEVEL

1. The wind pushes the parcels of air at 21°C up the hill

2. The moving air cools to 18.3°C

3. The air is cooler than the surrounding air and therefore it drops

Alti

tude

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The conditions of atmospheric instability

Temperature

UNSTABLE AIR

Altitude Temperature

GROUND LEVEL

1. The wind pushes the parcels of air at 21°C up the hill

2. The moving air cools to 18.1°C

3. The air is warmer than the surrounding air and therefore continues to rise

4. The air at 15.1°C continues to rise

5. The air at 12.1°C continues to rise

6. The air at 9.1°C continues to rise

Alti

tude

At altitude the air is relatively cool

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The conditions of atmospheric instability

Temperature

UNSTABLE AIR

Altitude Temperature

GROUND LEVEL

1. The wind pushes the parcels of air at 21°C up the hill

2. The moving air cools to 18.1°C

3. The air is warmer than the surrounding air and therefore continues to rise

4. The air at 15.1°C continues to rise

5. The air at 12.1°C continues to rise

6. The air at 9.1°C continues to rise

Alti

tude

At altitude the air is relatively cool

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What happens when water vapour is added?

The water content of the atmosphere is specified by the mixing

ratio w : w =

Mv

Md=

ρv

ρd

where Mv is the mass of vapour and Md is the mass of dry air.

Alternatively, one can refer to the specific humidity, q:

q =Mv

Md + Mv=

ρv

ρd + ρv≈ w

where the last equality is valid for Mv<<Md, which is generally true.

Given that humid air can be considered, in good approximation, an

ideal gas its degrees of freedom are restricted once more by the

ideal gas law:p = ρRT

where the value of the constant depends on the humidity. At the

extremes the values are Rd=287J.K-1kg-1 for dry air and

Rv=461J.K-1kg-1 for vapour.

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What happens when water vapour is added?

Let us now introduce a thermodynamic parameter, the potential

temperature θ, that takes account of this phenomenon. It is

defined as the temperature of a parcel of air that has moved

adiabatically from a starting point with temperature T and

pressure p to a reference altitude (and therefore reference

pressure), conventionally set at p0=1,000hPa (sea level). In other

words it describes an adiabatic transformation from (p,T) to

(p0, θ). Qualitatively, the potential temperature represents a

temperature correction based on the altitude.

θv = Tv

�p0

p

�Rd/cop

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Conditional stability

Alti

tude

Temperature

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Conditional stability

Alti

tude

Temperature

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Conditional stability

Alti

tude

Temperature

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!"#$%$&$'%('#()*+,

!"##$%&'()"&*&+,-."#

+()/&'()"&*&0)1(-$)2")3

+$4(3(1"&5-",&*&65+0

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CAPEconvective available potential energy

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The temporal variability of stability

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The temporal variability of stability

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FREE TROPOSPHERE

RESIDUAL

LAYER

STABLE LAYER

MIXED LAYERB

L G

row

th

Eddies/Plumes

STABLE LAYER

RESIDUAL

LAYER

Entrainment

Diurnal Evolution of the ABL

Kumar et al., WRRKumar et al. WRR, 2006

Kleissl et al. WRR, 2006Albertson and P., WRR, AWR 1999

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Stable vs. Convective Boundary Layer (Potential Temp.)

SBL

CBL

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Precipitations

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The temporal variability of stability

Alti

tude

(km

)Inversion layer

Alti

tude

(km

)

Surface layer

Surface layer

Mixed layer

Inversion layer

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The mechanisms of precipitation formation:

- Convective

- Frontal

- Orographic

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The convective mechanism

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The convective mechanism

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Th

e fr

on

tal

mec

han

ism

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!"#$%#&#'()$*+'*,)(-+.&

+&$($'.-(-+&%$(-/.01"#'#Deja Vu

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High pressurepolar, cold

Easterliescold

Westerlies, warm

High pressuresubtropical

warm

Polar

front

Low pressurezone

Dej

a V

u

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Th

e fr

on

tal

mec

han

ism

Initial stage Open stage

Occlusion stage DIssolution stage

Warm air(less dense)

Cold air(dense)

Cold air

Warm air

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Th

e oro

gra

ph

ic m

ech

anis

m

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Passage of low pressure center over mountains

Whiteman (2000)

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Th

e oro

gra

ph

ic m

ech

anis

m

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Th

e oro

gra

ph

ic m

ech

anis

m

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T=318 min

Rainfall evolution over topography

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Rainfall evolution over topography

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T=516 min

Rainfall evolution over topography

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Rainfall evolution over topography

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T=672 min

Rainfall evolution over topography

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Rainfall evolution over topography

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A. A

dam

s -

Pio

ggia

Ten

aya,

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Why it rains

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Why it rains

•Large-scale atmospheric movements are caused by the variability of solar

radiation at the Earth’s surface, due to the spherical shape of the Earth.

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Why it rains

•Large-scale atmospheric movements are caused by the variability of solar

radiation at the Earth’s surface, due to the spherical shape of the Earth.

•Also, given the rotation of the Earth about its own axis, every air mass in

movement is deflected because of the (apparent) Coriolis force.

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Why it rains

•Large-scale atmospheric movements are caused by the variability of solar

radiation at the Earth’s surface, due to the spherical shape of the Earth.

•This situation:

•generates movements between “quasi-stable” positions of high and low

pressures

•causes large-scale discontinuities in the air’s flow field and discontinuities

of the thermodynamic properties of the air masses in contact with one

another

•generates, therefore, the situation where the lighter masses of air “slide”

over heavier ones, being lifted upwards in the process.

•Also, given the rotation of the Earth about its own axis, every air mass in

movement is deflected because of the (apparent) Coriolis force.

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Why it rains

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•The surface of the Earth is composed of various material masses (air, water,

soil) that are oriented differently. They each respond to solar radiation in

different ways causing further movements of the air masses (at the scale of the

variability that presents itself) in order to redistribute the incoming radiant

energy.

Why it rains

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•The surface of the Earth is composed of various material masses (air, water,

soil) that are oriented differently. They each respond to solar radiation in

different ways causing further movements of the air masses (at the scale of the

variability that presents itself) in order to redistribute the incoming radiant

energy.

•Because of these movements, localised lifting of air masses can occur.

Why it rains

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•The surface of the Earth is composed of various material masses (air, water,

soil) that are oriented differently. They each respond to solar radiation in

different ways causing further movements of the air masses (at the scale of the

variability that presents itself) in order to redistribute the incoming radiant

energy.

•Because of these movements, localised lifting of air masses can occur.

•Moving masses of air are lifted by the presence of orography.

Why it rains

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•The surface of the Earth is composed of various material masses (air, water,

soil) that are oriented differently. They each respond to solar radiation in

different ways causing further movements of the air masses (at the scale of the

variability that presents itself) in order to redistribute the incoming radiant

energy.

•Because of these movements, localised lifting of air masses can occur.

•Moving masses of air are lifted by the presence of orography.

• Heating of the Earth’s surface also causes air to be lifted, causing conditions

of atmospheric instability.

Why it rains

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Why it rains

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•As air rises it cools, due to adiabatic (isentropic) expansion, and the

equilibrium vapour pressure is reduced. Hence, the condensation of water

vapour becomes possible (though not always probable).

Why it rains

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•As air rises it cools, due to adiabatic (isentropic) expansion, and the

equilibrium vapour pressure is reduced. Hence, the condensation of water

vapour becomes possible (though not always probable).

•In this way, at a suitable altitude above the ground, clouds are formed: particles

of liquid or solid water suspended in the air.

Why it rains

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•As air rises it cools, due to adiabatic (isentropic) expansion, and the

equilibrium vapour pressure is reduced. Hence, the condensation of water

vapour becomes possible (though not always probable).

•In this way, at a suitable altitude above the ground, clouds are formed: particles

of liquid or solid water suspended in the air.

Why it rains

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•As air rises it cools, due to adiabatic (isentropic) expansion, and the

equilibrium vapour pressure is reduced. Hence, the condensation of water

vapour becomes possible (though not always probable).

•In this way, at a suitable altitude above the ground, clouds are formed: particles

of liquid or solid water suspended in the air.

Storm building near Arvada, Colorado. U.S. © Brian Boyle.

Why it rains

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•If the particles are able to increase in size to the point of reaching sufficient

weight they precipitate to the ground. Rain, snow or hail.

Precipitation, Thriplow in Cambridgeshire. U.K © John Deed.

Why it rains

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Stratiform clouds

69

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70

Stratiform clouds

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Extr

atro

pic

al c

ycl

on

e

71

Hou

ze,

1

99

4

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Cloudbursts

72

Hou

ze,

1

99

4

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73

Hou

ze,

1

99

4

Cloudbursts

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Factors that influence the nature and quantity of precipitation at the ground

•Latitude: precipitations are distributed over the surface of the Earth in

function of the general circulation systems.

•Altitude: precipitation (mean annual) tends to grow with altitude - up to a

limit (the highest altitudes are arid, on average).

•Position with respect to the oceanic masses, the prevalent winds, and the

general orographic position.

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F. G

iorg

iou

, 2

00

8

75

Spat

ial

dis

trib

uti

on

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76

Spat

ial

dis

trib

uti

on

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Precipitation exhibits spatial variability at a large range of scales

(mm/hr)

512 k

m

pixel = 4 km

0 4 9 13 17 21 26 30R (mm/hr)

2

km

4

km

pixel = 125 m

Fou

fula

-Geo

rgio

u, 2

00

8

77

Spat

ial

dis

trib

uti

on

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!"#$%#&'(#%)*#&&

Fou

fula

-Geo

rgio

u, 2

00

8

78

Spat

ial

dis

trib

uti

on

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Spatial distribution

79

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Characteristics of precipitation at the ground

•The physical state (rain, snow, hail, dew)

•Depth: the quantity of precipitation per unit area (projection),

often expressed in mm or cm.

•Duration: the time interval during which continuous precipitation is

registered, or, depending on the context, the duration to register a

certain amount of precipitation (independently of its continuity)

•Cumulative depth, the depth of precipitation measured in a pre-fixed

time interval, even if due to more than one event.

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•Storm inter-arrival time

•The spatial distribution of the rain volumes

•The frequency or return period of a certain precipitation event with

assigned depth and duration

•The quality, that is to say the chemical composition of the

precipitation

Characteristics of precipitation at the ground

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Events

1

2 3

4

5 6

82

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!"#$%&'()*'+,-'((

Fou

fula

-Geo

rgio

u, 2

00

8

83

Temporal Rainfall Questo titolo era gia in inglese e l’ho lasciato - ma non mi e` chiaro!JT

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84

Mon

thly

pre

cip

itat

ion

h

isto

gra

ms

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Stat

isti

cs

85

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86

Du

rati

on

sa

logn

orm

al d

istr

ibu

tion

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87

Inte

nsi

tylo

gn

orm

al ?

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88

Extr

eme

pre

cip

itat

ion

s

Saturday, September 11, 2010

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Kan

din

ski

-Com

posi

tion

VI

(Il

dil

uvi

o)-

19

13

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Objectives:

90

•Describe extreme precipitation events and their characteristics

•Calculate the extreme precipitations of assigned return period with R

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Let is consider the maximum annual precipitationsThese can be found in hydrological records, registered by characteristic durations:

1h, 3h, 6h,12h 24 h and they represent the maximum cumulative rainfall over the

pre-fixed time.

91

year 1h 3h 6h 12h 24h1 1925 50.0 NA NA NA NA2 1928 35.0 47.0 50.0 50.4 67.6

......................................

......................................

46 1979 38.6 52.8 54.8 70.2 84.247 1980 28.2 42.4 71.4 97.4 107.451 1987 32.6 40.6 64.6 77.2 81.252 1988 89.2 102.0 102.0 102.0 104.2

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92

Let is consider the maximum annual precipitations

for each duration there is a precipitation distribution

Precipitazioni Massime a Paperopoli

durata

Pre

cip

ita

zio

ne

(m

m)

1 3 6 12 24

50

100

150

50

100

150

Pre

cipi

tatio

n (m

m)

Duration

Maximum Precipitations at Toontown

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1 3 6 12 24

50

100

150

Precipitazioni Massime a Paperopoli

durata

Pre

cip

itazio

ne (

mm

)

Median

>boxplot(hh ~ h,xlab="duration",ylab="Precipitation (mm)",main="Maximum Precipitations at Toontown") 93

Let is consider the maximum annual precipitations

Pre

cipi

tatio

n (m

m)

Duration

Maximum Precipitations at Toontown

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1 3 6 12 24

50

100

150

Precipitazioni Massime a Paperopoli

durata

Pre

cip

itazio

ne (

mm

)

upper quantile

94

Let is consider the maximum annual precipitations

Pre

cipi

tatio

n (m

m)

Duration

Maximum Precipitations at Toontown

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1 3 6 12 24

50

100

150

Precipitazioni Massime a Paperopoli

durata

Pre

cip

itazio

ne (

mm

)

lower quantile

95

Let is consider the maximum annual precipitations

Pre

cipi

tatio

n (m

m)

Duration

Maximum Precipitations at Toontown

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1 ora

Precipitazion in mm

Frequenza

20 40 60 80

05

10

15

20

25

3 ore

Precipitazion in mm

Frequenza

20 40 60 80 100

05

10

15

6 ore

Precipitazion in mm

Frequenza

40 60 80 1000

510

15

96

Freq

uenc

y

Precipitation (mm)

Freq

uenc

y

Freq

uenc

y

Precipitation (mm) Precipitation (mm)

6 hours 3 hour 1 hour

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12 ore

Precipitazion in mm

Frequenza

40 60 80 100 120

02

46

8

24 ore

Precipitazion in mm

Frequenza

40 80 120 160

02

46

810

12

97

Freq

uenc

y

Precipitation (mm)

12 hours

Freq

uenc

y

Precipitation (mm)

24 hours

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Return period

It is the average time interval in which a certain precipitation intensity is

repeated (or exceeded).

Let:

T

be the time interval for which a certain measure is available.

Let:

n

be the measurements made in T.

And let:

m=T/n

be the sampling interval of a single measurement (the duration of the event in

consideration).

98

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Then, the return period for the depth h* is:

99

where Fr= l/n is the success frequency (depths greater or equal to h*).

If the sampling interval is unitary (m=1), then the return period is the

inverse of the exceedance frequency for the value h*.

Tr :=T

l= n

m

l=

m

ECDF (h∗) =m

1− Fr(H < h∗)

N.B. On the basis of the above, there is a bijective relation between

quantiles and return period

Return period

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1 3 6 12 24

50

100

150

Precipitazioni Massime a Paperopoli

durata

Pre

cip

itazio

ne (

mm

)

Median -> q(0.5) -> Tr = 2 yearsq(0.25) -> Tr = 1.33 years

100

Pre

cipi

tatio

n (m

m)

Duration

Maximum Precipitations at Toontown

q(0.75) -> Tr = 4 years

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h(tp, Tr) = a(Tr) tnp

101

Rainfall Depth-Duration-Frequency (DDF) curves

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h(tp, Tr) = a(Tr) tnp

102

depth of precipitation

power law

Rainfall Depth-Duration-Frequency (DDF) curves

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h(tp, Tr) = a(Tr) tnp

103

coefficient dependent on the return period

depth of precipitation

Rainfall Depth-Duration-Frequency (DDF) curves

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h(tp, Tr) = a(Tr) tnp

104

duration considered

depth of precipitation

Rainfall Depth-Duration-Frequency (DDF) curves

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h(tp, Tr) = a(Tr) tnp

105

exponent (not dependent on t h e r e t u r n period)

depth of precipitation

Rainfall Depth-Duration-Frequency (DDF) curves

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h(tp, Tr) = a(Tr) tnp

Given that the depth of cumulated precipitation is a non-decreasing function

of duration, it therefore stands that n >0

Also, it is known that average intensity of precipitation:

J(tp, Tr) :=h(tp, Tr)

tp= a(Tr) tn−1

p

decreases as the duration increases. Therefore, we also have n < 1

Rainfall Depth-Duration-Frequency (DDF) curves

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Tr = 50 years a = 36.46 n = 0.472 Tr = 100 years a = 40.31Tr = 200 years a = 44.14

curve di possibilità pluviometrica

1.4

1.5

1.6

1.7

1.8

1.9

2

2.1

2.2

2.3

2.4

1 10 100tp[h]

log(prec) [mm]

tr=50 annitr=100 annitr=200 annia 50a 100a 200

107

Rainfall Depth-Duration-Frequency (DDF) curves

Tr=50 years

Tr=100 years

Tr=200 years

DDF Curve

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curve di possibilità pluviometrica

1.4

1.5

1.6

1.7

1.8

1.9

2

2.1

2.2

2.3

2.4

1 10 100tp[h]

log(prec) [mm]

tr=50 annitr=100 annitr=200 annia 50a 100a 200

DDF curves are parallel to each other in the bilogarithmic plane

108

Tr=50 years

Tr=100 years

Tr=200 years

DDF Curve

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curve di possibilità pluviometrica

1.4

1.5

1.6

1.7

1.8

1.9

2

2.1

2.2

2.3

2.4

1 10 100tp[h]

log(prec) [mm]

tr=50 annitr=100 annitr=200 annia 50a 100a 200

tr = 500 years

tr = 200 yearsh(,500) > h(200)

109

DDF curves are parallel to each other in the bilogarithmic plane

Tr=50 years

Tr=100 yearsTr=200 years

DDF Curve

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curve di possibilità pluviometrica

1.4

1.5

1.6

1.7

1.8

1.9

2

2.1

2.2

2.3

2.4

1 10 100tp[h]

log(prec) [mm]

tr=50 annitr=100 annitr=200 annia 50a 100a 200

tr = 500 years tr = 200 years

Invece h(,500) < h(200) !!!!

110

DDF curves are parallel to each other in the bilogarithmic plane

Tr=50 years

Tr=100 yearsTr=200 years

DDF Curve

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The problem to solve using probability theory and statistical analysis...

...is, therefore, to determine, for each duration, the correspondence between

quantiles (assigned return periods) and the depth of precipitation

For each duration, the data will need to be interpolated to a probability distribution. The family of distribution curves suitable to this scope is the Type I Extreme Value Distribution, or the Gumbel Distribution

b is a form parameter, a is a position parameter (it is, in effect, the mode)

P [H < h; a, b] = e−e−

h−ab −∞ < h <∞

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Gumbel Distribution

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Gumbel Distribution

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The distribution mean is given by:

E[X] = bγ + a

where:

is the Euler-Mascheroni constant

γ ≈ 0.57721566490153228606

Gumbel Distribution

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The median:

The variance:

a− b log(log(2))

V ar(X) = b2 π2

6

Gumbel Distribution

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The standard form of the distribution (with respect to which there are tables

of the significant values) is

P [Y < y] = ee−y

Gumbel Distribution

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117

Gumbel Distribution

which yields:

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In order to adapt the family of Gumbel distributions to the data of interest methods of adjusting the parameters are used.

We shall use three:

- The method of the least squares

- The method of moments

- The method of maximum likelihood

Let us consider, therefore, a series of n measures, h = {h1, ....., hn}

118

Methods of adjusting parameterswith respect to the Gumbel distribution but having general validity

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The method of moments consists in equalising the moments of the sample with the moments of the population. For example, let us consider

The mean and the variance and

the t-th moment of the SAMPLE

119

µH

σ2H

M (t)H

Methods of adjusting parameterswith respect to the Gumbel distribution but having general validity

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If the probabilistic model has t parameters, then the method of

moments consists in equalising the t sample moments with the t

population moments, which are defined by:

In order to obtain a sufficient number of equations one must consider as

many moments as there are parameters. Even though, in principle, the resulting parameter function can be solved numerically by points, the method becomes effective when the integral in the second member admits an analytical solution.

120

MH [t; θ] =� ∞

−∞(h− EH [h])t pdfH(h; θ) dh t > 1

MH [1; θ] = EH [h] =� ∞

−∞h pdfH(h; θ) dh

Methods of adjusting parameterswith respect to the Gumbel distribution but having general validity

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The application of the method of moments to the Gumbel distribution

consists, therefore, in imposing:

or:

�bγ + a = µH

b2 π2

6 = σ2H

�MH [1; a, b] = µH

MH [2; a, b] = σ2H

Methods of adjusting parameterswith respect to the Gumbel distribution but having general validity

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The method is based on the evaluation of the (compound) probability of

obtaining the recorded temporal series:

P [{h1, · · ·, hN}; a, b]

In the hypothesis of independence of observations, the probability is:

P [{h1, · · ·, hN}; a, b] =N�

i=1

P [hi; a, b]

The method of maximum likelihoodwith respect to the Gumbel distribution but having general validity

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This probability is also called the likelihood function - it is evidently a

function of the parameters. In order to simplify calculation the log-

likelihood is also defined:

123

P [{h1, · · ·, hN}; a, b] =N�

i=1

P [hi; a, b]

log(P [{h1, · · ·, hN}; a, b]) =N�

i=1

log(P [hi; a, b])

The method of maximum likelihoodwith respect to the Gumbel distribution but having general validity

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124

If the observed series is sufficiently long, it is assumed that it must be such that

the probability of observing it is maximum. Then, the parameters of the curve

that describe the population can be obtained from:

�∂ log(P [{h1,···,hN};a,b])

∂a = 0∂ log(P [{h1,···,hN};a,b])

∂b = 0

Which gives a system of two non-linear equations with two unknowns.

The method of maximum likelihoodwith respect to the Gumbel distribution but having general validity

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125

e.g. Adjusting the Gumbel DistributionThe logarithm of the likelihood function, in this case, assumes the form:

Deriving with respect to u and α the following relations are obtained:

That is:

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The method of least squares

It consists of defining the the standard deviation of the measures, the ECDF,

and the probability of non-exceedance:

δ2(θ) =

n�

i=1

(Fi − P [H < hi; θ])2

and then minimising it

126

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Standard deviation

The method of least squares

It consists of defining the the standard deviation of the measures, the ECDF,

and the probability of non-exceedance:

δ2(θ) =

n�

i=1

(Fi − P [H < hi; θ])2

and then minimising it

126

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ECDFStandard deviation

The method of least squares

It consists of defining the the standard deviation of the measures, the ECDF,

and the probability of non-exceedance:

δ2(θ) =

n�

i=1

(Fi − P [H < hi; θ])2

and then minimising it

126

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ProbabilityECDFStandard deviation

The method of least squares

It consists of defining the the standard deviation of the measures, the ECDF,

and the probability of non-exceedance:

δ2(θ) =

n�

i=1

(Fi − P [H < hi; θ])2

and then minimising it

126

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∂δ2(θj)∂θj

= 0 j = 1 · · · m

The minimisation is obtained by deriving the standard deviation expression

with respect to the m parameters

so obtaining the m equations, with m unknowns, that are necessary.

127

The method of least squares

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we have, as a result, three pairs of parameters which are all, to a certain extent, optimal. In order to distinguish which of these sets of parameters is the best we must use a confrontation criterion (a non-parametric test). We will use Pearson’s Test.

128

After the application of the various adjusting methods...

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Pearson’s test is NON-parametric and consists in:

1 - Sub-dividing the probability field into k parts. These can be, for example, of equal size.

129

Pearson’s Test

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130

Pearson’s Test

Pearson’s test is NON-parametric and consists in:

2 - From this sub-division, deriving a sub-division of the domain.

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131

Pearson’s Test

Pearson’s test is NON-parametric and consists in:

3 - Counting the number of data in each interval (of the five in the figure).

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Pearson’s test is NON-parametric and consists in:

4 - Evaluating the function:

P [H < h0] = P [H < 0]

P [H < hn+1] = P [H <∞]

where:

in the case of the figure of the previous slides we have:

(P [H < hj+1]− P [H < hj ]) = 0.2

X2 =

1n + 1

n+1�

j=0

(Nj − n (P [H < hj+1]− P [H < hj ])2

n (P [H < hj+1]− P [H < hj ])

132

Pearson’s Test

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0 50 100 150

0.0

0.2

0.4

0.6

0.8

1.0

Precipitazione [mm]

P[h]

1h

3h

6h

12h

24h

133

After having applied Pearson’s test...

Precipitation (mm)

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0 50 100 150

0.0

0.2

0.4

0.6

0.8

1.0

Precipitazione [mm]

P[h]

1h

3h

6h

12h

24h

Tr = 10 anni

h1 h3 h6 h12 h24

134

After having applied Pearson’s test...

Precipitation (mm)

Tr = 10 years

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0 5 10 15 20 25 30 35

40

60

80

100

120

140

160

180

Linee Segnalitrici di Possibilita' Pluviometrica

h [mm]

t [o

re]

135

By interpolation one obtains...

DDF Curves

t (ho

urs)

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0.5 1.0 2.0 5.0 10.0 20.0

60

80

100

120

140

160

Linee Segnalitrici di Possibilita' Pluviometrica

t [ore]

h [

mm

]

136

By interpolation one obtains...

DDF Curves

t (hours)

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Riccardo Rigon

χ2

If a variable, X, is distributed normally with null mean and unit variance, then the variable

is distributed according to the “Chi squared” distribution (as proved by Ernst Abbe, 1840-1905) and it is indicated

which is a monoparametric distribution of the Gamma family of distributions. The only parameter is called “degrees of freedom”.

137

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In fact, the distribution is:

And its cumulated probability is:

where is the incomplete “gamma” functionγ()

χ2

from Wikipedia

138

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γ(s, z) :=� x

0ts−1 e−tdt

The incomplete gamma function

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Riccardo Rigon

χ2

from Wikipedia

140

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The expected value of the distribution is equal to the number of degrees of freedom

χ2

The variance is equal to twice the number of degrees of freedom

E(χk) = k

V ar(χk) = 2k

from Wikipedia

141

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Riccardo Rigon

Generally, the distribution is used in statistics to estimate the goodness of an

inference. Its general form is:

χ2

Assuming that the root of the variables represented in the summation has a

gaussian distribution, then it is expected that the sum of squares variable is

distributed according to with a number of degrees of freedom equal to

the number of addenda reduced by 1.

χ2

χ2

from Wikipedia

142

χ2=

� (Observed− Expected)2

Expected

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The distribution is important because we can make two mutually exclusive hypotheses. The null hypothesis:

χ2

It is conventionally assumed that the alternative hypothesis can be excluded from being valid if X^2 is inferior to the 0.05 quantile of the distribution with the appropriate number of degrees of freedom.

χ2

from Wikipedia

And its opposite, the alternative hypothesis:

that the sample and the population have the same distribution

that the sample and the population do NOT have the same distribution

χ2

143

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Extreme Events - GEV

Riccardo Rigon

Mic

hel

angel

o, I

l d

ilu

vio,

15

08

-15

09

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A little more formally

The choice of the Gumbel distribution is not a whim, it is due to a Theorem which states that, under quite general hypotheses, the distribution of maxima chosen from samples that are sufficiently numerous can only belong to one of the following families of distributions:

I) The Gumbel Distribution

G(z) = e−e−z−b

a −∞ < z <∞a > 0

145

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II) The Frechèt Distribution

G(z) =

�0 z ≤ b

e−( z−ba )−α

z > b

α > 0a > 0

146

A little more formally

The choice of the Gumbel distribution is not a whim, it is due to a Theorem, which states that, under quite general hypotheses, the distribution of maxima chosen from samples that are sufficiently numerous can only belong to one of the following families of distributions:

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Mean

Mode

Median

Variance

P [X < x] = e−x−α

II) The Frechèt Distribution from Wikipedia

147

A little more formally

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dfrechet(x, loc=0, scale=1, shape=1, log = FALSE) pfrechet(q, loc=0, scale=1, shape=1, lower.tail = TRUE) qfrechet(p, loc=0, scale=1, shape=1, lower.tail = TRUE)rfrechet(n, loc=0, scale=1, shape=1)

R:

148

A little more formally

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α > 0a > 0

G(z) =

�e−[−( z−b

a )]−α

z < b1 z ≥ b

III) The Weibull Distribution

149

A little more formally

The choice of the Gumbel distribution is not a whim, it is due to a Theorem, which states that, under quite general hypotheses, the distribution of maxima chosen from samples that are sufficiently numerous can only belong to one of the following families of distributions:

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from Wikipedia

III) The Weibull Distribution(P. Rosin and E. Rammler, 1933)

150

A little more formally

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When k = 1, the Weibull distribution reduces to the exponential distribution. When k = 3.4, the Weibull distribution becomes very similar to the normal distribution.

Mean

Mode

Median

Variance

from Wikipedia

151

A little more formally

III) The Weibull Distribution(P. Rosin and E. Rammler, 1933)

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dweibull(x, shape, scale = 1, log = FALSE)pweibull(q, shape, scale = 1, lower.tail = TRUE, log.p = FALSE)qweibull(p, shape, scale = 1, lower.tail = TRUE, log.p = FALSE)rweibull(n, shape, scale = 1)

R:

152

A little more formally

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For the distribution reduces to the Gumbel distribution

For the distribution becomes a Frechèt distribution

For the distribution becomes a Weibull distribution

ξ = 0ξ > 0ξ < 0

The aforementioned theorem can be reformulated in terms of a three-parameter distribution called the Generalised Extreme Values (GEV) Distribution.

G(z) = e−[1+ξ( z−µσ )]−1/ξ

z : 1 + ξ(z − µ)/σ > 0−∞ < µ <∞ σ > 0

−∞ < ξ <∞

153

A little more formally

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Riccardo Rigon

G(z) = e−[1+ξ( z−µσ )]−1/ξ

z : 1 + ξ(z − µ)/σ > 0−∞ < µ <∞ σ > 0

−∞ < ξ <∞

154

A little more formally

The aforementioned theorem can be reformulated in terms of a three-parameter distribution called the Generalised Extreme Values (GEV) Distribution.

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gk = Γ(1− kξ)

155

A little more formally

The aforementioned theorem can be reformulated in terms of a three-parameter distribution called the Generalised Extreme Values (GEV) Distribution.

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Riccardo Rigon

dgev(x, loc=0, scale=1, shape=0, log = FALSE) pgev(q, loc=0, scale=1, shape=0, lower.tail = TRUE) qgev(p, loc=0, scale=1, shape=0, lower.tail = TRUE)rgev(n, loc=0, scale=1, shape=0)

R

156

A little more formally

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Bibliography and Further Reading

Riccardo Rigon

•Albertson, J., and M. Parlange, Surface Length Scales and Shear Stress: Implications

for Land-Atmosphere Interaction Over Complex Terrain, Water Resour. Res., vol. 35,

n. 7, p. 2121-2132, 1999

•Burlando, P. and R. Rosso, (1992) Extreme storm rainfall and climatic change,

Atmospheric Res., 27 (1-3), 169-189.

•Burlando, P. and R. Rosso, (1993) Stochastic Models of Temporal Rainfall:

Reproducibility, Estimation and Prediction of Extreme Events, in: Salas, J.D., R.

Harboe, e J. Marco-Segura (eds.), Stochastic Hydrology in its Use in Water Resources

Systems Simulation and Optimization, Proc. of NATO-ASI Workshop, Peniscola,

Spain, September 18-29, 1989, Kluwer, pp. 137-173.

Bibliography and Further Reading

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Bibliography and Further Reading

Riccardo Rigon

•Burlando, P. e R. Rosso, (1996) Scaling and multiscaling Depth-Duration-Frequency

curves of storm precipitation, J. Hydrol., vol. 187/1-2, pp. 45-64.

•Burlando, P. and R. Rosso, (2002) Effects of transient climate change on basin

hydrology. 1. Precipitation scenarios for the Arno River, central Italy, Hydrol.

Process., 16, 1151-1175.

•Burlando, P. and R. Rosso, (2002) Effects of transient climate change on basin

hydrology. 2. Impacts on runoff variability of the Arno River, central Italy, Hydrol.

Process., 16, 1177-1199.

• Coles S.,ʻʻAn Introduction to Statistical Modeling of Extreme Values, Springer,

2001

• Coles, S., and Davinson E., Statistical Modelling of Extreme Values, 2008

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Bibliography and Further Reading

Riccardo Rigon

•Foufula-Georgiou, Lectures at 2008 Summer School on Environmental Dynamics,

2008

•Fréchet M., Sur la loi de probabilité de l'écart maximum, Annales de la Société

Polonaise de Mathematique, Crocovie, vol. 6, p. 93-116, 1927

•Gumbel, On the criterion that a given system of deviations from the probable in

the case of a correlated system of variables is such that it can be reasonably

supposed to have arisen from random sampling, Phil. Mag. vol. 6, p. 157-175, 1900

• Houze, Clouds Dynamics, Academic Press, 1994

Saturday, September 11, 2010

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Bibliography and Further Reading

Riccardo Rigon

• Kleissl J., V. Kumar, C. Meneveau, M. B. Parlange, Numerical study of dynamic

Smagorinsky models in large-eddy simulation of the atmospheric boundary layer:

Validation in stable and unstable conditions, Water Resour. Res., 42, W06D10, doi:

10.1029/2005WR004685, 2006

•Kottegoda and R. Rosso, Applied statistics for civil and environmental engineers,

Blackwell, 2008

•Kumar V., J. Kleissl, C. Meneveau, M. B. Parlange, Large-eddy simulation of a diurnal

cycle of the atmospheric boundary layer: Atmospheric stability and scaling issues,

Water Resour. Res., 42, W06D09, doi:10.1029/2005WR004651, 2006

•Lettenmaier D., Stochastic modeling of precipitation with applications to climate

model downscaling, in von Storch and, Navarra A., Analysis of Climate Variability:

Applications and Statistical Techniques,1995

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Bibliography and Further Reading

Riccardo Rigon

•Salzman, William R. (2001-08-21). "Clapeyron and Clausius–Clapeyron

Equations" (in English). Chemical Thermodynamics. University of Arizona. Archived

from the original on 2007-07-07. http://web.archive.org/web/20070607143600/

http://www.chem.arizona.edu/~salzmanr/480a/480ants/clapeyro/clapeyro.html.

Retrieved 2007-10-11.

•von Storch H, and Zwiers F. W, Statistical Analysis in climate Research, Cambridge

University Press, 2001

•Whiteman, Mountain Meteorology, Oxford University Press, p. 355, 2000

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Self-Similar Distributions

Riccardo Rigon

Thank you for your attention!

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avora

to a

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slid

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Saturday, September 11, 2010