9 Hybridization
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Transcript of 9 Hybridization
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Hybridization - The Blending of Orbitals
Poodle
+
+ Cocker Spaniel
=
=
=
=
+
+s orbital p orbital
Cockapoo
sp orbital
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We have studied electronconfiguration notation andthe sharing of electrons inthe formation of covalentbonds.
Methane is a simple natural
gas. Its molecule has acarbon atom at the centerwith four hydrogen atomscovalently bonded around it.
What Proof Exists for Hybridization?
Lets look at a molecule ofmethane, CH 4.
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What is the expected orbital notation of
carbon in its ground state?
(Hint : How many unpaired electrons does thiscarbon atom have available for bonding?)
Can you see a problem with this?
Carbon ground state configuration
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You should conclude that carbon only hasTWO electrons available for bonding. Thatis not not enough.
What is taking place in order that carbonmay form four bonds?
Carbons Bonding Problem
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The first thought thatchemists had was thatcarbon promotes one ofits 2s electrons
to the empty 2p orbital.
Carbons Empty Orbital
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However, they quickly recognized a problem with suchan arrangement
Three of the carbon-hydrogen bonds would involvean electron pair in which the carbon electron was a2p , matched with the lone 1s electron from ahydrogen atom.
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This would mean that threeof the bonds in a methanemolecule would be identical,because they would involveelectron pairs of equalenergy.
But what about the
fourth bond?
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The fourth bond is between a 2s electronfrom the carbon and the lone 1s hydrogen
electron.
Such a bond would have slightly less energythan the other bonds in a methane molecule.
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This bond would be slightly
different in character thanthe other three bonds inmethane.
This difference would bemeasurable to a chemistby determining the bondlength and bond energy.
But is this what they observe?
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In the case of methane, they call the hybridizationsp 3 , meaning that an s orbital is combined with three
p orbitals to create four equal hybrid orbitals .
These new orbitals have slightly MORE energy than
the 2s orbital and slightly LESS energy than the 2p orbitals.
1s2sp 3 2sp 3 2sp 3 2sp 3
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While sp 3 is the hybridization observed in methane,there are other types of hybridization that atoms
undergo.These include sp hybridization, inwhich one s orbital combines witha single p orbital.
This produces two hybrid orbitals, while leaving twonormal p orbitals
sp Hybrid Orbitals
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Another hybrid is the sp 2 , which combines two orbitals
from a p sublevel with one orbital from an s sublevel.
One p orbitalremains unchanged.
sp2 Hybrid Orbitals
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An understanding of the derivation and depiction of these orbitals is beyond the scope of this course and the AP Exam. Current evidence suggests that hybridization involving d orbitals does not exist , and there is controversy about the need to teach any hybridization. Until there is agreement in the chemistry community, we will continue to include sp, sp 2 , and sp 3 hybridization in the current course.
Exclusion Warning
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Hybridization Involving d Orbitals
Beginning with elements in the third row, d orbitals may also hybridizedsp 3 = five hybrid orbitals of equal energy
d 2 sp 3 = six hybrid orbitals of equal energy
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Hybridization and Molecular Geometry
Forms Overall StructureHybridization
of A AX2 Linear sp
AX3, AX2E Trigonal Planar sp 2
AX4, AX3E, AX2E2 Tetrahedral sp 3
AX5, AX4E, AX3E2, AX2E3 Trigonal bipyramidal dsp 3 AX6, AX5E, AX4E2 Octahedral d 2 sp 3
A = central atomX = atoms bonded to AE = nonbonding electron pairs on A
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Sigma and Pi Bonds
Sigma ( ) bonds exist in the region directly betweentwo bonded atoms.
Pi ( ) bonds exist in the region above and below a linedrawn between two bonded atoms.
Single bond 1 sigma bond
Double Bond 1 sigma, 1 pi bond
Triple Bond 1 sigma, 2 pi bonds
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Sigma and Pi BondsSingle Bonds
C C
H
H
H
H
H
H
Ethane
1 bond
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Sigma and Pi Bonds: Double bonds
C C
H
H
H
H
Ethene
CC
H
H
H
H
1 bond
1 bond
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Sigma and Pi BondsTriple Bonds
C C HH
CC HH
Ethyne1 bond
1 bond
1 bond
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The De-Localized Electron ModelPi bonds ( ) contribute to the delocalized model ofelectrons in bonding, and help explain resonance
H
H
H
H
H
H
H
H
H
H
H
H
Electron density from bonds can be distributedsymmetrically all around the ring, above and belowthe plane.