8.2Fisher Information CR Inequality J I
Transcript of 8.2Fisher Information CR Inequality J I
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8.2 Fisher Information CR Inequality
• X ∼ f (x, θ), θ ∈ Θ = (a, b).
• Regular cases:
f (x, θ) > 0,∂
∂θ
∫f =
∫∂
∂θf,
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Since∫f (x, θ) = 1, then∫
∂f (x, θ)
∂θdx = 0,
i.e. ∫∂ ln f (x, θ)
∂θf (x, θ)dx = 0.
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⇒∫
[∂2 ln f (x, θ)
∂θ2f (x, θ)
+∂ ln f (x, θ)
∂θ
∂f (x, θ)
∂θ]dx = 0,
⇒∫
(∂ ln f (x, θ)
∂θ)2f (x, θ)dx
+
∫∂2 ln f (x, θ)
∂θ2f (x, θ)dx = 0.
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Therefore,
I(θ) =:
∫ (∂ ln f (x, θ)
∂θ
)2
f (x, θ)dx
= E
[∂ ln f (x, θ)
∂θ
]2
= −∫∂2 ln f (x, θ)
∂θ2f (x, θ)dx
= −E∂2 ln f (x, θ)
∂θ2.
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• The larger of I(θ), the more information
of θ.
• If I(θ) = 0, then ∂ ln f∂θ = 0. No informa-
tion in ln f (x, θ).
• ∂ ln f (x,θ)∂θ is an important function.
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MLE θ̂ satisfies:
n∑i=1
∂ ln f (xi, θ̂)
∂θ= 0.
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Example 1: X ∼ N(θ, σ20),
f (x, θ) =1√
2πσ0
exp{−(x− θ)2
2σ20
}.
Then
ln f (x, θ) = − ln(√
2πσ0)
−(x− θ)2
2σ20
.
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⇒∂ ln f (x, θ)
∂θ=x− θσ2
0
,
⇒∂2 ln f (x, θ)
∂θ2= − 1
σ20
.
Then
I(θ) =1
σ20
.
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Example 2: X ∼ B(1, θ), then
ln f (x, θ) = x ln θ
+ (1− x) ln(1− θ),
∂2 ln f (x, θ)
∂θ2= − x
θ2− (1− x)
(1− θ)2.
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Hence,
I(θ) = E
[x
θ2+
1− x(1− θ)2
]
=1
θ+
1
1− θ=
1
θ(1− θ).
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• SupposeX1, · · · , Xn iid. ∼ f (x, θ), then
L(θ) =
n∏i=1
f (xi, θ)
and
lnL(θ) =
n∑i=1
ln f (xi, θ).
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⇒∂ lnL(θ)
∂θ=
n∑i=1
∂ ln f (xi, θ)
∂θ.
In(θ) = E[∂ lnL(θ)
∂θ]2
=
n∑i=1
E(∂ ln f (xi, θ)
∂θ)2
= nI(θ).
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• Rao-Cramer inequalityµ
Y = u(X1, · · · , Xn) ∼ θ,
E(Y ) = k(θ).
⇒ k(θ) =
∫u(x1, · · · , xn)∏
f (xi, θ)dxi
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k′(θ) =
∫u(x1, · · · , xn)
(
n∑i=1
∂ ln f (xi, θ)
∂θ)∏
f (xi, θ)dxi.
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Let Z =∑n
i=1∂ ln f (xi,θ)
∂θ , then
EZ = 0,
V ar(Z) = nE
[∂ ln f (X, θ)
∂θ
]2
= nI(θ).
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Since k′(θ) = E(Y Z), then
k′(θ) ≤√V ar(Y )V ar(Z)
⇒
V ar(Y ) ≥ [k′(θ)]2
V ar(Z)
=[k′(θ)]2
nI(θ).
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• If k(θ) = θ, then Y is unbiased and
V ar(Y ) ≥ 1
nI(θ)
CR-lower bound.
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Example 1µX1, · · · , Xn iid. ∼N(θ, σ2)with known σ2. Then
V ar(Y ) ≥ σ2
n.
Example 2µX1, · · · , Xn iid. ∼ B(1, θ).
Then
V ar(Y ) ≥ θ(1− θ)
n.
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Def 1: Y is a efficient unbiased estimator
of θ⇐⇒ the variance of Y attains the CR
lower bound.
Def 2: EfficiencyThe CR lower bound
V ar(Y )
is called the efficiency of unbiased estima-
tor Y .
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Example 3: X1, · · · , Xn iid. ∼ N(µ, θ),
0 < θ < +∞ with known µ.
E(S2) = θ.
and
ln f (x, θ) = −(x− µ)2
2θ− ln θ
2+ c.
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I(θ) = −E
[∂ ln2 f (X, θ)
∂θ2
]
= E
[(X − µ)2
θ3− 1
2θ2
]=
1
2θ2.
and1
nI(θ)=
2θ2
n.
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Since
V ar(S2) =2(n− 1)
(n− 1)2θ2 =
2θ2
n− 1
>2θ2
n,
then
eff(S2) =n− 1
n.
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Take S20 = 1
n
∑ni=1(Xi − µ)2, then
eff(S20) = 1.
• Asymptotically efficient:
eff(Yn)→ 1 (n→∞).