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7.7 EXPONENTIAL GROWTH AND DECAY: Exponential Decay: An equation that decreases. Exponential Growth: An equation that increases. Growth Factor: 1 plus the percent rate of change which is expressed as a decimal. Decay Factor: 1 minus the percent rate of change expressed as a decimal.

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### Transcript of 7.7 EXPONENTIAL GROWTH AND DECAY: Exponential Decay: An equation that decreases. Exponential Growth:...

7.7 EXPONENTIAL GROWTH AND DECAY:

Exponential Decay: An equation that decreases.

Exponential Growth: An equation that increases.

Growth Factor: 1 plus the percent rate of change which is expressed as a decimal.

Decay Factor: 1 minus the percent rate of change expressed as a decimal.

GOAL:

Definition:An EXPONENTIAL FUNCTION is a function

of the form:

𝑦=𝑎 ∙𝑏𝑥

BaseExponentWhere a ≠ 0, b > o, b ≠ 1,

and x is a real number.

Constant

GRAPHING: To provide the graph of the equation we can go back to basics and create a table.

Ex: What is the graph of y = 3 2∙ x?

GRAPHING:X y = 3 2∙ x y

-2 3 2∙ (-2) = 𝟑𝟒

3 2∙ (-1) = 𝟑𝟐-1

0 3 2∙ (0) 3 = 3 1 ∙

1 3 2∙ (1) 6 = 3 2 ∙

2 3 2∙ (2) 12 = 3 4 ∙

GRAPHING: X y

-2 𝟑𝟒𝟑𝟐-1

0 3

1 6

2 12

This graph grows fast = Exponential Growth

YOU TRY IT:

Ex: What is the graph of y = 3∙x?

GRAPHING:X y = 3∙x y

-2 3 ∙ (-2) 12

6-1

0 3 = 3 1 ∙

1

2

=3 (2)∙ 2

3 ∙ (-1) =3 (2)∙ 1

3 ∙ (0)

3 ∙ (1) =3 ∙𝟑𝟐𝟑𝟒

3 ∙ (2) =3 ∙

GRAPHING: X y

-2

𝟑𝟒

𝟑𝟐

-1

0 3

1

6

2

12

This graph goes down = Exponential Decay

YOU TRY IT:

Ex: What are the differences and

similarities between:

y = 3 2∙ x

and y = 3∙x?

y = 3 2∙ x

Base = 2 Exponential growth y- intercept (x=0) = 3

y = 3∙x

Base = Exponential Decay y- intercept (x=0) = 3

MODELING: We use the concept of exponential growth in the real world:Ex: Since 2005, the amount of money spent at restaurants in the U.S. has increased 7% each year. In 2005, about 36 billion was spend at restaurants. If the trend continues, about how much will be spent in 2015?

EVALUATING: To provide the solution we must know the following formula:

y = a∙bx

y = totala = initial amount b = growth factor (1 + rate)x = time in years.

SOLUTION:

Y= total:

Since 2005, … has increased 7% each year. In 2005, about 36 billion was spend at restaurants…. about how much will be spent in 2015?

\$36 billion Initial:

Growth: 1 + 0.07

Time (x): 10 years(2005-2015)

unknown y = a∙bx

y = 36∙(1.07)10

y = 36∙(1.967)

y = 70.8 b.

BANKING: We also use the concept of exponential growth in banking:

A = P(1+)nt

A = total balanceP = Principal (initial) amount

n = # of times compound interestt = time in years.

r = interest rate in decimal form

MODELING GROWTH:Ex:

You are given \$6,000 at the beginning of your freshman year. You go to a bank

and they offer you 7% interest. How much money will you have after

graduation if the money is:a) Compounded annuallyb) Compounded quarterlyc) Compounded monthly

COMPOUNDED ANNUALLY:

A = P(1+)nt

A = ?P = \$6000

n = 1t = 4 yrs

r = 0.07

A = 6000(1+)1(4)

A = 6000(1.07)4

A = 6000(1.3107)A = \$7864.77

COMPOUNDED QUARTERLY:

A = P(1+)nt

A = ?P = \$6000

n = 4 timest = 4 yrs

r = 0.07

A = 6000(1+)4(4)

A = 6000(1.0175)16

A = 6000(1.3199)A = \$7919.58

COMPOUNDED MONTHLY:

A = P(1+)nt

A = ?P = \$6000

n = 12 timest = 4 yrs

r = 0.07

A = 6000(1+)12(4)

A = 6000(1.0058)48

A = 6000(1.3221)A = \$7932.32

MODELING DECAY:Ex:

Doctors can use radioactive iodine to treat some forms of cancer. The half-life

of iodine-131 is 8 days. A patient receives a treatment of 12 millicuries (a unit of radioactivity) of iodine-131. How much iodine-131 remains in the patient

after 16 days?:

DECAY: To provide the solution we g back to the following formula:

y = a∙bx

y = totala = initial amount b = decay factor (1 - rate)x = time in years.

SOLUTION:

Y= total:

The half-life of iodine-131 is 8 days. A patient receives a treatment of 12 millicuries (a unit of radioactivity) of iodine-131. How much iodine-131 remains in the patient 16 days later?:

12Initial:

Growth: 1- 1/2

Time (x): 16/8 = 2

unknown y = a∙bx

y = 12∙(1/2)2

y = 12∙(.25)

y = 3

CLASSWORK:

Page 450-452:

Problems: As many as needed to master the concept.