5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli...

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5.8 Exponential Growth and Decay Mon Dec 7 • Do Now • In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k = 0.41. Assume that 1000 bacteria are present at time = 0 • 1) Find the formula for the # of bacteria P(t) at time t • 2) How large is the population after 5 hours? • 3) When will the population reach 10,000?

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Exponential growth and decay When P0 is the initial size at t = 0 If k > 0, then P(t) grows exponentially If k < 0 then P(t) decreases exponentially K is either known as the growth or decay constant. We’ve done these things in Pre-calc

Transcript of 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli...

Page 1: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

5.8 Exponential Growth and DecayMon Dec 7

• Do Now• In the laboratory, the number of Escherichia

coli bacteria grows exponentially with growth constant k = 0.41. Assume that 1000 bacteria are present at time = 0

• 1) Find the formula for the # of bacteria P(t) at time t

• 2) How large is the population after 5 hours?• 3) When will the population reach 10,000?

Page 2: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

HW Review p.339

Page 3: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

Exponential growth and decay

•When P0 is the initial size at t = 0•If k > 0, then P(t) grows exponentially•If k < 0 then P(t) decreases exponentially•K is either known as the growth or decay constant.

•We’ve done these things in Pre-calc

Page 4: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

Y’ = ky

• If y(t) is a differentiable function satisfying the differential equation

then , where P0 is the initial value P0 = y(0)

Page 5: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

Notes

• This theorem tells us that a process obeys an exponential law precisely when its rate of change is proportional to the amount present.

• A population grows exponentially because each present organism contributes to growth

Page 6: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

Ex

• Find all solutions of y’ = 3y. Which solution satisfies y(0) = 9?

Page 7: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

Ex

• Pharmacologists have shown that penicillin leaves a person’s bloodstream at a rate proportional to the amount present.

• A) Express this as a differential equation• B) Find the decay constant if 50 mg of penicillin

remains in the bloodstream 7 hours after an injection of 450 mg

• C) Under the hypothesis of (B), at what time was 200 mg present?

Page 8: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

Doubling Time / Half-life

• If , then

is the doubling time if k >0

is the half-life if k < 0

Page 9: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

Compound Interest

• If P0 dollars are deposited into an account earning interest at an annual rate r, compounded M times yearly, then the value of the account after t years is

• If compounded continuously, is

Page 10: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

Present Value• The concept of present value (PV) is used to

compare payments made at different times

• The PV of P dollars received at time t is

• Having money now means you can get interest from it right away.

• Getting money later means you will lose out on any interest you could have gotten

Page 11: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

Ex

• Is it better to receive $2000 today or $2200 in 2 years? Consider a 3% and 7% compounded interest rate

Page 12: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

Ex• You must decide whether to upgrade your

company’s computer system. The upgrade costs $400,000 and will save $150,000 per year for the next 3 years. Is this a good investment if r = 7%?

Page 13: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

Income stream

• An income stream is a sequence of periodic payments that continue over an interval of T years

• This is like winning the lottery and taking several payments over the years vs taking a lump sum

Page 14: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

PV of an income stream

• If the interest rate is r, the present value of an income stream paying out R(t) dollars per year continuously for T years is

Page 15: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

Ex

• An investment pays out 800,000 pesos per year, continuously for 5 years. Find the PV of the investment for r = 0.04

Page 16: 5.8 Exponential Growth and Decay Mon Dec 7 Do Now In the laboratory, the number of Escherichia coli bacteria grows exponentially with growth constant k.

Closure

• For the investment that paid out 800,000 pesos per year for 5 years, find the PV of the investment if r = 0.06

• HW: p.350 #3 7 13 14 15 39 44 45