5-6 Direct Variation Lesson Quiz Lesson Quiz Lesson Presentation Lesson Presentation Warm Up Warm...
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5-6 Direct Variation
Lesson QuizLesson Quiz
Lesson PresentationLesson Presentation
Warm UpWarm Up
5-6 Direct Variation
Warm UpSolve for y.1. 3 + y = 2x 2. 6x = 3y
Write an equation that describes the relationship.
3.
y = 2xy = 2x – 3
4. 5.
y = 3x
9 0.5
Solve for x.
5-6 Direct Variation
MA.912.A.3.12 Graph a linear equation…in two variables…Also MA.912.A.2.1, MA.912.A.2.13.
Sunshine State Standards
5-6 Direct Variation
Identify, write, and graph direct variation.
Objective
5-6 Direct Variation
Vocabulary
direct variationconstant of variation
5-6 Direct Variation
A recipe for paella calls for 1 cup of rice to make 5 servings. In other words, a chef needs 1 cup of rice for every 5 servings.
The equation y = 5x describes this relationship. In this relationship, the number of servings varies directly with the number of cups of rice.
5-6 Direct Variation
A direct variation is a special type of linear relationship that can be written in the form y = kx, where k is a nonzero constant called the constant of variation.
5-6 Direct Variation
Additional Example 1A: Identifying Direct Variations from Equations
Tell whether the equation represents a direct variation. If so, identify the constant of variation. y = 3x
This equation represents a direct variation because it is in the form of y = kx. The constant of variation is 3.
5-6 Direct Variation
3x + y = 8 Solve the equation for y.Since 3x is added to y, subtract 3x
from both sides.–3x –3x
y = –3x + 8
This equation is not a direct variation because it cannot be written in the form y = kx.
Additional Example 1B: Identifying Direct Variations from Equations
Tell whether the equation represents a direct variation. If so, identify the constant of variation.
5-6 Direct Variation
–4x + 3y = 0 Solve the equation for y.Since –4x is added to 3y, add 4x
to both sides.
+4x +4x3y = 4x
This equation represents a direct variation because it is in the form of y = kx. The constant of variation is .
Since y is multiplied by 3, divide both sides by 3.
Additional Example 1C: Identifying Direct Variations from Equations
Tell whether the equation represents a direct variation. If so, identify the constant of variation.
5-6 Direct Variation
Check It Out! Example 1a
3y = 4x + 1
This equation is not a direct variation because it is not written in the form y = kx.
Tell whether the equation represents a direct variation. If so, identify the constant of variation.
5-6 Direct Variation
Check It Out! Example 1c
y + 3x = 0 Solve the equation for y.Since 3x is added to y, subtract 3x
from both sides.
– 3x –3xy = –3x
This equation represents a direct variation because it is in the form of y = kx. The constant of variation is –3.
Tell whether the equation represents a direct variation. If so, identify the constant of variation.
5-6 Direct Variation
What happens if you solve y = kx for k?
y = kx
So, in a direct variation, the ratio is equal to the constant of variation. Another way to identify a direct variation is to check whether is the same for each ordered pair (except where x = 0).
Divide both sides by x (x ≠ 0).
5-6 Direct Variation
Additional Example 2A: Identifying Direct Variations from Ordered Pairs
Tell whether the relationship is a direct variation. Explain.
Method 1 Write an equation.
y = 3x
This is direct variation because it can be written as y = kx, where k = 3.
Each y-value is 3 times the corresponding x-value.
5-6 Direct Variation
Additional Example 2A Continued
Tell whether the relationship is a direct variation. Explain.
Method 2 Find for each ordered pair.
This is a direct variation because is the same for each ordered pair.
5-6 Direct Variation
Method 1 Write an equation.
y = x – 3 Each y-value is 3 less than the corresponding x-value.
This is not a direct variation because it cannot be written as y = kx.
Additional Example 2B: Identifying Direct Variations from Ordered Pairs
Tell whether the relationship is a direct variation. Explain.
5-6 Direct Variation
Method 2 Find for each ordered pair.
This is not direct variation because is the not the same for all ordered pairs.
Additional Example 2B Continued
Tell whether the relationship is a direct variation. Explain.
…
5-6 Direct Variation
Tell whether the relationship is a direct variation. Explain.
Check It Out! Example 2b
Method 1 Write an equation.
y = –4x Each y-value is –4 times the corresponding x-value .
This is a direct variation because it can be written as y = kx, where k = –4.
5-6 Direct Variation
Tell whether the relationship is a direct variation. Explain.
Check It Out! Example 2c
Method 2 Find for each ordered pair.
This is not direct variation because is the not the same for all ordered pairs.
5-6 Direct Variation
If you know one ordered pair that satisfies a direct variation, you can write the equation. You can also find other ordered pairs that satisfy the direct variation.
5-6 Direct Variation
Additional Example 3: Writing and Solving Direct Variation Equations
The value of y varies directly with x, and y = 3, when x = 9. Find y when x = 21.
Method 1 Find the value of k and then write the equation.
y = kx Write the equation for a direct variation.
3 = k(9) Substitute 3 for y and 9 for x. Solve for k.
Since k is multiplied by 9, divide both sides by 9.
The equation is y = x. When x = 21, y = (21) = 7.
5-6 Direct Variation
The value of y varies directly with x, and y = 3 when x = 9. Find y when x = 21.
Method 2 Use a proportion.
9y = 63
y = 7
In a direct variation is the same for all values of x and y.
Use cross products.
Since y is multiplied by 9 divide both sides by 9.
Additional Example 3 Continued
5-6 Direct Variation
Check It Out! Example 3
The value of y varies directly with x, and y = 4.5 when x = 0.5. Find y when x = 10.
Method 1 Find the value of k and then write the equation.
y = kx Write the equation for a direct variation.
4.5 = k(0.5) Substitute 4.5 for y and 0.5 for x. Solve for k.
Since k is multiplied by 0.5, divide both sides by 0.5.
The equation is y = 9x. When x = 10, y = 9(10) = 90.
9 = k
5-6 Direct Variation
Check It Out! Example 3 Continued
Method 2 Use a proportion.
0.5y = 45
y = 90
In a direct variation is the same for all values of x and y.
Use cross products.
Since y is multiplied by 0.5 divide both sides by 0.5.
The value of y varies directly with x, and y = 4.5 when x = 0.5. Find y when x = 10.
5-6 Direct Variation
Check It Out! Example 4
The perimeter y of a square varies directly with its side length x. Write a direct variation equation for this relationship. Then graph.
Step 1 Write a direct variation equation.
perimeter = 4 sides times length
y = 4 • x
5-6 Direct Variation
Check It Out! Example 4 Continued
Step 2 Choose values of x and generate ordered pairs.
x y = 4x (x, y)
0 y = 4(0) = 0 (0, 0)
1 y = 4(1) = 4 (1, 4)
2 y = 4(2) = 8 (2, 8)
The perimeter y of a square varies directly with its side length x. Write a direct variation equation for this relationship. Then graph.
5-6 Direct Variation
Step 3 Graph the points and connect.
Check It Out! Example 4 Continued
The perimeter y of a square varies directly with its side length x. Write a direct variation equation for this relationship. Then graph.
5-6 Direct Variation
Standard Lesson Quiz
Lesson Quizzes
Lesson Quiz for Student Response Systems
5-6 Direct Variation
Lesson Quiz: Part ITell whether each equation represents a direct variation. If so, identify the constant of variation.
1. 2y = 6x yes; 3
2. 3x = 4y – 7 no
Tell whether the relationship is a direct variation. Explain.
3.
5-6 Direct Variation
Lesson Quiz: Part II
4. The value of y varies directly with x, and y = –8 when x = 20. Find y when x = –4. 1.6
5. Apples cost $0.80 per pound. Write a direct variation equation to describe the cost y of x pounds of apples. Then graph.
2
4
6
y = 0.8x
5-6 Direct Variation
Lesson Quiz for Student Response Systems
1. Identify the equation that represents
direct variation and its constant of variation.
A. 4y = 12x; 3
B. 4x = 3y − 8; 2
C. 4y = 5x + 3; 5
D. 3y = 5x + 11; 3
5-6 Direct Variation
Lesson Quiz for Student Response Systems
2. Identify the equation that does not
represent direct variation.
A. 6x = 8y − 14
B. 6y = 12x
C. 18x = 3y
D. 4y = 12x
5-6 Direct VariationLesson Quiz for Student Response Systems
3. Identify the relationship that represents a direct variation.
x 4 28 40
y 15 7 10
x 15 19 23
y 5 8 11
x 6 4 2
y 5 7 9
x 2 4 8
y 10 20 40A.
B.
C.
D.
5-6 Direct VariationLesson Quiz for Student Response Systems
4. Identify the relationship that does not represent a direct variation.
x 5 7 9
y 1 2 3
x 6 12 18
y 3 6 9
x 2 4 8
y 10 20 40
x 4 8 12
y 10 20 30A.
B.
C.
D.
5-6 Direct Variation
Lesson Quiz for Student Response Systems
5. The value of y varies directly with x, and
y = –5 when x = 25. Identify the value of y
when x = –10.
A. y = –1
B. y = 0
C. y = 2
D. y = –2