4 Practice Buoyancy Problems
-
Upload
dylan-jimenez -
Category
Documents
-
view
29 -
download
2
description
Transcript of 4 Practice Buoyancy Problems
CHAPTER 9
What is the mass of the block floating in water?
10 cm
10 cm
25 cm
Wblock = Fbuoyant
mg = Vg
m = (1000) ½(.25)(.10)(.10)Volume of block
m = 1.25 kg
What is the mass of the cylinder floating in oil?
Wcylinder = Fbuoyant
mg = Vg
m = (926) ¾ (.12)(.03)2
Volume of cylinder
r = 3 cm L = 12 cm
= 926 kg/m3 m = .236 kg
What % of a solid cork ( = 240 ) will float below the surface of water?
Wcork = Fbuoyant
mg = Vgcork =
mcork
Vcork
cork Vcork = (water)(x)Vcork
corkwater
= x
2401000
= .24 = 24%
For ONE side
2 MASSLESS SIDES & BOTTOM!
The thick walls are made of Copper ( = 8930). How wide must the box be to float in water?
5 cm
24 cm
30 cm
x?
Wbox = Fbuoyant
mg = Vgside = mside
Vside
8930 = m
(.24)(.30)(.05)
m = 32.14 kg
64.3 = 1000 (.30)(.24)x
x = .893 m