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20
4 Elastic Properties of Dislocations 4.1 Introduction The atoms in a crystal containing a dislocation are displaced from their perfect lattice sites, and the resulting distortion produces a stress field in the crystal around the dislocation. The dislocation is therefore a source of internal stress in the crystal. For example, consider the edge disloca- tion in Fig. 1.18(b). The region above the slip plane contains the extra half-plane forced between the normal lattice planes, and is in compres- sion: the region below is in tension. The stresses and strains in the bulk of the crystal are sufficiently small for conventional elasticity theory to be applied to obtain them. This approach only ceases to be vaUd at positions very close to the centre of the dislocation. Although most crystaUine sohds are elastically anisotropic, i.e. their elastic properties are different in different crystallographic directions, it is much simpler to use isotropic elasticity theory. This still results in a good approximation in most cases. From a knowledge of the elastic field, the energy of the dislocation, the force it exerts on other dislocations, its energy of inter- action with point defects, and other important characteristics, can be obtained. The elastic field produced by a dislocation is not affected by the apphcation of stress from external sources: the total stress on an element within the body is the superposition of the internal and external stresses. 4.2 Elements of The displacement of a point in a strained body from its position in the Elasticity Theory unstrained state is represented by the vector ^X") ^y") '^z (4.1) The components u^, Uy, u^ represent projections of u on the x, y, z axes, as shown in Fig. 4.1. In linear elasticity, the nine components of strain are given in terms of the first derivatives of the displacement components thus: OX dUy dy duz (4.2)

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4 Elastic Properties of Dislocations

4.1 Introduction The atoms in a crystal containing a dislocation are displaced from their perfect lattice sites, and the resulting distortion produces a stress field in the crystal around the dislocation. The dislocation is therefore a source of internal stress in the crystal. For example, consider the edge disloca­tion in Fig. 1.18(b). The region above the slip plane contains the extra half-plane forced between the normal lattice planes, and is in compres­sion: the region below is in tension. The stresses and strains in the bulk of the crystal are sufficiently small for conventional elasticity theory to be applied to obtain them. This approach only ceases to be vaUd at positions very close to the centre of the dislocation. Although most crystaUine sohds are elastically anisotropic, i.e. their elastic properties are different in different crystallographic directions, it is much simpler to use isotropic elasticity theory. This still results in a good approximation in most cases. From a knowledge of the elastic field, the energy of the dislocation, the force it exerts on other dislocations, its energy of inter­action with point defects, and other important characteristics, can be obtained. The elastic field produced by a dislocation is not affected by the apphcation of stress from external sources: the total stress on an element within the body is the superposition of the internal and external stresses.

4.2 Elements of The displacement of a point in a strained body from its position in the Elasticity Theory unstrained state is represented by the vector

^X") ^y") '^z (4.1)

The components u^, Uy, u^ represent projections of u on the x, y, z axes, as shown in Fig. 4.1. In linear elasticity, the nine components of strain are given in terms of the first derivatives of the displacement components thus:

OX

dUy

dy

duz

(4.2)

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Elastic properties of dislocations 63

Figure 4.1 Displacement of P to P' by displacement vector u.

and

(b)

Figure 4.2 (a) Pure shear and (b) simple shear of an area element in the xy plane.

^yz ^zy •

1 l^dUy

dy

2\dx dz

1 fdux duy

(4.3)

^xy ^yx 2\dy dx

The magnitude of these components is <C 1. Partial differentials are used because in general each displacement component is a function of posi­tion (x , j , z). The three strains defined in (4.2) are the normal strains. They represent the fractional change in length of elements parallel to the X, y and z axes respectively. The six components defined in (4.3) are the shear strains, and they also have simple physical meaning. This is demonstrated by Cxy in Fig. 4.2(a), in which a small area element ABCD in the xy plane has been strained to the shape AB'C'D' without change of area. The angle between the sides AB and AD initially parallel to X and y respectively has decreased by le^y. By rotating, but not deforming, the element as in Fig. 4.2(b), it is seen that the element has undergone a simple shear. The simple shear strain often used in engineering practice is Icxy, as indicated.

The volume F of a small volume element is changed by strain to (F + AF) = F(l + exx){^ + eyy){\ + e,,). The fractional change in volume A, known as the dilatation, is therefore

/:^ = /^VlV={exx^eyy^e,: ) (4.4)

A is independent of the orientation of the axes x, j , z. In elasticity theory, an element of volume experiences forces via

stresses applied to its surface by the surrounding material. Stress is the force per unit area of surface. A complete description of the stresses acting therefore requires not only specification of the magnitude and direction of the force but also of the orientation of the surface, for as the

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64 Introduction to Dislocations

^ . ^ ^ ^ ^ ^ . ^ - ^ r ^

^ y^ --r 1

(a) (b)

Figure 4.3 Components of stress acting on (a) the top and front faces and (b) the bottom and back faces of an elemental cube.

eface

rface

Figure 4.4 Components of stress in cylindrical polar coordinates.

orientation changes so, in general, does the force. Consequently, nine components must be defined to specify the state of stress. They are shown with reference to an elemental cube aligned with the x, y, z axes in Fig. 4.3(a). The component cr/,, where / and j can be x, y or z, is defined as the force per unit area exerted in the +/ direction on a face with outward normal in the -fy direction by the material outside upon the material inside. For a face with outward normal in the —j direction, i.e. the bottom and back faces shown in Fig. 4.3(b), GIJ is the force per unit area exerted in the — / direction. For example, Oy^ acts in the positive y direction on the top face and the negative y direction on the bottom face.

The six components with / 7^7 are the shear stresses. (As explained in section 3.1, it is customary in dislocation studies to represent the shear stress acting on the slip plane in the slip direction of a crystal by the symbol r.) By considering moments of forces taken about x, y and z axes placed through the centre of the cube, it can be shown that rotational equiUbrium of the element, i.e. net couple = 0, requires

^yz ^yx (4.5)

Thus, the order in which subscripts / and 7 is written is immaterial. The three remaining components a^x, cTyy, CTZZ are the normal components. From the definition given above, a positive normal stress results in tension and a negative one in compression. The effective pressure acting on a volume element is therefore

1, P = -:^ [(^xx + CFyy + az: (4.6)

For some problems, it is more convenient to use cyHndrical polar coordinates (r,9,z). The stresses are still defined as above, and are shown in Fig. 4.4. The notation is easier to follow if the second subscript j is considered as referring to the face of the element having a constant value of the coordinate/

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Elastic properties of dislocations 65

The relationship between stress and strain in Hnear elasticity is Hooke's Law, in which each stress component is linearly proportional to each strain. For isotropic soHds, only two proportionaUty constants are required:

T^x = IGcxx + K^xx + eyy + e^,)

7yy = IGCyy + \{e ^^ + eyy + 6^^)

(J,^ = IGe^Z + K^XX + eyy + Czz)

^xy = ^Ge^y ayz = 2Geyz G^X =

(4.7)

IGe.

A and G are the Lame constants, but G is more commonly known as the shear modulus. Other elastic constants are frequently used, the most useful being Young's modulus, E, Poisson's ratio, u, and bulk modulus, K. Under uniaxial, normal loading in the longitudinal direction, E is the ratio of longitudinal stress to longitudinal strain and v is minus the ratio of lateral strain to longitudinal strain. K is defined to be —p/A. Since only two material parameters are required in Hooke's law, these con­stants are interrelated. For example.

E = 2G{1 + z/) 1/ = A/2(A + G) K= E/3{\ - Iv) (4.8)

Typical values of E and v for metaUic and ceramic solids He in the ranges 40-600 GNm-2 and 0.2-0.45 respectively.

The internal energy of a body is increased by strain. The strain energy per unit volume is one-half the product of stress times strain for each component. Thus, for an element of volume d V, the elastic strain energy is

i=x,y,z j—x^y,z

and similarly for polar coordinates.

(4.9)

4.3 Stress Field of a Straight Dislocation

Screw Dislocation

The elastic distortion around an infinitely-long, straight dislocation can be represented in terms of a cyHnder of elastic material. Consider the screw dislocation AB shown in Fig. 4.5(a); the elastic cylinder in Fig. 4.5(b) has been deformed to produce a similar distortion. A radial sUt LMNO was cut in the cyhnder parallel to the z-axis and the free surfaces displaced rigidly with respect to each other by the distance b, the magni­tude of the Burgers vector of the screw dislocation, in the z-direction.

The elastic field in the dislocated cyhnder can be found by direct inspection. First, it is noted that there are no displacements in the X and y directions:

— Uy =^ (4.10)

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66 Introduction to Dislocations

(a) (b)

Figure 4.5 (a) Screw dislocation AB formed in a crystal, (b) Elastic distortion of a cylindrical ring simulating the distortion produced by the screw dislocation in (a).

Secondly, the displacement in the z-direction increases uniformly from zero to Z? as ^ increases from 0 to 27r:

be b _ i , / ,

It is then readily found from equations (4.2) and (4.3) that

^xx — ^yy — ^zz — ^xy — ^yx — ^

^xz — ^zx — b y b sin0

47r(x2+J^) 47r r

b X b cos 6 ^vz — ^zv — '' '" 4 7 r ( x 2 + / ) 47r r

From equations (4.7) and (4.12), the components of stress are

(7XX — ^yy — ^zz — '^xy — ^yx — ^

f v z — <y7x = — Gb y Gb sine Iw (x^ + y^) Iw r

Gb X Gbco&9 "'''"''''2-K{x^+y^)'lTT r

(4.11)

(4.12)

(4.13)

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Elastic properties of dislocations 67

The components in cylindrical polar coordinates (Fig. 4.4) take a sim­pler form. Using the relations

(^rz — o'xz COS ^ + ayz sin 0

crez = -cTxz sin 9 -\- ciyz cos 6

and similarly for the found to be

b eez = ezd = -.— 47rr

Gb crez = cFzO = T;—

ZTrr

shear strains, the only non--zero

(4.14)

components are

(4.15)

The elastic distortion contains no tensile or compressive components and consists of pure shear: aze acts parallel to the z-axis in radial planes of constant 0 and aoz acts in the fashion of a torque on planes normal to the axis (Fig. 4.4). The field exhibits complete radial symmetry and the cut LMNO can be made on any radial plane 9 — constant. For a dislocation of opposite sign, i.e. a left-handed screw, the signs of all the field components are reversed.

The stresses and strains are proportional to 1/r and therefore diverge to infinity as r -^ 0. SoUds cannot withstand infinite stresses, and for this reason the cylinder in Fig. 4.5 is shown as hollow with a hole of radius TQ. Real crystals are not hollow, of course, and so as the centre of a dislocation in a crystal is approached, elasticity theory ceases to be vaHd and a non-linear, atomistic model must be used (see section 10.3). The region within which the Unear-elastic solution breaks down is called the core of the dislocation. From equation (4.15) it is seen that the stress reaches the theoretical limit (equation (1.5)) and the strain exceeds about 10% when r ^ b. A reasonable value for the dislocation core radius ro therefore lies in the range b to 4b, i.e. ro < 1 nm in most cases.

Edge Dislocation

The stress field is more complex than that of a screw but can be represented in an isotropic cyUnder in a similar way. Considering the edge dislocation in Fig. 4.6(a), the same elastic strain field can be produced in the cyHnder by a rigid displacement of the faces of the sHt by a distance b in the x-direction (Fig. 4.6(b)). The displacement and strains in the z-direction are zero and the deformation is called plane strain. Derivation of the field components is beyond the scope of the present treatment, however. The stresses are found to be

""""" ^ ( x 2 + / ) 2

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68 Introduction to Dislocations

(a) (b)

Figure 4.6 (a) Edge dislocation formed in a crystal, (b) Elastic distortion of a cylindrical ring simulating the distortion produced by the edge dislocation in (a).

Dx ( x 2 - / )

O'zz = ^{cFxx + CFyy)

(^xz

where

D =

= (^zx = CFyz = Cr^y =0

Gb

(4.16)

27r(l-z/)

The stress field has, therefore, both dilational and shear components. The largest normal stress is axx which acts parallel to the slip vector. Since the slip plane can be defined as > = 0, the maximum compressive stress (axx negative) acts immediately above the slip plane and the maximum tensile stress (a^x positive) acts immediately below the slip plane. The effective pressure (equation (4.6)) on a volume element is

p-h + )D7~r^ (x2+j2) (4.17)

It is compressive above the slip plane and tensile below. These observa­tions are implied qualitatively by the type of distortion illustrated in Figs 1.18 and 4.6(a).

As in the case of the screw, the signs of the components are reversed for a dislocation of opposite sign, i.e. a negative edge dislocation with extra half-plane along the negative j-axis. Again, the elastic solution has

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Elastic properties of dislocations 69

an inverse dependence on distance from the line axis and breaks down when X and y tend to zero. It is vahd only outside a core of radius TQ.

The elastic field produced by a mixed dislocation (Fig. 3.8(b)) having edge and screw character is obtained from the above equations by adding the fields of the edge and screw constituents, which have Burgers vectors given by equation (3.2). The two sets are independent of each other in isotropic elasticity.

4.4 Strain Energy of a Dislocation

The existence of distortion around a dislocation implies that a crystal containing a dislocation is not in its lowest energy state. The extra energy is the strain energy. The total strain energy may be divided into two parts

^tota l — ^core i ^elastic < (4.18)

The elastic part, stored outside the core, may be determined by integra­tion of the energy of each small element of volume. This is a simple calculation for the screw dislocation, because from the symmetry the appropriate volume element is a cyhndrical shell of radius r and thick­ness dr. From equation (4.9), the elastic energy stored in this volume/7er unit length of dislocation is

d£'ei (screw) = -lirr dr^aezCez + (Jzeezo)

= 47rr dr Ge]^

(4.19)

Thus, from equation (4.15), the total elastic energy stored in the cyhnder (Fig. 4.5) per unit length of dislocation is

£"61 (screw) An Jro r 47r \roJ

(4.20)

where R is the outer radius. The above approach is much more complicated for other dislocations

having less symmetric fields. It is generally easier to consider EQ\ as the work done in displacing the faces of the cut LMNO by b (Figs 4.5 and 4.6) against the resisting internal stresses. For an infinitesimal element of area dA of LMNO, the work done is

d£'ei (screw)

d£'ei(edge)

^zy bdA 1 2

-a^ybdA

(4.21)

with the stresses evaluated on y = 0. The factor ^ enters because the stresses build up from zero to the final values given by equations (4.13) and (4.16) during the displacement process. The element of area is a strip

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70 Introduction to Dislocations

of width dx parallel to the z-axis, and so the total strain energy per unit length of dislocation is

, Gb^ f^dx Gb\ fR^ jfcei(screw) = —— / — = ——In —

The screw result is the same as equation (4.20). Strictly, equations (4.22) neglect small contributions from the work done on the core surface r = ro of the cylinder, but they are adequate for most requirements.

Equations (4.22) demonstrate that EQ\ depends on the core radius ro and the crystal radius R, but only logarithmically. EQ\ (edge) is greater than EQ\ (screw) by 1/(1 — ly) ^ 3/2. Taking R = 1 mm, ro = 1 nm, G = 40GNm~^ and b = 0.25 nm, the elastic strain energy of an edge dislocation will be about 4nJm~^ or about laJ(6eY) for each atom plane threaded by the dislocation. In crystals containing many disloca­tions, the dislocations tend to form in configurations in which the super­imposed long-range elastic fields cancel. The energy per dislocation is thereby reduced and an appropriate value of R is approximately half the average spacing of the dislocations arranged at random.

Estimates of the energy of the core of the dislocation are necessarily very approximate. However, the estimates that have been made suggest that the core energy will be of the order of 1 eV for each atom plane threaded by the dislocation, and is thus only a small fraction of the elastic energy. However, in contrast to the elastic energy, the energy of the core will vary as the dislocation moves through the crystal and this gives rise to the lattice resistance to dislocation motion discussed in section 10.3.

The vahdity of elasticity theory for treating dislocation energy outside a core region has been demonstrated by computer simulation (section 2.7). Figure 4.7 shows data for an atomic model of alpha iron containing a straight edge dislocation with Burgers vector 5[111] and line direction [112]. £'totai is the strain energy within a cyhnder of radius R with the dislocation along its axis. The energy varies logarithmically with R, as predicted by equation (4.22), outside a core of radius 0.7 nm, which is about 2.6b. The core energy is about 7eVnm~^

It was mentioned in the preceding section that the elastic field of a m/x^J dislocation (see Fig. 3.8(b)) is the superposition of the fields of its edge and screw parts. As there is no interaction between them, the total elastic energy is simply the sum of the edge and screw energies with b replaced by b sin 9 and b cos 9 respectively:

£"61 (mixed) Gb^sm^9 Gb^cos^9'^

+ -47r(l - u) 4n

Gb^(\-ucos^9)^ [R -In'

47r(l-zy) \ro

(4^23)

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Elastic properties of dislocations 71

20

15

E c \ 10

J 5 h

-

-

_

^core

// // /J

// // / / ^/y

''o

m l 1 1 1 1 1 m l

0.1 1

R, nm

10

Figure 4.7 The strain energy within a cyhnder of radius R that contains a straight edge dislocation along its axis. The data was obtained by computer simulation for a model of iron. (Courtesy Yu. N. Osetsky.)

bi

+

line 1 line 2 line 3

bi+b2 = ba

Figure 4.8 Reaction of two dislocations to form a third.

which falls between the energy of an edge and a screw dislocation. From the expressions for edge, screw and mixed dislocations it is clear

that the energy per unit length is relatively insensitive to the character of the dislocation and also to the values of i and TQ. Taking reahstic values for R and ro all the equations can be written approximately as

EQ\ — oiGh (4.24)

where a ? 0.5—1.0. This leads to a very simple rule {Frank's rule) for determining whether or not it is energetically feasible for two dislocations to react and combine to form another. Consider the two dislocations in Fig. 4.8 with Burgers vectors bi and b2 given by the Burgers circuit construction (section 1.4). Allow them to combine to form a new dislocation with Burgers vector bs as indicated. From equation (4.24), the elastic energy per unit length of the dislocations is proportional to b], b\ and b\ respectively. Thus, if {b\ + b^ > b\, the

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72 Introduction to Dislocations

reaction is favourable for it results in a reduction in energy. If {b\ + bj) < b\, the reaction is unfavourable and the dislocation with Burgers vector b^ is Uable to dissociate into the other two. If {b\ + b^ — b\, there is no energy change. These three conditions corre­spond to the angle 0 in Fig. 4.8 satisfying 7r/2 <(/)<7r, ^ <<i) < i{\l and 0 = 7r/2 respectively. In this argument the assumption is made that there is no additional interaction energy involved, i.e. that before and after the reaction the reacting dislocations are separated sufficiently so that the interaction energy is small. If this is not so, the reactions are still favourable and unfavourable, but the energy changes are smaller than implied above. Frank's rule is used to consider the feasibihty of various dislocation reactions in Chapters 5 and 6.

4.5 Forces on Dislocations

When a sufficiently high stress is appHed to a crystal containing disloca­tions, the dislocations move and produce plastic deformation either by slip as described in section 3.3 or, at sufficiently high temperatures, by climb (section 3.6). The load producing the applied stress therefore does work on the crystal when a dislocation moves, and so the dislocation responds to the stress as though it experiences a force equal to the work done divided by the distance it moves. The force defined in this way is a virtual, rather than real, force, but the force concept is useful for treating the mechanics of dislocation behaviour. The glide force is considered in this section and the climb force in section 4.7.

Consider a dislocation moving in a slip plane under the influence of a uniform resolved shear stress r (Fig. 4.9). When an element d/ of the dislocation line of Burgers vector b moves forward a distance d^ the crystal planes above and below the slip plane will be displaced relative to each other by b. The average shear displacement of the crystal surface produced by ghde of d/ is

d^d (4.25)

Figure 4.9 The displacement d used to determine the glide force on an element d/ in its glide plane.

where A is the area of the slip plane. The external force due to r acting over this area is AT, SO that the work done when the element of sHp occurs is

AW-- ( ^ >

(4.26)

The glide force F ona unit length of dislocation is defined as the work done when unit length of dislocation moves unit distance. Therefore

AW _dW

~ dTd/ ~ dJ' Tb (4.27)

The stress r is the shear stress in the glide plane resolved in the direction of b and the ghde force F acts normal to the dislocation at every point

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Elastic properties of dislocations 73

R

^^.^ k' dislocation de/2 -Ai-^ /

T

Figure 4.10 Curved element of dislocation under line tension forces T.

de/2~

T

along its length, irrespective of the line direction. The positive sense of the force is given by the physical reasoning of section 3.3.

In addition to the force due to an externally applied stress, a disloca­tion has a line tension which is analogous to the surface tension of a soap bubble or a Hquid. This arises because, as outlined in the previous section, the strain energy of a dislocation is proportional to its length and an increase in length results in an increase in energy. The line tension has units of energy per unit length. From the approximation used in equation (4.24), the line tension, w^hich may be defined as the increase in energy per unit increase in the length of a dislocation line, will be

T=aGb^ (4.28)

Consider the curved dislocation in Fig. 4.10. The line tension will produce forces tending to straighten the line and so reduce the total energy. The direction of the net force is perpendicular to the dislocation and towards the centre of curvature. The line will only remain curved if there is a shear stress which produces a force on the dislocation line in the opposite sense. The shear stress TQ needed to maintain a radius of curvature R is found in the following way. The angle subtended at the centre of curvature is dO = dl/R, assumed to be <C 1. The outward force along OA due to the apphed stress acting on the elementary piece of dislocation is robdl from equation (4.27), and the opposing inward force along OA due to the hne tension T at the ends of the element is 2rsin(d^/2), which is equal to TdO for small values of dO. The line will be in equihbrium in this curved position when

Tde = robdl T (4.29)

'•'' '' = bR

Substituting for T from equation (4.28)

^0 = - ^ (4.30)

This gives an expression for the stress required to bend a dislocation to a radius R and is used many times in subsequent chapters. A particularly

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74 Introduction to Dislocations

direct application is in the understanding of the Frank-Read dislocation multipHcation source described in Chapter 8.

Equation (4.30) assumes from equation (4.24) that edge, screw and mixed segments have the same energy per unit length, and the curved dislocation of Fig. 4.10 is therefore the arc of a circle. This is only strictly vaHd if Poisson's ratio v equals zero. In all other cases, the Une experi­ences a torque tending to rotate it towards the screw orientation where its energy per unit length is lower. The true line tension of a mixed segment is

T=E.m+^^ (4.31)

where EQ\{9) is given by equation (4.23). T for a screw segment is four times that of an edge when v = 1/3. Thus, for a Une bowing under a uniform stress, the radius of curvature at any point is still given by equation (4.29), but the overall Hne shape is approximately elliptical with major axis parallel to the Burgers vector; the axial ratio is approx­imately 1/(1 — p). For most calculations, however, equation (4.30) is an adequate approximation.

4.6 Forces between A simple semi-qualitative argument will illustrate the significance of the Dislocations concept of a force between dislocations. Consider two parallel edge dis­

locations lying in the same slip plane. They can either have the same sign as in Fig. 4.11(a) or opposite sign as in Fig. 4.11(b). When the dislocations are separated by a large distance the total elastic energy per unit length of the dislocations in both situations will be, from equation (4.24)

aGb^ + aGb^ (4.32)

When the dislocations in Fig. 4.11(a) are very close together the arrang­ement can be considered approximately as a single dislocation with a Burgers vector magnitude lb and the elastic energy will be given by

aG{2bf (4.33)

which is twice the energy of the dislocations when they are separated by a large distance. Thus the dislocations will tend to repel each other to reduce their total elastic energy. When dislocations of opposite sign (Fig. 4.11(b)) are close together, the effective magnitude of their Burgers vectors will be zero, and the corresponding long-range elastic energy zero also. Thus dislocations of opposite sign will attract each other to reduce their total elastic energy. The positive and negative edge disloca­tions in Fig. 4.11(b) will combine and annihilate each other. These conclusions regarding repulsion and attraction also follow for disloca­tions of mixed orientation from Frank's rule by putting 0 = 0 or TT in Fig. 4.8. Similar effects occur when the two dislocations do not lie in the same slip plane (Fig. 4.11(c)), but the conditions for attraction and repulsion are usually more complicated, as discussed below.

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Elastic properties of dislocations 75

slip plane

(a)

slip plane A

slip plane B

(b)

(c)

Figure 4.11 Arrangement of edge dislocations with parallel Burgers vectors lying in parallel slip planes, (a) Like dislocations on the same slip plane, (b) unlike dislocations on the same slip plane, and (c) unlike dislocations on slip planes separated by a few atomic spacings.

The basis of the method used to obtain the force between two dis­locations is the determination of the additional work done in introdu­cing the second dislocation into a crystal which already contains the first. Consider two dislocations lying parallel to the z-axis (Fig. 4.12). The total energy of the system consists of (a) the self-energy of disloca­tion I, (b) the self-energy of dislocation II, and (c) the elastic interaction energy between I and II. The interaction energy E{^x is the work done in displacing the faces of the cut which creates II in the presence of the stress field of I. The displacements across the cut are b^, by, bz, the components of the Burgers vector b of II. By visualising the cut parallel to either the x or y axes, two alternative expressions for Ei^yt per unit length of II are

poo

= + / {bxCTxy + byayy + bzCFzy)<^X J X

/•oo

= - / ( XCT X + byCFy^ + bz(Jzx)^y Jy

(4.34)

where the stress components are those due to I. (The signs of the right-hand side of these equations arise because if the displacements of b are taken to occur on the face of a cut with outward normal in the positive y and x directions, respectively, they are in the direction of positive x, j , z for the first case (x-axis cut) and negative x, y, z for the second (y-axis cut).)

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76 Introduction to Dislocations

The interaction force on II is obtained simply by differentiation of these expressions, i.e. F^ = —dEint/dx and Fy = —dEi^xjdy. For the two parallel edge dislocations with parallel Burgers vectors shown in Fig. 4.12, Z? = Z? = 0 and b^ = b, and the components of the force per unit length acting on II are therefore

VL

'4 n

Figure 4.12 Forces considered for the interaction between two edge dislocations.

vb Fy -CFxxb (4.35)

where Gxy and a^ are the stresses of I evaluated at position {x,y) of II. The forces are reversed if II is a negative edge i.e. the dislocations have opposite sign. Equal and opposite forces act on I. F^ is the force in the gUde direction and Fy the force perpendicular to the ghde plane. Sub­stituting from equation (4.16) gives

Fr = Gb' x[x" • / )

27r(l-J/)(x2+j2)2

Gb'^ j ( 3 x ^ + / )

27r(l- i /) {x^+y^f

(4.36)

Since an edge dislocation can move by slip only in the plane contained by the dislocation line and its Burgers vector, the component of force which is most important in determining the behaviour of the disloca­tions in Fig. 4.12 is F^. For dislocations of the same sign, inspection of the variation of F^ with x reveals the following:

nature X range

negative repulsive positive attractive negative attractive positive repulsive

—oo < X < —y -y <x <Q

0 <x <y y < X < oo

The sign and nature of F^ is reversed if I and II are edge dislocations of opposite sign. F^ is plotted against x, expressed in units of j , in Fig. 4.13. It is zero when x = 0, ±.y, ±oo, but of these, the positions of stable equiUbrium are seen to be x = 0, ±OQ for edges of the same sign and ±y if they have the opposite sign.

It follows that an array of edge dislocations of the same sign is most stable when the dislocations lie vertically above one another as in Fig. 4.14(a). This is the arrangement of dislocations in a small angle pure tilt boundary described in Chapter 9. Furthermore, edge dislocations of opposite sign ghding past each other on parallel slip planes tend to form stable dipole pairs as in Fig. 4.14(b) at low appHed stresses (section 10.8).

Comparison of the glide force F^ in equation (4.35) with Fin equation (4.27) shows that since cjxy is the shear stress in the glide plane of

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Elastic properties of dislocations 11

CO

c CO o o (0

T3 0 D)

T5 0 C 0

I 0

JQ 0 £2 o u.

0.3

0.2

•i 0.1 +

0

-0.1

-0.2

-0.3 -8y -ly -6y -5y -4y -3y -2y -1y 0 1y 2y 3y 4y 5y 6y 7y 8y

Figure 4.13 Glide force per unit length between parallel edge dislocations with parallel Burgers vectors from equation (4.36). Unit of force F^ is Gb^/27r(\ - v)y. The full curve A is for like dislocations and the broken curve B for unHke dislocations.

X

±. s90*

..T J-

±:C^. 45-

T ^.'\45-

(a) (b)

Figure 4.14 Stable positions for two edge dislocations of (a) the same sign and (b) opposite sign.

dislocation II acting in the direction of its Burgers vector, equation (4.27) holds for both external and internal sources of stress.

Consider two parallel screw dislocations, one lying along the z-axis. The radial and tangential components of force on the other are

Fr = (J,eb Fe = a,rb (4.37)

and substituting from equations (4.15)

Gb^/lur Fe Fr 0 (4.38)

The force is much simpler in form than that between two edge disloca­tions because of the radial symmetry of the screw field, iv is repulsive for

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78 Introduction to Dislocations

screws of the same sign and attractive for screws of opposite sign. It is readily shown from either equations (4.35) or equations (4.37) that no forces act between a pair of parallel dislocations consisting of a pure edge and a pure screw, as expected from the lack of mixing of their stress fields (see section 4.3).

4.7 Climb Forces The force component Fy in equation (4.35) is a climb force per unit length resulting from the normal stress GXX of dislocation I attempting to squeeze the extra half-plane of II from the crystal. This can only occur physically if intrinsic point defects can be emitted or absorbed at the dislocation core of II (see section 3.6). As in the case of ghde forces, climb forces can arise from external and internal sources of stress. The former are important in creep, and the latter provided the example of conservative climb in section 3.8. Line tension can also produce climb forces, but in this case the force acts to reduce the line length in the extra half-plane: shrinkage of prismatic loops as in Fig. 3.19 is an example. However, since the creation and annihilation of point defects are involved in climb, chemical forces due to defect concentration changes must be taken into account in addition to these mechanical forces.

It was seen in section 3.6 that when an element 1 of dislocation is displaced through s, the local volume change is b x 1 • s. Consider a segment length / of a positive edge dislocation climbing upwards through distance s in response to a mechanical climb force F per unit length. The work done is Fls and the number of vacancies absorbed is blsjQ., where 17 is the volume per atom. The vacancy formation energy is therefore changed by FVtlb. As a result of this chemical potential, the equiUbrium vacancy concentration at temperature T in the presence of the dislocation is reduced to

c = tx^[-{E} + mib)lkT\

— coQxp{-FQ/bkT)

where CQ is the equihbrium concentration in a stress-free crystal (equa­tion (1.3)). For negative climb involving vacancy emission (F < 0) the sign of the chemical potential is changed so that c> CQ- Thus, the vacancy concentration deviates from CQ, building up a chemical force per unit length on the Hne

hkT / = — l n ( c / c o ) (4.40)

until/balances Fin equilibrium. Conversely, in the presence of a super-saturation c/co of vacancies, the dislocation climbs up under the chem­ical force/until compensated by, say, external stresses or line tension. The latter is used in the analysis for a dislocation climb source in section 8.7. The nature of these forces is illustrated schematically in Fig. 4.15. By substituting reasonable values of T and ft in equation (4.40), it is easy

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Elastic properties of dislocations 79

mechanical force F

chemical force f

Figure 4.15 Mechanical and chemical forces for climb of an edge dislocation. Vacancies (shown as D) have a local concentration c in comparison with the equiUbrium concentration CQ in a dislocation-free crystal.

to show that even moderate supersaturations of vacancies can produce forces much greater than those arising from external stresses.

The rate of climb of a dislocation in practice depends on (a) the direction and magnitude of the mechanical and chemical forces, F a n d / , (b) the mobihty of jogs (section 3.6) and (c) the rate of migration of vacancies through the lattice to or from the dislocation.

4.8 Image Forces A dislocation near a surface experiences forces not encountered in the bulk of a crystal. The dislocation is attracted towards a free surface because the material is effectively more compliant there and the disloca­tion energy is lower: conversely, it is repelled by a rigid surface layer. To treat this mathematically, extra terms must be added to the infmite-body stress components given in section 4.3 in order that the required surface conditions are satisfied. When evaluated at the dislocation line, as in equa­tions (4.35) and (4.37), they result in a force. The analysis for infinite, straight dislocation lines parallel to the surface is relatively straight-forward.

Consider screw and edge dislocations parallel to, and distance d from, a surface x = 0 (Fig. 4.16); the edge dislocation has Burgers vector b in the X direction. For difree surface, the tractions GXX, cFyx and GZX must be zero on the plane x = 0. Consideration of equation (4.13) shows that these boundary conditions are met for the screw if the infinite-body result is modified by adding to it the stress field of an imaginary screw dislocation of opposite sign at x = —d (Fig. 4.16(a)). The required solution for the stress in the body {x > 0) is therefore

^- = (]^r^7) + ( 4 ^ 7 ) (4.41)

^ ^ - ^^+ (4.42) (xi + j2) ( 2 + j2

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80 Introduction to Dislocations

image

3--d

y

- 0

screw

C

d

(a)

image

•"?

d

Y'

— 0

^ d

edge

- 1 . • X

(b)

Figure 4.16 (a) Screw and (b) edge dislocations a distance d from a surface x = 0. The image dislocations are in space a distance d from the surface.

where x_ = (x - ^ , x+ = (x + J) and A — Gb/ln. The force per unit length in the x-direction Fx(= cFzyb) induced by the surface is obtained from the second term in cFzy evaluated at x = <i, JF = 0. It is

F^ = -Gh^jAi^d (4.43)

and is simply the force due to the image dislocation at x = —d. For the edge dislocation (Fig. 4.16(b)), superposing the field of an imaginary edge dislocation of opposite sign dX x— —d annuls the stress cr x on X = 0, but not Gy^. When the extra terms are included to fully match the boundary conditions, the shear stress in the body is found to be

CTi /)x_ (xl - / ) /)x+ {x\ - / ) lDd{x^x\ - 6 x x + / + / ]

yx (X2_+/) ' (4+/)' [A^y^f (4.44)

where D — A\(\ — v). The first term is the stress in the absence of the surface, the second is the stress appropriate to an image dislocation at x——d, and the third is that required to make Gy^ — 0 when x = 0. The force per unit length FJ^—GyJ)) arising from the surface is given by putting X = (i, jF = 0 in the second and third terms. The latter contrib­utes zero, so that the force is

-Gh^lAi^(\-v)d (4.45)

and is again equivalent to the force due to the image dislocation. The image forces decrease slowly with increasing <iand are capable of

removing dislocations from near-surface regions. They are important, for example, in specimens for transmission electron microscopy (section 2.4) when the slip planes are orientated at large angles (~90°) to the surface. It should be noted that a second dislocation near the surface would experience a force due to its own image and the surface terms in the field of the first. The interaction of dipoles, loops and curved dislocations with surfaces is therefore compHcated, and only given approximately by images.

Further Reading Bacon, D. J., Barnett, D. M. and Scattergood, R. O. (1979) 'Anisotropic con­tinuum theory of lattice defects', Prog, in Mater. Sci. 23, 51. Cottrell, A. H. (1953) Dislocations and Plastic Flow in Crystals, Oxford Uni­

versity Press. Friedel, J. (1964) Dislocations, Pergamon Press. Hirth, J. P. and Lothe, J. (1982) Theory of Dislocations, Wiley. Lardner, R. W. (1974) Mathematical Theory of Dislocations and Fracture, Univ.

of Toronto Press. Mura, T. (1982) Micromechanics of Defects in Solids, Martinus Nijhoff. Nabarro, F. R. N. (1967) The Theory of Crystal Dislocations, Oxford University

Press. Nye, J. F. (1967) Physical Properties of Crystals, Oxford University Press.

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Elastic properties of dislocations 81

Seeger, A. (1955) 'Theory of lattice imperfections', Handbuch der Physik, Vol. VII, part 1, p. 383, Springer-Verlag.

Steeds, J. W. (1973) Anisotropic Elasticity Theory of Dislocations, Oxford. Teodosiu, C. (1982) Elastic Models of Crystal Defects, Springer. Timoshenko, S. P. and Goodier, J. N. (1970) Theory of Elasticity, McGraw-Hill. Weertman, J. and Weertman, J. R. (1964) Elementary Dislocation Theory,

Macmillan.