3.4 Rates of Change Tues Sept 29 Do Now Find the derivative of each: 1) 2)
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Transcript of 3.4 Rates of Change Tues Sept 29 Do Now Find the derivative of each: 1) 2)
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3.4 Rates of ChangeTues Sept 29
Do Now
Find the derivative of each:
1)
2)
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Rates of Change
• Review: Average Rate of Change
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Instantaneous Rate of Change
• Because slope is a rate of change, we can use derivatives to compute the instantaneous rate of change using different variables
• Note: dA/dR means you are differentiating A in terms of R
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Ex
• Let A be the area of a circle with radius r.
• Compute dA/dr at r = 2 and r = 5
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F’(x) and 1 unit change
• For small values of h, slope of two points represents the derivative
• F’(x) can be used to approximate the change in f(x) caused by a one-unit change
• Note: you can always just plug in the 2 values into f(x)
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Ex• For speeds x between 30 and 75 mph, the
stopping distance of an automobile after the brakes are applied is approximately F(x) = 1.1x +0.05x^2 ft
• For x = 60mph, estimate the change in stopping distance if the speed is increased by 1mph
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Marginal Cost in Economics
• To study the relation between cost and production, the marginal cost is the cost of producing one additional unit
• Ex 4 p.152
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Linear Motion
• Linear motion - motion along a straight line
• S(t) denotes the distance from the origin at time t
• Velocity v(t) can be computed by ds/dt
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Linear Motion
• Derivatives can also show us the relationship between position and velocity (and acceleration)
• If s(t) = position function then
• Velocity v(t) = ds/dt
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Velocity
• The sign of velocity indicates going forward or backwards
• We can look at position graphs to determine the velocity of the function
• Ex 5 p.153
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Ex5
• A truck enters the off-ramp of a highway at t = 0. Its position after t seconds is s(t) = 25t – 0.3t^3 m for [0,5]
• (A) How fast is the truck going at the moment it enters the off-ramp?
• (B) Is the truck speeding up or slowing down?
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Velocity and Gravity
• The height s(t) of an object tossed vertically in the air is
• Its velocity is given by
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#22
• The height (in meters) of a helicopter at time t (in min) is s(t) = 600t – 3t^3 for [0,12]
• (b) Find the velocity at t = 8, 10
• (c ) Find the maximum height
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Closure
• Journal Entry: What other applications of derivatives did we learn about today? How r position and velocity related?
• HW: p.156 #6 7 11 16 21 27 39 43