3.2.4 Rectangular Footing
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Transcript of 3.2.4 Rectangular Footing
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RF ID :
Concrete Stength, f'c = 20.7 MPaSteel Yield Strength, fy = 414 MPa
Reduction factor, φ = 0.0 !for "e#ure$φ = 0.%& !for hear$
Colu(n i)e, * = +00 ((
h = +00 ((
llo-a*le gro
1.20 (.oil*earing ca/acity, = 120 Pa
Ma#.ooting idth, 3 = 1.&0 (
#ial eadload, = 20.00 5t = 0.4& (.
#ial 6ieload, = 110.00 5
8otal #ial 6oad, = 400.0 5
actored #ial 6oad, = &+.00 59nit eight of Soil, = :::
Main Reinforce(ent, φ = 1; (( = %%.4% Pa
FOOTING AREA:
4.&2
rea = 6 # 3
6 = +.01 (
3 = 1.&0 (
9S< +.00 1.&0 ( >>8?5@
4.&0
THICKNESS:= PuA
= 1+2 Pa
t
P 8
f=B
allo-
P6
P66
P 8
P9γ
S>?6 5A(+ B
allo-!net$ = B
all !γ
S>?6#
f $ !γ
C>5CR
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TWO-WAY SHEAR:
d =
= +&% ((
dA2 dA2
Critical ection
for t-o-ay
hear
c
::: Pa
c d
Dc = c d = colu(n -idth d
= ::: 5 = ::: ((/eri(eter of the critical ecti
Du = for t-o-ay hear
critical area = = 4E!c d$
= 4.07 = 2;+2 ((
Du = ::: 5
Vu < Vc, ADEQUATE SECTION
ONE-WAY SHEAR:
d = +&% ((
Du =Critical area critical area = !6A2 *A2 d$ # 3
= :::
1.&0Du = ::: 5
Critical ection for Dc =one-ay hear = ::: 5
1.&1
Vu < Vc, ADEQUATE THICKNESS
+.01
8he critical ection i at ditance d/2 fro( the edge of the colu(n.
t cc φA2
φ 0.+4 √f'c *o d
*o =
B # critical area
footing area !cd$2
(2
8he critical ection i at ditance d fro( the edge of the colu(n.
B # critical area
(2
φ 0.17 √f'c * d
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Check fo !e"#$% C"&"c#'( of Co$ce'e Co)u*$ "' 'he I$'ef"ce +#'h Fou$"'#o$
&+.00 5
3earing Strength = 0.70= ::: 5 .u, &o/#e *#$#*u* "e" of o+e)0
ini(u( area of teel = 0.00& # area of colu(n
= 4&0.00
uing 1;
201.0;
no. of do-el = 2
1#$#*u* e2u#e e/e)o&*e$' )e$%'h of o+e)0 #$'o 'he fou$"'#o$
6d = = ::: (( %o/e$0 n
*ut not le than
6d = = ::: ((
REINFORCE1ENT:
F 6>5@ ?R5G
P9 =
0.%& φ f'c 1 φ =
((2
(( φ *ar
1*ar = ((2
0.24 fy d*√f'c
0.044 fy d*
