3-3 Parallel Lines and Transversals. Section 3.2.

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3-3 Parallel Lines and Transversal s

Transcript of 3-3 Parallel Lines and Transversals. Section 3.2.

Page 1: 3-3 Parallel Lines and Transversals. Section 3.2.

3-3 Parallel Lines and

Transversals

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Section3.2

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PROPERTIES OF PARALLEL LINES

POSTULATE

POSTULATE 15 Corresponding Angles Postulate

1

2

1 2

If two parallel lines are cut by a transversal, then the pairs of corresponding angles are congruent.

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PROPERTIES OF PARALLEL LINES

THEOREMS ABOUT PARALLEL LINES

THEOREM 3.4 Alternate Interior Angles

3

4

3 4

If two parallel lines are cut by a transversal, then the pairs of alternate interior angles are congruent.

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PROPERTIES OF PARALLEL LINES

THEOREMS ABOUT PARALLEL LINES

THEOREM 3.5 Consecutive Interior Angles

5

6

m 5 + m 6 = 180°

If two parallel lines are cut by a transversal, then the pairs of consecutive interior angles are supplementary.

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PROPERTIES OF PARALLEL LINES

THEOREMS ABOUT PARALLEL LINES

THEOREM 3.6 Alternate Exterior Angles

7

8

7 8

If two parallel lines are cut by a transversal, then the pairs of alternate exterior angles are congruent.

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PROPERTIES OF PARALLEL LINES

THEOREMS ABOUT PARALLEL LINES

THEOREM 3.7 Perpendicular Transversal

j k

If a transversal is perpendicular to one of two parallellines, then it is perpendicular to the other.

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Proving the Alternate Interior Angles Theorem

Prove the Alternate Interior Angles Theorem.

SOLUTION

GIVEN p || q

p || q Given

Statements Reasons

1

2

3

4

PROVE 1 2

1 3 Corresponding Angles Postulate

3 2 Def first -Vertical Angles Theorem

1 2 Transitive property of Congruence

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Using Properties of Parallel Lines

SOLUTION

Given that m 5 = 65°, find each measure. Tellwhich postulate or theoremyou use.

Linear Pair Postulatem 7 = 180° – m 5 = 115°

Alternate Exterior Angles Theoremm 9 = m 7 = 115°

Corresponding Angles Postulatem 8 = m 5 = 65°

m 6 = m 5 = 65° Vertical Angles Theorem

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Using Properties of Parallel Lines

Use properties ofparallel lines to findthe value of x.

SOLUTION

Corresponding Angles Postulatem 4 = 125°

Linear Pair Postulatem 4 + (x + 15)° = 180°

Substitute.125° + (x + 15)° = 180°

PROPERTIES OF SPECIAL PAIRS OF ANGLES

Subtract.x = 40°