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Transcript of 293 g
( )293 g
1 mol( )150.0 g
1
THANKSGIVING H.W. ANSWERS
K 2 mol x 39.00 g/mol = 78.00 g
Cr 2 mol x 51.996 g/mol= 103.992 g
O 7mol x 15.99 g/mol= 111.93 g
1a) Molar mass (GFM) = 293.992 g/mol
K2Cr2O7
1b) 2 moles of K are in I mole of K2Cr2O7
1c)How many moles are in the 150.00 grams of
K2Cr2O7
=0.5102mol K2Cr2O7
( )1 mol
6.02 x 1023
particles( )293 g
1 mol( )150.0 g
1
= 3.07 x 1023 molecules K2Cr2O7
1c) How many particles are in the 150.00 g
1d) What is the mass of 12.04 x 1023 particles of K2Cr2O7
( )1 mol( ) 293 g1 mol( ) 12.01 x 1023
particles
1 6.02 x 1023
particles
= 3.07 x 1023 molecules K2Cr2O7
( )1 mol( ) 17 g1 mol( ) 51.0 g NH3
1
18.06 x 1023
PARTICLES
2a-b)what is the mass of 18.06 x 1023 particles of NH3 (gfm=17g/mol)
2c) What is the mass of 12.04 x 1023 particles of K2Cr2O7
( )1 mol( ) 22.4L1 mol
6.02 x 1023
particles
=67.2 L NH3( )18.06 x 1023
particles
1
6.02 x 1023
PARTICLES
Pb 1 mol x 207.2 g/mol = 207.20 g
N 2 mol x 14.006 g/mol= 28.012 g
O 6mol x 15.99 g/mol= 95.94 g
Molar mass (GFM) = 331.152 g/mol
Pb(NO3)2
( )293 g
1 mol( )150.0 g
1 =0.5102 mol K2Cr2O7
( )331.152 g
1 mol( )0.5102 mol
1
168.954 g= Pb(NO3)2
3)How many grams of lead nitrate = the moles of 150.00 grams of K2Cr2O7 ?