2.1C Acceleration

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    Acceleration = change invelocitytime

    Acceleration = rate of change invelocity

    a = acceleration

    vf= final velocity

    vi= initial

    velocity

    a = Vf - Vi

    t

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    Acceleration- has

    direction, just like

    velocity.

    Acceleration is aVECTOR (it has both amagnitude and a direction).

    The roller coaster

    accelerates bothbecause its speed

    changes and its

    direction

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    For its velocity to change, anobject must accelerate.

    An object accelerateswhenever its speed

    speed or

    directiondirection or bothboth change.

    So this means.

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    An object moving in a circle at

    constant speed is alwaysaccelerating (changing direction).

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    How can you accelerate at a constantspeed?

    Acceleration at constant speedAcceleration at constant speed

    Its like gravity. An objects

    velocity gets faster every second,but it gets faster at the samerate.

    Objects accelerate toward theearth at a rate of 9.8 m/s2. Inother words they fall 9.8m/s

    faster every second.

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    O p o s i t i v e d i r e c t i o n

    0 . 4 m 0 . 7 m 1 . 0 m 1 . 3 m

    t = 0 s t = 1 s t = 2 s t = 3 s t = 4 s

    An object is moving with uniform acceleration.

    Its positions at one-second interval are shown below.

    distance traveled in

    the first second

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    O p o s i t i v e d i r e c t i o n

    0 . 4 m 0 . 7 m 1 . 0 m 1 . 3 m

    t = 0 s t = 1 s t = 2 s t = 3 s t = 4 s

    An object is moving with uniform acceleration.

    Its positions at one-second interval are shown below.

    distance traveled in

    thesecond second.

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    O p o s i t i v e d i r e c t i o n

    0 . 4 m 0 . 7 m 1 . 0 m 1 . 3 m

    t = 0 s t = 1 s t = 2 s t = 3 s t = 4 s

    An object is moving with uniform acceleration.

    Its positions at one-second interval are shown below.

    distance traveled in

    thethird second

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    O p o s i t i v e d i r e c t i o n

    0 . 4 m 0 . 7 m 1 . 0 m 1 . 3 m

    t = 0 s t = 1 s t = 2 s t = 3 s t = 4 s

    An object is moving with uniform acceleration.

    Its positions at one-second interval are shown below.

    distance traveled in

    thefourth second

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    O p o s i t i v e d i r e c t i o n

    0 . 4 m 0 . 7 m 1 . 0 m 1 . 3 m

    t = 0 s t = 1 s t = 2 s t = 3 s t = 4 s

    An object is moving with uniform acceleration.

    Its positions at one-second interval are shown below.

    0.4 , 0.7 , 1.0 , 1.3 is an arithmetic progression with a

    common difference 0.3.

    This is an important characteristic of motion with

    uniform acceleration.

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    ACCELERATIONAcceleration is the change in speed in an object in a period of

    time.

    change invelocity (m/s)

    acceleration

    (m/s/s)

    Where do the units come from?

    a = v t

    a = m/s s

    a = m/s/s=m/s2

    It takes a cyclist 20 secondsto go from

    a standing start to 14m/s.

    What is their acceleration?

    What is 14m/s in km/hr?

    a = v/t a = 14m/s / 20s a = 0.7ms-2

    = 14 60s 60min 1000m

    = 50.4km/hr

    v

    a t

    change intime (s)

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    Acceleration

    A cyclist accelerates from 0 to 10m/s in 5 seconds. What is heracceleration?

    A ball is dropped and accelerates downwards at a rate of 10m/s2

    for 12 seconds. How much will the balls velocity increase by? A car accelerates from 10 to 20m/s with an acceleration of 2m/s2.

    How long did this take?

    A rocket accelerates from 1,000m/s to 5,000m/s in 2 seconds.What is its acceleration?

    Acceleration = change in velocity (in m/s)

    (in m/s2) time taken (in s)

    V

    TA

    SPEED/TIME GRAPHS

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    SPEED/TIME GRAPHS

    Time (sec)

    10 20 30

    Speed

    (m/s)

    4

    8

    Using the speed/time graph:

    3. What distance is covered in part 1?

    4. What is the total distance covered?

    d = v t

    d = 4m/s 10s

    d = 40 m

    Part 1 = 40m

    Part 2 = 0m

    Part 3 = 0m

    Part 5 = v t = 8m/s 10 s = 80m

    Part 4 = v t = 8m/s 5s = 20m

    Total = 40 + 80 + 20 =140m

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    ACCELERATION QUESTIONSWhat would these look like on a speed/time graph?

    1. stopped

    2. slow

    3. fast

    4. accelerating

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    Velocity-time graphs

    80

    60

    40

    20

    010 20 30 40 50

    Velocity

    m/s

    T/s

    1) Upwards line =

    Constantacceleration

    2) Horizontal line =

    Constant velocity

    3) Upwards line =

    constant accel,slower velocity

    4) Downward line =constant accel

    opposite direction

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    80

    60

    40

    20

    0

    1) How fast was the object going after 10 seconds?

    2) What is the acceleration from 20 to 30 seconds?

    3) What was the deceleration from 30 to 50s?

    4) How far did the object travel altogether?

    10 20 30 40 50

    Velocity

    m/s

    T/s

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    Which car (red, green, or blue) experiences the greatest acceleration?

    Blue car has the greatest acceleration

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    Match the car to the graphMatch the car to the graph

    Match the car tothe appropriategraph line.

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    MORE RESOURCES

    http://www.glenbrook.k12.il.us/GBSSCI/PH

    http://www.fearofphysics.com/Xva/xva.html

    http://www.quia.com/rr/121411.html?AP_ra http://www.physics4kids.com/files/motion_v

    http://www.glenbrook.k12.il.us/GBSSCI/PHYS/CLASS/1DKin/U1L1d.htmlhttp://www.fearofphysics.com/Xva/xva.htmlhttp://www.quia.com/rr/121411.html?AP_rand=1991654762http://www.physics4kids.com/files/motion_velocity.htmlhttp://www.physics4kids.com/files/motion_velocity.htmlhttp://www.quia.com/rr/121411.html?AP_rand=1991654762http://www.fearofphysics.com/Xva/xva.htmlhttp://www.glenbrook.k12.il.us/GBSSCI/PHYS/CLASS/1DKin/U1L1d.html