2.1 the basic language of functions x
Transcript of 2.1 the basic language of functions x
The Basic Language of FunctionsA function is a procedure that assigns each input
exactly one output.
The Basic Language of FunctionsA function is a procedure that assigns each input
exactly one output. In mathematics, usually we name
functions as f, g, h…
The Basic Language of FunctionsA function is a procedure that assigns each input
exactly one output. In mathematics, usually we name
functions as f, g, h…and by default we let x represent
the input and y represent the output.
Example A.
a. The inputs are driver-license numbers x,
the outputs y are the names of the license-holders.
The Basic Language of FunctionsA function is a procedure that assigns each input
exactly one output. In mathematics, usually we name
functions as f, g, h…and by default we let x represent
the input and y represent the output.
Example A.
a. The inputs are driver-license numbers x,
the outputs y are the names of the license-holders.
This is a function because for each license number,
there is exactly one owner of that license.
The Basic Language of FunctionsA function is a procedure that assigns each input
exactly one output. In mathematics, usually we name
functions as f, g, h…and by default we let x represent
the input and y represent the output.
Example A.
a. The inputs are driver-license numbers x,
the outputs y are the names of the license-holders.
This is a function because for each license number,
there is exactly one owner of that license.
The Basic Language of Functions
b. The inputs are driver-license numbers x,
the outputs y are the names of all the siblings of the
license-holders.
A function is a procedure that assigns each input
exactly one output. In mathematics, usually we name
functions as f, g, h…and by default we let x represent
the input and y represent the output.
Example A.
a. The inputs are driver-license numbers x,
the outputs y are the names of the license-holders.
This is a function because for each license number,
there is exactly one owner of that license.
The Basic Language of Functions
b. The inputs are driver-license numbers x,
the outputs y are the names of all the siblings of the
license-holders. This is not a function because for
some inputs of license numbers, there might be many
outputs of names of the siblings of the license holders.
A function is a procedure that assigns each input
exactly one output. In mathematics, usually we name
functions as f, g, h…and by default we let x represent
the input and y represent the output.
Given a function, the set D of all the inputs is called
the domain of the function.
The Basic Language of Functions
Given a function, the set D of all the inputs is called
the domain of the function. The domain D of the
license-number-to-name function in example A
are all valid driver license numbers.
The Basic Language of Functions
Given a function, the set D of all the inputs is called
the domain of the function. The domain D of the
license-number-to-name function in example A
are all valid driver license numbers. The set R of all
the outputs is called the range and the range R of the
license-number-to-name function are all the names
of drivers with a valid license.
The Basic Language of Functions
Given a function, the set D of all the inputs is called
the domain of the function. The domain D of the
license-number-to-name function in example A
are all valid driver license numbers. The set R of all
the outputs is called the range and the range R of the
license-number-to-name function are all the names
of drivers with a valid license.
A function may be given by a chart where
the input and outputs are listed explicitly.
The Basic Language of Functions
x y
–1 4
2 3
5 –3
6 4
7 2
Given a function, the set D of all the inputs is called
the domain of the function. The domain D of the
license-number-to-name function in example A
are all valid driver license numbers. The set R of all
the outputs is called the range and the range R of the
license-number-to-name function are all the names
of drivers with a valid license.
A function may be given by a chart where
the input and outputs are listed explicitly.
From the table we see that 3 is the output for
the input 2.
The Basic Language of Functions
x y
–1 4
2 3
5 –3
6 4
7 2
Given a function, the set D of all the inputs is called
the domain of the function. The domain D of the
license-number-to-name function in example A
are all valid driver license numbers. The set R of all
the outputs is called the range and the range R of the
license-number-to-name function are all the names
of drivers with a valid license.
A function may be given by a chart where
the input and outputs are listed explicitly.
From the table we see that 3 is the output for
the input 2. The domain D = {–1, 2, 5, 6, 7}
and the range is R = {4, 3, –3, 2}.
The Basic Language of Functions
x y
–1 4
2 3
5 –3
6 4
7 2
Given a function, the set D of all the inputs is called
the domain of the function. The domain D of the
license-number-to-name function in example A
are all valid driver license numbers. The set R of all
the outputs is called the range and the range R of the
license-number-to-name function are all the names
of drivers with a valid license.
A function may be given by a chart where
the input and outputs are listed explicitly.
From the table we see that 3 is the output for
the input 2. The domain D = {–1, 2, 5, 6, 7}
and the range is R = {4, 3, –3, 2}.
Note that we may have the same output 4
for two different inputs –1 and 6.
The Basic Language of Functions
x y
–1 4
2 3
5 –3
6 4
7 2
Functions may be given graphically:
For instance, Nominal Price(1975) $0.50
The Basic Language of Functions
Functions may be given graphically:
Domain (Nominal Price) = {year 1918 2005}
For instance, Nominal Price(1975) $0.50
The Basic Language of Functions
Functions may be given graphically:
Domain (Nominal Price) = {year 1918 2005}
Range (Nominal Price) = {$0.20$2.51}
For instance, Nominal Price(1975) $1.00
The Basic Language of Functions
The Basic Language of FunctionsFunctions may be given graphically:
Inflation Adjusted Price(1975) $1.85
The Basic Language of FunctionsFunctions may be given graphically:
Inflation Adjusted Price(1975) $1.85
Domain (Inflation Adjusted Price) = {1918 2005}
The Basic Language of FunctionsFunctions may be given graphically:
Domain (Inflation Adjusted Price) = {1918 2005}
Range (Inflation Adjusted Price) = {$1.25$3.50}
Inflation Adjusted Price(1975) $1.85
For example,
f(X) = X2 – 2X + 3 = y
The Basic Language of Functions
Most functions are given by mathematics formulas.
For example,
f(X) = X2 – 2X + 3 = y
name of
the function
The Basic Language of Functions
Most functions are given by mathematics formulas.
For example,
f(X) = X2 – 2X + 3 = y
name of
the function
The Basic Language of Functions
Most functions are given by mathematics formulas.
input box
For example,
f(X) = X2 – 2X + 3 = y
name of actual formula
the function
The output
The Basic Language of Functions
Most functions are given by mathematics formulas.
input box
For example,
f(X) = X2 – 2X + 3 = y
name of actual formula
the function
The Basic Language of Functions
Most functions are given by mathematics formulas.
input box
For example,
f(X) = X2 – 2X + 3 = y
name of actual formula
the function
The output
The Basic Language of Functions
Most functions are given by mathematics formulas.
input box
The input box holds the input for the formula.
For example,
f(X) = X2 – 2X + 3 = y
name of actual formula
the function
The output
The Basic Language of Functions
Most functions are given by mathematics formulas.
input box
The input box holds the input for the formula.
Hence f (2) means to replace x by (2) in the formula,
so f(2) = (2)2 – 2(2) + 3 = 3 = y.
For example,
f(X) = X2 – 2X + 3 = y
name of actual formula
the function
The output
The Basic Language of Functions
Most functions are given by mathematics formulas.
input box
The input box holds the input for the formula.
Hence f (2) means to replace x by (2) in the formula,
so f(2) = (2)2 – 2(2) + 3 = 3 = y.
The domain of this f(x) is the set of all real numbers.
For example,
f(X) = X2 – 2X + 3 = y
name of actual formula
the function
The output
The Basic Language of Functions
Most functions are given by mathematics formulas.
input box
The input box holds the input for the formula.
Hence f (2) means to replace x by (2) in the formula,
so f(2) = (2)2 – 2(2) + 3 = 3 = y.
Function names are used with the +, –, /, and *
with the obvious interpretation.
The domain of this f(x) is the set of all real numbers.
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3.
a. Evaluate f(–2)
f(x) = –3x + 2
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3.
a. Evaluate f(–2)
f(x) = –3x + 2
f(–2)
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3.
a. Evaluate f(–2)
f(x) = –3x + 2
f(–2)
copy the input
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3.
a. Evaluate f(–2)
f(x) = –3x + 2
f(–2)
copy the input then paste the input
where the x is
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3.
a. Evaluate f(–2)
f(x) = –3x + 2
f(–2) = –3(–2) + 2
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(x) = –2x2 – 3x + 1
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(x) = –2x2 – 3x + 1
g(–2)
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(x) = –2x2 – 3x + 1
g(–2)
copy the input
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(x) = –2x2 – 3x + 1
g(–2)
copy the input
then paste the input
where the x’s are
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(x) = –2x2 – 3x + 1
g(–2) = –2(–2)2 – 3(–2) + 1
copy the input
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(–2) = –2(–2)2 – 3(–2) + 1
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(–2) = –2(–2)2 – 3(–2) + 1
= –8 + 6 + 1 = –1
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(–2) = –2(–2)2 – 3(–2) + 1
= –8 + 6 + 1 = –1
c. Evaluate f(–2) – g(–2).
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(–2) = –2(–2)2 – 3(–2) + 1
= –8 + 6 + 1 = –1
c. Evaluate f(–2) – g(–2).
Using the outputs of parts a and b we’ve
f(–2) – g(–2)
=
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(–2) = –2(–2)2 – 3(–2) + 1
= –8 + 6 + 1 = –1
c. Evaluate f(–2) – g(–2).
Using the outputs of parts a and b we’ve
f(–2) – g(–2)
= 3 – (–1) = 4
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(–2) = –2(–2)2 – 3(–2) + 1
= –8 + 6 + 1 = –1
c. Evaluate f(–2) – g(–2).
Using the outputs of parts a and b we’ve
f(–2) – g(–2)
= 3 – (–1) = 4
The function f(x) = c where c is a number is called
a constant function.
The Basic Language of Functions
Example B. Let f(x) = –3x – 3, g(x) = –2x2 – 3x + 1.
a. Evaluate f(–2).
f(–2) = –3(–2) – 3 = 3
b. Evaluate g(–2).
g(–2) = –2(–2)2 – 3(–2) + 1
= –8 + 6 + 1 = –1
c. Evaluate f(–2) – g(–2).
Using the outputs of parts a and b we’ve
f(–2) – g(–2)
= 3 – (–1) = 4
The function f(x) = c where c is a number is called
a constant function. The outputs of such functions
do not change.
There are two main things to consider when
determining the domains of functions of real numbers.
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0.
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0.
2. The radicand of square root (or any even root)
can't be negative.
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0.
2. The radicand of square root (or any even root)
can't be negative.
Example C. Find the domain of the following functions.
a. f(x) = 1/(2x + 6)
b. f (X) = 2x + 6
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0.
2. The radicand of square root (or any even root)
can't be negative.
Example C. Find the domain of the following functions.
a. f(x) = 1/(2x + 6)
The denominator can’t be 0
b. f (X) = 2x + 6
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0.
2. The radicand of square root (or any even root)
can't be negative.
Example C. Find the domain of the following functions.
a. f(x) = 1/(2x + 6)
The denominator can’t be 0 i.e. 2x + 6 = 0 x = -3
b. f (X) = 2x + 6
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0.
2. The radicand of square root (or any even root)
can't be negative.
Example C. Find the domain of the following functions.
a. f(x) = 1/(2x + 6)
The denominator can’t be 0 i.e. 2x + 6 = 0 x = -3
So the domain = {all numbers except x = -3}.
b. f (X) = 2x + 6
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0.
2. The radicand of square root (or any even root)
can't be negative.
Example C. Find the domain of the following functions.
a. f(x) = 1/(2x + 6)
The denominator can’t be 0 i.e. 2x + 6 = 0 x = -3
So the domain = {all numbers except x = -3}.
b. f (X) = 2x + 6
We must have square root of nonnegative numbers.
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0.
2. The radicand of square root (or any even root)
can't be negative.
Example C. Find the domain of the following functions.
a. f(x) = 1/(2x + 6)
The denominator can’t be 0 i.e. 2x + 6 = 0 x = -3
So the domain = {all numbers except x = -3}.
b. f (X) = 2x + 6
We must have square root of nonnegative numbers.
Hence 2x + 6 > 0 x > -3
The Basic Language of Functions
There are two main things to consider when
determining the domains of functions of real numbers.
1. The denominators can't be 0.
2. The radicand of square root (or any even root)
can't be negative.
Example C. Find the domain of the following functions.
a. f(x) = 1/(2x + 6)
The denominator can’t be 0 i.e. 2x + 6 = 0 x = -3
So the domain = {all numbers except x = -3}.
b. f (X) = 2x + 6
We must have square root of nonnegative numbers.
Hence 2x + 6 > 0 x > -3
So the domain = {all numbers x > -3}
The Basic Language of Functions
The Basic Language of FunctionsGraphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
The Basic Language of FunctionsGraphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
For example, let the function
f(x) = x + 1,
The Basic Language of FunctionsGraphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
For example, let the function
f(x) = x + 1, set y = f(x) and
make a table of few of the
ordered pairs (x, y)’s that
satisfy the equation y = f(x).
The Basic Language of FunctionsGraphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
For example, let the function
f(x) = x + 1, set y = f(x) and
make a table of few of the
ordered pairs (x, y)’s that
satisfy the equation y = f(x).
x 0 1 2 3
y = f(x) 1 2 3 4
The Basic Language of FunctionsGraphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
For example, let the function
f(x) = x + 1, set y = f(x) and
make a table of few of the
ordered pairs (x, y)’s that
satisfy the equation y = f(x).
x 0 1 2 3
y = f(x) 1 2 3 4
Plot the (x, y)’s and we have the graph of f(x) = x + 1,
a line.
The Basic Language of FunctionsGraphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
For example, let the function
f(x) = x + 1, set y = f(x) and
make a table of few of the
ordered pairs (x, y)’s that
satisfy the equation y = f(x).
x 0 1 2 3
y = f(x) 1 2 3 4
y = x + 1
Plot the (x, y)’s and we have the graph of f(x) = x + 1,
a line.
The Basic Language of FunctionsGraphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
For example, let the function
f(x) = x + 1, set y = f(x) and
make a table of few of the
ordered pairs (x, y)’s that
satisfy the equation y = f(x).
x 0 1 2 3
y = f(x) 1 2 3 4
y = x + 1
Plot the (x, y)’s and we have the graph of f(x) = x + 1,
a line. Note that the graph of a function may cross any
vertical line at most at one point because for each x
there is only one corresponding output y.
The Basic Language of FunctionsGraphs of Functions
The plot of all points (x, y)’s
that satisfy a given function
y = f(x) is the graph of the
function y = f(x).
For example, let the function
f(x) = x + 1, set y = f(x) and
make a table of few of the
ordered pairs (x, y)’s that
satisfy the equation y = f(x).
x 0 1 2 3
y = f(x) 1 2 3 4
y = x + 1
Plot the (x, y)’s and we have the graph of f(x) = x + 1,
a line. Note that the graph of a function may cross any
vertical line at most at one point because for each x
there is only one corresponding output y.
The Basic Language of Functions
The equation x = y2, treating x
as the input, is not a function.
For instance, for the input
x = 4, there are two outputs,
y’s that satisfy 4 = y2,
The Basic Language of Functions
The equation x = y2, treating x
as the input, is not a function.
For instance, for the input
x = 4, there are two outputs,
y’s that satisfy 4 = y2, namely
y = 2 and y = –2.
The Basic Language of Functions
The equation x = y2, treating x
as the input, is not a function.
For instance, for the input
x = 4, there are two outputs,
y’s that satisfy 4 = y2, namely
y = 2 and y = –2. So x = y2 is
not a function.
The Basic Language of Functions
The equation x = y2, treating x
as the input, is not a function.
For instance, for the input
x = 4, there are two outputs,
y’s that satisfy 4 = y2, namely
y = 2 and y = –2. So x = y2 is
not a function.
Plot the graph by the table
shown.
x 0 1 1 4 4
y 0 1 -1 2 -2
The Basic Language of Functions
The equation x = y2, treating x
as the input, is not a function.
For instance, for the input
x = 4, there are two outputs,
y’s that satisfy 4 = y2, namely
y = 2 and y = –2. So x = y2 is
not a function.
Plot the graph by the table
shown.
x 0 1 1 4 4
y 0 1 -1 2 -2
x 0 1 1 4 4
y 0 1 -1 2 -2
x = y2
The Basic Language of Functions
The equation x = y2, treating x
as the input, is not a function.
For instance, for the input
x = 4, there are two outputs,
y’s that satisfy 4 = y2, namely
y = 2 and y = –2. So x = y2 is
not a function.
Plot the graph by the table
shown. In particular, if we
draw the vertical line x = 4,
x 0 1 1 4 4
y 0 1 -1 2 -2
x 0 1 1 4 4
y 0 1 -1 2 -2
x = y2
it intersects the graph at two points (4, 2) and (4, –2).
The Basic Language of Functions
The equation x = y2, treating x
as the input, is not a function.
For instance, for the input
x = 4, there are two outputs,
y’s that satisfy 4 = y2, namely
y = 2 and y = –2. So x = y2 is
not a function.
Plot the graph by the table
shown. In particular, if we
draw the vertical line x = 4,
x 0 1 1 4 4
y 0 1 -1 2 -2
x 0 1 1 4 4
y 0 1 -1 2 -2
x = y2
it intersects the graph at two points (4, 2) and (4, –2).
In general, if any vertical line crosses a graph at two
or more points, then the graph does not represent
any function.
The Basic Language of FunctionsSince for functions each
input x has exactly one
output, therefore each
vertical line can only
intersect it’s graph at exactly
one location (e.g. y = x + 1).
The Basic Language of FunctionsSince for functions each
input x has exactly one
output, therefore each
vertical line can only
intersect it’s graph at exactly
one location (e.g. y = x + 1).
y = x + 1
Linear Equations and LinesC. Estimate the slope by eyeballing two points then find an
equation of each line below.
1. 2. 3. 4.
5. 6. 7. 8.
Linear Equations and LinesD. Draw each line that passes through the given two points.
Find the slope and an equation of the line.
Again Identify the vertical lines and the horizontal lines by
inspection and solve for them first.
(Fraction Review: slide 99 of 1.2)
1. (0, –1), (–2, 1) 2. (3, –1), (3, 1)
4. (1, –2), (–2, 3)
3. (2, –1), (3, –1)
6. (4, –2), (4, 0)5. (7, –2), (–2, –6)
7. (3/2, –1), (3/2, 1) 8. (3/4, –1/3), (1/3, 3/2)
9. (–1/4, –3/2), (2/3, –3/2) 10. (–1/3, –1/6), (–3/4, 1/2)
11. (2/5, –3/10), (–1/2, –3/5) 12. (–3/4, 5/6), (–3/4, –4/3)
Linear Equations and Lines
2. It’s perpendicular to 2x – 4y = 1 and passes through (–2, 1)
6. It’s perpendicular to 3y = x with x–intercept at x = –3.
12. It has y–intercept at y = 3 and is parallel to 3y + 4x = 1.
8. It’s perpendicular to the y–axis with y–intercept at 4.
9. It has y–intercept at y = 3 and is parallel to the x axis.
10. It’s perpendicular to the x– axis containing the point (4, –3).
11. It is parallel to the y axis has x–intercept at x = –7.
5. It is parallel to the x axis has y–intercept at y = 7.
E. Find the equations of the following lines.
1. The line that passes through (0, 1) and has slope 3.
7. The line that passes through (–2 ,1) and has slope –1/2.
3. The line that passes through (5, 2) and is parallel to y = x.
4. The line that passes through (–3, 2) and is perpendicular
to –x = 2y.
Linear Equations and Lines
The cost y of renting a tour boat consists of a base–cost plus
the number of tourists x. With 4 tourists the total cost is $65,
with 11 tourists the total is $86.
1. What is the base cost and what is the charge per tourist?
2. Find the equation of y in terms of x.
3. What is the total cost if there are 28 tourists?
The temperature y of water in a glass is rising slowly.
After 4 min. the temperature is 30 Co, and after 11 min. the
temperature is up to 65 Co. Answer 42–44 assuming the
temperature is rising linearly.
4. What is the temperature at time 0 and what is the rate of
the temperature rise?
5. Find the equation of y in terms of time.
6. How long will it take to bring the water to a boil at 100 Co?
F. Find the equations of the following lines.
Linear Equations and LinesThe cost of gas y on May 3 is $3.58 and on May 9 is $4.00.
Answer 45–47 assuming the price is rising linearly.
7. Let x be the date in May, what is the rate of increase in
price in terms of x?
8. Find the equation of the price in term of the date x in May.
9. What is the projected price on May 20?
G. Find the coordinates of the following points assuming
all points are evenly spaced.
1. 1 4
2. –1 5
1 3 11
3. a. Find x and y.
x zy
The number z is a “weighted average” of {1, 3, 11}
whose average is 5. In this case z is the average of
{1, 3, 3,11} instead because “3” is used both for x and y.
1 3 11
b. Find z the mid-point of x and y.
x y
The Basic Language of FunctionsSince for functions each
input x has exactly one
output, therefore each
vertical line can only
intersect it’s graph at exactly
one location (e.g. y = x + 1).
y = x + 1
However, if any vertical line
intersects a graph at two or
more points, i.e. there are two
or more outputs y associated
to one input x (eg. x = y2),
The Basic Language of FunctionsSince for functions each
input x has exactly one
output, therefore each
vertical line can only
intersect it’s graph at exactly
one location (e.g. y = x + 1).
y = x + 1
However, if any vertical line
intersects a graph at two or
more points, i.e. there are two
or more outputs y associated
to one input x (eg. x = y2),
then the graph must not be
the graph of a function.
The Basic Language of FunctionsSince for functions each
input x has exactly one
output, therefore each
vertical line can only
intersect it’s graph at exactly
one location (e.g. y = x + 1).
x 0 1 1 4 4
y 0 1 -1 2 -2
y = x + 1
However, if any vertical line
intersects a graph at two or
more points, i.e. there are two
or more outputs y associated
to one input x (eg. x = y2),
then the graph must not be
the graph of a function.
The Basic Language of FunctionsExercise A. For problems 1 – 6, determine if the
given represents a function. If it’s not a function,
give a reason why it’s not.
x y
2 4
2 3
4 3
1. x y
2 4
3 4
4 4
2. 3. 4.
x
y y
6. For any real number input x that is a rational
number, the output is 0, otherwise the output is 1
5. For any input x that is a positive integer, the
outputs are it’s factors.
x
All the (x, y)’s on the curve
The Basic Language of FunctionsExercise B.
Given the functions
f, g and h, find the
outcomes of the
following expressions.
If it’s not defined,
state so.
x y = g(x)
–1 4
2 3
5 –3
6 4
7 2
y = h(x)
f(x) = –3x + 7
1. f(–1) 2. g(–1) 3.h(–1)
4. –f(3) 5. –g(3) 6. –h(3)
7. 3g(6) 8. 2f(2) 9. h(3) + h(0)
10. 2f(4) + 3g(2) 11. –f(4) + f(–4) 12. h(6)*[f(2)]2
The Basic Language of Functions
1. f(x) =1
2x – 6 2. f (x) = 2x – 6
C. Find the domain of the following functions.
5. f(x) =1
(x – 2)(x + 6)
7. f (x) = (x – 2)(x + 6)
3. f(x) =1
3 – 2x 4. f (x) = 3 – 2x
6. f(x) =1
x2 – 1
8. f (x) = 1 – x2
9. f (x) = (x – 2)/(x + 6) 10. f (x) = 4x2 – 9
For problem 7-10, draw sign charts (section 1.6)
to solve for the domains.
The Basic Language of Functions
1. –f(3) 2. –g(3) 3. –h(3)
4. 3g(2) 5. 2f(2) 6. h(3) + h(0)
7. 2f(4) + 3g(2) 8. f(–3/2) 9. g(1/2)
13. f(3 + a) 14. g(3 + a) 15. g(3 + a)
16. f(a – b) 17. g(a – b)
18. f( )a1 19. f(a)
1
11. h(–3/2) 12. g(–1/2) 10. 1/g(2)
Exercise D. Given the functions f, g and h, find the
outcomes of the following expressions. If it’s not
defined, state so.
f(x) = –2x + 3 g(x) = –x2 + 3x – 2 h(x) =x + 2x – 3