2.1, 6.7 Exponential Equations OBJ: To solve an exponential equation To solve an exponential...
-
Upload
claud-dean -
Category
Documents
-
view
215 -
download
0
Transcript of 2.1, 6.7 Exponential Equations OBJ: To solve an exponential equation To solve an exponential...
![Page 1: 2.1, 6.7 Exponential Equations OBJ: To solve an exponential equation To solve an exponential equation using properties of rational number exponents.](https://reader036.fdocuments.net/reader036/viewer/2022082820/56649e9a5503460f94b9cd10/html5/thumbnails/1.jpg)
2.1, 6.7 Exponential Equations
OBJ: To solve an exponential
equation
To solve an exponential
equation using properties of rational
number exponents
![Page 2: 2.1, 6.7 Exponential Equations OBJ: To solve an exponential equation To solve an exponential equation using properties of rational number exponents.](https://reader036.fdocuments.net/reader036/viewer/2022082820/56649e9a5503460f94b9cd10/html5/thumbnails/2.jpg)
DEF: Exponential EquationGet same bases; set exponents =EX: 5 8 x = 16P158 23x = 24
3x = 4 x = 4/3
EX: 9 x = 27 32x = 33
2x = 3 x = 3/2
EX: (1/3) x = 9 3-x = 32
-x = 2 x = -2 EX: (3/4) x = 16/9 (3/4) x = (3/4)-2
x = -2
![Page 3: 2.1, 6.7 Exponential Equations OBJ: To solve an exponential equation To solve an exponential equation using properties of rational number exponents.](https://reader036.fdocuments.net/reader036/viewer/2022082820/56649e9a5503460f94b9cd10/html5/thumbnails/3.jpg)
EX: 6 (5) 4x + 1 = 125P 33 (5) 4x + 1 = 5 3
4x + 1 = 3 x = 1/2
EX: (3) 2x + 4 = 243 32x + 4 = 35
2x + 4 = 5 x = 1/2
EX: (8) 4z = (4) z + 1
(23)4z = (22) z + 1
12 z = 2z + 2
10z = 2 z = 1/5EX: (64) t = (32) 1 - t
(2 6) t = (2 5) 1- t
6 t = 5 – 5t t = 5/11
![Page 4: 2.1, 6.7 Exponential Equations OBJ: To solve an exponential equation To solve an exponential equation using properties of rational number exponents.](https://reader036.fdocuments.net/reader036/viewer/2022082820/56649e9a5503460f94b9cd10/html5/thumbnails/4.jpg)
EX: 625 –x = 125 3 x
(54) –x = (53) 3x
- 4x = 9x 0 = 13x 0 = xEX: 125 3 – a = 25 a (5 3) 3 – a = (5 2) a
9 – 3a = 2a 9 = 5a
9/5 = aEX: (1/27)– 2 p=(3)p+3
(3- 3)– 2 p = (3)p+3
6p = p + 35p = 3p = 3/5
EX: 2 – h = (1/8) 1 – h
2 – h = (2 - 3) 1 – h
- h = - 3 + 3h - 4h = - 3
h = 3/4EX: (1/3) – x = (1/9) x + 1 (1/3) – x = [(1/3)2]x + 1
-x = 2x + 2 -3x = 2
x = -2/3EX: 2 – x = 1/8
2 – x = 2 -3
- x = -3 x = 3
x = 3, -3