2021 Physics-nht Written examination

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PHYSICS Written examination Wednesday 26 May 2021 Reading time: 10.00 am to 10.15 am (15 minutes) Writing time: 10.15 am to 12.45 pm (2 hours 30 minutes) QUESTION AND ANSWER BOOK Structure of book Section Number of questions Number of questions to be answered Number of marks A 20 20 20 B 18 18 110 Total 130 Students are permitted to bring into the examination room: pens, pencils, highlighters, erasers, sharpeners, rulers, pre-written notes (one folded A3 sheet or two A4 sheets bound together by tape) and one scientific calculator. Students are NOT permitted to bring into the examination room: blank sheets of paper and/or correction fluid/tape. Materials supplied Question and answer book of 33 pages Formula sheet Answer sheet for multiple-choice questions Instructions Write your student number in the space provided above on this page. Check that your name and student number as printed on your answer sheet for multiple-choice questions are correct, and sign your name in the space provided to verify this. Unless otherwise indicated, the diagrams in this book are not drawn to scale. All written responses must be in English. At the end of the examination Place the answer sheet for multiple-choice questions inside the front cover of this book. You may keep the formula sheet. Students are NOT permitted to bring mobile phones and/or any other unauthorised electronic devices into the examination room. © VICTORIAN CURRICULUM AND ASSESSMENT AUTHORITY 2021 SUPERVISOR TO ATTACH PROCESSING LABEL HERE Victorian Certificate of Education 2021 STUDENT NUMBER Letter

Transcript of 2021 Physics-nht Written examination

Page 1: 2021 Physics-nht Written examination

PHYSICSWritten examination

Wednesday 26 May 2021 Reading time: 10.00 am to 10.15 am (15 minutes) Writing time: 10.15 am to 12.45 pm (2 hours 30 minutes)

QUESTION AND ANSWER BOOK

Structure of bookSection Number of

questionsNumber of questions

to be answeredNumber of

marks

A 20 20 20B 18 18 110

Total 130

• Studentsarepermittedtobringintotheexaminationroom:pens,pencils,highlighters,erasers,sharpeners,rulers,pre-writtennotes(onefoldedA3sheetortwoA4sheetsboundtogetherbytape)andonescientificcalculator.

• StudentsareNOTpermittedtobringintotheexaminationroom:blanksheetsofpaperand/orcorrectionfluid/tape.

Materials supplied• Questionandanswerbookof33pages• Formulasheet• Answersheetformultiple-choicequestions

Instructions• Writeyourstudentnumberinthespaceprovidedaboveonthispage.• Checkthatyournameandstudent numberasprintedonyouranswersheetformultiple-choice

questionsarecorrect,andsignyournameinthespaceprovidedtoverifythis.• Unlessotherwiseindicated,thediagramsinthisbookarenotdrawntoscale.• AllwrittenresponsesmustbeinEnglish.

At the end of the examination• Placetheanswersheetformultiple-choicequestionsinsidethefrontcoverofthisbook.• Youmaykeeptheformulasheet.

Students are NOT permitted to bring mobile phones and/or any other unauthorised electronic devices into the examination room.

©VICTORIANCURRICULUMANDASSESSMENTAUTHORITY2021

SUPERVISOR TO ATTACH PROCESSING LABEL HEREVictorian Certificate of Education 2021

STUDENT NUMBER

Letter

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SECTION A – continued

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Question 1Awirecarryingacurrent,I,of6.0Apassesthroughamagneticfield,B,ofstrength1.4×10–5T,asshownbelow.Themagneticfieldisexactly1.0mwide.

1.0 m

B = 1.4 × 10–5 T

I = 6.0 A

ThemagnitudeoftheforceonthewireisclosesttoA. 0NB. 2.3×10–6NC. 8.4×10–5ND. 4.3×105N

SECTION A – Multiple-choice questions

Instructions for Section AAnswerallquestionsinpencilontheanswersheetprovidedformultiple-choicequestions.Choosetheresponsethatiscorrectorthatbest answersthequestion.Acorrectanswerscores1;anincorrectanswerscores0.Markswillnotbedeductedforincorrectanswers.Nomarkswillbegivenifmorethanoneansweriscompletedforanyquestion.Unlessotherwiseindicated,thediagramsinthisbookarenotdrawntoscale.Takethevalueofgtobe9.8ms–2.

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SECTION A – continuedTURN OVER

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Question 2Threecharges,–Q,+2Qand+2Q,areplacedattheverticesofanequilateraltriangle,asshownbelow.

–Q

+2Q+2Q

Whichoneofthefollowingarrowsbestrepresentsthedirectionofthenetforceonthecharge–Q?

A. B.

C. D.

Question 3A45ggolfball,initiallyatrest,ishitbyagolfclub.Thecontacttimebetweentheclubandtheballis 0.50ms.Themagnitudeofthefinalvelocityoftheballis41ms–1.Whichoneofthefollowingisclosesttotheaverageforceexperiencedbythegolfball?A. 0.18kNB. 0.37kNC. 1.8kND. 3.7kN

Question 4Apersonhasamassof60.0kg.WhichoneofthefollowingisclosesttotheweightofthispersononEarth’ssurface?A. 60.0kgB. 60.0NC. 588kgD. 588N

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SECTION A – continued

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Question 5WhenaspacecraftorbitsEarth,itsorbitalperiodisnotafunctionoftheA. massofEarth.B. massofthespacecraft.C. velocityofthespacecraft.D. heightofthespacecraftaboveEarth.

Question 6ThemainsvoltageinaparticularpartofAustraliaisACwithavoltageof240VRMS.Whichoneofthefollowingisclosesttothepeak-to-peakvoltage,Vp–p ,forthismainsvoltage?A. 170VB. 340VC. 480VD. 680V

Question 7Electricalpowerstationsareoftensituatedfarfromthecitiesthatrequirethepowerthattheygenerate.Whichoneofthefollowingbestdescribesthereasonforthehigh-voltagetransmissionofelectricalenergy?A. Transformerscanbeusedtoincreasethevoltageinthecities.B. Highvoltagesreducetheenergylossesinthetransmissionlines.C. Highvoltagesprovidethelargecurrentsneededforefficienttransmission.D. Highvoltagescanreducetheoveralltotalresistanceinthetransmissionlines.

Question 8Inthediagrambelow,thesolidlinerepresentsthegraphofoutputEMF,ε,versustimeproducedbyan ACgenerator.AsinglechangeismadetotheACgeneratoranditsoperation,andthenewgraphofoutputEMF,ε,versustimeisshownasadashedline.

0.05 0.10 0.15 0.20

ε (V)

10

5

0

–5

–10

t (s)

WhichoneofthefollowingbestdescribesthechangemadetotheACgenerator?A. Theareaofthecoilwasdoubled.B. Thespeedofrotationwashalved.C. Thespeedofrotationwasdoubled.D. Thenumberofturnsofthewireinthecoilwasdoubled.

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SECTION A–continuedTURN OVER

Question 9Thediagrambelowshowsabarmagnetmovingupwardintoacoil.

A

N

Whichofthefollowingcorrectlyidentifiesthedirectionoftheinducedcurrent,asviewedfromthetopofthecoil,andthedirectionofthemagneticfieldproducedbytheinducedcurrentinsidethecoil?

Current direction Magnetic field direction

A. clockwise ↓

B. clockwise ↑

C. anticlockwise ↑

D. anticlockwise ↓

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SECTION A–continued

Use the following information to answer Questions 10 and 11.Melissalaunchesaballfromheighthabovethegroundataspeedof8.0ms–1andatanangleof30°abovethehorizontal.Thetimeoftheball’sflightis1.0s.Thediagrambelowshowsthetrajectoryoftheball.

h

30°8.0 m s–1

trajectory

ball lands here

ball

ground level

Question 10Ignoringairresistance,whichoneofthefollowingisclosesttothehorizontaldistancethattheballlandedfromMelissa?A. 4.6mB. 5.0mC. 6.9mD. 8.0m

Question 11Whichoneofthefollowingdiagramsbestshowsthedirectionoftheresultantforce,F,ontheballatthepositionofmaximumheightintherealsituationwhereairresistanceisnotignored?

A.

C.

B.

D.

F

F

F

F

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SECTION A–continuedTURN OVER

Question 12Amassattheendofanidealspringisoscillatingfreelyupanddown.

top of motion

bottom of motion

Whichoneofthefollowingbestdescribesthemotionofthisoscillatingmass?A. Itsspeedisaminimumonlyatthetopofthemotion.B. Itsspeedisamaximumwhenitsaccelerationisamaximum.C. Itsaccelerationhasaminimumvalueatboththetopandthebottomofthemotion.D. Itsaccelerationhasamaximumvalueupwardwhenthemassisstationaryatthebottom.

Question 13JoannaisanobserverinSpaceshipPandiswatchingSpaceshipQflypastatarelativespeedof0.943c(γ=3.00).Sheobservesastationaryclockmeasuringatimeintervalof75.0sbetweentwoeventsinSpaceshipQ.Thisisapropertimeinterval.

Spaceship P

Spaceship Q

WhichoneofthefollowingisclosesttothetimeintervalobservedbetweenthetwoeventsinSpaceshipP’sframeofreference?A. 15.0sB. 25.0sC. 125sD. 225s

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SECTION A–continued

Question 14Thediagrambelowrepresentsastandingwave.

P

fixedwall

fixedwall

standing wave

ThepointPonthestandingwaveisA. anoderesultingfromdestructiveinterference.B. anoderesultingfromconstructiveinterference.C. anantinoderesultingfromdestructiveinterference.D. anantinoderesultingfromconstructiveinterference.

Question 15ThepolarisationoflightsupportsA. thewavemodeloflight.B. theparticlemodeloflight.C. boththewavemodelandtheparticlemodeloflight.D. neither thewavemodelnortheparticlemodeloflight.

Question 16Aredlaserusedinadouble-slitexperimentcreatesaninterferencepatternonascreen,asshownbelow.

slits

S1 S2

laser

laser beam

bright banddark band

screen

Theredlaserisreplacedwithagreenlaser.Whichoneofthefollowingbestexplainswhathappenstothespacingbetweenadjacentbrightbandswhenthegreenlaserisused?A. Thespacingincreases.B. Thespacingdecreases.C. Thespacingstaysthesame.D. Thespacingcannotbedeterminedfromtheinformationgiven.

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END OF SECTION ATURN OVER

Question 17Protonsofmass1.67×10–27kgareacceleratedtoaspeedof2.0×103ms–1.ThebestestimateofthedeBrogliewavelengthoftheseprotonsisA. 1.2×10–10mB. 2.0×10–10mC. 1.2×10–7mD. 2.0×10–7m

Question 18Experimentsonthephotoelectriceffectinvolveshininglightontoametalsurface.Measurementsaremadeofthenumberofemittedelectronsandtheirmaximumkineticenergyfromthemetalsurface.Thisisdonefordifferentfrequenciesandintensitiesoflight.Whichoneofthefollowingstatementswouldnotbeoneoftheexperimentalfindings?A. Theabilitytoejectelectronsfromthismetaldependedonlyonthefrequencyoflight.B. Thestoppingpotentialforthephotoelectronswasindependentofthelightintensity.C. Themaximumkineticenergyofthephotoelectronsdependedonlyonthelightintensity.D. Atfrequenciesbelowthethresholdfrequency,noelectronswereejectedfromthismetalnomatterhow

highthelightintensitywas.

Question 19Inanexperimentalinvestigation,anindependentvariableisonethatisA. independentoftheinvestigator’scontrol.B. avalueselectedbytheinvestigator.C. fixedthroughouttheexperiment.D. thekeyvariabletobemeasured.

Question 20Anucleusinanexcitedenergystateemitsagammarayofenergy3.6×10–13Jasitdecaystoitsgroundstate.TheinitialmassoftheexcitednucleusisMi.ThefinalmassofthenucleusafterdecayisclosesttoA. Mi–4×10

–30kgB. Mi–8×10

–30kgC. MikgD. Mi+4×10

–30kg

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SECTION B – continued

Question 1 (3marks)Asmallspherecarryingachargeof–2.7µCisplacedbetweenchargedparallelplates,asshownin Figure1.Thepotentialdifferencebetweentheplatesissetat15.5V,whichjustholdsthespherestationary.Theelectricfieldbetweentheplatesisuniform.

–2.7 μC

Figure 1

a. Inwhichdirection(up,down,right,left)willthespheremoveifthevoltageisincreased? 1mark

b. Calculatethevalueoftheelectricforcethatisholdingthespherestationaryiftheplatesare2.0mmapart.Showyourworking. 2marks

N

SECTION B

Instructions for Section BAnswerallquestionsinthespacesprovided.Whereananswerboxisprovided,writeyourfinalanswerinthebox.Ifananswerboxhasaunitprintedinit,giveyouranswerinthatunit.Inquestionswheremorethanonemarkisavailable,appropriateworkingmustbeshown.Unlessotherwiseindicated,thediagramsinthisbookarenotdrawntoscale.Takethevalueofgtobe9.8ms–2.

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SECTION B – continuedTURN OVER

Question 2 (8marks)AnelectronisacceleratedfromrestbyapotentialdifferenceofV0.Itemergesataspeedof 2.0×107ms–1intoamagneticfield,B,ofstrength2.5×10–3Tandfollowsacirculararc, asshowninFigure2.

V0

electronsource

B = 2.5 × 10–3 T

Figure 2

a. Calculatethevalueoftheacceleratingvoltage,V0 .Showyourworking. 3marks

kV

b. Explainwhythepathoftheelectroninthemagneticfieldfollowsacirculararc. 2marks

c. Calculatetheradiusofthepathtravelledbytheelectron.Showyourworking. 3marks

m

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SECTION B – Question 3–continued

Question 3 (6marks)ThemotionofEarth’smooncanbemodelledasacircularorbitaroundEarth,asshowninFigure3.

moon

Earth

Figure 3

Data

massofEarth 5.98×1024kg

massofthemoon 7.35×1022kg

radiusofthemoon’sorbitaroundEarth 3.84×108m

universalgravitationalconstant(G) 6.67×10–11Nm2kg–2

a. CalculatethemagnitudeofthegravitationalforcethatEarthexertsontheorbitingmoon.Giveyouranswercorrecttothreesignificantfigures.Showyourworking. 3marks

N

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SECTION B – continuedTURN OVER

b. TheaverageorbitalperiodofEarth’smoonis27.32days.ThemoonismovingslightlyfurtherawayfromEarthatanaveragerateof4cmperyear.

Giventhisinformation,willtheaverageorbitalperiodofEarth’smoondecrease,staythesameorincrease?Explainyouranswer. 3marks

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SECTION B – continued

Question 4 (3marks)Figure4showsaschematicdiagramofasimpleone-coilDCmotor.Acurrentisflowingthroughthecoil.

split-ring commutator

DC power supply

K L

J M

+ –

N S

Figure 4

a. DrawanarrowonFigure4toindicatethedirectionoftheforceactingonthesideJKof thecoil. 1mark

b. Explainthepurposeofthesplit-ringcommutator. 2marks

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SECTION B – continuedTURN OVER

Question 5 (3marks)Physicsstudentswhoareinvestigatingthegenerationofelectricityspinacoilataconstant10rotations persecondinauniformmagneticfield.Theyobservetheoutputonanoscilloscope.Theexperimentalset-upisshowninFigure5.Thepeakvoltageproducedbythecoilis5mV.

SN

Figure 5

Ontheaxesbelow,sketchthevoltageversustimegraphobservedonthescreenoftheoscilloscopeforonecompleterotationofthecoilfromthepositionshowninFigure5.Includeappropriatescalesoneachaxis.

V (mV)

t (s)

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SECTION B – Question 6–continued

Question 6 (7marks)GirandKauareinvestigatingelectromagneticinduction.TheyhaveasinglewireloopofdimensionsXY=0.030mlongandYZ=0.020mwide,whichisplacedinauniformmagneticfieldofstrength0.20T.Theloopisrotatedclockwiseaboutanaxis,asshowninFigure6.

N S

X

Y

W

Z

BA

sliprings

axis

Figure 6

a. ExplainthepurposeoftheslipringsintheapparatusshowninFigure6. 2marks

b. Calculatethesizeofthemagneticfluxthroughtheloopwhenitisorientedasshownin Figure6.Showyourworking. 2marks

Wb

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SECTION B – continuedTURN OVER

TheloopisrotatedbyKauataconstantfrequency,f,andanEMF,ε,isgenerated.Figure7showsthegeneratedEMFversustimetraceobservedonthescreenofanoscilloscope.

0.1 0.2 0.3 0.4

ε (mV)

t (s)

1086420

–2–4–6–8

–10

Figure 7

c. CalculatethefrequencyoftherotationfromtheoscilloscopetraceshowninFigure7. 1mark

Hz

d. Girnowdoublesthenumberofturnsintheloopfromoneturntotwoturns,creatingtwoloops.Theloopsareagainrotatedatthesameconstantfrequency,f.

OnFigure8below,sketchagraphthatshowstheresultingvariationoftheEMFwithtimebetweenpointsAandB,aslabelledinFigure6.Theoriginaloutputisshownasadashedline. 2marks

0.1 0.2 0.3 0.4

ε (mV)

t (s)

1086420

–2–4–6–8

–10

Figure 8

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SECTION B – Question 7–continued

Question 7 (10marks)AngelaandJanekareinstallingtwolow-voltagelightsintheiroutdoorgarden.Theyhavea 240VRMSACtransformerwithanoutputvoltageof12VRMSAC.Eachlighthasaconstantresistanceof6.0Ω.Forthepurposesofcalculations,assumethatthetransformerisideal.

a. Describewhatismeantbyanidealtransformerintermsoftheinputpowerandtheoutputpower. 1mark

b. Calculatetheratioofthenumberofturnsoftheprimarycoiltothenumberofturnsofthesecondarycoil. 1mark

c. Eachlightisdesignedtooperateat12VRMS.

Calculatethepowerdissipatedinonelightwhenitisoperatedat12VRMS.Showyourworking. 2marks

W

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SECTION B – continuedTURN OVER

AngelaandJaneknowconnectthefirstlight,Light1,tothetransformerusingtwowires,each 12.0mlong,asshowninFigure9.Eachwirehasaresistanceof0.05Ωpermetre.

12.0 m

Light 1 12 VRMS AC

transformer

240 VRMS AC

Figure 9

d. CalculatetheRMSvoltageacrossLight1.Showyourworking. 3marks

V

e. AngelaandJaneknowconnectthesecondlight,Light2,directlyacrossthesecondaryofthetransformer,asshowninFigure10.

12.0 m

Light 1Light 2

transformer

Figure 10

TheythoughtthatwiththecircuitshowninFigure10,Light1andLight2wouldbeequallybright.However,theyobservedthatLight2wasbrighterthanLight1.

ExplainwhyLight2wasobservedtobebrighterthanLight1. 3marks

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SECTION B – Question 8–continued

Question 8 (8marks)Acarisdrivingupauniformslopewithatrailerattached,asshowninFigure11.Theslopeisangledat15°tothehorizontal.Thetrailerhasamassof200kgandthecarhasamassof750kg.Ignoreallretardingfrictionforcesdowntheslope.

15°

carcoupling

trailer

Figure 11

a. OnFigure12below,drawlabelledarrowstoindicatethedirectionoftheforcesactingonthetrailer.Thelabelsshouldalsoindicatethekindofforcethateacharrowrepresents. 3marks

trailer

15°

Figure 12

b. Thecarandtraileraretravellingataconstantspeedof8ms–1uptheslope.

Calculatethemagnitudeoftheforcethatthecarexertsonthetrailer.Showyourworking. 2marks

N

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SECTION B – continuedTURN OVER

c. Calculatethegravitationalpotentialenergygainedbythecarandtrailerwhentheyhavetravelled100malongtheslope.Showyourworking. 3marks

kJ

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SECTION B – Question 9–continued

Question 9 (10marks)Inamodelofaproposedrideatathemepark,a5.0kgsmoothblockslidesdownarampfrompointWandintoanidealspringbumperwithoutanyfrictionorairresistance,asshowninFigure13. Thefinalsectionoftheramp,betweenpointsXandY,ishorizontal.TheblockcomestoaninstantaneousstopatpointY.

block

X

W

h

ideal spring bumper

Y

Figure 13

a. DescribetheaccelerationoftheblockatpointsW,XandY. 4marks

b. Themaximumcompressionofthespringismeasuredas3.0manditsspringconstant,k,is100Nm–1.

Calculatethereleaseheight,h.Showyourworking. 3marks

m

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SECTION B – continuedTURN OVER

c. Calculatethemagnitudeofthemaximummomentumoftheblock.Showyourworking. 2marks

kgms–1

d. Whentheblockcomestorest,itsmomentumiszero.

Intermsoftheprincipleofconservationofmomentum,statewhathashappenedtothemomentumoftheblockasitcomestorest. 1mark

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SECTION B – continued

Question 10 (4marks)JacintaisstandingstillwhileobservingaspaceshippassingEarthataspeedof0.984c.

a. Calculateγforthisspeed,correcttothreesignificantfigures.Showyourworking. 2marks

b. ThespaceshipistravellingtotheAlphaCentauristarsysteminastraightlineatthisspeed.InJacinta’sframeofreference,thisdistanceismeasuredtobe4.37light-years(thatis,itwouldtakelight4.37yearstotravelthisdistance).

CalculatethetimethatwouldbemeasuredbyJacintaforthespaceship’sjourney,correcttothreesignificantfigures.Showyourworking. 2marks

years

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SECTION B – continuedTURN OVER

Question 11 (4marks)Atransversewaveistravellingthroughamedium,asshowninFigure14.Thefrequencyofthesourceproducingthewaveis40Hzandthewavetravelsataspeedof35ms–1.Theamplitudeofthewaveis0.50m.

35 m s−1P

Figure 14

a. WhatistheperiodofoscillationforpointPinFigure14? 1mark

ms

b. Ontheaxesbelow,sketchthedisplacementversustimegraphforthepointPofthistransversewave,showingatleasttwocompletecycles.Includescalesandunitsoneachaxis. 3marks

displacement

time

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SECTION B – continued

Question 12 (5marks)Studentsaretestingtwoidenticalradiotransmitters,R1andR2,onafootballfield.Thetransmittersarepositioned24mapart,asshowninFigure15.Thetransmittersareinphase,bothemittingcrestssimultaneously,andemitwavesofwavelength18minalldirections.ThestudentsarestandingatpointX,whichislocated72mawayfromthenearesttransmitter,R1.

R1

R2

24 m

X

Y

72 m

Figure 15

a. Duringtesting,theradiosignalreceivedatpointXisdetectedtobeaminimum.

CalculatetheshortestdistancethatpointXcouldbefromR2.Showyourworking. 2marks

m

b. Atanotherlocationonthefootballfield,pointY,thestudentsdetectamaximum.

ExplainwhythetwoobservationsatpointsXandYwouldsupportthewavemodeloflight. 3marks

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SECTION B – continuedTURN OVER

Question 13 (4marks)Theboundarybetweentwotransparentmaterials,Medium1andMedium2,eachhavingdifferentrefractiveindices,isshowninFigure16.Anincidentrayatanangleθiisalsoshown.

θi

normal

Medium 1, n = 1.56 Medium 2, n = 1.42

Figure 16

a. TherefractedrayappearsinMedium2.

SketchtheapproximatedirectionoftherefractedrayinMedium2onFigure16. 1mark

b. Whatrangeofincidentangles,θi,wouldresultinalightrayemerginginMedium2?Showyourworking. 3marks

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2021PHYSICSEXAM(NHT) 28

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SECTION B – continued

Question 14 (2marks)Toexplaindifferentaspectsofmechanicalwaves,aPhysicsteachersetsupademonstrationinaPhysicslaboratoryusinga0.80mwideloudspeakerandamicrophone.ThemicrophonemeasuresthesoundintensityatdifferentpositionsonacirclearoundthespeakerfrompositionAtopositionB,asshowninFigure17.

A B

loudspeaker

Figure 17

ThespeedofsoundinthePhysicslaboratoryis334ms–1.Measurementsaremadeatfrequenciesof100Hzand10000Hz.Theloudspeakeremitsthe100Hzand10000Hzfrequencieswithequalintensity.Figure18showstheintensity,I,measuredforeachfrequencyatpositionsonthesemicircularlineshowninFigure17betweenpositionsAandB.

I 10000 Hz

100 Hz

A B

Figure 18

Explainwhytheresponseat10000Hzhasagreaterintensitydirectlyinfrontoftheloudspeaker,whiletheresponseat100Hzisnearlythesameatallpositions.

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SECTION B – continuedTURN OVER

Question 15 (7marks)TheapparatusshowninFigure19isusedtoinvestigatethephotoelectriceffect.Lightofvariouswavelengthsisshoneontoasilverplate(cathode).Theworkfunctionofsilveris4.9eV.

V

µA

cathode

light

vacuum

photoelectron

battery

anode

Figure 19

a. Explainwhathappenswhenlightofwavelength400nmhitsthesilverplate.Usecalculationstosupportyouranswer. 2marks

b. Explainwhathappenswhenlightwithaphotonenergyof5.4eVhitsthesilverplate. 2marks

c. Whichmodeloflightdoesthisphotoelectricinvestigationsupport?Givetworeasonstojustifyyouranswer. 3marks

Modeloflight

1.

2.

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SECTION B – continued

Question 16 (6marks)X-raysofwavelength2.0nmareemittedfromanX-raysource.

a. CalculatetheenergyofonephotonoftheseX-rays.Showyourworking. 3marks

eV

b. The2.0nmX-raysareincidentonasinglenarrowslitofwidth5×10–8m.

Wouldadiffractionpatternbeobserved?Justifyyouranswer. 3marks

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SECTION B – continuedTURN OVER

Question 17 (5marks)Lightfromamercuryvapourlampshowsalinespectrumrelatedtodiscreteenergylevels.SomeoftheenergylevelsforthemercuryatomareshowninFigure20.

ionisation10.48.8

6.7

4.9

0

n = 4

n = 3

n = 2

ground state n = 1

energy (eV)

Figure 20

a. DrawanarrowonFigure20toindicatethetransitionbetweenthelistedenergystatesthatwouldproducethelowestfrequencyofanemittedphoton. 1mark

b. Calculatetheenergyofthelightemittedwhenthemercuryatommakesatransitionfromthethirdenergylevel(n =3)toitsgroundstate(n =1).Showyourworking. 2marks

J

c. Explainwhathappenstoamercuryatominitsgroundstateifaphotonofenergy2.1eVisincidentonit. 2marks

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SECTION B – Question 18–continued

Question 18 (15marks)Asmallrubberballofmass50gfallsverticallyfromagivenheightandreboundsfromahardfloor.Theball’sspeedimmediatelybeforeimpactis3.6ms–1.Theballreboundsupwardataspeedof3.3ms–1immediatelyafteritleavesthefloor.Theballisincontactwiththefloorfor40ms.

a. Calculatethemagnitudeanddirectionofthenetaverageforceactingonthe50gballwhileitisincontactwiththefloor.Showyourworking. 4marks

N

b. Justbeforetheballhitsthefloor,ithasacertainamountofkineticenergy,Ek. Atoneinstantwhentheballisincontactwiththefloor,itisstationarybeforeitrebounds.

Explainwhathashappenedtothekineticenergy,Ek,oftheballwhenitisstationary. 2marks

c. Justbeforetheballhitsthefloor,ithasacertainamountofverticalmomentum,p. Atoneinstantwhentheballisincontactwiththefloor,itisstationarybeforeitrebounds.

Whathashappenedtotheverticalmomentum,p,oftheballwhenitisstationary? 1mark

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Duringtheirpracticalinvestigation,somePhysicsstudentsinvestigatethemovementofasmallrubberball.Theballfallsfromaheightof1.00mandreboundstoaheightof0.78m.Thestudentsrecordtheball’sverticalpositionversustimebyusingasmartphone’svideofeatureandametrerulescale.Theuncertaintyintheball’sverticalpositionis±0.03m.Theresultsfromthestudents’recordeddataareplottedonthegraphinFigure21.

0.00 0.10 0.20 0.30 0.40 0.50 0.60 0.70 0.80 0.90

1.20

1.00

0.80

0.60

0.40

0.20

0.00

Figure 21

d. OnthegraphinFigure21:• labeleachaxisandincludeunitsoneachaxis• insertappropriateuncertaintybarsfortheheightvaluesonthegraph,forthereadingsfor

thefirstfourdatapointsaftertheballisreleased• drawsmoothcurvesofbestfit. 5marks

e. EstimatethespeedoftheballattheinstantofimpactusinganappropriategradientofthegraphinFigure21.Usecalculationstosupportyouranswer. 3marks

ms–1

END OF QUESTION AND ANSWER BOOK

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Victorian Certificate of Education 2021

PHYSICS

Written examination

FORMULA SHEET

Instructions

This formula sheet is provided for your reference.A question and answer book is provided with this formula sheet.

Students are NOT permitted to bring mobile phones and/or any other unauthorised electronic devices into the examination room.

© VICTORIAN CURRICULUM AND ASSESSMENT AUTHORITY 2021

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PHYSICS FORMULA SHEET 2

Physics formulas

Motion and related energy transformations

velocity; acceleration v st

a vt

� ���

��

;

equations for constant acceleration

v u at

s ut at

s vt at

v u as

s v u t

� �

� �

� �

� �

� �� �

1212

212

2

2

2 2

Newton’s second law ΣF = ma

circular motion a vr

rT

� �2 2

24�

Hooke’s law F = –kΔ x

elastic potential energy12

k(Δ x)2

gravitational potential energy near the surface of Earth mgΔh

kinetic energy12

2mv

Newton’s law of universal gravitation F G m mr

= 1 22

gravitational field g G Mr

= 2

impulse FΔ t

momentum mv

Lorentz factor� �

1

12

2vc

time dilation t = toγ

length contraction L L� o�

rest energy Erest = mc2

relativistic total energy Etotal = γmc2

relativistic kinetic energy Ek = (γ – 1)mc2

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3 PHYSICS FORMULA SHEET

TURN OVER

Fields and application of field concepts

electric field between charged plates E Vd

=

energy transformations of charges in an electric field

12

2mv qV=

field of a point charge E kqr

= 2

force on an electric charge F = qE

Coulomb’s law F kq qr

= 1 22

magnetic force on a moving charge F = qvB

magnetic force on a current carrying conductor F = nIlB

radius of a charged particle in a magnetic field r mvqB

=

Generation and transmission of electricity

voltage; power V = RI; P = VI = I2R

resistors in series RT = R1 + R2

resistors in parallel1 1 1

1 2R R RT� �

ideal transformer actionVV

NN

II

1

2

1

2

2

1= =

AC voltage and current V VRMS peak=12

I IRMS peak=12

electromagnetic induction Β ΒEMF: flux:N B A

tΦε Φ ⊥

∆= − =

transmission losses Vdrop = Iline Rline Ploss = I 2line Rline

Wave concepts

wave equation v = f λ

constructive interference path difference = nλ

destructive interference path difference � ����

���n 1

2�

fringe spacing �x Ld

��

Snell’s law n1 sinθ1 = n2 sinθ2

refractive index and wave speed n1 v1 = n2 v2

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PHYSICS FORMULA SHEET 4

END OF FORMULA SHEET

The nature of light and matter

photoelectric effect E hfk max � ��

photon energy E = hf

photon momentum p h��

de Broglie wavelength � �hp

Data

acceleration due to gravity at Earth’s surface g = 9.8 m s–2

mass of the electron me = 9.1 × 10–31 kg

magnitude of the charge of the electron e = 1.6 × 10–19 C

Planck’s constant h = 6.63 × 10–34 J s h = 4.14 × 10–15 eV s

speed of light in a vacuum c = 3.0 × 108 m s–1

universal gravitational constant G = 6.67 × 10–11 N m2 kg–2

mass of Earth ME = 5.98 × 1024 kg

radius of Earth RE = 6.37 × 106 m

Coulomb constant k = 8.99 × 109 N m2 C–2

Prefixes/Units

p = pico = 10–12 n = nano = 10–9 μ = micro = 10–6 m = milli = 10–3

k = kilo = 103 M = mega = 106 G = giga = 109 t = tonne = 103 kg