2003 Chemistry Higher Finalised Marking Instructions · 7 Where a wrong numerical answer ... 15...
Transcript of 2003 Chemistry Higher Finalised Marking Instructions · 7 Where a wrong numerical answer ... 15...
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Higher Chemistry
General information for markers
The general comments given below should be considered during all marking.
1 Marks should not be deducted for incorrect spelling or loose language as long as the meaning ofthe word(s) is conveyed.
Example: Answers like 'distiling' (for 'distillation') and 'it gets hotter' (for 'the temperature rises')should be accepted.
2 A right answer followed by a wrong answer should be treated as a cancelling error and no marksshould be given.
Example: What is the colour of universal indicator in acid solution?
The answer 'red, blue' gains no marks.
3 If a right answer is followed by additional information which does not conflict, the additionalinformation should be ignored, whether correct or not.
Example: Why can the tube not be made of copper?
If the correct answer is related to a low melting point, 'It has a low melting point andis coloured grey' would not be treated as having a cancelling error.
4 Full marks are usually awarded for the correct answer to a calculation on its own; the part marksshown in the marking scheme are for use when working is given. An exception is whencandidates are asked to ‘Find, by calculation, …..’.
5 A half mark should be deducted in a calculation for each arithmetic slip.
6 A half mark should be deducted for incorrect or missing units only when stated in the markingscheme. No marks should be deducted for incorrect or missing units at intermediate stages in acalculation.
7 Where a wrong numerical answer (already penalised) is carried forward to another step, nofurther penalty is incurred provided the result is used correctly.
8 Ignore the omission of one H atom from a full structural formula provided the bond is shown.
9 With structures involving an –OH or an –NH2 group, a half mark should be deducted if the 'O' or'N' are not bonded to a carbon, i.e. OH–CH2 and NH2–CH2.
10 When drawing structural formulae, a half mark should be deducted if the bond points to the'wrong' atom, eg
11 A symbol or correct formula should be accepted in place of a name unless stated otherwise inthe marking scheme.
12 When formulae of ionic compounds are given as answers it will only be necessary to show ioncharges if these has been specifically asked for. However, if ion charges are shown, they must becorrect. If incorrect charges are shown, no marks should be awarded.
C C
OH
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13 If an answer comes directly from the text of the question, no marks should be given.
Example: A student found that 0·05 mol of propane, C3H8 burned to give 82·4 kJ of energy.
C3H8(g) + 5O2(g) 3CO2(g) + 4H2O(l)
Name the kind of enthalpy change which the student measured.
No marks should be given for 'burning' since the word 'burned' appears in the text.
14 A guiding principle in marking is to give credit for (partially) correct chemistry rather than tolook for reasons not to give marks.
Example 1: The structure of a hydrocarbon found in petrol is shown below.
Name the hydrocarbon.
Although the punctuation is not correct, '3, methyl-hexane' should gain the fullmark.
Example 2: A student measured the pH of four carboxylic acids to find out how their strength isrelated to the number of chlorine atoms in the molecule. The results are shown.
Structural formula pHCH3COOH 1·65CH2ClCOOH 1·27CHCl2COOH 0·90CCl3COOH 0·51
How is the strength of the acids related to the number of chlorine atoms in themolecule?
Although not completely correct, an answer such as 'the more Cl2, the stronger theacid' should gain the full mark.
15 Unless the question is clearly about a non-chemistry issue, eg costs in industrial chemistry, anon-chemical answer gains no marks.
Example: Why does the (catalytic) converter have a honeycomb structure?
A response such as 'to make it work' may be correct but it is not a chemical answerand the mark should not be given.
16 When it is very difficult to make a decision about a partially correct answer, a half mark can beawarded.
17 When marks have been totalled, a half mark should be rounded up.
CH3 CH2 CH CH2 CH3CH2
CH3
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2003 Chemistry Higher
Marking Scheme
Section A
1. C 11. D 21. A 31. D
2. D 12. A 22. C 32. B
3. B 13. B 23. D 33. A
4. C 14. D 24. D 34. D
5. D 15. C 25. A 35. B
6. B 16. C 26. D 36. D
7. C 17. A 27. C 37. C
8. B 18. C 28. A 38. C
9. C 19. A 29. B 39. A
10. D 20. B 30. A 40. B
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1.(a
)2,
3,3–
trim
ethy
lpen
tane
or 3,3,
2–tr
imet
hlyp
enta
ne(c
omm
as, d
ash
may
be
omit
ted)
1
2-m
ethy
l, 3-
dim
ethy
lpen
tane
or 3,3,
4–tr
imet
hylp
enta
neor 2,
3,3–
met
hylp
enta
ne
2,3–
met
hylp
enta
neor m
ethy
lpen
tane
(b)
cycl
oalk
anes
orri
ng s
truc
ture
orna
phth
aor
arom
atic
s (b
enze
nes)
orcy
clic
phen
ol
benz
yl h
ydro
carb
ons
1 (2)
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2.(a
)St
rong
or
rigi
d or
dur
able
or toug
h or
har
d or
har
d to
pun
ctur
e1
ligh
tor do
es n
ot b
urn
(b)
amid
e li
nkor pe
ptid
e li
nk1
poly
amid
eor po
lype
ptid
e
amin
o gr
oup
or amin
e gr
oup
(2)
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3.(a
)pl
ottin
g po
ints
cor
rect
ly a
nd jo
inin
g w
ith
a lin
e1
poin
ts n
ot jo
ined
or one
poin
t not
plo
tted
corr
ectly
or poin
ts jo
ined
by
stra
ight
line
(b)
210 Po
20
6 Pb +
He
(or
α)or
num
bers
on
rhs
any
wro
ng s
ubsc
ript
or
supe
rscr
ipt
210 Po
206 Pb
1
(c)
210
g co
ntai
n 6
x 10
23 (
atom
s)
105
g co
ntai
n ½
x 6
x 1
023 (
atom
s)
= 3
x 1
023
(½)
(½)
6 x
1023
in 1
mol
(3)
α
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4.(a
)an
y su
gges
tion
that
iron
for
med
is m
olte
n or
in li
quid
stat
eor
iron
is f
orm
ed (
in q
uest
ion)
or exot
herm
ican
swer
impl
ies
that
iron
flo
ws
dow
n in
to c
rack
1or ra
il m
elts
, etc
(b)
∆H re
quire
d = ∆H
1 – ∆
H2
= (
-167
6) –
(-8
25)
(½)
= -
851
kJ
(mol
-1)
(½)
(2)
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5.(a
)sy
nthe
sis
gas
or s
yn. g
as1
synt
hetic
gas
(b)
oxid
atio
n or
deh
ydro
gena
tion
1
(c)
(i)
1
(ii)
the
rmos
ettin
g1
ther
moh
arde
ning
(4)
CN
N
OH
H HH
CO
NH
2H
2N
NC
ON
H H
H H
CO
NH
2N
H2
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6.(a
)(i
)re
acta
nts
or p
rodu
cts
coul
d go
on
fire
(fl
amm
able
)or to
pre
vent
bur
ning
1
(ii)
to c
onde
nse
any
vapo
urs
(or
reac
tant
s or
pro
duct
s w
hich
eva
pora
te)
1ea
sier
to c
ontr
ol th
ete
mpe
ratu
re/c
onde
nsat
ion
or safe
r w
ay to
hea
t
(b)
1
HC
CO
CC
CC
CH
HH
HH
HH
HH
OH
HH
H
O
CH
3CH
2-O
-CC
H2C
H2C
H2C
H3
or
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6.(c
)1
mol
C2H
5OH
=
46
g
46 g
x 13
0 g
3.6
g x
130
x
=
7.1
2 g
or 1 m
ol C
2H5O
H =
46
g
(½)
(½)
(½)
(½)
(½)
46 g
13
0 g
3.6
g13
0 x
= 1
0.17
4 g
a
ctua
l yie
ld =
10.
174
x
= 7
.12
g
(-½
for
wro
ng o
r no
uni
ts)
(½)
(½)
(½)
(5)
70
100
70
100
3.6
g 4
6 100
70
46
6.3
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7.(a
)m
oles
of
Mg
=
=
0.1
65 m
ol (
½)
mol
es o
f ac
id=
=
0.2
mol
es (
½)
mol
e ra
tio =
1 m
ol M
g :
2 m
ol a
cid
Not
eno
ugh
HC
l(aq
). T
here
fore
Mg
in e
xces
s (1
)2
(b)
1
Syst
em n
ot s
eale
d
(c)
rate
– s
low
er(½
)vo
lum
e –
sam
e
(½)
1 (4)
to s
yrin
ge
wat
er
3.24
0.4 100050
x
4
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8.(a
)(i
)ca
rbon
yl g
roup
at e
nd o
f ca
rbon
cha
in in
ald
ehyd
eor on
ly o
ne H
att
ache
d to
car
bony
lor al
dehy
de
or keto
ne1
(ii)
blu
e (½
)or
ange
/bri
ck r
ed/b
row
n (½
)1
(iii)
C3H
6O +
H2O
2H+(a
q) +
C2H
5CO
OH
+ 2
e-1
H+(a
q) a
nd e
- on
rhs
but n
otba
lanc
ed(i
v) p
ropa
noic
(ac
id)
1
(b)
(i)
addi
tion
or redu
ctio
n1
(ii)
1 (6)
HC
CC
H
HC
NHH
OH
H
orC C
N
H3C
CH
3
OH
CC
C
O
(
C C
O C
)
H
O (
– C
HO
)C
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9.(a
)to
tal v
olum
e no
t kep
t con
stan
t (ch
ange
s, in
crea
ses)
or chan
ges
conc
entr
atio
n of
all
rea
ctan
ts –
not
just
pota
ssiu
m io
dide
or mor
e th
an o
ne v
aria
ble
chan
ged
1
(b)
use
mor
e ac
cura
te m
easu
ring
cyl
inde
rs (
or s
yrin
ges)
for
smal
ler
volu
mes
in s
tep
1or st
art t
imer
whi
le a
ddin
g hy
drog
en p
erox
ide
(whe
n ha
lfof
the
pero
xide
has
bee
n ad
ded)
or put w
hite
tile
/pap
er b
elow
bea
ker
or repe
at e
xper
imen
t (a
ny tw
o)1 (2
)
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10.
(a)
rate
of
forw
ard
reac
tion
equa
ls r
ate
of b
ackw
ard
reac
tion
or conc
entr
atio
ns o
f re
acta
nt(s
) an
d pr
oduc
t(s)
are
con
stan
t1
rate
s ar
e co
nsta
nt
(b)
iodi
ne w
ill g
o fr
om c
hlor
ofor
m la
yer
(bot
tom
laye
r) in
toth
e K
I la
yer
(top
laye
r) to
res
tore
equ
ilibr
ium
or equi
libr
ium
mov
es to
left
(ra
te o
f ba
ckw
ard
reac
tion
incr
ease
s)1
(c)
0.3
g of
iodi
ne is
dis
solv
ed in
chl
orof
orm
(½
)
ther
efor
e, c
once
ntra
tion
= =
30
g l-1
(½
)
(uni
ts n
ot n
eces
sary
)1 (3
)
01.03.0
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11.
(a)
line
sho
uld
go u
p to
+ 7
5(½
)
line
sho
uld
then
go
dow
n to
– 2
6(½
)1
(b)
(i)
het
erog
eneo
us1
(ii)
sam
e st
artin
g le
vel
low
er p
eak
(½)
sam
e fi
nish
ing
leve
l(½
)1
(c)
(i)
=
1.2
cm
3 s-1
(-½
for
wro
ng o
r no
uni
ts)
110
24 - 36
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11(c
)(i
i)
1 m
ol O
2 fr
om 2
mol
of
H2O
2 (½
)1
mol
H2O
2 =
34
g (
½)
24 li
tres
O2
from
2 x
34
g of
H2O
2 (½
)
0.04
litr
es f
rom
=
0.1
13 g
(½
)
( -
½ f
or w
rong
or
no u
nits
)
2 (6)
24
0.04
x
68
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12.
(a)
prop
ane
mol
ecul
es a
re h
eld
toge
ther
by
wea
k fo
rces
or etha
nol m
olec
ules
are
hel
d to
geth
er b
y st
rong
for
ces
(1)
the
inte
rmol
ecul
ar f
orce
s in
pro
pane
are
van
der
Waa
ls’
forc
es(½
)
the
inte
rmol
ecul
ar f
orce
s in
eth
anol
are
hyd
roge
n bo
nds
(½)
van
der
Waa
ls’
forc
es a
re d
ue to
mom
enta
rydi
spla
cem
ent o
f el
ectr
ons
betw
een
atom
s(½
)(½
)
hydr
ogen
bon
ding
ari
ses
beca
use
the
O-H
bon
d is
hig
hly
pola
rise
d (t
here
is a
larg
e di
ffer
ence
in th
eel
ectr
oneg
ativ
itie
s of
O a
nd H
)(½
)
the
smal
l pos
itive
cha
rge
on H
and
sm
all n
egat
ive
char
geon
O s
tron
gly
attr
act
(½)
(4)
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13.
(a)
[H+(a
q)]
= 1
x 1
0-8 m
ol l-1
(uni
ts n
ot n
eces
sary
)
1
(b)
this
mus
t be
the
salt
of a
str
ong
alka
li (
or b
ase)
and
aw
eak
acid
or alka
li s
tron
ger
than
aci
d1
(c)
HC
N o
r C
NH
1 (3)
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14.
(a)
Seaw
ater
(so
dium
chl
orid
e), c
arbo
n di
oxid
e, a
mm
onia
(- ½
for
any
om
issi
on)
or corr
ect f
orm
ulae
1
(b)
CaC
O3
CaO
+ C
O2
∆
H =
+ve
(½)
C +
O2
CO
2∆H
= -v
e
(½)
1
use
of e
xoth
erm
ic/
endo
ther
mic
(c)
Ca(
OH
) 2 +
2N
H4C
lC
aCl 2
+ 2
H2O
+ 2
NH
31
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14.
(d)
mag
nesi
um c
arbo
nate
is in
solu
ble
or mag
nesi
um c
arbo
nate
for
ms
a pr
ecip
itate
1
(e)
CO
2 or
NH
3 or
NH
4Cl r
ecyc
led
(reu
sed)
or coke
add
ed to
lim
esto
ne to
pro
vide
ene
rgy
by r
eact
ing
wit
h O
2 fr
om a
ir (
or b
y bu
rnin
g)or ca
lciu
m c
hlor
ide
prod
uced
as
by-p
rodu
ctor (s
ome)
rea
ctan
ts f
ound
nat
ural
ly (
easi
ly o
btai
ned,
che
ap)
or cont
inuo
us p
roce
ss
recy
clin
g oc
curs
or no w
aste
pro
duct
sor no
n-po
llutin
gor by
-pro
duct
s ar
e us
eful
(any
two,
1 m
ark
each
)2 (6
)
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15.
(a)
hydr
olys
is (
hydr
olys
ing)
1di
gest
ion
or dena
turi
ng
(b)
(i)
1
(ii)
A
CB
on
rhs
(ign
ore
dist
ance
s; o
rder
mus
t be
corr
ect)
AB
C, B
AC
, CA
B o
n rh
sor C
BA
on
lhs
(w
orth
1 m
ark)
2
BC
Aor C
BA
on
rhs
(4)
HC
H
CO
O–
NH
2
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16.
(a)
Q =
It =
0.5
x 1
4 x
60 (
½)
= 4
20 C
(½
)
2H+ +
2e-
H
2
n =
2
(½)
2 x
96 5
00 C
1
mol
H2 (½
)
420
C0.
052
litre
s
2 x
96 5
00 C
x
0.05
2 (½
)
= 2
3.89
5 lit
res
(½)
(– ½
for
wro
ng o
r no
uni
ts)
3
(b)
add
vari
able
res
isto
r (t
o ke
ep c
urre
nt c
onst
ant)
or use
plat
inum
ele
ctro
des
1
add
a de
vice
to k
eep
cons
tant
curr
ent
(4)
[EN
D O
F M
AR
KIN
G I
NST
RU
CT
ION
S]
2 x
96 5
00
420