20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack...
Transcript of 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack...
![Page 1: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/1.jpg)
20. Dynamic Programming II
Subset sum problem, knapsack problem, greedy algorithm vsdynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,Cormen et al, Kap. 15,35.5]
612
![Page 2: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/2.jpg)
Task
Partition the set of the “item” above into two set such that both setshave the same value.
A solution:
613
![Page 3: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/3.jpg)
Task
Partition the set of the “item” above into two set such that both setshave the same value.
A solution:
613
![Page 4: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/4.jpg)
Subset Sum Problem
Consider n ∈ N numbers a1, . . . , an ∈ N.
Goal: decide if a selection I ⊆ {1, . . . , n} exists such that∑i∈I
ai =∑
i∈{1,...,n}\I
ai.
614
![Page 5: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/5.jpg)
Naive Algorithm
Check for each bit vector b = (b1, . . . , bn) ∈ {0, 1}n, if
n∑i=1
biai?=
n∑i=1
(1− bi)ai
Worst case: n steps for each of the 2n bit vectors b. Number ofsteps: O(n · 2n).
615
![Page 6: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/6.jpg)
Naive Algorithm
Check for each bit vector b = (b1, . . . , bn) ∈ {0, 1}n, if
n∑i=1
biai?=
n∑i=1
(1− bi)ai
Worst case: n steps for each of the 2n bit vectors b. Number ofsteps: O(n · 2n).
615
![Page 7: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/7.jpg)
Algorithm with PartitionPartition the input into two equally sized parts a1, . . . , an/2 andan/2+1, . . . , an.
Iterate over all subsets of the two parts and compute partial sumSk1 , . . . , S
k2n/2
(k = 1, 2).
Sort the partial sums: Sk1 ≤ Sk2 ≤ · · · ≤ Sk2n/2
.Check if there are partial sums such that S1
i + S2j = 1
2
∑ni=1 ai =: h
Start with i = 1, j = 2n/2.If S1
i + S2j = h then finished
If S1i + S2
j > h then j ← j − 1
If S1i + S2
j < h then i← i+ 1
616
![Page 8: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/8.jpg)
Algorithm with PartitionPartition the input into two equally sized parts a1, . . . , an/2 andan/2+1, . . . , an.Iterate over all subsets of the two parts and compute partial sumSk1 , . . . , S
k2n/2
(k = 1, 2).
Sort the partial sums: Sk1 ≤ Sk2 ≤ · · · ≤ Sk2n/2
.Check if there are partial sums such that S1
i + S2j = 1
2
∑ni=1 ai =: h
Start with i = 1, j = 2n/2.If S1
i + S2j = h then finished
If S1i + S2
j > h then j ← j − 1
If S1i + S2
j < h then i← i+ 1
616
![Page 9: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/9.jpg)
Algorithm with PartitionPartition the input into two equally sized parts a1, . . . , an/2 andan/2+1, . . . , an.Iterate over all subsets of the two parts and compute partial sumSk1 , . . . , S
k2n/2
(k = 1, 2).
Sort the partial sums: Sk1 ≤ Sk2 ≤ · · · ≤ Sk2n/2
.
Check if there are partial sums such that S1i + S2
j = 12
∑ni=1 ai =: h
Start with i = 1, j = 2n/2.If S1
i + S2j = h then finished
If S1i + S2
j > h then j ← j − 1
If S1i + S2
j < h then i← i+ 1
616
![Page 10: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/10.jpg)
Algorithm with PartitionPartition the input into two equally sized parts a1, . . . , an/2 andan/2+1, . . . , an.Iterate over all subsets of the two parts and compute partial sumSk1 , . . . , S
k2n/2
(k = 1, 2).
Sort the partial sums: Sk1 ≤ Sk2 ≤ · · · ≤ Sk2n/2
.Check if there are partial sums such that S1
i + S2j = 1
2
∑ni=1 ai =: h
Start with i = 1, j = 2n/2.If S1
i + S2j = h then finished
If S1i + S2
j > h then j ← j − 1
If S1i + S2
j < h then i← i+ 1
616
![Page 11: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/11.jpg)
Algorithm with PartitionPartition the input into two equally sized parts a1, . . . , an/2 andan/2+1, . . . , an.Iterate over all subsets of the two parts and compute partial sumSk1 , . . . , S
k2n/2
(k = 1, 2).
Sort the partial sums: Sk1 ≤ Sk2 ≤ · · · ≤ Sk2n/2
.Check if there are partial sums such that S1
i + S2j = 1
2
∑ni=1 ai =: h
Start with i = 1, j = 2n/2.
If S1i + S2
j = h then finishedIf S1
i + S2j > h then j ← j − 1
If S1i + S2
j < h then i← i+ 1
616
![Page 12: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/12.jpg)
Algorithm with PartitionPartition the input into two equally sized parts a1, . . . , an/2 andan/2+1, . . . , an.Iterate over all subsets of the two parts and compute partial sumSk1 , . . . , S
k2n/2
(k = 1, 2).
Sort the partial sums: Sk1 ≤ Sk2 ≤ · · · ≤ Sk2n/2
.Check if there are partial sums such that S1
i + S2j = 1
2
∑ni=1 ai =: h
Start with i = 1, j = 2n/2.If S1
i + S2j = h then finished
If S1i + S2
j > h then j ← j − 1
If S1i + S2
j < h then i← i+ 1
616
![Page 13: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/13.jpg)
Algorithm with PartitionPartition the input into two equally sized parts a1, . . . , an/2 andan/2+1, . . . , an.Iterate over all subsets of the two parts and compute partial sumSk1 , . . . , S
k2n/2
(k = 1, 2).
Sort the partial sums: Sk1 ≤ Sk2 ≤ · · · ≤ Sk2n/2
.Check if there are partial sums such that S1
i + S2j = 1
2
∑ni=1 ai =: h
Start with i = 1, j = 2n/2.If S1
i + S2j = h then finished
If S1i + S2
j > h then j ← j − 1
If S1i + S2
j < h then i← i+ 1
616
![Page 14: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/14.jpg)
Algorithm with PartitionPartition the input into two equally sized parts a1, . . . , an/2 andan/2+1, . . . , an.Iterate over all subsets of the two parts and compute partial sumSk1 , . . . , S
k2n/2
(k = 1, 2).
Sort the partial sums: Sk1 ≤ Sk2 ≤ · · · ≤ Sk2n/2
.Check if there are partial sums such that S1
i + S2j = 1
2
∑ni=1 ai =: h
Start with i = 1, j = 2n/2.If S1
i + S2j = h then finished
If S1i + S2
j > h then j ← j − 1
If S1i + S2
j < h then i← i+ 1
616
![Page 15: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/15.jpg)
Example
Set {1, 6, 2, 3, 4} with value sum 16 has 32 subsets.
Partitioning into {1, 6} , {2, 3, 4} yields the following 12 subsets withvalue sums:
{1, 6} {2, 3, 4}
{} {1} {6} {1, 6} {} {2} {3} {4} {2, 3} {2, 4} {3, 4} {2, 3, 4}
0 1 6 7 0 2 3 4 5 6 7 9
⇔ One possible solution: {1, 3, 4}
617
![Page 16: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/16.jpg)
Example
Set {1, 6, 2, 3, 4} with value sum 16 has 32 subsets.
Partitioning into {1, 6} , {2, 3, 4} yields the following 12 subsets withvalue sums:
{1, 6} {2, 3, 4}
{} {1} {6} {1, 6} {} {2} {3} {4} {2, 3} {2, 4} {3, 4} {2, 3, 4}
0 1 6 7 0 2 3 4 5 6 7 9
⇔ One possible solution: {1, 3, 4}
617
![Page 17: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/17.jpg)
Example
Set {1, 6, 2, 3, 4} with value sum 16 has 32 subsets.
Partitioning into {1, 6} , {2, 3, 4} yields the following 12 subsets withvalue sums:
{1, 6} {2, 3, 4}
{} {1} {6} {1, 6} {} {2} {3} {4} {2, 3} {2, 4} {3, 4} {2, 3, 4}
0 1 6 7 0 2 3 4 5 6 7 9
⇔ One possible solution: {1, 3, 4}
617
![Page 18: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/18.jpg)
Example
Set {1, 6, 2, 3, 4} with value sum 16 has 32 subsets.
Partitioning into {1, 6} , {2, 3, 4} yields the following 12 subsets withvalue sums:
{1, 6} {2, 3, 4}
{} {1} {6} {1, 6} {} {2} {3} {4} {2, 3} {2, 4} {3, 4} {2, 3, 4}
0 1 6 7 0 2 3 4 5 6 7 9
⇔ One possible solution: {1, 3, 4}
617
![Page 19: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/19.jpg)
Example
Set {1, 6, 2, 3, 4} with value sum 16 has 32 subsets.
Partitioning into {1, 6} , {2, 3, 4} yields the following 12 subsets withvalue sums:
{1, 6} {2, 3, 4}
{} {1} {6} {1, 6} {} {2} {3} {4} {2, 3} {2, 4} {3, 4} {2, 3, 4}
0 1 6 7 0 2 3 4 5 6 7 9
⇔ One possible solution: {1, 3, 4}
617
![Page 20: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/20.jpg)
Example
Set {1, 6, 2, 3, 4} with value sum 16 has 32 subsets.
Partitioning into {1, 6} , {2, 3, 4} yields the following 12 subsets withvalue sums:
{1, 6} {2, 3, 4}
{} {1} {6} {1, 6} {} {2} {3} {4} {2, 3} {2, 4} {3, 4} {2, 3, 4}
0 1 6 7 0 2 3 4 5 6 7 9
⇔ One possible solution: {1, 3, 4}
617
![Page 21: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/21.jpg)
Example
Set {1, 6, 2, 3, 4} with value sum 16 has 32 subsets.
Partitioning into {1, 6} , {2, 3, 4} yields the following 12 subsets withvalue sums:
{1, 6} {2, 3, 4}
{} {1} {6} {1, 6} {} {2} {3} {4} {2, 3} {2, 4} {3, 4} {2, 3, 4}
0 1 6 7 0 2 3 4 5 6 7 9
⇔ One possible solution: {1, 3, 4}
617
![Page 22: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/22.jpg)
Analysis
Generate partial sums for each part: O(2n/2 · n).Each sorting: O(2n/2 log(2n/2)) = O(n2n/2).Merge: O(2n/2)
Overal running time
O(n · 2n/2
)= O
(n(√
2)n)
.
Substantial improvement over the naive method –but still exponential!
618
![Page 23: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/23.jpg)
Dynamic programmingTask: let z = 1
2
∑ni=1 ai. Find a selection I ⊂ {1, . . . , n}, such that∑
i∈I ai = z.
DP-table: [0, . . . , n]× [0, . . . , z]-table T with boolean entries. T [k, s]specifies if there is a selection Ik ⊂ {1, . . . , k} such that∑
i∈Ik ai = s.
Initialization: T [0, 0] = true. T [0, s] = false for s > 1.
Computation:
T [k, s]←
{T [k − 1, s] if s < ak
T [k − 1, s] ∨ T [k − 1, s− ak] if s ≥ ak
for increasing k and then within k increasing s.
619
![Page 24: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/24.jpg)
Dynamic programmingTask: let z = 1
2
∑ni=1 ai. Find a selection I ⊂ {1, . . . , n}, such that∑
i∈I ai = z.
DP-table: [0, . . . , n]× [0, . . . , z]-table T with boolean entries. T [k, s]specifies if there is a selection Ik ⊂ {1, . . . , k} such that∑
i∈Ik ai = s.
Initialization: T [0, 0] = true. T [0, s] = false for s > 1.
Computation:
T [k, s]←
{T [k − 1, s] if s < ak
T [k − 1, s] ∨ T [k − 1, s− ak] if s ≥ ak
for increasing k and then within k increasing s.
619
![Page 25: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/25.jpg)
Dynamic programmingTask: let z = 1
2
∑ni=1 ai. Find a selection I ⊂ {1, . . . , n}, such that∑
i∈I ai = z.
DP-table: [0, . . . , n]× [0, . . . , z]-table T with boolean entries. T [k, s]specifies if there is a selection Ik ⊂ {1, . . . , k} such that∑
i∈Ik ai = s.
Initialization: T [0, 0] = true. T [0, s] = false for s > 1.
Computation:
T [k, s]←
{T [k − 1, s] if s < ak
T [k − 1, s] ∨ T [k − 1, s− ak] if s ≥ ak
for increasing k and then within k increasing s.
619
![Page 26: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/26.jpg)
Dynamic programmingTask: let z = 1
2
∑ni=1 ai. Find a selection I ⊂ {1, . . . , n}, such that∑
i∈I ai = z.
DP-table: [0, . . . , n]× [0, . . . , z]-table T with boolean entries. T [k, s]specifies if there is a selection Ik ⊂ {1, . . . , k} such that∑
i∈Ik ai = s.
Initialization: T [0, 0] = true. T [0, s] = false for s > 1.
Computation:
T [k, s]←
{T [k − 1, s] if s < ak
T [k − 1, s] ∨ T [k − 1, s− ak] if s ≥ ak
for increasing k and then within k increasing s.619
![Page 27: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/27.jpg)
Example
{1, 6, 2, 5}0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
0 • · · · · · · · · · · · · · ·1 • • · · · · · · · · · · · · ·6 • • · · · · • • · · · · · · ·2 • • • • · · • • • • · · · · ·5 • • • • · • • • • • · • • • •
summe s
k
Determination of the solution: if T [k, s] = T [k − 1, s] then ak unused and continue with T [k − 1, s] , otherwise ak used
and continue with T [k − 1, s− ak] .
620
![Page 28: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/28.jpg)
Example
{1, 6, 2, 5}0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
0 • · · · · · · · · · · · · · ·1 • • · · · · · · · · · · · · ·6 • • · · · · • • · · · · · · ·2 • • • • · · • • • • · · · · ·5 • • • • · • • • • • · • • • •
summe s
k
Determination of the solution: if T [k, s] = T [k − 1, s] then ak unused and continue with T [k − 1, s] , otherwise ak used
and continue with T [k − 1, s− ak] .
620
![Page 29: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/29.jpg)
Example
{1, 6, 2, 5}0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
0 • · · · · · · · · · · · · · ·1 • • · · · · · · · · · · · · ·6 • • · · · · • • · · · · · · ·2 • • • • · · • • • • · · · · ·5 • • • • · • • • • • · • • • •
summe s
k
Determination of the solution: if T [k, s] = T [k − 1, s] then ak unused and continue with T [k − 1, s] , otherwise ak used
and continue with T [k − 1, s− ak] .
620
![Page 30: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/30.jpg)
Example
{1, 6, 2, 5}0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
0 • · · · · · · · · · · · · · ·1 • • · · · · · · · · · · · · ·6 • • · · · · • • · · · · · · ·2 • • • • · · • • • • · · · · ·5 • • • • · • • • • • · • • • •
summe s
k
Determination of the solution: if T [k, s] = T [k − 1, s] then ak unused and continue with T [k − 1, s] , otherwise ak used
and continue with T [k − 1, s− ak] .
620
![Page 31: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/31.jpg)
Example
{1, 6, 2, 5}0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
0 • · · · · · · · · · · · · · ·1 • • · · · · · · · · · · · · ·6 • • · · · · • • · · · · · · ·2 • • • • · · • • • • · · · · ·5 • • • • · • • • • • · • • • •
summe s
k
Determination of the solution: if T [k, s] = T [k − 1, s] then ak unused and continue with T [k − 1, s] , otherwise ak used
and continue with T [k − 1, s− ak] .
620
![Page 32: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/32.jpg)
Example
{1, 6, 2, 5}0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
0 • · · · · · · · · · · · · · ·1 • • · · · · · · · · · · · · ·6 • • · · · · • • · · · · · · ·2 • • • • · · • • • • · · · · ·5 • • • • · • • • • • · • • • •
summe s
k
Determination of the solution: if T [k, s] = T [k − 1, s] then ak unused and continue with T [k − 1, s] , otherwise ak used
and continue with T [k − 1, s− ak] .
620
![Page 33: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/33.jpg)
Example
{1, 6, 2, 5}0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
0 • · · · · · · · · · · · · · ·1 • • · · · · · · · · · · · · ·6 • • · · · · • • · · · · · · ·2 • • • • · · • • • • · · · · ·5 • • • • · • • • • • · • • • •
summe s
k
Determination of the solution: if T [k, s] = T [k − 1, s] then ak unused and continue with T [k − 1, s] , otherwise ak used
and continue with T [k − 1, s− ak] .
620
![Page 34: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/34.jpg)
That is mysterious
The algorithm requires a number of O(n · z) fundamental operations.
What is going on now? Does the algorithm suddenly havepolynomial running time?
621
![Page 35: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/35.jpg)
That is mysterious
The algorithm requires a number of O(n · z) fundamental operations.
What is going on now? Does the algorithm suddenly havepolynomial running time?
621
![Page 36: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/36.jpg)
That is mysterious
The algorithm requires a number of O(n · z) fundamental operations.
What is going on now? Does the algorithm suddenly havepolynomial running time?
621
![Page 37: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/37.jpg)
Explained
The algorithm does not necessarily provide a polynomial run time. zis an number and not a quantity!
Input length of the algorithm ∼= number bits to reasonably representthe data. With the number z this would be ζ = log z.
Consequently the algorithm requires O(n · 2ζ) fundamentaloperations and has a run time exponential in ζ.
If, however, z is polynomial in n then the algorithm has polynomialrun time in n. This is called pseudo-polynomial.
622
![Page 38: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/38.jpg)
Explained
The algorithm does not necessarily provide a polynomial run time. zis an number and not a quantity!
Input length of the algorithm ∼= number bits to reasonably representthe data. With the number z this would be ζ = log z.
Consequently the algorithm requires O(n · 2ζ) fundamentaloperations and has a run time exponential in ζ.
If, however, z is polynomial in n then the algorithm has polynomialrun time in n. This is called pseudo-polynomial.
622
![Page 39: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/39.jpg)
Explained
The algorithm does not necessarily provide a polynomial run time. zis an number and not a quantity!
Input length of the algorithm ∼= number bits to reasonably representthe data. With the number z this would be ζ = log z.
Consequently the algorithm requires O(n · 2ζ) fundamentaloperations and has a run time exponential in ζ.
If, however, z is polynomial in n then the algorithm has polynomialrun time in n. This is called pseudo-polynomial.
622
![Page 40: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/40.jpg)
Explained
The algorithm does not necessarily provide a polynomial run time. zis an number and not a quantity!
Input length of the algorithm ∼= number bits to reasonably representthe data. With the number z this would be ζ = log z.
Consequently the algorithm requires O(n · 2ζ) fundamentaloperations and has a run time exponential in ζ.
If, however, z is polynomial in n then the algorithm has polynomialrun time in n. This is called pseudo-polynomial.
622
![Page 41: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/41.jpg)
NPIt is known that the subset-sum algorithm belongs to the class ofNP-complete problems (and is thus NP-hard).
P: Set of all problems that can be solved in polynomial time.
NP: Set of all problems that can be solved Nondeterministically inPolynomial time.
Implications:
NP contains P.Problems can be verified in polynomial time.Under the not (yet?) proven assumption41 that NP 6= P, there is noalgorithm with polynomial run time for the problem consideredabove.
41The most important unsolved question of theoretical computer science. 623
![Page 42: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/42.jpg)
NPIt is known that the subset-sum algorithm belongs to the class ofNP-complete problems (and is thus NP-hard).
P: Set of all problems that can be solved in polynomial time.
NP: Set of all problems that can be solved Nondeterministically inPolynomial time.
Implications:
NP contains P.Problems can be verified in polynomial time.Under the not (yet?) proven assumption41 that NP 6= P, there is noalgorithm with polynomial run time for the problem consideredabove.
41The most important unsolved question of theoretical computer science. 623
![Page 43: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/43.jpg)
NPIt is known that the subset-sum algorithm belongs to the class ofNP-complete problems (and is thus NP-hard).
P: Set of all problems that can be solved in polynomial time.
NP: Set of all problems that can be solved Nondeterministically inPolynomial time.
Implications:
NP contains P.Problems can be verified in polynomial time.Under the not (yet?) proven assumption41 that NP 6= P, there is noalgorithm with polynomial run time for the problem consideredabove.
41The most important unsolved question of theoretical computer science. 623
![Page 44: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/44.jpg)
The knapsack problemWe pack our suitcase with ...
toothbrush
dumbell set
coffee machine
uh oh – too heavy.
Toothbrush
Air balloon
Pocket knife
identity card
dumbell set
Uh oh – too heavy.
toothbrush
coffe machine
pocket knife
identity card
Uh oh – too heavy.
Aim to take as much as possible with us. But some things are morevaluable than others!
624
![Page 45: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/45.jpg)
The knapsack problemWe pack our suitcase with ...
toothbrush
dumbell set
coffee machine
uh oh – too heavy.
Toothbrush
Air balloon
Pocket knife
identity card
dumbell set
Uh oh – too heavy.
toothbrush
coffe machine
pocket knife
identity card
Uh oh – too heavy.
Aim to take as much as possible with us. But some things are morevaluable than others!
624
![Page 46: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/46.jpg)
The knapsack problemWe pack our suitcase with ...
toothbrush
dumbell set
coffee machine
uh oh – too heavy.
Toothbrush
Air balloon
Pocket knife
identity card
dumbell set
Uh oh – too heavy.
toothbrush
coffe machine
pocket knife
identity card
Uh oh – too heavy.
Aim to take as much as possible with us. But some things are morevaluable than others!
624
![Page 47: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/47.jpg)
The knapsack problemWe pack our suitcase with ...
toothbrush
dumbell set
coffee machine
uh oh – too heavy.
Toothbrush
Air balloon
Pocket knife
identity card
dumbell set
Uh oh – too heavy.
toothbrush
coffe machine
pocket knife
identity card
Uh oh – too heavy.
Aim to take as much as possible with us. But some things are morevaluable than others!
624
![Page 48: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/48.jpg)
Knapsack problem
Given:
set of n ∈ N items {1, . . . , n}.Each item i has value vi ∈ N and weight wi ∈ N.Maximum weight W ∈ N.Input is denoted as E = (vi, wi)i=1,...,n.
Wanted:
a selection I ⊆ {1, . . . , n} that maximises∑
i∈I vi under∑i∈I wi ≤ W .
625
![Page 49: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/49.jpg)
Knapsack problem
Given:
set of n ∈ N items {1, . . . , n}.Each item i has value vi ∈ N and weight wi ∈ N.Maximum weight W ∈ N.Input is denoted as E = (vi, wi)i=1,...,n.
Wanted:
a selection I ⊆ {1, . . . , n} that maximises∑
i∈I vi under∑i∈I wi ≤ W .
625
![Page 50: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/50.jpg)
Greedy heuristics
Sort the items decreasingly by value per weight vi/wi: Permutation pwith vpi/wpi ≥ vpi+1
/wpi+1
Add items in this order (I ← I ∪ {pi}), if the maximum weight is notexceeded.
That is fast: Θ(n log n) for sorting and Θ(n) for the selection. But is itgood?
626
![Page 51: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/51.jpg)
Greedy heuristics
Sort the items decreasingly by value per weight vi/wi: Permutation pwith vpi/wpi ≥ vpi+1
/wpi+1
Add items in this order (I ← I ∪ {pi}), if the maximum weight is notexceeded.
That is fast: Θ(n log n) for sorting and Θ(n) for the selection. But is itgood?
626
![Page 52: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/52.jpg)
Greedy heuristics
Sort the items decreasingly by value per weight vi/wi: Permutation pwith vpi/wpi ≥ vpi+1
/wpi+1
Add items in this order (I ← I ∪ {pi}), if the maximum weight is notexceeded.
That is fast: Θ(n log n) for sorting and Θ(n) for the selection. But is itgood?
626
![Page 53: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/53.jpg)
Counterexample
v1 = 1 w1 = 1 v1/w1 = 1
v2 = W − 1 w2 = W v2/w2 = W−1W
Greed algorithm chooses {v1} with value 1.Best selection: {v2} with value W − 1 and weight W .
Greedy heuristics can be arbitrarily bad.
627
![Page 54: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/54.jpg)
Counterexample
v1 = 1 w1 = 1 v1/w1 = 1
v2 = W − 1 w2 = W v2/w2 = W−1W
Greed algorithm chooses {v1} with value 1.Best selection: {v2} with value W − 1 and weight W .
Greedy heuristics can be arbitrarily bad.
627
![Page 55: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/55.jpg)
Dynamic Programming
Partition the maximum weight.
Three dimensional table m[i, w, v] (“doable”) of boolean values.
m[i, w, v] = true if and only if
A selection of the first i parts exists (0 ≤ i ≤ n)with overal weight w (0 ≤ w ≤ W ) anda value of at least v (0 ≤ v ≤
∑ni=1 vi) .
628
![Page 56: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/56.jpg)
Dynamic Programming
Partition the maximum weight.
Three dimensional table m[i, w, v] (“doable”) of boolean values.
m[i, w, v] = true if and only if
A selection of the first i parts exists (0 ≤ i ≤ n)with overal weight w (0 ≤ w ≤ W ) anda value of at least v (0 ≤ v ≤
∑ni=1 vi) .
628
![Page 57: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/57.jpg)
Dynamic Programming
Partition the maximum weight.
Three dimensional table m[i, w, v] (“doable”) of boolean values.
m[i, w, v] = true if and only if
A selection of the first i parts exists (0 ≤ i ≤ n)with overal weight w (0 ≤ w ≤ W ) anda value of at least v (0 ≤ v ≤
∑ni=1 vi) .
628
![Page 58: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/58.jpg)
Computation of the DP tableInitially
m[i, w, 0]← true für alle i ≥ 0 und alle w ≥ 0.m[0, w, v]← false für alle w ≥ 0 und alle v > 0.
Computation
m[i, w, v]←{m[i− 1, w, v] ∨m[i− 1, w − wi, v − vi] if w ≥ wi und v ≥ vim[i− 1, w, v] otherwise.
increasing in i and for each i increasing in w and for fixed i and wincreasing by v.
Solution: largest v, such that m[i, w, v] = true for some i and w.
629
![Page 59: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/59.jpg)
Computation of the DP tableInitially
m[i, w, 0]← true für alle i ≥ 0 und alle w ≥ 0.m[0, w, v]← false für alle w ≥ 0 und alle v > 0.
Computation
m[i, w, v]←{m[i− 1, w, v] ∨m[i− 1, w − wi, v − vi] if w ≥ wi und v ≥ vim[i− 1, w, v] otherwise.
increasing in i and for each i increasing in w and for fixed i and wincreasing by v.
Solution: largest v, such that m[i, w, v] = true for some i and w.629
![Page 60: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/60.jpg)
Observation
The definition of the problem obviously implies that
for m[i, w, v] = true it holds:m[i′, w, v] = true ∀i′ ≥ i ,m[i, w′, v] = true ∀w′ ≥ w ,m[i, w, v′] = true ∀v′ ≤ v.fpr m[i, w, v] = false it holds:m[i′, w, v] = false ∀i′ ≤ i ,m[i, w′, v] = false ∀w′ ≤ w ,m[i, w, v′] = false ∀v′ ≥ v.
This strongly suggests that we do not need a 3d table!
630
![Page 61: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/61.jpg)
2d DP table
Table entry t[i, w] contains, instead of boolean values, the largest v,that can be achieved42 with
items 1, . . . , i (0 ≤ i ≤ n)at maximum weight w (0 ≤ w ≤ W ).
42We could have followed a similar idea in order to reduce the size of the sparse table.631
![Page 62: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/62.jpg)
Computation
Initially
t[0, w]← 0 for all w ≥ 0.
We compute
t[i, w]←{t[i− 1, w] if w < wi
max{t[i− 1, w], t[i− 1, w − wi] + vi} otherwise.
increasing by i and for fixed i increasing by w.
Solution is located in t[n,w]
632
![Page 63: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/63.jpg)
ExampleE = {(2, 3), (4, 5), (1, 1)}
0 1 2 3 4 5 6 7
∅ 0 0 0 0 0 0 0 0
(2, 3) 0 0 3 3 3 3 3 3
(4, 5) 0 0 3 3 5 5 8 8
(1, 1) 0 1 3 4 5 6 8 9
w
i
Reading out the solution: if t[i, w] = t[i− 1, w] then item i unused and continue with t[i− 1, w] otherwise used and
continue with t[i− 1, s− wi] .
633
![Page 64: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/64.jpg)
ExampleE = {(2, 3), (4, 5), (1, 1)}
0 1 2 3 4 5 6 7
∅ 0 0 0 0 0 0 0 0
(2, 3) 0 0 3 3 3 3 3 3
(4, 5) 0 0 3 3 5 5 8 8
(1, 1) 0 1 3 4 5 6 8 9
w
i
Reading out the solution: if t[i, w] = t[i− 1, w] then item i unused and continue with t[i− 1, w] otherwise used and
continue with t[i− 1, s− wi] .
633
![Page 65: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/65.jpg)
ExampleE = {(2, 3), (4, 5), (1, 1)}
0 1 2 3 4 5 6 7
∅ 0 0 0 0 0 0 0 0
(2, 3) 0 0 3 3 3 3 3 3
(4, 5) 0 0 3 3 5 5 8 8
(1, 1) 0 1 3 4 5 6 8 9
w
i
Reading out the solution: if t[i, w] = t[i− 1, w] then item i unused and continue with t[i− 1, w] otherwise used and
continue with t[i− 1, s− wi] .
633
![Page 66: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/66.jpg)
ExampleE = {(2, 3), (4, 5), (1, 1)}
0 1 2 3 4 5 6 7
∅ 0 0 0 0 0 0 0 0
(2, 3) 0 0 3 3 3 3 3 3
(4, 5) 0 0 3 3 5 5 8 8
(1, 1) 0 1 3 4 5 6 8 9
w
i
Reading out the solution: if t[i, w] = t[i− 1, w] then item i unused and continue with t[i− 1, w] otherwise used and
continue with t[i− 1, s− wi] .
633
![Page 67: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/67.jpg)
ExampleE = {(2, 3), (4, 5), (1, 1)}
0 1 2 3 4 5 6 7
∅ 0 0 0 0 0 0 0 0
(2, 3) 0 0 3 3 3 3 3 3
(4, 5) 0 0 3 3 5 5 8 8
(1, 1) 0 1 3 4 5 6 8 9
w
i
Reading out the solution: if t[i, w] = t[i− 1, w] then item i unused and continue with t[i− 1, w] otherwise used and
continue with t[i− 1, s− wi] .
633
![Page 68: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/68.jpg)
ExampleE = {(2, 3), (4, 5), (1, 1)}
0 1 2 3 4 5 6 7
∅ 0 0 0 0 0 0 0 0
(2, 3) 0 0 3 3 3 3 3 3
(4, 5) 0 0 3 3 5 5 8 8
(1, 1) 0 1 3 4 5 6 8 9
w
i
Reading out the solution: if t[i, w] = t[i− 1, w] then item i unused and continue with t[i− 1, w] otherwise used and
continue with t[i− 1, s− wi] .633
![Page 69: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/69.jpg)
Analysis
The two algorithms for the knapsack problem provide a run time inΘ(n ·W ·
∑ni=1 vi) (3d-table) and Θ(n ·W ) (2d-table) and are thus
both pseudo-polynomial, but they deliver the best possible result.
The greedy algorithm is very fast butmight deliver an arbitrarily badresult.
Now we consider a solution between the two extremes.
634
![Page 70: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/70.jpg)
21. Dynamic Programming III
FPTAS [Ottman/Widmayer, Kap. 7.2, 7.3, Cormen et al, Kap.15,35.5]
635
![Page 71: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/71.jpg)
Approximation
Let ε ∈ (0, 1) given. Let Iopt an optimal selection.
No try to find a valid selection I with∑i∈I
vi ≥ (1− ε)∑i∈Iopt
vi.
Sum of weights may not violate the weight limit.
636
![Page 72: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/72.jpg)
Different formulation of the algorithm
Before: weight limit w→ maximal value v
Reversed: value v→ minimal weight w
⇒ alternative table g[i, v] provides the minimum weight with
a selection of the first i items (0 ≤ i ≤ n) thatprovide a value of exactly v (0 ≤ v ≤
∑ni=1 vi).
637
![Page 73: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/73.jpg)
Computation
Initially
g[0, 0]← 0
g[0, v]←∞ (Value v cannot be achieved with 0 items.).
Computation
g[i, v]←{g[i− 1, v] falls v < vimin{g[i− 1, v], g[i− 1, v − vi] + wi} sonst.
incrementally in i and for fixed i increasing in v.
Solution can be found at largest index v with g[n, v] ≤ w.
638
![Page 74: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/74.jpg)
ExampleE = {(2, 3), (4, 5), (1, 1)}
0 1 2 3 4 5 6 7 8 9
∅ 0 ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞
(2, 3) 0 ∞ ∞ 2 ∞ ∞ ∞ ∞ ∞ ∞
(4, 5) 0 ∞ ∞ 2 ∞ 4 ∞ ∞ 6 ∞
(1, 1) 0 1 ∞ 2 3 4 5 ∞ 6 7
v
i
Read out the solution: if g[i, v] = g[i− 1, v] then item i unused and continue with g[i− 1, v] otherwise used and continue
with g[i− 1, b− vi] .
639
![Page 75: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/75.jpg)
ExampleE = {(2, 3), (4, 5), (1, 1)}
0 1 2 3 4 5 6 7 8 9
∅ 0 ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞
(2, 3) 0 ∞ ∞ 2 ∞ ∞ ∞ ∞ ∞ ∞
(4, 5) 0 ∞ ∞ 2 ∞ 4 ∞ ∞ 6 ∞
(1, 1) 0 1 ∞ 2 3 4 5 ∞ 6 7
v
i
Read out the solution: if g[i, v] = g[i− 1, v] then item i unused and continue with g[i− 1, v] otherwise used and continue
with g[i− 1, b− vi] .
639
![Page 76: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/76.jpg)
ExampleE = {(2, 3), (4, 5), (1, 1)}
0 1 2 3 4 5 6 7 8 9
∅ 0 ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞
(2, 3) 0 ∞ ∞ 2 ∞ ∞ ∞ ∞ ∞ ∞
(4, 5) 0 ∞ ∞ 2 ∞ 4 ∞ ∞ 6 ∞
(1, 1) 0 1 ∞ 2 3 4 5 ∞ 6 7
v
i
Read out the solution: if g[i, v] = g[i− 1, v] then item i unused and continue with g[i− 1, v] otherwise used and continue
with g[i− 1, b− vi] .
639
![Page 77: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/77.jpg)
ExampleE = {(2, 3), (4, 5), (1, 1)}
0 1 2 3 4 5 6 7 8 9
∅ 0 ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞
(2, 3) 0 ∞ ∞ 2 ∞ ∞ ∞ ∞ ∞ ∞
(4, 5) 0 ∞ ∞ 2 ∞ 4 ∞ ∞ 6 ∞
(1, 1) 0 1 ∞ 2 3 4 5 ∞ 6 7
v
i
Read out the solution: if g[i, v] = g[i− 1, v] then item i unused and continue with g[i− 1, v] otherwise used and continue
with g[i− 1, b− vi] .
639
![Page 78: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/78.jpg)
ExampleE = {(2, 3), (4, 5), (1, 1)}
0 1 2 3 4 5 6 7 8 9
∅ 0 ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞
(2, 3) 0 ∞ ∞ 2 ∞ ∞ ∞ ∞ ∞ ∞
(4, 5) 0 ∞ ∞ 2 ∞ 4 ∞ ∞ 6 ∞
(1, 1) 0 1 ∞ 2 3 4 5 ∞ 6 7
v
i
Read out the solution: if g[i, v] = g[i− 1, v] then item i unused and continue with g[i− 1, v] otherwise used and continue
with g[i− 1, b− vi] .
639
![Page 79: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/79.jpg)
ExampleE = {(2, 3), (4, 5), (1, 1)}
0 1 2 3 4 5 6 7 8 9
∅ 0 ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞ ∞
(2, 3) 0 ∞ ∞ 2 ∞ ∞ ∞ ∞ ∞ ∞
(4, 5) 0 ∞ ∞ 2 ∞ 4 ∞ ∞ 6 ∞
(1, 1) 0 1 ∞ 2 3 4 5 ∞ 6 7
v
i
Read out the solution: if g[i, v] = g[i− 1, v] then item i unused and continue with g[i− 1, v] otherwise used and continue
with g[i− 1, b− vi] .639
![Page 80: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/80.jpg)
The approximation trick
Pseduopolynomial run time gets polynmial if the number of occuringvalues can be bounded by a polynom of the input length.
Let K > 0 be chosen appropriately. Replace values vi by “roundedvalues” vi = bvi/Kc delivering a new input E ′ = (wi, vi)i=1...n.
Apply the algorithm on the input E ′ with the same weight limit W .
640
![Page 81: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/81.jpg)
Idea
Example K = 5
Values
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, . . . , 98, 99, 100
→0, 0, 0, 0, 1, 1, 1, 1, 1, 2, . . . , 19, 19, 20
Obviously less different values
641
![Page 82: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/82.jpg)
Properties of the new algorithm
Selection of items in E ′ is also admissible in E. Weight remainsunchanged!Run time of the algorithm is bounded by O(n2 · vmax/K)(vmax := max{vi|1 ≤ i ≤ n})
642
![Page 83: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/83.jpg)
How good is the approximation?
It holds thatvi −K ≤ K ·
⌊ viK
⌋= K · vi ≤ vi
Let I ′opt be an optimal solution of E ′. Then∑i∈Iopt
vi
− n ·K |Iopt|≤n≤
∑i∈Iopt
(vi −K) ≤∑i∈Iopt
(K · vi) = K∑i∈Iopt
vi
≤I ′optoptimal
K∑i∈I ′opt
vi =∑i∈I ′opt
K · vi ≤∑i∈I ′opt
vi.
643
![Page 84: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/84.jpg)
Choice of K
Requirement: ∑i∈I ′
vi ≥ (1− ε)∑i∈Iopt
vi.
Inequality from above:
∑i∈I ′opt
vi ≥
∑i∈Iopt
vi
− n ·Kthus: K = ε
∑i∈Iopt
vi
n .
644
![Page 85: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/85.jpg)
Choice of K
Choose K = ε
∑i∈Iopt
vi
n . The optimal sum is unknown. Therefore wechoose K ′ = εvmax
n .43
It holds that vmax ≤∑
i∈Ioptvi and thus K ′ ≤ K and the
approximation is even slightly better.
The run time of the algorithm is bounded by
O(n2 · vmax/K′) = O(n2 · vmax/(ε · vmax/n)) = O(n3/ε).
43We can assume that items i with wi > W have been removed in the first place.645
![Page 86: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/86.jpg)
FPTAS
Such a family of algorithms is called an approximation scheme: thechoice of ε controls both running time and approximation quality.
The runtime O(n3/ε) is a polynom in n and in 1ε . The scheme is
therefore also called a FPTAS - Fully Polynomial TimeApproximation Scheme
646
![Page 87: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/87.jpg)
21. Dynamic Programming III
Optimal Search Tree [Ottman/Widmayer, Kap. 5.7]
647
![Page 88: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/88.jpg)
Optimal binary Search TreesGiven: search probabilities pi for each key ki (i = 1, . . . , n) and qi ofeach interval di (i = 0, . . . , n) between search keys of a binarysearch tree.
∑ni=1 pi +
∑ni=0 qi = 1.
Wanted: optimal search tree T with key depths depth(·), thatminimizes the expected search costs
C(T ) =n∑i=1
pi · (depth(ki) + 1) +n∑i=0
qi · (depth(di) + 1)
= 1 +n∑i=1
pi · depth(ki) +n∑i=0
qi · depth(di)
648
![Page 89: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/89.jpg)
Optimal binary Search TreesGiven: search probabilities pi for each key ki (i = 1, . . . , n) and qi ofeach interval di (i = 0, . . . , n) between search keys of a binarysearch tree.
∑ni=1 pi +
∑ni=0 qi = 1.
Wanted: optimal search tree T with key depths depth(·), thatminimizes the expected search costs
C(T ) =n∑i=1
pi · (depth(ki) + 1) +n∑i=0
qi · (depth(di) + 1)
= 1 +n∑i=1
pi · depth(ki) +n∑i=0
qi · depth(di)
648
![Page 90: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/90.jpg)
Example
Expected Frequencies
i 0 1 2 3 4 5pi 0.15 0.10 0.05 0.10 0.20qi 0.05 0.10 0.05 0.05 0.05 0.10
649
![Page 91: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/91.jpg)
Example
k2
k1
d0 d1
k4
k3
d2 d3
k5
d4 d5
Search tree with expectedcosts 2.8
k2
k1
d0 d1
k5
k4
k3
d2 d3
d4
d5
Search tree with expectedcosts 2.75
650
![Page 92: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/92.jpg)
Structure of a optimal binary search tree
Subtree with keys ki, . . . , kj and intervals di−1, . . . , dj must beoptimal for the respective sub-problem.44
Consider all subtrees with roots kr and optimal subtrees for keyski, . . . , kr−1 and kr+1, . . . , kj
44The usual argument: if it was not optimal, it could be replaced by a better solution improving the overal solution.651
![Page 93: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/93.jpg)
Sub-trees for Searching
ki
di−1
ki+1..j
di dj· · ·
empty left subtree
kr
ki..r−1 kr+1..j
di−1 dr−1· · · dr dj· · ·
non-empty left andright subtrees
kj
dj
ki..j−1
di−1 dj−1· · ·
empty right subtree
652
![Page 94: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/94.jpg)
Expected Search Costs
Let depthT (k) be the depth of a node k in the sub-tree T . Let k bethe root of subtrees Tr and TLr
and TRrbe the left and right sub-tree
of Tr. Then
depthT (ki) = depthTLr(ki) + 1, (i < r)
depthT (ki) = depthTRr(ki) + 1, (i > r)
653
![Page 95: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/95.jpg)
Expected Search CostsLet e[i, j] be the costs of an optimal search tree with nodeski, . . . , kj.
Base case e[i, i− 1], expected costs di−1Let w(i, j) =
∑jl=i pl +
∑jl=i−1 ql.
If kr is the root of an optimal search tree with keys ki, . . . , kj, then
e[i, j] = pr + (e[i, r − 1] + w(i, r − 1)) + (e[r + 1, j] + w(r + 1, j))
with w(i, j) = w(i, r − 1) + pr + w(r + 1, j):
e[i, j] = e[i, r − 1] + e[r + 1, j] + w(i, j).
654
![Page 96: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/96.jpg)
Dynamic Programming
e[i, j] =
{qi−1 if j = i− 1,
mini≤r≤j{e[i, r − 1] + e[r + 1, j] + w[i, j]} if i ≤ j
655
![Page 97: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/97.jpg)
ComputationTables e[1 . . . n+ 1, 0 . . . n], w[1 . . . n+ 1, 0 . . .m], r[1 . . . n, 1 . . . n]Initially
e[i, i− 1]← qi−1, w[i, i− 1]← qi−1 for all 1 ≤ i ≤ n+ 1.
We compute
w[i, j] = w[i, j − 1] + pj + qje[i, j] = min
i≤r≤j{e[i, r − 1] + e[r + 1, j] + w[i, j]}
r[i, j] = arg mini≤r≤j{e[i, r − 1] + e[r + 1, j] + w[i, j]}
for intervals [i, j] with increasing lengths l = 1, . . . , n, each fori = 1, . . . , n− l + 1. Result in e[1, n], reconstruction via r. RuntimeΘ(n3). 656
![Page 98: 20. Dynamic Programming II - ETH Z · 20. Dynamic Programming II Subset sum problem, knapsack problem, greedy algorithm vs dynamic programming [Ottman/Widmayer, Kap. 7.2, 7.3, 5.7,](https://reader033.fdocuments.net/reader033/viewer/2022060221/5f0752477e708231d41c682f/html5/thumbnails/98.jpg)
Example
i 0 1 2 3 4 5pi 0.15 0.10 0.05 0.10 0.20qi 0.05 0.10 0.05 0.05 0.05 0.10
j
0 0.05
1 0.30 0.10
2 0.45 0.25 0.05
3 0.55 0.35 0.15 0.05
4 0.70 0.50 0.30 0.20 0.05
5 1.00 0.80 0.60 0.50 0.35 0.10
1 2 3 4 5 6 i
w
j
0 0.05
1 0.45 0.10
2 0.90 0.40 0.05
3 1.25 0.70 0.25 0.05
4 1.75 1.20 0.60 0.30 0.05
5 2.75 2.00 1.30 0.90 0.50 0.10
1 2 3 4 5 6 i
ej
1 1
2 1 2
3 2 2 3
4 2 2 4 4
5 2 4 5 5 5
1 2 3 4 5 i
r
657